in_array fails when using implode in if statement - php

Question

This attamept is to create a search condition where eventually the output will be processed to show results based on increasing order of matches
"PHP implode function in if and foreach condition [closed]" is a different question !
Why is the following code failing ?
$terms = array("HELLO", "HI", "HOWDY");
$row = array("HELLO", "HI", "Hey");
$chkcond = "in_array('".implode("',$"."row".")"." && in_array"."('",$terms)."',$"."row)";
echo "$chkcond<br/><br/>";
if ($chkcond) {
echo "All Found in Array !<br>";}else{echo "Not Found !<br/>";
}
The echo result is
in_array('HELLO',$row) && in_array('HI',$row) && in_array('HOWDY',$row)
And the if condition outputs "All Found in Array !"
When the if condition says that all three terms have to be in the row array to be "All Found in Array", then why is it returning True when "Howdy" doesn't exist in the row array ?

Answer 1

juste use array_diff http://php.net/array_diff
<?php
$terms=array("HELLO","HI","HOWDY");
$row=array("HELLO","HI","Hey");
$diff = array_diff($terms, $row);
if (0 === count($diff)){echo "All terms Found in Array row !<br>";}else{echo "Not all terms Found in Array row !<br>";}
$terms=array("HELLO","HI","HOWDY");
$row=array("HELLO","HI","Hey","HOWDY");
$diff = array_diff($terms, $row);
if (0 === count($diff)){echo "All terms Found in Array row !<br>";}else{echo "Not all terms Found in Array row !<br>";}

Answer 2

You could use array_diff
Something like:
<?php
$terms=array("HELLO","HI","HOWDY");
$row=array("HELLO","HI","Hey");
$chkcond=array_diff($terms, $row);
var_dump($chkcond);
if(empty($chkcond)) {
echo "All Found in Array !<br>";
} else {
echo "Not Found !<br>";
}
?>

Answer 3

Not sure what you are attempting but you can use array_diff.
$terms = array("HELLO","HI","HOWDY");
$row = array("HELLO","HI","Hey");
$differences = array_diff($terms, $row);
if ($differences) {
echo "All Found in array";
} else {
"Not Found !<br>";
}
https://secure.php.net/manual/en/function.array-diff.php

Answer 4

If you would like to stick with in_array you need to loop your terms:
<?php
$terms=array("HELLO","HI","HOWDY");
$row=array("HELLO","HI","Hey");
$chkcond = true;
foreach($row as $needle){
if(!in_array($needle, $terms)){
$chkcond = false;
break;
}
}
if($chkcond){
echo "All Found in Array !<br>";
} else {
echo "Not Found !<br>";
}
?>
Heck re-reading the manual http://php.net/manual/en/function.in-array.php you do not even need to loop:
<?php
$terms=array("HELLO","HI","HOWDY");
$row=array("HELLO","HI","Hey");
if(in_array($row, $terms)){
echo "All Found in Array !<br>";
} else {
echo "Not Found !<br>";
}
?>