PHP SQL Query - unable to add HTML formatting - php

I have a database with three tables. A, B and C. Table A has one column: entity_id. Table B has two columns; entity_id, entity_name. Table C has two columns; entity_id, entity_body.
I am trying to use php to create an html table that displays entity_name and entity_body for all entity_id that appear in Table A.
$sql1 = $dbh->prepare('Select B.entity_name, C.entity_body FROM A
INNER JOIN B ON A.entity_id = B.entity_id
INNER JOIN C on A.entity_id = C.entity_id');
$sql1->execute();
while ($row = $sql1->fetchObject()) {
echo '<br><tr><td>';
echo $row->body_value;
echo '</td><td>';
echo $row->title;
echo '</td></tr>';
}
The above query is returning the correct database records: it shows all the relevant rows separated by a line-break.
However, the and HTML tags never seem to be added. The tags are added. All other tags are recognised and work as expected (e.g. p, div etc.).
Is it possible to format the outputs of a query as a table with HTML tags around the cells and the rows?
Apologies if this is obvious - this is my first attempt at using php with a database. Many thanks,
Ben

try
$sql1 = $dbh->prepare('Select B.entity_name, C.entity_body FROM A
INNER JOIN B ON A.entity_id = B.entity_id
INNER JOIN C on A.entity_id = C.entity_id');
$sql1->execute();
echo '<table width="100%">';
while ($row = $sql1->fetch(PDO::FETCH_OBJ)) {
echo '<tr>
<td>';
echo $row->entity_body;
echo ' </td>
<td>';
echo $row->entity_name;
echo '</td>
</tr>';
}
echo '</table>';

Looks like you are missing table tag before ''
//add table tag here.
echo '<table>'; //you can set table style using css as well
while ($row = $sql1->fetchObject()) {
echo '<tr><td>'; // no need to add <br> here
echo $row->body_value;
echo '</td><td>';
echo $row->title;
echo '</td></tr>';
}
//close table tag here
echo '</table>';
Hope this helps!

Related

Show most recent topic in forum category with PHP MySQL JOINS

I'm currently making a forum section in my website and I have a categories page that show the different categories that you can post in, in a table. One column of this table is a "Most recent topic" column. The table is made up of a while loop, running through each category in my categories database table. My issue is, the while loop keeps outputting EVERY topic and just reuses categories that it has already shown.
Here is the code:
$sql = "SELECT categories.cat_id, categories.cat_name, categories.cat_description, topics.topic_id, topics.topic_subject, topics.topic_date, topics.topic_cat FROM categories LEFT JOIN topics ON topics.topic_cat = categories.cat_id";
$query = $DB_con->prepare($sql);
$query->execute();
if (!$query) {
echo 'No categories found.';
} else {
echo '<table class="table">
<tr>
<th>Category</th>
<th>Last Topic</th>
</tr>';
while($catRow = $query->fetch(PDO::FETCH_ASSOC)) {
echo '<tr>';
echo '<td>';
echo '<h3>' . $catRow['cat_name'] . '</h3>' . $catRow['cat_description'];
echo '</td>';
echo '<td>';
echo '' . $catRow['topic_subject'] . ' on ' . substr($catRow['topic_date'],0,-8);
echo '</td>';
echo '</tr>';
}
echo '</table>';
}
?>
As I said before, the table keeps showing the same category multiple times, so that it can show me every topic that has been posted. I only want each category displayed once with the most recent topic in that category.
I hope somebody can help me. Let me know if it's not clear enough. Thanks.
If I understood correctly your question, maybe you should change your query:
Updated:
SELECT categories.cat_id
,categories.cat_name
,categories.cat_description
,topics.topic_id
,topics.topic_subject
,T1.topic_date
,T1.topic_cat
FROM categories
LEFT JOIN (SELECT topic_cat, MAX(topic_date) AS topic_date
FROM topics
GROUP BY topic_cat) AS T1 ON T1.topic_cat = categories.cat_id
LEFT JOIN topics ON T1.topic_cat = topics.topic_cat AND T1.topic_date=topics.topic_date

