Creating Categories using database in PHP - php

Question

Hi I want to create Categories listed which are saved in my database so when user upload his images and he select the category it saves the data in database in Cat column
Now I want to show category in PHP like this
Categories Total
Animals (4)
Celebrations (2)
Locations And Travel (11)
Object or still life (1)
Transportation (9)
Here is my PHP I am succeeded to show Categories names but not total category in each category
<?php
$con=mysqli_connect("localhost","root","123","user");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"Select Cat from save_data Group By Cat ")
or die(mysql_error());
echo "<table border='1'>
<tr>
<th>Categories</th>
<th>Total</th>
</tr>";
while($row = mysqli_fetch_array($result, MYSQL_ASSOC))
{
echo "<tr>";
echo "<td>" . $row['Cat'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($con);
?>

Answer 1

Extend the table cell:
<td colspan="2"></td>
This way it extends over another cell.
Also I notice you are mixing mysqli and mysql:
or die(mysql_error());
Try to use mysqli as objects and \Exceptions instead of errors. It's worth learning about :-)
Update:
I did not understand your question at first. Please provide your schema so we can see your table structure.
Usually you would have 2 tables, one with categories and one with data and join them with a GROUP BY (if an item can be in several categories, you would have a third table like category_has_item!):
SELECT c.category AS cat,
COUNT(i.items) AS num
FROM category c
LEFT JOIN items i
ON c.category_id = i.category_id
GROUP BY c.category
Use LEFT JOIN to display empty categories and JOIN (without LEFT) to avoid empty categories.
Change your table echo:
echo "<td>" . $row['cat'] . "</td><td>(" . $row['num'] . ")</td>";
Update:
If you only have 1 table, I strongly suggest you to read about database normalization.
Update your query:
Select Cat,COUNT(Data) AS num from save_data Group By Cat
Replace Data by your data column
and your echo line:
echo "<td>" . $row['Cat'] . "</td><td>(" . $row['num'] . ")</td>";

Answer 2

try to change your sql query like this
SELECT count(*) AS total_count FROM (SELECT Cat FROM save_data GROUP BY Cat HAVING COUNT(Cat) > 1) AS t