$this->Release->recursive = 0;
$this->paginate['Release']['joins'] =
array(
array(
'table' => ' game_potential_amazon_matches',
'alias' => 'PotentialAmazonMatch',
'type' => 'inner',
'conditions' =>
array(
'PotentialAmazonMatch.release_id = Release.id'
)
)
);
$this->set('releases', $this->paginate('Release'));
$this->set('title_for_layout', 'Release with Potential Amazon Matches)');
I am getting multiple records and would just like to get distinct by Release.id?
You have to use DISTINCT in fields in that case.
just after conditions array use fields array like
fields => array('DISTINCE Release.id','field 2','field 3',...etc)
Related
I have a find method that uses a DISTINCT clause to get results from my Model. The Controller code looks like below
$options = array(
'limit' => 10,
'fields' => array(
'DISTINCT id', 'title',
),
'contain' => array(
'Dealer' => array('id'),
),
'paramType' => 'querystring'
);
$this->Paginator->settings = $options;
$cars = $this->Paginator->paginate('Car'); // returns 6 distinct rows
The above query return 6 distinct rows and 12 total rows. So when I am displaying, the screen shows 6 distinct rows
However in the View, when I use
echo $this->Paginator->param('count'); // returns 12
I get a count of 12
I checked the SQL Log and noticed that the count query is not using the distinct clause. Any idea how I can override the Paginator count query to use the DISTINCT clause?
Found the solution,
In controller add distinct as an array parameter with other pagination options. So if I was trying to retrieve a list of Cars in my inventory with 10 cars at a time, the options would have a DISTINCT clause in the fields parameter and a separate parameter called distinct would also be added as shown below
$options = array(
'conditions' => $conditions,
'joins' => $joins,
'limit' => 10,
'fields' => array(
'DISTINCT Car.id', 'title', 'user_id'),
'contain' => array(
'Dealer' => array('id'),
),
'paramType' => 'querystring',
'distinct' => 'Car.id'
);
$this->Paginator->settings = $options;
$cars = $this->Paginator->paginate('Car');
In Model, use the below function to override the original paginateCount method
public function paginateCount($conditions = null, $recursive = 0, $extra = array()) {
$parameters = compact('conditions', 'recursive');
if (isset($extra['distinct'])) {
$parameters['fields'] = 'DISTINCT ' . $extra['distinct'];
$count = $this->find('count', array_merge($parameters, $extra));
} else {
// regular pagination
$count = $this->find('count', array_merge($parameters, $extra));
}
return $count;
}
No change in View
I am building an application using CakePHP and I am stuck on a problem retrieving data using a series of joins. In the simplified example below the join with the alias Delivery could have more than record and I want to bring back the record with a max value in a particular field in that table.
$inv_conditions = array( 'Invoice.invoice_date >=' => $DateFormatter->dateForDB($dateFrom),
'Invoice.invoice_date <=' => $DateFormatter->dateForDB($dateTo),
'Invoice.id >' => 385380 );
$join = array(array(
'table' => 'jobs',
'alias' => 'Jobs',
'type' => 'LEFT',
'conditions' => array('Invoice.job_id = Jobs.JOB_ID' )
),
array(
'table' => 'functional',
'alias' => 'Delivery',
'type' => 'LEFT'
'conditions'=> array('AND ' => array('Invoice.job_id = Delivery.JOB',
'Delivery.TYPE_STAGE = 1')
)
)
);
$invoices = $this->Invoice->find("all", array(
"fields" => array(
'Invoice.id',
'Invoice.job_id',
'Invoice.invoice_no',
'Invoice.consolidated_type',
'Invoice.customer_id_tbc',
'Invoice.invoice_date',
'Invoice.invoice_reference',
'Invoice.invoice_req',
'Jobs.PAYMENT_TYPE',
'Jobs.CUSTOMER',
'Jobs.MOST_RELEVANT_LINE',
'Delivery.DEPARTURE_DATE',
'Delivery.CNOR_CNEE_NAME',
'Delivery.TOWN_NAME',
),
"conditions" => $inv_conditions,
"joins" => $join
)
);
}
I can do this with SQL no problem as follows:
SELECT
jobs.JOB_ID,
jobs.CUSTOMER,
functional.JOB_LINE_ORDER,
functional.CNOR_CNEE_NAME,
functional.TOWN_NAME
FROM jobs JOIN functional ON
jobs.JOB_ID = 'M201409180267'
AND
functional.JOB = jobs.JOB_ID
AND
functional.TYPE_STAGE = 0
AND
functional.JOB_LINE_ORDER =
(SELECT MAX(JOB_LINE_ORDER) FROM functional
WHERE functional.JOB = 'M201409180267' AND functional.TYPE_STAGE = 0)
I have tried using the following to the conditions array:
'conditions' => array('AND ' =>
array( 'Invoice.job_id = Delivery.JOB',
'Delivery.TYPE_STAGE = 1'
'Delivery.JOB_LINE_ORDER = MAXIMUM(Delivery.JOB_LINE_ORDER)' )
)
This does bring back results but not the correct ones and the resulting SQL generated by Cake does have a select in the where clause. Is there a way of doing this when retrieving data in cake where the sql statement created will have a select in the where clause.