Display Multiple PHP Queries

I need to display multiple queries (they can't be combined into one large query, at least I don't think so) together in a webpage. I'll explain a little about the queries to give an idea of the problem. I have a database in MySQL with 3 question tables of the same format linked to a response table via a classid. The response table is linked to an instructor table via an instructorid. I need to display a table showing all 3 question scores for each record existing for an instructor, with each table followed by some text indicating which question had the highest value as well as the least. I created a uniontbl view in MySQL which is a union query with fields ClassID, Average and TableName. What I have so far is:
$query2 = "SELECT `tbl_instructor`.`FirstName`,
`tbl_instructor`.`LastName`,
`tbl_term`.`TermID`,
`tbl_ucourse`.`Abbreviation`,
`tbl_ucourse`.`Series`,
`tbl_uquestion01`.`Average` AS `Q1`,
`tbl_uquestion02`.`Average` AS `Q2`,
`tbl_uquestion03`.`Average` AS `Q3`
FROM `tbl_instructor`
LEFT JOIN `undergrad`.`tbl_uresponse` ON `tbl_instructor`.`InstructorID` = `tbl_uresponse`.`InstructorID`
LEFT JOIN `undergrad`.`tbl_ucourse` ON `tbl_uresponse`.`CourseID` = `tbl_ucourse`.`CourseID`
LEFT JOIN `undergrad`.`tbl_Term` ON `tbl_UResponse`.`TermID` = `tbl_Term`.`TermID`
LEFT JOIN `undergrad`.`tbl_uquestion01` ON `tbl_uresponse`.`ClassID` = `tbl_uquestion01`.`ClassID`
LEFT JOIN `undergrad`.`tbl_uquestion02` ON `tbl_uresponse`.`ClassID` = `tbl_uquestion02`.`ClassID`
LEFT JOIN `undergrad`.`tbl_uquestion03` ON `tbl_uresponse`.`ClassID` = `tbl_uquestion03`.`ClassID`
WHERE CONCAT(LastName, ', ', FirstName, ' (', UserID, ')') = '{$instructor}'";
$query3 = "SELECT `tbl_instructor`.`FirstName`,
`tbl_instructor`.`LastName`,
`uniontbl`.`ClassID`,
`uniontbl`.`TableName`,
`tbl_uresponse`.`InstructorID`
FROM `tbl_Instructor`
LEFT JOIN `undergrad`.`tbl_uresponse` ON `tbl_instructor`.`InstructorID` = `tbl_uresponse`.`InstructorID`
LEFT JOIN `undergrad`.`uniontbl` ON `tbl_uresponse`.`ClassID` = `uniontbl`.`ClassID`
WHERE CONCAT(LastName, ', ', FirstName, ' (', UserID, ')') = '{$instructor}'
ORDER BY `uniontbl`.`Average` DESC
LIMIT 1";
$query4 = "SELECT `tbl_instructor`.`FirstName`,
`tbl_instructor`.`LastName`,
`uniontbl`.`ClassID`,
`uniontbl`.`TableName`,
`tbl_uresponse`.`InstructorID`
FROM `tbl_Instructor`
LEFT JOIN `undergrad`.`tbl_uresponse` ON `tbl_instructor`.`InstructorID` = `tbl_uresponse`.`InstructorID`
LEFT JOIN `undergrad`.`uniontbl` ON `tbl_uresponse`.`ClassID` = `uniontbl`.`ClassID`
WHERE CONCAT(LastName, ', ', FirstName, ' (', UserID, ')') = '{$instructor}'
ORDER BY `uniontbl`.`Average` ASC
LIMIT 1";
$result2 = mysqli_query($query2);
$result3 = mysqli_query($query3);
$result4 = mysqli_query($query4);
while($row2 = mysqli_fetch_assoc($result2))
{
echo "<br>";
echo"<table>";
echo "<tr>";
echo "<th>Q1</th>";
echo "<th>Q2</th>";
echo "<th>Q3</th>";
echo "</tr>";
echo "<tr>";
echo "<td>" . $row2['Q1'] . "</td>";
echo "<td>" . $row2['Q2'] . "</td>";
echo "<td>" . $row2['Q3'] . "</td>";
echo "</tr>";
echo"<br>";
echo "</table>";
while($row3 = mysqli_fetch_assoc($result3))
{
echo $row3['TableName'];
}
echo "<br>";
while($row4 = mysqli_fetch_assoc($result4))
{
echo $row4['TableName'];
}
echo "<br>";
}
So, how I've tried to tackle the problem is using the second and third queries to determine which questions had the highest and lowest score from the uniontbl view and displaying that after each table containing the question scores. The problem is that the second and third queries ONLY display after the first table (or record) and do not show at all after that. I have a feeling that the problem lies in the actual queries themselves but I can't think of another way to solve the problem. P.S. I know my code isn't the best (echoing HTML and such) but I'm just trying to get it to work...
After you print the first row of $result2, you fetch all the rows of $result3 and $result4. So after you print the second row of $result2, there's nothing left to fetch from the second and third queries.
Since the second and third queries use LIMIT 1, there's just one row for each of them. You could fetch them each once, and then display that row after each row of the first query. But I'm not sure why you need to display the same thing multiple times. Maybe you should just show the output of these two queries once, at the beginning or end, rather than after each row.
Also, do you really want to create a whole new table for each row of $result2? Usually each row is just a row in one big table, not a separate table with just one row for each row from the DB.

