$r1 = mysql_query("
SELECT *, SUM(bps.price) as sum FROM accounts
FULL JOIN bps on bps.id = mid
");
echo "Total price: ".$row['price']."<br>" ;
while($row = mysql_fetch_array($r1))
{
echo $row['name']." <b>:::</b> ".$row['mid']." <b>:::</b> ".$row['price'];
echo "<br />";
}
this is my query. I need to get the total(the sum) of the column : bps.price
some of the rows have : 10.5 , others -5.5 etc... in other words some are negative values and others are positive.It will list all the results then at the end display the sum of column price.
Does this work the way you want? I'm not sure which columns belong to which tables, just edit the table names (a / b) as needed...
$r1 = mysql_query("
SELECT *, sum(a.price) as sum FROM accounts as a
FULL JOIN bps as b on a.mid = b.id
");
echo "Total price: ".$row['sum']."<br>" ;
while($row = mysql_fetch_array($r1))
{
echo $row['a.name']." <b>:::</b> ".$row['a.mid']." <b>:::</b> ".$row['a.price'];
echo "<br />";
}
select sum(bps.price) FROM accounts a
FULL JOIN bps on bps.id = a.mid
That would work, right? It will sum positive and negative values, that doesn't matter.
Related
I have the following Mysql query:
$sql = "select r.brand AS brand, r.name AS name, r.cost AS cost, e.price AS price, d.shipping as shipping
FROM tab.rawproduct r
INNER JOIN price e ON r.housecode=e.housecode
INNER JOIN product d ON e.productid=d.productid
WHERE r.housecode='$housecode'";
The houscode is assigned to a variable which is then passed to the sql statement:
<label>Housecode:</label><input class="boxes" type="text" name="housecode" value="<?php echo $housecode; ?>"><br />
$housecode = $_POST['housecode'];
Housecode is submitted through a form with action set to $_SERVER[PHP_SELF]
I am trying to iterate over the results with PHP with the following:
$result = $con->query($sql);
if ($result->num_rows >0) {
while($row = mysqli_fetch_array($result)) {
$brand = $row['brand'];
$housecode = $row['housecode'];
$name = $row['name'];
$cost = $row['cost'];
$salesprice = $row['price'];
$shipraw = $row['shipping'];
}
} else {
echo "0 Results";
}
$con->close();
Nothing is getting returned when a user submits a housecode and the "0 Results" is echoed.
I have looked into this problem and read Lucas Knuth's post:
If two or more columns of the result have the same field names, the
last column will take precedence. To access the other column(s) of the
same name, you must use the numeric index of the column or make an
alias for the column. For aliased columns, you cannot access the
contents with the original column name. So, you can either use an AS
in your SQL-query to set other names for the doubled rows or use the
numbered indexes to access them.
So I have used the AS keyword in the above query but I still don't get any results. I have also tried changing to mysqli_fetch_row($result) and tried to assign the $row[0], 1 ... etc instead. Again no luck.
When I run Apache error_log I get the following:
Trying to get property of non-object on line 34. On line 34 and 35 I have:
if ($result->num_rows >0) {
while($row = mysqli_fetch_array($result)) {
Any help would be much appreciated.
Cheers
I have figured out the answer for myself.
The problem was that I was selecting just one database, ie tab.rawproduct BUT tables price e and procduct d are from a totally different database.
So the sql query should have been this:
$sql = "SELECT r.brand, r.name, r.cost, e.price, d.shipping FROM
tab.rawproduct r
INNER JOIN t1.price e on r.housecode=e.housecode
INNER JOIN t1.product d on e.productid=d.productid
WHERE r.housecode = '$housecode' ";
If found the error by checking the mysqli->errno:
if(!$result = $mysqli->query($sql)) {
echo "Error: Our query failed to execute and here is why: \n";
echo "Query: " . $sql . "\n";
echo "Errno: " . $mysqli->errno . "\n";
echo "Error: " . $mysqli->error . "\n";
exit;
}
Hopefully this may help someone else facing the same problem.
