Cakephp AND constraint for array in query operation - php

I have a Table schedules that needs to be joined in my Query.
$joins[] = array(
'table' => 'schedules',
'alias' => 'Schedule',
'conditions' => array(
'Schedule.provider_id = Provider.id',
'Schedule.endtime > "' . date('Y-m-d H:i:s') . '"',
'Schedule.starttime' => $startTimes,
),
'type' => 'INNER'
);
$starttimesis an array consisting of DateTime Objects.
Providers can have multiple schedules and I want to get all providers, which match at least all starttimes from the $starttimesarray.

Thanks to ndm I got the solution. What I was missing was the group stetement:
$group = 'Provider.id HAVING COUNT(DISTINCT Schedule.id) = ' . count($startTimes);

Related

Cakephp get all months records with a single query i.e with single find

I am working on a ecommerce with platform cakephp and using google charts for reports.My requirement is to get all records as per all 12 months, so I have used following code for a single month
Query
SELECT COUNT(*) AS count FROM orderproductmasters AS Orderproductmaster
LEFT JOIN ordermasters AS Ordermaster ON
(Orderproductmaster.ordermaster_id = Ordermaster.id) LEFT JOIN productmasters AS Productmaster ON
(Orderproductmaster.productmaster_id = Productmaster.id)
WHERE Ordermaster.orderstatusmaster_id = 1 AND Month(Orderproductmaster.created) = 8
Code
$this->Orderproductmaster->find('count',
array('conditions'=>array('Ordermaster.orderstatusmaster_id'=>1,'
Month(Orderproductmaster.created)'=>8)));
Since, I need records as per Jan, feb,march and all 12 months...,so for 12 months I am using following code
for($i=1;$i<13;$i++)
{
$orderproductmasters[$i] = $this->Orderproductmaster->find('count',
array('conditions'=>array('Ordermaster.orderstatusmaster_id'=>1,
'Month(Orderproductmaster.created)'=>$i)));
}
So question might be silly, but is it possible to get all months record without using for loop i.e, within a single query.
Thanks in advance
I think , your need can be fulfilled by using cursors in stored procedure. And then using stored procedure to cake-php.
Example on db side is here
$options = array();
$options['fields'] = array('COUNT(Orderproductmaster.id)');
$options['conditions'] = array('Ordermaster.orderstatusmaster_id = 1',
'Month(Orderproductmaster.created) BETWEEN 1 AND 12');
$options['joins'] = array(
array(
'table' => 'ordermasters',
'alias' => 'Ordermaster',
'type' => 'left',
'conditions' => array(
'Orderproductmaster.ordermaster_id = Ordermaster.id'
)
),
array(
'table' => 'productmasters',
'alias' => 'Productmaster',
'type' => 'left',
'conditions' => array(
'Orderproductmaster.productmaster_id = Productmaster.id'
)
)
);
$options['group'] => array('Month(Orderproductmaster.created)');
$this->Orderproductmaster->find('all',$options);
What About something like:
$this->Orderproductmaster->find('count',
array(
'fields'=>'DISTINCT(Month(Orderproductmaster.created)),
'conditions'=>array('Ordermaster.orderstatusmaster_id'=>1,'
Month(Orderproductmaster.created)'=>8)));

