I have this main sting.
S,SR,DSR,DS,FX,FXS,SR,DS,S,SR,DS,FX,S,SR,DS,FX,FXS
and i want to find each of the following strings ..
DSR and FXS
i have tried by following code but it can not given me perfect result.
code...
<?php
$mainstring ="S,SR,DSR,DS,FX,FXS,SR,DS,S,SR,DS,FX,S,SR,DS,FX,FXS";
$needed = "DSR,FXS";
if( strpos( $mainstring, $needed ) !== false ) {
echo "Found";
}else{
echo "Not match";
}
?>
One solution would be to explode those strings by comma and verify if the resulted arrays intersection count is the same as your search:
$mainstring ="S,SR,DSR,DS,FX,FXS,SR,DS,S,SR,DS,FX,S,SR,DS,FX,FXS";
$needed = "DSR,FXS";
$mainStringArr = explode(',', $mainstring);
$neededArr = explode(',', $needed);
if (count(array_unique(array_intersect($mainStringArr, $neededArr))) == count($neededArr)) {
echo 'found';
} else {
echo 'not found';
}
Explode the $needed string by command and traverse the array to and compare each value of array into $mainstring using strpos() function. If found then put that value into $arrResut with 'Found' or 'not found' value and finally print the $arrResult to view which value of $needed is found and which is not.
Also, we increment $cntNeeded variable if value if found. at the end of foreach loop compare value of $cntNeeded & $arrNeeded are same then all values are found into $mainstring else not.
$mainstring ="S,SR,DSR,DS,FX,FXS,SR,DS,S,SR,DS,FX,S,SR,DS,FX,FXS";
$needed = "DSR,FXS";
$arrNeeded = explode(",", $needed);
$arrResult = array();
$cntNeeded = 0;
foreach($arrNeeded as $index => $needed) {
if( strpos( $mainstring, $needed ) !== false ) {
$arrResult[$needed] = "Found";
$cntNeeded++;
}
else{
$arrResult[$needed] = "Not match";
}
}
print("<pre> :: arrResult ::");
print_r($arrResult);
print("</pre>");
if($cntNeeded == count($arrNeeded)) {
echo "Found";
}
else {
echo "Not match";
}
Related
$meal_type= "Free Breakfast|Free Wireless";
if ($meal_type != '' && $meal_type !='None') {
$meal = explode('|', $meal_type);
$meal = array_search('Breakfast',$meal);
$meal = $meal_type;
} else {
$meal= 'No Breakfast';
}
echo $meal;
This is my code. here i want to search Breakfast in the array and return searched value, if not found return No Breakfast.
Here i was explode string to array with | symbol and returned array search Breakfast if exist return funded array value else echo No Breakfast value.
A simple foreach() will do the job:-
<?php
$match_counter =0;
$array = Array
(
0 => 'Free Breakfast',
1 => 'Free Wireless Internet'
);
$search = 'Breakfast';
foreach($array as $arr){
if(stripos($arr,$search) !==false){
echo $arr.PHP_EOL;
$match_counter++;
}
}
if($match_counter ==0){
echo 'No '.$search;
}
Output:-
https://3v4l.org/ogOEB (occurrence found)
https://3v4l.org/AOuTJ (occurrence not found)
https://3v4l.org/NTH1W (occurrence found more than one time)
Reference:- stripos()
<?php
$array = array('Free Breakfast','Free Wireless Internet');
$string = 'Breakfast';
foreach ($array as $a) {
if (stripos($a, $string) !== FALSE) {
echo $string;
return true;
}
}
echo "No" .$string;
return false;
?>
You can also use stripos() for case-insensitive.
case 1 : if array contains multiple same values
<?php
$array = array('Free Breakfast','Free Wireless Internet' ,'breakfast time');
$string = 'Breakfast';
$flag=true;
foreach ($array as $key=> $a) {
if (stripos($a, $string) !== FALSE) {
$flag = false;
echo $string." contain in key position ".$key.'<br>';
//return true;
}
}
if($flag)
{
echo "No" .$string;
}
?>
How can I search a word in a PHP array?
I try in_array, but it find just exactly the same values.
<?php
$namesArray = array('Peter', 'Joe', 'Glenn', 'Cleveland');
if (in_array('Peter Parker', $namesArray)) {echo "There is.";}
else {echo "There is not.";}
I want this instance to return true. How can I do it? Is there any function?