Thanks for all your comments and help.
I reproduced your example and I found a bug in your select query: you're missing the r.housecode.
$sql = "select r.brand AS brand, r.name AS name, r.cost AS cost, e.price AS price, d.shipping as shipping, r.housecode AS housecode
FROM tab.rawproduct r
INNER JOIN price e ON r.housecode=e.housecode
INNER JOIN product d ON e.productid=d.productid
WHERE r.housecode='$housecode'";
Check if the cross references match in your tables, because in my examples the rows are correctly returned
table price:
housecode productid price
HT0008 4 3400
HT0008 5 5400
table product:
shipping productid
64 4
78 5
table rawproduct:
brand name cost housecode
Cani bellaaa 63824 HT0008
I have two tables. Player and Stats. In player is username and id. In stats is honor and id. IDs are same in both tables. One player, one id. I would like to order stats by honor and echo it together with username to the table.
Here is my try, but i can't do anything with order.
Player counter is count of player. +1 reason is that it starts from 2
$getPlayerCounter = mysql_query("SELECT `id` FROM `player`");
$playerCounter = mysql_num_rows($getPlayerCounter);
for ($i = 2; $i <= $playerCounter + 1; $i++) {
$username = mysql_query("SELECT `player`.*, `stats`.* FROM `player` INNER JOIN `stats` ON `player`.`id`=$i AND `stats`.`id`=$i") or die(mysql_error());;
$fetch = mysql_fetch_assoc($username);
echo "<tr>";
echo "<td>".$fetch['username']."</td>";
echo "<td>".$fetch['honor']."</td>";
echo "</tr>";
}
Without using your loop. How about a solution where you query a sorted list already? Kind of like:
SELECT * FROM player p
JOIN stats s on p.id = s.id
ORDER BY s.honor DESC
Where honor is the name of your column for the stats value (hopefully it's a column you can sort like a number).
You will get an array of rows that is ordered by the stats value in descending order (maximum value on top). Now you can just fetch row by row in the order it is in the fetched array.
You walk through the array doing this:
$result = mysql_query(the_query_above);
while ($row = mysql_fetch_assoc($result)) {
echo "<tr>";
echo "<td>".$row['username']."</td>";
echo "<td>".$row['honor']."</td>";
echo "</tr>";
}
I have a table with 32 rows, with pairwise rows containing same "name-values", but with different raspberry-values (respectively "one" and "two".)
I want to extract each row with a unique name and the lowest average_distance - giving me 16 rows, and for that I am using this query:
SelectFinally();
function SelectFinally (){
$con = connectToDB();
$sql = "SELECT name,MIN(average_distance),raspberry From average GROUP BY name";
$result= mysqli_query($con,$sql);
$num_rows = mysqli_num_rows($result);
echo "number of rows" .$num_rows ."<br />";
while($row=mysqli_fetch_assoc($result)) {
extract($row);
$name = $row['name'];
$distance = $row['MIN(average_distance)']; //."<br />";
$raspberry = $row['raspberry']; //."<br />";
echo "select inside selectFinally name: " .$name ." distance: " .$distance ." raspberry " .$raspberry ."<br />";
}
}
This query gives me the lowest values of the average_distance allright, BUT it messes up my raspberry values. e.g. blå_bil should have a raspberry value of "two", hence it has the lowest average_distance - value.
I can not seem to get it right. Would somebody please help me to get it right?
try:
SELECT a.name, a.raspberry
FROM average a
INNER JOIN
(
SELECT name, MIN(average_distance) as avg_dist
FROM average
GROUP BY name
) a2 ON a.name = a2.name AND a.average_distance = a2.avg_dist
Instead of SELECT name,MIN(average_distance),raspberry From average GROUP BY name
thanks Nishant Matha
It worked - I simply needed to add te raspberry in my first select. Now it adds the average_distance to the output.