Any suggestions would be greatly appreciated.
Thanks
Bas
You need to use subquery to generate the select in the where clause. You can create a method in your model that does this and call it from your controller.
$subQuery = $db->buildStatement(
array(
'fields' => array(''),
'table' => $db->fullTableName($this),
'alias' => 'aliasName',
'limit' => null,
'offset' => null,
'joins' => array(),
'conditions' => $conditionsArray,
'order' => null,
'group' => null
),
$this
);
$subQuery = ' <<YOUR MAIN QUERY CONDITION (' . $subQuery . ') >>';
$subQueryExpression = $db->expression($subQuery);
$conditions[] = $subQueryExpression;
return $this->Model->find('list', compact('conditions'));
I want to match course_id with $courseInfo which is fetching from $cLID.
When I change this $clID['Relationscl']['course_id'] line as 1 everything is ok, but the other way an error appears like Undefined index: Relationscl.
Here is my code:
$this->loadModel('Course');
$this->loadModel('Lecturer');
$clID = $this->Relationscl->find('all', array(
'conditions' => array(
'student_id' => $id
),
'fields' => array(
'course_id','lecturer_id'
)
));
$this->set('clIDs', $clID);
$courseInfo = $this->Course->find('first',array(
'conditions' => array(
'course_id' => $clID['Relationscl']['course_id']
),
'fields' => array(
'course_name','course_code','course_credit'
)
));
$this->set('cInfos', $courseInfo);
Correct me if I'm wrong, but the find('all') function returns and indexed array, so it should be something like
$clID = array( 0 => array('Relationscl'=>array('course_id'=>1 /*and more fields*/)),
1 => array('Relationscl'=>array('course_id'=>2 /*and more fields*/))
/*etc*/);
So clearly $clID['Relationscl'] is undefined. Try with $clID[0]['Relationscl']. Though even that seems weird, why would you do a find('all') if you only plan on using the one record, isn't find('first') better? Or set that $courseInfo definition inside a loop?
How do I use DISTINCT to get unique user id with highest value for total_time_driven_at_this_trip and also pull user_name from another table which has belongsto relations based on user_id?
I tried this...
$this->set('tripNsws', $this->TripNsw->find('all',array('limit' => 20,'fields' => array('DISTINCT(TripNsw.user_id)','TripNsw.total_time_driven_at_this_trip'),'group' => array('TripNsw.user_id') ,'order' => array('TripNsw.total_time_driven_at_this_trip desc'))));
but it's not working.
I suppose you need to get below....
SELECT DISTINCT(user_id),`total_time_driven_at_this_trip` FROM `trip_nsws` order by `total_time_driven_at_this_trip` desc
// see below url
http://book.cakephp.org/1.3/view/1018/find
array(
'conditions' => array('Model.field' => $thisValue), //array of conditions
'recursive' => 1, //int
'fields' => array('Model.field1', 'DISTINCT Model.field2'), //array of field names
'order' => array('Model.created', 'Model.field3 DESC'), //string or array defining order
'group' => array('Model.field'), //fields to GROUP BY
'limit' => n, //int
'page' => n, //int
'offset'=>n, //int
'callbacks' => true //other possible values are false, 'before', 'after'
)
// or try this
function some_function() {
$total = $this->Article->find('count');
$pending = $this->Article->find('count', array('conditions' => array('Article.status' => 'pending')));
$authors = $this->Article->User->find('count');
$publishedAuthors = $this->Article->find('count', array(
'fields' => 'DISTINCT Article.user_id',
'conditions' => array('Article.status !=' => 'pending')
));
}
Correct Syntax for DISTINCT keywork in cakephp
$this->set('banners', $this->Banner->find('all',array('fields'=>'DISTINCT Banner.id')));
Make sure DISTINCT uses in fields array.
