CakePHP Retrieving data from multiple tables with select conditions - php

I am building an application using CakePHP and I am stuck on a problem retrieving data using a series of joins. In the simplified example below the join with the alias Delivery could have more than record and I want to bring back the record with a max value in a particular field in that table.
$inv_conditions = array( 'Invoice.invoice_date >=' => $DateFormatter->dateForDB($dateFrom),
'Invoice.invoice_date <=' => $DateFormatter->dateForDB($dateTo),
'Invoice.id >' => 385380 );
$join = array(array(
'table' => 'jobs',
'alias' => 'Jobs',
'type' => 'LEFT',
'conditions' => array('Invoice.job_id = Jobs.JOB_ID' )
),
array(
'table' => 'functional',
'alias' => 'Delivery',
'type' => 'LEFT'
'conditions'=> array('AND ' => array('Invoice.job_id = Delivery.JOB',
'Delivery.TYPE_STAGE = 1')
)
)
);
$invoices = $this->Invoice->find("all", array(
"fields" => array(
'Invoice.id',
'Invoice.job_id',
'Invoice.invoice_no',
'Invoice.consolidated_type',
'Invoice.customer_id_tbc',
'Invoice.invoice_date',
'Invoice.invoice_reference',
'Invoice.invoice_req',
'Jobs.PAYMENT_TYPE',
'Jobs.CUSTOMER',
'Jobs.MOST_RELEVANT_LINE',
'Delivery.DEPARTURE_DATE',
'Delivery.CNOR_CNEE_NAME',
'Delivery.TOWN_NAME',
),
"conditions" => $inv_conditions,
"joins" => $join
)
);
}
I can do this with SQL no problem as follows:
SELECT
jobs.JOB_ID,
jobs.CUSTOMER,
functional.JOB_LINE_ORDER,
functional.CNOR_CNEE_NAME,
functional.TOWN_NAME
FROM jobs JOIN functional ON
jobs.JOB_ID = 'M201409180267'
AND
functional.JOB = jobs.JOB_ID
AND
functional.TYPE_STAGE = 0
AND
functional.JOB_LINE_ORDER =
(SELECT MAX(JOB_LINE_ORDER) FROM functional
WHERE functional.JOB = 'M201409180267' AND functional.TYPE_STAGE = 0)
I have tried using the following to the conditions array:
'conditions' => array('AND ' =>
array( 'Invoice.job_id = Delivery.JOB',
'Delivery.TYPE_STAGE = 1'
'Delivery.JOB_LINE_ORDER = MAXIMUM(Delivery.JOB_LINE_ORDER)' )
)
This does bring back results but not the correct ones and the resulting SQL generated by Cake does have a select in the where clause. Is there a way of doing this when retrieving data in cake where the sql statement created will have a select in the where clause.
Any suggestions would be greatly appreciated.
Thanks
Bas

You need to use subquery to generate the select in the where clause. You can create a method in your model that does this and call it from your controller.
$subQuery = $db->buildStatement(
array(
'fields' => array(''),
'table' => $db->fullTableName($this),
'alias' => 'aliasName',
'limit' => null,
'offset' => null,
'joins' => array(),
'conditions' => $conditionsArray,
'order' => null,
'group' => null
),
$this
);
$subQuery = ' <<YOUR MAIN QUERY CONDITION (' . $subQuery . ') >>';
$subQueryExpression = $db->expression($subQuery);
$conditions[] = $subQueryExpression;
return $this->Model->find('list', compact('conditions'));