$sql = "SELECT a.name, a.average_distance, a.raspberry
from average a
INNER JOIN
(
select name,MIN(average_distance) AS avg_dist,raspberry
FROM average
GROUP BY name
)
a2 ON a.name=a2.name AND a.average_distance = a2.avg_dist ";
I need to display multiple queries (they can't be combined into one large query, at least I don't think so) together in a webpage. I'll explain a little about the queries to give an idea of the problem. I have a database in MySQL with 3 question tables of the same format linked to a response table via a classid. The response table is linked to an instructor table via an instructorid. I need to display a table showing all 3 question scores for each record existing for an instructor, with each table followed by some text indicating which question had the highest value as well as the least. I created a uniontbl view in MySQL which is a union query with fields ClassID, Average and TableName. What I have so far is:
$query2 = "SELECT `tbl_instructor`.`FirstName`,
`tbl_instructor`.`LastName`,
`tbl_term`.`TermID`,
`tbl_ucourse`.`Abbreviation`,
`tbl_ucourse`.`Series`,
`tbl_uquestion01`.`Average` AS `Q1`,
`tbl_uquestion02`.`Average` AS `Q2`,
`tbl_uquestion03`.`Average` AS `Q3`
FROM `tbl_instructor`
LEFT JOIN `undergrad`.`tbl_uresponse` ON `tbl_instructor`.`InstructorID` = `tbl_uresponse`.`InstructorID`
LEFT JOIN `undergrad`.`tbl_ucourse` ON `tbl_uresponse`.`CourseID` = `tbl_ucourse`.`CourseID`
LEFT JOIN `undergrad`.`tbl_Term` ON `tbl_UResponse`.`TermID` = `tbl_Term`.`TermID`
LEFT JOIN `undergrad`.`tbl_uquestion01` ON `tbl_uresponse`.`ClassID` = `tbl_uquestion01`.`ClassID`
LEFT JOIN `undergrad`.`tbl_uquestion02` ON `tbl_uresponse`.`ClassID` = `tbl_uquestion02`.`ClassID`
LEFT JOIN `undergrad`.`tbl_uquestion03` ON `tbl_uresponse`.`ClassID` = `tbl_uquestion03`.`ClassID`
WHERE CONCAT(LastName, ', ', FirstName, ' (', UserID, ')') = '{$instructor}'";
$query3 = "SELECT `tbl_instructor`.`FirstName`,
`tbl_instructor`.`LastName`,
`uniontbl`.`ClassID`,
`uniontbl`.`TableName`,
`tbl_uresponse`.`InstructorID`
FROM `tbl_Instructor`
LEFT JOIN `undergrad`.`tbl_uresponse` ON `tbl_instructor`.`InstructorID` = `tbl_uresponse`.`InstructorID`
LEFT JOIN `undergrad`.`uniontbl` ON `tbl_uresponse`.`ClassID` = `uniontbl`.`ClassID`
WHERE CONCAT(LastName, ', ', FirstName, ' (', UserID, ')') = '{$instructor}'
ORDER BY `uniontbl`.`Average` DESC
LIMIT 1";
$query4 = "SELECT `tbl_instructor`.`FirstName`,
`tbl_instructor`.`LastName`,
`uniontbl`.`ClassID`,
`uniontbl`.`TableName`,
`tbl_uresponse`.`InstructorID`
FROM `tbl_Instructor`
LEFT JOIN `undergrad`.`tbl_uresponse` ON `tbl_instructor`.`InstructorID` = `tbl_uresponse`.`InstructorID`
LEFT JOIN `undergrad`.`uniontbl` ON `tbl_uresponse`.`ClassID` = `uniontbl`.`ClassID`
WHERE CONCAT(LastName, ', ', FirstName, ' (', UserID, ')') = '{$instructor}'
ORDER BY `uniontbl`.`Average` ASC
LIMIT 1";
$result2 = mysqli_query($query2);
$result3 = mysqli_query($query3);
$result4 = mysqli_query($query4);
while($row2 = mysqli_fetch_assoc($result2))
{
echo "<br>";
echo"<table>";
echo "<tr>";
echo "<th>Q1</th>";
echo "<th>Q2</th>";
echo "<th>Q3</th>";
echo "</tr>";
echo "<tr>";
echo "<td>" . $row2['Q1'] . "</td>";
echo "<td>" . $row2['Q2'] . "</td>";
echo "<td>" . $row2['Q3'] . "</td>";
echo "</tr>";
echo"<br>";
echo "</table>";
while($row3 = mysqli_fetch_assoc($result3))
{
echo $row3['TableName'];
}
echo "<br>";
while($row4 = mysqli_fetch_assoc($result4))
{
echo $row4['TableName'];
}
echo "<br>";
}
So, how I've tried to tackle the problem is using the second and third queries to determine which questions had the highest and lowest score from the uniontbl view and displaying that after each table containing the question scores. The problem is that the second and third queries ONLY display after the first table (or record) and do not show at all after that. I have a feeling that the problem lies in the actual queries themselves but I can't think of another way to solve the problem. P.S. I know my code isn't the best (echoing HTML and such) but I'm just trying to get it to work...
