Display MySQL table ( number of rows are not same ) in PHP - php

Question

I have one MySQL table and it has two columns -
I want to display in my site like this -
I can easily take the table name Boy | Girl . But when i try to display the table I get like this -
I am just showing one example here. There may be 50 boys and 10 girls.. So I need help.
After displaying the heading
while($row_type = mysql_fetch_array($type))
{
$type_name = $row_type['type_name']; //Boy (or) Girl taking from another table
$type_name = Database::getInstance()->query("SELECT * FROM details WHERE type='type_name'");
echo "<tr>";
while($row_name = mysql_fetch_array($type_name))
{
echo "<td>$row_name[type_name]</td>"; //Displaying the names
}
echo "</tr>";
}
So many views but not getting any answer. Please help guys. Please catch my mistake.

Answer 1

Try with two queries.
Make an array for each category(Male & Female)
It Works.
$maleQuery = mysql_query("SELECT * FROM table WHERE category='male'");
$femaleQuery = mysql_query("SELECT * FROM table WHERE category='female'");
while(($row = mysql_fetch_assoc($maleQuery))) {
$males[] = $row['name'];
}
while(($row = mysql_fetch_assoc($femaleQuery))) {
$females[] = $row['name'];
}
$number_of_rows = max(sizeof($males),sizeof($females));
echo "<table border='1'>";
echo "<tr><td>Male</td><td>Female</td></tr>";
for($i=0;$i<$number_of_rows;$i++)
{
echo "<tr><td>".#$males[$i]."</td><td>".#$females[$i]."</td></tr>";
}

Answer 2

Try this query 100% working but set php code.
SELECT IFNULL(c.Boy,'')AS Boy,IFNULL(c.Girl,'')AS Girl FROM
(SELECT x.name,CASE WHEN (x.category = 'boy') THEN x.name END AS Boy,CASE WHEN (x.category = 'girl') THEN x.name END AS Girl FROM (SELECT * FROM tablename) X)c

Answer 3

Is your problem to do with the creation of the table using PHP or is it related to the SQL query itself?
If it is the creation of the table then I suggest you use two tables embedded in a single table like this. That way you can build the first table using one SQL query, then build the second table using a second query, then display the table and girls and boys will appear side by side regardless of how many entries on each side. Your code would look a bit like this:
echo "<table>
<tr>
<td>
<table>
<tr><th>Boy</th></tr>";
$table = mysql_query("SELECT Name FROM details WHERE Category = 'Boy'") or die(mysql_error());
while($row = mysql_fetch_row($table))
echo "<tr><td>".$row[0]."</td>";
echo "</table>
</td>
<td>
<table>
<tr><th>Girl</th></tr>";
$table = mysql_query("SELECT Name FROM details WHERE Category = 'Girl'") or die(mysql_error());
while($row = mysql_fetch_row($table))
echo "<tr><td>".$row[0]."</td>";
echo "</table>
</td>
</tr>
</table>";
If you need to cater for more categories, do an initial search to determine the distinct categories, then put the section of code above that creates the inner table in a loop.
eg. in pseudo code:
echo the outer table <table><tr>
SELECT DISTINCT Category FROM details
while row1=get next category
$cat = row1[0];
echo "<td>
<table>
<tr><th>".$cat."</th></tr>";
$table = mysql_query("SELECT Name FROM details WHERE Category = '".$cat."'") or die(mysql_error());
while($row = mysql_fetch_row($table))
echo "<tr><td>".$row[0]."</td>";
echo "</table>
</td>
echo the </tr></table> to close the outer table