Related

CakePHP pagination - order by virtual field

Contributors have songs and songs have contributors. I want to be able to sort by the number of songs that a contributor has.
In my Controller:
public $paginate = array(
'fields' => array(
'Contributor.id',
'Contributor.name',
'COUNT(DISTINCT ContributorsSong.song_id) AS Contributor__TotalSongs',
),
'joins' => array(
array(
'alias' => 'ContributorsSong',
'table' => 'contributors_songs',
'type' => 'LEFT',
'conditions' => 'ContributorsSong.contributor_id = Contributor.id'
),
array(
'alias' => 'Song',
'table' => 'songs',
'type' => 'LEFT',
'conditions' => 'ContributorsSong.song_id = Song.id'
)
),
'group' => array('ContributorsSong.contributor_id')
);
And in my index method.
$this->Contributor->recursive = 0;
$this->Paginator->settings = $this->paginate;
$this->Contributor->virtualFields['TotalSongs'] = 0;
$items = $this->paginate();
echo '<pre>';print_r($items);echo '</pre>';
I'm trying to sort by the number of songs by using a virtual field, so when I go to
localhost/site/contributors/index/sort:TotalSongs/
I get this error:
Error: SQLSTATE[42S22]: Column not found: 1054 Unknown column '0' in 'order clause'
SQL Query:
SELECT Contributor.id,
Contributor.name,
COUNT(DISTINCT ContributorsSong.song_id) AS Contributor__TotalSongs
FROM db_songs2.contributors AS Contributor LEFT JOIN
db_songs2.contributors_songs AS ContributorsSong ON
(ContributorsSong.contributor_id = Contributor.id) LEFT JOIN
db_songs2.songs AS Song ON (ContributorsSong.song_id =
Song.id) WHERE 1 = 1 GROUP BY ContributorsSong.contributor_id
ORDER BY (0) desc LIMIT 18
I thought that TotalSongs would get turned into Contributor__TotalSongs in the query but it gets turned into 0. What is going on here? Thanks.
I replaced:
$this->Contributor->virtualFields['TotalSongs'] = 0;
with:
$this->Contributor->virtualFields['TotalSongs'] = 'COUNT(DISTINCT ContributorsSong.song_id)';
And deleted:
'COUNT(DISTINCT ContributorsSong.song_id) AS Contributor__TotalSongs',
And it works for ordering now, but I can't use it in the conditions. I think this is part of the Limitations of virtualFields? I'm trying to select only tables where TotalSongs > 0, but I think I can get this another way, by changing the join from LEFT to INNER.

Yii Framework : Help to translate relational Sql query

I encountered a problem to write this query in a Yii model oriented style.
I have a 3 main tables : questions, categories, countries
and relational tables : questions_has_categories, questions_has_countries.
Now i try to search questions that belongs to country, category.
With normal SQL statement i write :
SELECT q.id, q.question, c.name, co.name
FROM questions AS q,
categories AS c,
countries AS co,
questions_has_countries AS ta,
questions_has_categories AS qhc
WHERE
q.id = qhc.questions_id
AND c.id = qhc.categories_id
AND q.id = ta.questions_id
AND co.id = ta.countries_id
AND c.id = 1
AND co.id = 2
This works fine.
Now with Yii Active Record i try to search like this :
$model = Questions::model()->with(
array( 'categories' => array (
'select' => 'name',
'condition' => 'categories.id=:cat_id',
'params' => array (':cat_id' => $_POST["Questions"]["categories"])
)
),
array( 'countries' => array (
'select' => 'name',
'condition' => 'countries.id=:cou_id',
'params' => array (':cou_id' => $_POST["Questions"]["countries"])
)
)
)->findAll(array ('select' => 'question'));
This code respects only the categories, not countries ( returns for all countries, doesnt filter, narrow down ).
What am i doing wrong ?
My Question Model relations function looks like this :
public function relations()
{
return array('categories' => array(self::MANY_MANY, 'Categories', 'questions_has_categories(questions_id, categories_id)'),
'countries' => array(self::MANY_MANY, 'Countries', 'questions_has_countries(questions_id, countries_id)'),
);
}
Pls help :)
Thanks
try this
$model = Questions::model()->with(
array( 'categories' => array (
'select' => 'name',
'condition' => 'categories.id=:cat_id',
'params' => array (':cat_id' => $_POST["Questions"]["categories"])
),
'countries' => array (
'select' => 'name',
'condition' => 'countries.id=:cou_id',
'params' => array (':cou_id' => $_POST["Questions"]["countries"])
)
)
)->findAll(array ('select' => 'question'));

How do I get a DISTINCT value from my paginate statement?

$this->Release->recursive = 0;
$this->paginate['Release']['joins'] =
array(
array(
'table' => ' game_potential_amazon_matches',
'alias' => 'PotentialAmazonMatch',
'type' => 'inner',
'conditions' =>
array(
'PotentialAmazonMatch.release_id = Release.id'
)
)
);
$this->set('releases', $this->paginate('Release'));
$this->set('title_for_layout', 'Release with Potential Amazon Matches)');
I am getting multiple records and would just like to get distinct by Release.id?
You have to use DISTINCT in fields in that case.
just after conditions array use fields array like
fields => array('DISTINCE Release.id','field 2','field 3',...etc)