How to run subqueries in cakephp

Cakephp 2.6
I have a Model, Temps, which has many tickets. In the index view of Temps I want to return for each record, the ticket with the date closest to the current date.
In mySQL it can be done as
'SELECT expiry_date FROM uploads WHERE expiry_date > CURDATE() ORDER BY expiry_date ASC LIMIT 1'
But I don't know how to run this as a sub query. My Current query to generate my results is as follows: (bearing in mind this has been configured for datatables) Tickets is an alias for the Upload Model
public function getAjaxIndexData($data) {
$tokens = explode(" ", $data['searchString']);
$conditions = array(
$this->alias . '.deleted' => false,
'OR' => array(
'CONCAT(' . $this->alias . '.first_name," ",' . $this->alias . '.last_name) LIKE' => '%' . implode(' ', $tokens) . '%',
),
$data['columnsFilter']
);
$fields = array(
'id',
'full_name',
'pps_number',
'mobile',
'email',
'start_date',
'time_served'
);
$order = array(
$data['orderField'] => $data['order']
);
$contain = array(
'LocalOffice.name',
);
$options = array(
'conditions' => $conditions,
'fields' => $fields,
'order' => $order,
'contain' => $contain,
'limit' => $data['limit'],
'offset' => $data['start']
);
$optionsNoFields = array(
'conditions' => $conditions,
'contain' => $contain,
);
$result['draw'] = $data['draw'];
$result['recordsTotal'] = $recordTotal = $this->find('count');
$result['recordsFiltered'] = $this->find('count', $optionsNoFields);
$result['data'] = $this->find('all', $options); //standard search
$result['data'] = $this->formatTable($result['data']);
return json_encode($result);
}
Within this query I would like to add a field that shows the nearest expiry date for each Temp.
How would I construct this?
Dynamically create a virtual field:
$this->virtualFields['nearest'] = '(SELECT expiry_date FROM uploads WHERE expiry_date > CURDATE() AND uploads.owner_id = '.$this->alias.'.ticket_id ORDER BY expiry_date ASC LIMIT 1')';
Then adjust your fields array
$fields = array(
'id',
'full_name',
'pps_number',
'mobile',
'email',
'start_date',
'time_served',
'nearest'
);
Also, the query could be rewritten as ("temp" needs to be replaced with the model alias)
SELECT MIN(expiry_date)
FROM uploads
WHERE expiry_date > CURDATE()
AND uploads.owner_id = temp.ticket_id;
Which means that a potentially better performing query would be to move that subquery out of the columns of the SELECT statement to a JOIN. For example:
SELECT *
FROM temp
LEFT JOIN (SELECT MIN(expiry_date) AS expiry,owner_id
FROM uploads
WHERE expiry_date > CURDATE())
GROUP BY owner_id) AS next_dates
ON next_dates.owner_id = temp.ticket_id;

CakePHP Retrieving data from multiple tables with select conditions

I am building an application using CakePHP and I am stuck on a problem retrieving data using a series of joins. In the simplified example below the join with the alias Delivery could have more than record and I want to bring back the record with a max value in a particular field in that table.
$inv_conditions = array( 'Invoice.invoice_date >=' => $DateFormatter->dateForDB($dateFrom),
'Invoice.invoice_date <=' => $DateFormatter->dateForDB($dateTo),
'Invoice.id >' => 385380 );
$join = array(array(
'table' => 'jobs',
'alias' => 'Jobs',
'type' => 'LEFT',
'conditions' => array('Invoice.job_id = Jobs.JOB_ID' )
),
array(
'table' => 'functional',
'alias' => 'Delivery',
'type' => 'LEFT'
'conditions'=> array('AND ' => array('Invoice.job_id = Delivery.JOB',
'Delivery.TYPE_STAGE = 1')
)
)
);
$invoices = $this->Invoice->find("all", array(
"fields" => array(
'Invoice.id',
'Invoice.job_id',
'Invoice.invoice_no',
'Invoice.consolidated_type',
'Invoice.customer_id_tbc',
'Invoice.invoice_date',
'Invoice.invoice_reference',
'Invoice.invoice_req',
'Jobs.PAYMENT_TYPE',
'Jobs.CUSTOMER',
'Jobs.MOST_RELEVANT_LINE',
'Delivery.DEPARTURE_DATE',
'Delivery.CNOR_CNEE_NAME',
'Delivery.TOWN_NAME',
),
"conditions" => $inv_conditions,
"joins" => $join
)
);
}
I can do this with SQL no problem as follows:
SELECT
jobs.JOB_ID,
jobs.CUSTOMER,
functional.JOB_LINE_ORDER,
functional.CNOR_CNEE_NAME,
functional.TOWN_NAME
FROM jobs JOIN functional ON
jobs.JOB_ID = 'M201409180267'
AND
functional.JOB = jobs.JOB_ID
AND
functional.TYPE_STAGE = 0
AND
functional.JOB_LINE_ORDER =
(SELECT MAX(JOB_LINE_ORDER) FROM functional
WHERE functional.JOB = 'M201409180267' AND functional.TYPE_STAGE = 0)
I have tried using the following to the conditions array:
'conditions' => array('AND ' =>
array( 'Invoice.job_id = Delivery.JOB',
'Delivery.TYPE_STAGE = 1'
'Delivery.JOB_LINE_ORDER = MAXIMUM(Delivery.JOB_LINE_ORDER)' )
)
This does bring back results but not the correct ones and the resulting SQL generated by Cake does have a select in the where clause. Is there a way of doing this when retrieving data in cake where the sql statement created will have a select in the where clause.
Any suggestions would be greatly appreciated.
Thanks
Bas
You need to use subquery to generate the select in the where clause. You can create a method in your model that does this and call it from your controller.
$subQuery = $db->buildStatement(
array(
'fields' => array(''),
'table' => $db->fullTableName($this),
'alias' => 'aliasName',
'limit' => null,
'offset' => null,
'joins' => array(),
'conditions' => $conditionsArray,
'order' => null,
'group' => null
),
$this
);
$subQuery = ' <<YOUR MAIN QUERY CONDITION (' . $subQuery . ') >>';
$subQueryExpression = $db->expression($subQuery);
$conditions[] = $subQueryExpression;
return $this->Model->find('list', compact('conditions'));

