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How can I search a word in a PHP array?
I try in_array, but it find just exactly the same values.
<?php
$namesArray = array('Peter', 'Joe', 'Glenn', 'Cleveland');
if (in_array('Peter Parker', $namesArray)) {echo "There is.";}
else {echo "There is not.";}
I want this instance to return true. How can I do it? Is there any function?
Snippet: https://glot.io/snippets/ek086tekl0
I have to say I like the simplicity of Gre_gor's answer, but for a more dynamic method you can also use array_filter():
function my_array_search($array, $needle){
$matches = array_filter($array, function ($haystack) use ($needle){
// return stripos($needle, $haystack) !== false; make the function case insensitive
return strpos($needle, $haystack) !== false;
});
return empty($matches) ? false : $matches;
}
$namesArray = ['Peter', 'Glenn', 'Meg', 'Griffin'];
Examples:
if(my_array_search($namesArray, 'Glenn Quagmire')){
echo 'There is'; // Glenn
} else {
echo 'There is not';
}
// optionally:
if(($retval = my_array_search($namesArray, 'Peter Griffin'))){
echo 'There is';
print_r($retval); // Peter, Griffin.
} else {
echo 'There is not';
}
Now $retval is optional, it captures an array of matching subjects. This works because if the $matches variable in my_array_search is empty, it returns false instead of an empty array.
Explode your string and then check, if there are any same strings in both arrays.
$namesArray = array('Peter', 'Joe', 'Glenn', 'Cleveland');
if (array_intersect(explode(' ', 'Peter Parker'), $namesArray))
echo "There is.";
else
echo "There is not.";
You can use Regular Expressions - preg_match ('i' means case insensitive) to check if array contains some words
for example:
$namesArray = array('Peter One', 'Other Peter', 'Glenn', 'Cleveland');
$check = false;
foreach($namesArray as $name)
{
if (preg_match("/.*peter.*/i", $name)) {
$check = true;
break;
}
}
if($check)
{
echo "There is.";
}
else {
echo "There is not.";
}
This attamept is to create a search condition where eventually the output will be processed to show results based on increasing order of matches
"PHP implode function in if and foreach condition [closed]" is a different question !
Why is the following code failing ?
$terms = array("HELLO", "HI", "HOWDY");
$row = array("HELLO", "HI", "Hey");
$chkcond = "in_array('".implode("',$"."row".")"." && in_array"."('",$terms)."',$"."row)";
echo "$chkcond<br/><br/>";
if ($chkcond) {
echo "All Found in Array !<br>";}else{echo "Not Found !<br/>";
}
The echo result is
in_array('HELLO',$row) && in_array('HI',$row) && in_array('HOWDY',$row)
And the if condition outputs "All Found in Array !"
When the if condition says that all three terms have to be in the row array to be "All Found in Array", then why is it returning True when "Howdy" doesn't exist in the row array ?
juste use array_diff http://php.net/array_diff
<?php
$terms=array("HELLO","HI","HOWDY");
$row=array("HELLO","HI","Hey");
$diff = array_diff($terms, $row);
if (0 === count($diff)){echo "All terms Found in Array row !<br>";}else{echo "Not all terms Found in Array row !<br>";}
$terms=array("HELLO","HI","HOWDY");
$row=array("HELLO","HI","Hey","HOWDY");
$diff = array_diff($terms, $row);
if (0 === count($diff)){echo "All terms Found in Array row !<br>";}else{echo "Not all terms Found in Array row !<br>";}
You could use array_diff
Something like:
<?php
$terms=array("HELLO","HI","HOWDY");
$row=array("HELLO","HI","Hey");
$chkcond=array_diff($terms, $row);
var_dump($chkcond);
if(empty($chkcond)) {
echo "All Found in Array !<br>";
} else {
echo "Not Found !<br>";
}
?>
Not sure what you are attempting but you can use array_diff.