Snippet: https://glot.io/snippets/ek086tekl0
I have to say I like the simplicity of Gre_gor's answer, but for a more dynamic method you can also use array_filter():
function my_array_search($array, $needle){
$matches = array_filter($array, function ($haystack) use ($needle){
// return stripos($needle, $haystack) !== false; make the function case insensitive
return strpos($needle, $haystack) !== false;
});
return empty($matches) ? false : $matches;
}
$namesArray = ['Peter', 'Glenn', 'Meg', 'Griffin'];
Examples:
if(my_array_search($namesArray, 'Glenn Quagmire')){
echo 'There is'; // Glenn
} else {
echo 'There is not';
}
// optionally:
if(($retval = my_array_search($namesArray, 'Peter Griffin'))){
echo 'There is';
print_r($retval); // Peter, Griffin.
} else {
echo 'There is not';
}
Now $retval is optional, it captures an array of matching subjects. This works because if the $matches variable in my_array_search is empty, it returns false instead of an empty array.
Explode your string and then check, if there are any same strings in both arrays.
$namesArray = array('Peter', 'Joe', 'Glenn', 'Cleveland');
if (array_intersect(explode(' ', 'Peter Parker'), $namesArray))
echo "There is.";
else
echo "There is not.";
You can use Regular Expressions - preg_match ('i' means case insensitive) to check if array contains some words
for example:
$namesArray = array('Peter One', 'Other Peter', 'Glenn', 'Cleveland');
$check = false;
foreach($namesArray as $name)
{
if (preg_match("/.*peter.*/i", $name)) {
$check = true;
break;
}
}
if($check)
{
echo "There is.";
}
else {
echo "There is not.";
}
I have this code:
$arr = array("Hello_backup","World!","Beautiful_backup","Day!");
if(in_array("backup", $arr)){
echo "Da";
} else { echo "Nu";
}
But is not working because,in_array instruction check the array for the complete string "backup" , which doesnt exist.I need to check for a part of the string,for example,to return true because backup is a part of the "Hello_backup" and "Beautiful_backup" strings
EDIT: I take the advice and i have used stripos like this:
$arr = array("Hello_backup-2014","World!","Beautiful_backup-2014","Day!");
$word='backup';
if(stripos($arr,$word) !== false){
echo "Da";
} else { echo "Nu";}
but now i get an error: "stripos() expects parameter 1 to be string, array given in if(stripos($arr,$word) !== false){"
Use implode to basically concatenate the array values as a string, then use strpos to check for a string within a string.
The first argument you pass to implode is used to separate each value in the array.
$array = array("Hello_backup","World!","Beautiful_backup","Day!");
$r = implode(" ", $array);
if (strpos($r, "backup") !== false) {
echo "found";
}
In this case you need to use stripos(). Example:
$arr = array("Hello_backup","World!","Beautiful_backup","Day!");
$needle = 'backup';
function check($haystack, $needle) {
foreach($haystack as $word) {
if(stripos($word, $needle) !== false) {
return 'Da!'; // if found
}
}
return 'Nu'; // if not found
}
var_dump(check($arr, $needle));
Without a function:
$arr = array("Hello_backup","World!","Beautiful_backup","Day!");
$found = false;
foreach($arr as $word) {
if(stripos($word, 'backup') !== false) {
$found = true;
break;
}
}
if($found) {
echo 'Da!';
} else {
echo 'Nu';
}
Try with strpos()
$arr = array("Hello_backup","World!","Beautiful_backup","Day!");
foreach($arr as $v){
echo (strpos($v,"backup")!== false ? "Da" : "Nu");
}
output :- DaNuDaNu
Here is the one line solution for you.
$arr = array("Hello_backup-2014","World!","Beautiful_backup-2014","Day!");
$returned_a = array_map(function($u){ if(stripos($u,'backup') !== false) return "Da"; else return "Nu";}, $arr);
You can use $returned_a with array as your answer..
Array ( [0] => Da [1] => Nu [2] => Da [3] => Nu )
Use this method. It is little bit simple to use.
$matches = preg_grep('/backup/', $arr);
$keys = array_keys($matches);
print_r($matches);
Look this working example
According to your question
$matches = preg_grep('/backup/', $arr);
$keys = array_keys($matches);
$matches = trim($matches);
if($matches != '')
{echo "Da";
}else { echo "Nu";}
<?php
$arr = array("Hello_backup","World!","Beautiful_backup","Day!");
foreach($arr as $arr1) {
if (strpos ($arr1,"backup")) {
echo "Da";
} else {
echo "Nu";
}
}
?>
I know how to find if your string equals an array value:
$colors = array("blue","red","white");
$string = "white";
if (!in_array($string, $colors)) {
echo 'not found';
}
...but how do I find if the string CONTAINS any part of the array values?