CakePHP pagination - order by virtual field

Contributors have songs and songs have contributors. I want to be able to sort by the number of songs that a contributor has.
In my Controller:
public $paginate = array(
'fields' => array(
'Contributor.id',
'Contributor.name',
'COUNT(DISTINCT ContributorsSong.song_id) AS Contributor__TotalSongs',
),
'joins' => array(
array(
'alias' => 'ContributorsSong',
'table' => 'contributors_songs',
'type' => 'LEFT',
'conditions' => 'ContributorsSong.contributor_id = Contributor.id'
),
array(
'alias' => 'Song',
'table' => 'songs',
'type' => 'LEFT',
'conditions' => 'ContributorsSong.song_id = Song.id'
)
),
'group' => array('ContributorsSong.contributor_id')
);
And in my index method.
$this->Contributor->recursive = 0;
$this->Paginator->settings = $this->paginate;
$this->Contributor->virtualFields['TotalSongs'] = 0;
$items = $this->paginate();
echo '<pre>';print_r($items);echo '</pre>';
I'm trying to sort by the number of songs by using a virtual field, so when I go to
localhost/site/contributors/index/sort:TotalSongs/
I get this error:
Error: SQLSTATE[42S22]: Column not found: 1054 Unknown column '0' in 'order clause'
SQL Query:
SELECT Contributor.id,
Contributor.name,
COUNT(DISTINCT ContributorsSong.song_id) AS Contributor__TotalSongs
FROM db_songs2.contributors AS Contributor LEFT JOIN
db_songs2.contributors_songs AS ContributorsSong ON
(ContributorsSong.contributor_id = Contributor.id) LEFT JOIN
db_songs2.songs AS Song ON (ContributorsSong.song_id =
Song.id) WHERE 1 = 1 GROUP BY ContributorsSong.contributor_id
ORDER BY (0) desc LIMIT 18
I thought that TotalSongs would get turned into Contributor__TotalSongs in the query but it gets turned into 0. What is going on here? Thanks.
I replaced:
$this->Contributor->virtualFields['TotalSongs'] = 0;
with:
$this->Contributor->virtualFields['TotalSongs'] = 'COUNT(DISTINCT ContributorsSong.song_id)';
And deleted:
'COUNT(DISTINCT ContributorsSong.song_id) AS Contributor__TotalSongs',
And it works for ordering now, but I can't use it in the conditions. I think this is part of the Limitations of virtualFields? I'm trying to select only tables where TotalSongs > 0, but I think I can get this another way, by changing the join from LEFT to INNER.

How do I get a DISTINCT value from my paginate statement?

$this->Release->recursive = 0;
$this->paginate['Release']['joins'] =
array(
array(
'table' => ' game_potential_amazon_matches',
'alias' => 'PotentialAmazonMatch',
'type' => 'inner',
'conditions' =>
array(
'PotentialAmazonMatch.release_id = Release.id'
)
)
);
$this->set('releases', $this->paginate('Release'));
$this->set('title_for_layout', 'Release with Potential Amazon Matches)');
I am getting multiple records and would just like to get distinct by Release.id?
You have to use DISTINCT in fields in that case.
just after conditions array use fields array like
fields => array('DISTINCE Release.id','field 2','field 3',...etc)

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