Display MySQL table ( number of rows are not same ) in PHP

I have one MySQL table and it has two columns -
I want to display in my site like this -
I can easily take the table name Boy | Girl . But when i try to display the table I get like this -
I am just showing one example here. There may be 50 boys and 10 girls.. So I need help.
After displaying the heading
while($row_type = mysql_fetch_array($type))
{
$type_name = $row_type['type_name']; //Boy (or) Girl taking from another table
$type_name = Database::getInstance()->query("SELECT * FROM details WHERE type='type_name'");
echo "<tr>";
while($row_name = mysql_fetch_array($type_name))
{
echo "<td>$row_name[type_name]</td>"; //Displaying the names
}
echo "</tr>";
}
So many views but not getting any answer. Please help guys. Please catch my mistake.
Try with two queries.
Make an array for each category(Male & Female)
It Works.
$maleQuery = mysql_query("SELECT * FROM table WHERE category='male'");
$femaleQuery = mysql_query("SELECT * FROM table WHERE category='female'");
while(($row = mysql_fetch_assoc($maleQuery))) {
$males[] = $row['name'];
}
while(($row = mysql_fetch_assoc($femaleQuery))) {
$females[] = $row['name'];
}
$number_of_rows = max(sizeof($males),sizeof($females));
echo "<table border='1'>";
echo "<tr><td>Male</td><td>Female</td></tr>";
for($i=0;$i<$number_of_rows;$i++)
{
echo "<tr><td>".#$males[$i]."</td><td>".#$females[$i]."</td></tr>";
}
Try this query 100% working but set php code.
SELECT IFNULL(c.Boy,'')AS Boy,IFNULL(c.Girl,'')AS Girl FROM
(SELECT x.name,CASE WHEN (x.category = 'boy') THEN x.name END AS Boy,CASE WHEN (x.category = 'girl') THEN x.name END AS Girl FROM (SELECT * FROM tablename) X)c
Is your problem to do with the creation of the table using PHP or is it related to the SQL query itself?
If it is the creation of the table then I suggest you use two tables embedded in a single table like this. That way you can build the first table using one SQL query, then build the second table using a second query, then display the table and girls and boys will appear side by side regardless of how many entries on each side. Your code would look a bit like this:
echo "<table>
<tr>
<td>
<table>
<tr><th>Boy</th></tr>";
$table = mysql_query("SELECT Name FROM details WHERE Category = 'Boy'") or die(mysql_error());
while($row = mysql_fetch_row($table))
echo "<tr><td>".$row[0]."</td>";
echo "</table>
</td>
<td>
<table>
<tr><th>Girl</th></tr>";
$table = mysql_query("SELECT Name FROM details WHERE Category = 'Girl'") or die(mysql_error());
while($row = mysql_fetch_row($table))
echo "<tr><td>".$row[0]."</td>";
echo "</table>
</td>
</tr>
</table>";
If you need to cater for more categories, do an initial search to determine the distinct categories, then put the section of code above that creates the inner table in a loop.
eg. in pseudo code:
echo the outer table <table><tr>
SELECT DISTINCT Category FROM details
while row1=get next category
$cat = row1[0];
echo "<td>
<table>
<tr><th>".$cat."</th></tr>";
$table = mysql_query("SELECT Name FROM details WHERE Category = '".$cat."'") or die(mysql_error());
while($row = mysql_fetch_row($table))
echo "<tr><td>".$row[0]."</td>";
echo "</table>
</td>
echo the </tr></table> to close the outer table