The correct syntaxis is
$this->set('tripNsws', $this->TripNsw->find('all',array('fields'=>'DISTINCT TripNsw.user_id')));
I've always used a GROUP BY in the query to get the same result as DISTINCT
You can consider setting it as a Virtual Field ( http://book.cakephp.org/1.3/view/1608/Virtual-fields )
$this->Model->virtualFields['distinct_user'] = 'DISTINCT Model.user_id';
'fields' => array('DISTINCT Model.Modelfield')
or
'fields' => array('Model.id','DISTINCT Model.Modelfield')
I apologize for the horrible title, I couldn't think of how to explain my problem.
In my database I have the following tables, articles, tags, and articles_tags. An article can have many tags.
Currently I am able to grab all the articles, with all the tags, but I want to be able to find articles based upon it's tags.
My select is simple:
$articles = $this->Article->find('all', array(
// extra condition to check for tag, maybe?
'conditions' => array('Article.status' => 'active'),
'limit' => $this->articles_per_page,
'offset' => ($page_num-1)*$this->articles_per_page
));
My return from the database is as follows:
Array
(
[0] => Array
(
[Article] => Array
(
[id] => 1
)
[Tag] => Array
(
[0] => Array
(
[id] => 1
[name] => Ruby
[slug] => ruby
[uses] => 1
[ArticlesTag] => Array
(
[id] => 1
[article_id] => 1
[tag_id] => 1
)
)
)
)
What do I do if I only want to return the articles with a Ruby tag?
Try this
// In your Article model
function getArticleByTagSql($tag)
{
$dbo = $this->getDataSource();
$subQuery = $dbo->buildStatement(
array(
'fields' => array('DISTINCT(ArticlesTag.article_id)'),
'table' => "articles_tags",
'joins' => array(
array('table' => 'tags',
'alias' => 'Tag',
'type' => 'INNER',
'conditions' => array('ArticlesTag.tag_id = Tag.id')
)
),
'alias'=>"ArticlesTag",
'conditions' => array("Tag.name"=>Sanitize::clean($tag_words)),
'order' => null,
'group' => "ArticlesTag.article_id"
),
$this
);
$subQuery = ' Article.id IN (' . $subQuery . ')';
return $dbo->expression($subQuery);
}
// In your Articles Controller
$this->paginate['conditions'][] = $this->Article->getArticleByTagSql($tag_name);
$this->paginate['conditions'][] = array('Article.status' => 'active');
$this->paginate['limit'] = $this->articles_per_page;
// or as per your example
$articles = $this->Article->find('all', array(
// extra condition to check for tag, maybe?
'conditions' => array('Article.status' => 'active',$this->Article->getArticleByTagSql($tag_name)),
'limit' => $this->articles_per_page,
'offset' => ($page_num-1)*$this->articles_per_page
));
For conditions like this you can use the LinkableBehavior. It's designed for exact your wanted result. In case you don't want to use it, you have to do a query on the tag controller:
$this->Tag->find('all', array('conditions' => array('Tag.name' => 'ruby')));
Not possible directly.
The easiest way is to make the query through the tag controller
I'm updating this question with an answer for CakePHP 3.x.
You can find all articles for a given tag using an INNER JOIN. The benefit of this join is that it keeps articles as the primary table in the query. Making this an easy solution when you're paginating results by a HABTM join.
$tag_id = 3; // the ID of the tag
$query = $this->Articles->find('all')
->innerJoin('articles_tags', [
'Articles.id = articles_tags.article_id',
'articles_tags.tag_id' => $tag_id
]);
The first join condition has to be the array key. If you use a => array assignment then CakePHP will pass the articles_tags.article_id as a string argument to the join condition. Which won't work.
You can also stack innerJoin for multiple HABTM conditions. For example; find all articles for a tag and also for a category. You can also use the in query expression to match multiple tags.
You can also use the above in pagination like this $articles = $this->paginate($query);
I'm sure this information is out on the web, but this question was the top of google's results. So maybe this will help others.