After you print the first row of $result2, you fetch all the rows of $result3 and $result4. So after you print the second row of $result2, there's nothing left to fetch from the second and third queries.
Since the second and third queries use LIMIT 1, there's just one row for each of them. You could fetch them each once, and then display that row after each row of the first query. But I'm not sure why you need to display the same thing multiple times. Maybe you should just show the output of these two queries once, at the beginning or end, rather than after each row.
Also, do you really want to create a whole new table for each row of $result2? Usually each row is just a row in one big table, not a separate table with just one row for each row from the DB.
I have this query which gives me the transactions for a user, and the output is a table with the information. There is this row named basket_value which contains some numbers, and I need to get the sum of those numbers. Could you please help me?
$query3 = 'SELECT users.first_name,users.last_name,users.phone,
retailer.date, SUM(retailer.basket_value),
retailer.time,retailer.location,retailer.type_of_payment
FROM users ,retailer
WHERE users.user_id="'.$id_user.'"
AND users.user_id=retailer.user_id GROUP BY users.user_id';
$result3 = mysql_query($query) or die(mysql_error());
// Print out result
while($row = mysql_fetch_array($result3)) {
echo "Total ". $row['user_id']. " = $". $row['SUM(basket_value)'];
echo "<br />";
}
I suppose that also your query have some problem and suppose that you have an id to retrieve users, I would do in that way
$query3 = 'SELECT users.user_id,users.first_name,users.last_name,
users.phone, retailer.date,
SUM(retailer.basket_value) as total_sum,
retailer.time,retailer.location,retailer.type_of_payment
FROM users ,retailer WHERE users.user_id="'.$id_user.'"
AND users.user_id=retailer.user_id
GROUP BY users.user_id,users.first_name,users.last_name,
users.phone, retailer.date,retailer.time,retailer.location,
retailer.type_of_payment '
$result = $mysqli->query($query3);
Now if you want the sum for each user:
while ($row = $result->fetch_row()) {
echo "Player: ".$row['user_id']." total: ".$row['total_sum'];
}
If you want the WHOLE GLOBAL sum, you have to way:
Modify your query in that way:
SELECT SUM(retailer.basket_value) as total_sum
FROM retailer
Sum into while loop like: $total += $row['total_sum'];
You're missing a GROUP BY on your query. You most likely want to add GROUP BY users.user_id
Try this query:
SELECT u.first_name, u.last_name, u.phone, SUM(r.basket_value) as total_sum
FROM users u
JOIN retailers r
ON u.user_id = r.user_id
WHERE u.user_id="'.$id_user.'"
GROUP BY u.user_id
You can omit all other columns in the select list and only have the sum() aggregate run on the set to avoid the GROUP BY clause.
$query3 = 'SELECT SUM(retailer.basket_value) as total_sum
FROM users ,retailer WHERE users.user_id="'.$id_user.'"
AND users.user_id=retailer.user_id';