$terms = array("HELLO","HI","HOWDY");
$row = array("HELLO","HI","Hey");
$differences = array_diff($terms, $row);
if ($differences) {
echo "All Found in array";
} else {
"Not Found !<br>";
}
https://secure.php.net/manual/en/function.array-diff.php
If you would like to stick with in_array you need to loop your terms:
<?php
$terms=array("HELLO","HI","HOWDY");
$row=array("HELLO","HI","Hey");
$chkcond = true;
foreach($row as $needle){
if(!in_array($needle, $terms)){
$chkcond = false;
break;
}
}
if($chkcond){
echo "All Found in Array !<br>";
} else {
echo "Not Found !<br>";
}
?>
Heck re-reading the manual http://php.net/manual/en/function.in-array.php you do not even need to loop:
<?php
$terms=array("HELLO","HI","HOWDY");
$row=array("HELLO","HI","Hey");
if(in_array($row, $terms)){
echo "All Found in Array !<br>";
} else {
echo "Not Found !<br>";
}
?>
Its strange to me, why stristr not matching data? It always print not found
$data = 'Saturday';
$find = 'sat,sun';
if(stristr($data, $find))
echo 'found';
else
echo 'not found';
The stristr() function searches for the first occurrence of a string inside another string. So you need to make the search string different, And for this you need make the $find string to an array and loop through it. That how you can get the sat and sun as different string, and simply use your code to match.
Online Check
$data = 'Saturday';
$find = 'sat,sun';
$find_arr = explode(",", $find);
foreach($find_arr as $find_val){
if(stristr($data, $find_val))
echo 'found';
else
echo 'not found';
}
The result should be for first found and for second not found.
If you find 'Sat', than it will show result Found.
In your case it will consider the 'sat,sun' to one word, so that it will try to find 'sat,sun' in $data and the result will display 'Not Found'.
stristr() find the first occurrence of a string. You can also use preg_match instead of stristr().
Try
<?php
$find = "sat,sun";
$data = 'Sat';
if (preg_match("/\b".$data."\b/i", $find, $match))
print "Match found!";
else
print "not match";
?>
You should use stripos instead of stristr for best results. The stripos function is faster and less memory intensive than stristr.
stripos() returns FALSE if the needle was not found. So if you just need to know if there are ocurrences, use it as follow:
echo stripos($data, 'sat,sun') !== false ? 'found' : 'not found';
Solution code edit from comment request:
To check if your $data value is sat OR sun, do it in a loop:
$data = 'Sunday';
$weekend = 'sat,sun';
$days = explode(',', $weekend);
$index = 0;
$found = false;
while (!$found && isset($days[$index])) {
$found = (stripos($data,$days[$index]) !== false) ? true : false;
$index++;
}
echo $found ? 'found' : 'not found';
Try this one code
$f = 'Saturday';
$data = 'sat,sun';
$find = strtolower(substr($f, 0,3));
$str = stristr($data , $find);
if($str)
echo 'found';
else
echo 'not found';
This question already has answers here:
String contains any items in an array (case insensitive)
(15 answers)
Closed 2 years ago.
I am trying to detect whether a string contains at least one URL that is stored in an array.
Here is my array:
$owned_urls = array('website1.com', 'website2.com', 'website3.com');
The string is entered by the user and submitted via PHP. On the confirmation page I would like to check if the URL entered is in the array.
I have tried the following:
$string = 'my domain name is website3.com';
if (in_array($string, $owned_urls))
{
echo "Match found";
return true;
}
else
{
echo "Match not found";
return false;
}
No matter what is inputted the return is always "Match not found".
Is this the correct way of doing things?
Try this.
$string = 'my domain name is website3.com';
foreach ($owned_urls as $url) {
//if (strstr($string, $url)) { // mine version
if (strpos($string, $url) !== FALSE) { // Yoshi version
echo "Match found";
return true;
}
}
echo "Not found!";
return false;
Use stristr() or stripos() if you want to check case-insensitive.
This was a lot easier to do if all you want to do is find a string in an array.