Cakephp joining tables via find option not working

I'm trying to join a Users table to my curent hasMany Through table which has Interest and User model id's.
Below is the find query with options:
$params = array(
'fields' => array('*', 'COUNT(DISTINCT(InterestsUser.interest_id)) as interest_count'),
'limit' => 15,
'recursive' => -1,
'offset' => $offset,
'conditions' => array('InterestsUser.interest_id' => $conditions),
'group' => array('InterestsUser.user_id'),
'order' => array('interest_count DESC', 'InterestsUser.user_id ASC', 'InterestsUser.interest_id ASC'),
'joins' => array(
array('table' => 'users',
'alias' => 'User',
'type' => 'LEFT',
'conditions' => array(
'User.id' => 'InterestsUser.user_id',
)
)
)
);
$results = $this->InterestsUser->find('all', $params);
This returns InterestsUser table fine but does not return any values for Users table. It only returns field names.
What could be wrong?
UPDATE:
OK, above is generating below SQL which I got from Cake's datasources sql log:
SELECT *, COUNT(DISTINCT(InterestsUser.interest_id)) as interest_count
FROM `interests_users` AS `InterestsUser`
LEFT JOIN users AS `User` ON (`User`.`id` = 'InterestsUser.user_id')
WHERE `InterestsUser`.`interest_id` IN (3, 2, 1)
GROUP BY `InterestsUser`.`user_id`
ORDER BY `interest_count` DESC, `InterestsUser`.`user_id` ASC, `InterestsUser`.`interest_id` ASC
LIMIT 15
Why is users table values returning NULL only for all fields?
UPDATE:
OK I tried below but this is working fine...What am I missing here!!??
SELECT * , COUNT( DISTINCT (
interests_users.interest_id
) ) AS interest_count
FROM interests_users
LEFT JOIN users ON ( users.id = interests_users.user_id )
WHERE interests_users.interest_id
IN ( 1, 2, 3 )
GROUP BY interests_users.user_id
ORDER BY interest_count DESC
LIMIT 15
The array syntax for join conditions should be like the following
array('User.id = InterestsUser.user_id')
as opposed to array('User.id' => 'InterestsUser.user_id'). For more, see http://book.cakephp.org/view/1047/Joining-tables.

Cakephp DISTINCT

How do I use DISTINCT to get unique user id with highest value for total_time_driven_at_this_trip and also pull user_name from another table which has belongsto relations based on user_id?
I tried this...
$this->set('tripNsws', $this->TripNsw->find('all',array('limit' => 20,'fields' => array('DISTINCT(TripNsw.user_id)','TripNsw.total_time_driven_at_this_trip'),'group' => array('TripNsw.user_id') ,'order' => array('TripNsw.total_time_driven_at_this_trip desc'))));
but it's not working.
I suppose you need to get below....
SELECT DISTINCT(user_id),`total_time_driven_at_this_trip` FROM `trip_nsws` order by `total_time_driven_at_this_trip` desc
// see below url
http://book.cakephp.org/1.3/view/1018/find
array(
'conditions' => array('Model.field' => $thisValue), //array of conditions
'recursive' => 1, //int
'fields' => array('Model.field1', 'DISTINCT Model.field2'), //array of field names
'order' => array('Model.created', 'Model.field3 DESC'), //string or array defining order
'group' => array('Model.field'), //fields to GROUP BY
'limit' => n, //int
'page' => n, //int
'offset'=>n, //int
'callbacks' => true //other possible values are false, 'before', 'after'
)
// or try this
function some_function() {
$total = $this->Article->find('count');
$pending = $this->Article->find('count', array('conditions' => array('Article.status' => 'pending')));
$authors = $this->Article->User->find('count');
$publishedAuthors = $this->Article->find('count', array(
'fields' => 'DISTINCT Article.user_id',
'conditions' => array('Article.status !=' => 'pending')
));
}
Correct Syntax for DISTINCT keywork in cakephp
$this->set('banners', $this->Banner->find('all',array('fields'=>'DISTINCT Banner.id')));
Make sure DISTINCT uses in fields array.
The correct syntaxis is
$this->set('tripNsws', $this->TripNsw->find('all',array('fields'=>'DISTINCT TripNsw.user_id')));
I've always used a GROUP BY in the query to get the same result as DISTINCT
You can consider setting it as a Virtual Field ( http://book.cakephp.org/1.3/view/1608/Virtual-fields )
$this->Model->virtualFields['distinct_user'] = 'DISTINCT Model.user_id';
'fields' => array('DISTINCT Model.Modelfield')
or
'fields' => array('Model.id','DISTINCT Model.Modelfield')

Categories