Creating Categories using database in PHP

Hi I want to create Categories listed which are saved in my database so when user upload his images and he select the category it saves the data in database in Cat column
Now I want to show category in PHP like this
Categories Total
Animals (4)
Celebrations (2)
Locations And Travel (11)
Object or still life (1)
Transportation (9)
Here is my PHP I am succeeded to show Categories names but not total category in each category
<?php
$con=mysqli_connect("localhost","root","123","user");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"Select Cat from save_data Group By Cat ")
or die(mysql_error());
echo "<table border='1'>
<tr>
<th>Categories</th>
<th>Total</th>
</tr>";
while($row = mysqli_fetch_array($result, MYSQL_ASSOC))
{
echo "<tr>";
echo "<td>" . $row['Cat'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($con);
?>
Extend the table cell:
<td colspan="2"></td>
This way it extends over another cell.
Also I notice you are mixing mysqli and mysql:
or die(mysql_error());
Try to use mysqli as objects and \Exceptions instead of errors. It's worth learning about :-)
Update:
I did not understand your question at first. Please provide your schema so we can see your table structure.
Usually you would have 2 tables, one with categories and one with data and join them with a GROUP BY (if an item can be in several categories, you would have a third table like category_has_item!):
SELECT c.category AS cat,
COUNT(i.items) AS num
FROM category c
LEFT JOIN items i
ON c.category_id = i.category_id
GROUP BY c.category
Use LEFT JOIN to display empty categories and JOIN (without LEFT) to avoid empty categories.
Change your table echo:
echo "<td>" . $row['cat'] . "</td><td>(" . $row['num'] . ")</td>";
Update:
If you only have 1 table, I strongly suggest you to read about database normalization.
Update your query:
Select Cat,COUNT(Data) AS num from save_data Group By Cat
Replace Data by your data column
and your echo line:
echo "<td>" . $row['Cat'] . "</td><td>(" . $row['num'] . ")</td>";
try to change your sql query like this
SELECT count(*) AS total_count FROM (SELECT Cat FROM save_data GROUP BY Cat HAVING COUNT(Cat) > 1) AS t

Get records from database in table with rowspan

I've try a lot of ways to get this table print as good as it should but I failed.
I know it's simple thing so I hope you help me with it.
Here's my code:
<?php
include('../connect.php');
$id=$_SESSION['login_user'];
$sql = "Select CourseName , Studentname from course p natural join student t";
$rs_result = mysql_query ($sql, $connection);
echo "<center>";
echo "<table>";
echo "<tr> <th>Course Name</th> <th> Students Name</th> </tr>";
// loop through results of database query, displaying them in the table
while($row = mysql_fetch_array( $rs_result )) {
// echo out the contents of each row into a table
echo "<tr>";
echo '<td>' . $row['CourseName'] . '</td>';
echo "<td rowspan=''> $row[Studentname] </td> ";
echo "</tr>";
}
echo "</table>";
echo "</center>";
?>
I want to be something like this
Course | Name | Student name |
Math101 | john, Mike |
...
Also, is the JOIN query between the two tables CORRECT or not?
The two tables are:
Course ( Course name - Course id )
Student ( Student name - Course id )
Try this query
$sql ="SELECT cor.CourseName,GROUP_CONCAT(stu.StudentName) AS StudentName
FROM course AS cor
LEFT JOIN student AS stu
ON stu.CourseId = cor.CourseId";
And change the the line in below
echo "<td rowspan=''>" . $row['Studentname'] . "</td> ";
This line:
echo "<td rowspan=''> $row[Studentname] </td> ";
You are accessing the array element improperly. Studentname should have single quotes around it like such:
echo "<td rowspan=''>" . $row['Studentname'] . "</td> ";
Also, in your query, this may work better:
$sql = "SELECT c.CourseName, s.StudentName
FROM course AS c
INNER JOIN student AS s
ON s.CourseId = c.CourseId";
Please use below format
SELECT CourseName , Studentname
FROM course
INNER JOIN student
ON course.id = student.id
Thanks
The problem is with Your rowspan attribute - You need to provide it with the exact number of rows to span through. Anyway, I think it is the collspan attribute You want to use, so e.g.
echo "<td collspan='2'> {$row['Studentname']} </td> ";
which means it will span through 2 columns, thus stundet's name will be both under the Name and Student name columns.
Is this what You were expecting?
Also I highly recommend not to use mysql_ functions but learn how to use mysqli or at least PDO.
I'm under the impression that you wanted to display a comma-separated list of names of all the students that attend each course, for each separate CourseName. In this case, you could change your SQL query to something like this:
SELECT CourseName, GROUP_CONCAT(Studentname SEPARATOR ', ') as names
FROM Course p NATURAL JOIN Student t
GROUP BY CourseName;
Hello please take a look of this answer. Dynamic rowspan while fetching records from database
I think it might be helpfull.

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