$array = ["they has mystring in it", "some", "other", "elements"];
if (stripos(json_encode($array),'mystring') !== false) {
echo "found mystring";
}
Try this:
$owned_urls= array('website1.com', 'website2.com', 'website3.com');
$string = 'my domain name is website3.com';
$url_string = end(explode(' ', $string));
if (in_array($url_string,$owned_urls)){
echo "Match found";
return true;
} else {
echo "Match not found";
return false;
}
-
Thanks
Simple str_replace with count parameter would work here:
$count = 0;
str_replace($owned_urls, '', $string, $count);
// if replace is successful means the array value is present(Match Found).
if ($count > 0) {
echo "One of Array value is present in the string.";
}
More Info - https://www.techpurohit.in/extended-behaviour-explode-and-strreplace-php
I think that a faster way is to use preg_match.
$user_input = 'Something website2.com or other';
$owned_urls_array = array('website1.com', 'website2.com', 'website3.com');
if ( preg_match('('.implode('|',$owned_urls_array).')', $user_input)){
echo "Match found";
}else{
echo "Match not found";
}
$string = 'my domain name is website3.com';
$a = array('website1.com','website2.com','website3.com');
$result = count(array_filter($a, create_function('$e','return strstr("'.$string.'", $e);')))>0;
var_dump($result );
output
bool(true)
Here is a mini-function that search all values from an array in a given string.
I use this in my site to check for visitor IP is in my permitted list on certain pages.
function array_in_string($str, array $arr) {
foreach($arr as $arr_value) { //start looping the array
if (stripos($str,$arr_value) !== false) return true; //if $arr_value is found in $str return true
}
return false; //else return false
}
how to use
$owned_urls = array('website1.com', 'website2.com', 'website3.com');
//this example should return FOUND
$string = 'my domain name is website3.com';
if (array_in_string($string, $owned_urls)) {
echo "first: Match found<br>";
}
else {
echo "first: Match not found<br>";
}
//this example should return NOT FOUND
$string = 'my domain name is website4.com';
if (array_in_string($string, $owned_urls)) {
echo "second: Match found<br>";
}
else {
echo "second: Match not found<br>";
}
DEMO: http://phpfiddle.org/lite/code/qf7j-8m09
stripos function is not very strict. it's not case sensitive or it can match a part of a word
http://php.net/manual/ro/function.stripos.php
if you want that search to be case sensitive use strpos
http://php.net/manual/ro/function.strpos.php
for exact match use regex (preg_match), check this guy answer https://stackoverflow.com/a/25633879/4481831
You can concatenate the array values with implode and a separator of |
and then use preg_match to search for the value.
Here is the solution I came up with ...
$emails = array('#gmail', '#hotmail', '#outlook', '#live', '#msn', '#yahoo', '#ymail', '#aol');
$emails = implode('|', $emails);
if(!preg_match("/$emails/i", $email)){
// do something
}
If your $string is always consistent (ie. the domain name is always at the end of the string), you can use explode() with end(), and then use in_array() to check for a match (as pointed out by #Anand Solanki in their answer).
If not, you'd be better off using a regular expression to extract the domain from the string, and then use in_array() to check for a match.
$string = 'There is a url mysite3.com in this string';
preg_match('/(?:http:\/\/)?(?:www.)?([a-z0-9-_]+\.[a-z0-9.]{2,5})/i', $string, $matches);
if (empty($matches[1])) {
// no domain name was found in $string
} else {
if (in_array($matches[1], $owned_urls)) {
// exact match found
} else {
// exact match not found
}
}
The expression above could probably be improved (I'm not particularly knowledgeable in this area)
Here's a demo
You are checking whole string to the array values. So output is always false.
I use both array_filter and strpos in this case.
<?php
$urls= array('website1.com', 'website2.com', 'website3.com');
$string = 'my domain name is website3.com';
$check = array_filter($urls, function($url){
global $string;
if(strpos($string, $url))
return true;
});
echo $check?"found":"not found";
$owned_urls= array('website1.com', 'website2.com', 'website3.com');
$string = 'my domain name is website3.com';
for($i=0; $i < count($owned_urls); $i++)
{
if(strpos($string,$owned_urls[$i]) != false)
echo 'Found';
}
$message = "This is test message that contain filter world test3";
$filterWords = array('test1', 'test2', 'test3');
$messageAfterFilter = str_replace($filterWords, '',$message);
if( strlen($messageAfterFilter) != strlen($message) )
echo 'message is filtered';
else
echo 'not filtered';
I find this fast and simple without running loop.
$array = array("this", "that", "there", "here", "where");
$string = "Here comes my string";
$string2 = "I like to Move it! Move it";
$newStr = str_replace($array, "", $string);
if(strcmp($string, $newStr) == 0) {
echo 'No Word Exists - Nothing got replaced in $newStr';
} else {
echo 'Word Exists - Some Word from array got replaced!';
}
$newStr = str_replace($array, "", $string2);
if(strcmp($string2, $newStr) == 0) {
echo 'No Word Exists - Nothing got replaced in $newStr';
} else {
echo 'Word Exists - Some Word from array got replaced!';
}
Little explanation!
Create new variable with $newStr replacing value in array of original string.
Do string comparison - If value is 0, that means, strings are equal and nothing was replaced, hence no value in array exists in string.
if it is vice versa of 2, i.e, while doing string comparison, both original and new string was not matched, that means, something got replaced, hence value in array exists in string.
$search = "web"
$owned_urls = array('website1.com', 'website2.com', 'website3.com');
foreach ($owned_urls as $key => $value) {
if (stristr($value, $search) == '') {
//not fount
}else{
//found
}
this is the best approach search for any substring , case-insensitive and fast
just like like im mysql
ex:
select * from table where name = "%web%"
I came up with this function which works for me, hope this will help somebody
$word_list = 'word1, word2, word3, word4';
$str = 'This string contains word1 in it';
function checkStringAgainstList($str, $word_list)
{
$word_list = explode(', ', $word_list);
$str = explode(' ', $str);
foreach ($str as $word):
if (in_array(strtolower($word), $word_list)) {
return TRUE;
}
endforeach;
return false;
}
Also, note that answers with strpos() will return true if the matching word is a part of other word. For example if word list contains 'st' and if your string contains 'street', strpos() will return true
I have a string and it can contain values like this
$string = '1,2,3,4,5';
I wanna put a check that will see if the string contains 4 or 5
if it contains 4 or 5 then I want to echo success
otherwise if it contains 9 or 10 I wanna echo fail
I know there is a n in_array function but not sure how to use it
thanks
You can test for the number 4 like this:
if(in_array('4', explode(',', $string))) echo "it's in there";
or just by string searching:
if(strpos(',4,', ','.$string.',') !== false) echo "it's in there";
in_array won't help you here because you have a string, not an array. What you're looking for is the strpos() function:
http://php.net/manual/en/function.strpos.php
Note that if it doesn't find what it's looking for in your string, it'll return false on its own, so all you have to do is check whether it returns a result or not to meet your conditions.
$set = array (1,2,3...,n); //you can use range() function if the numbers going one by one or explode if you have a string
if(in_array($var,$set))
{
Echo 'IS in ARRAY!';
} else {
Echo 'fail';
}
$goodString = '1,2,3,4,5';
$badString = '1,2,3,7,8,9,10';
function checkString($str) {
$arr = explode(',', $str);
$message = 'no message';
if (
in_array(4, $arr)||
in_array(5, $arr)
) {
$message = 'success';
} else if (
in_array(9, $arr)||
in_array(10, $arr)
) {
$message = 'fail';
}
echo $message;
}
checkString($goodString); // prints success
checkString($badString); // prints fail
you can use strpos() to check for the existence of a substring inside a string, like this:
if(strpos(','.$string.',', ','.$number_to_check_for.',') !== false) {
//success, substring was found
} else {
//error, substring was not found.
}
or you could explode it into an array then use in_array():
$array = explode(',',$string);
if(in_array($number_to_check_for, $array)) {
//success substring found
} else {
//error, substring not found
}
But I would recommend the first solution, as it is cleaner and more efficient.
Check all at once :)
if(in_array(array(4,5), explode(',', $string))) echo "success";
if(in_array(array(9,10), explode(',', $string))) echo "failure";