$colors = array("blue","red","white");
$string = "whitewash"; // I want this to be found in the array
if (!in_array($string, $colors)) {
echo 'not found';
}
Or in one shot:
if( preg_match("(".implode("|",array_map("preg_quote",$colors)).")",$string,$m)) {
echo "Found ".$m[0]."!";
}
This can also be expanded to only allow words that start with an item from your array:
if( preg_match("(\b(?:".implode("|",array_map("preg_quote",$colors))."))",$string,$m)) {
Or case-insensitive:
if( preg_match("(".implode("|",array_map("preg_quote",$colors)).")i",$string,$m)) {
CI with starting only:
if( preg_match("(\b(?:".implode("|",array_map("preg_quote",$colors))."))i",$string,$m)) {
Or anything really ;)
Just loop the array containing the values, and check if they are found in the input string, using strpos
$colors = array("blue","red","white");
$string = "whitewash"; // I want this to be found in the array
foreach ( $colors as $c ) {
if ( strpos ( $string , $c ) !== FALSE ) {
echo "found";
}
}
You can wrap it in a function:
function findString($array, $string) {
foreach ( $array as $a ) {
if ( strpos ( $string , $a ) !== FALSE )
return true;
}
return false;
}
var_dump( findString ( $colors , "whitewash" ) ); // TRUE
Try this working solution
$colors = array("blue", "red", "white");
$string = "whitewash";
foreach ($colors as $color) {
$pos = strpos($string, $color);
if ($pos === false) {
echo "The string '$string' not having substring '$color'.<br>";
} else {
echo "The string '$string' having substring '$color'.<br>";
}
}
There is no built-in function for that, but you could do something like:
$colors = array("blue","red","white");
$string = "whitewash"; // I want this to be found in the array
if (!preg_match('/\Q'.implode('\E|\Q',$colors).'\E/',$string)) {
echo 'not found';
}
This basically makes a regex from your array and matches the string against it. Good method, unless your array is really large.
You would have to iterate over each array element and individually check if it contains it (or a substr of it).
This is similar to what you want to do:
php check if string contains a value in array
$colors = array("blue","red","white");
$string = "whitewash"; // I want this to be found in the array
$hits = array();
foreach($colors as $color) {
if(strpos($string, $color) !== false) {
$hits[] = $color;
}
}
$hits will contain all $colors that have a match in $string.
if(empty($hits)) {
echo 'not found';
}
This question already has answers here:
String contains any items in an array (case insensitive)
(15 answers)
Closed 2 years ago.
This is for a chat page. I have a $string = "This dude is a mothertrucker". I have an array of badwords: $bads = array('truck', 'shot', etc). How could I check to see if $string contains any of the words in $bad?
So far I have:
foreach ($bads as $bad) {
if (strpos($string,$bad) !== false) {
//say NO!
}
else {
// YES! }
}
Except when I do this, when a user types in a word in the $bads list, the output is NO! followed by YES! so for some reason the code is running it twice through.
function contains($str, array $arr)
{
foreach($arr as $a) {
if (stripos($str,$a) !== false) return true;
}
return false;
}
1) The simplest way:
if ( in_array( 'three', ['one', 'three', 'seven'] ))
...
2) Another way (while checking arrays towards another arrays):
$keywords=array('one','two','three');
$targets=array('eleven','six','two');
foreach ( $targets as $string )
{
foreach ( $keywords as $keyword )
{
if ( strpos( $string, $keyword ) !== FALSE )
{ echo "The word appeared !!" }
}
}
can you please try this instead of your code
$string = "This dude is a mothertrucker";
$bads = array('truck', 'shot');
foreach($bads as $bad) {
$place = strpos($string, $bad);
if (!empty($place)) {
echo 'Bad word';
exit;
} else {
echo "Good";
}
}
There is a very short php script that you can use to identify bad words in a string which uses str_ireplace as follows:
$string = "This dude is a mean mothertrucker";
$badwords = array('truck', 'shot', 'ass');
$banstring = ($string != str_ireplace($badwords,"XX",$string))? true: false;
if ($banstring) {
echo 'Bad words found';
} else {
echo 'No bad words in the string';
}
The single line:
$banstring = ($string != str_ireplace($badwords,"XX",$string))? true: false;
does all the work.
You can flip your bad word array and do the same checking much faster. Define each bad word as a key of the array. For example,
//define global variable that is available to too part of php script
//you don't want to redefine the array each time you call the function
//as a work around you may write a class if you don't want global variable
$GLOBALS['bad_words']= array('truck' => true, 'shot' => true);
function containsBadWord($str){
//get rid of extra white spaces at the end and beginning of the string
$str= trim($str);
//replace multiple white spaces next to each other with single space.
//So we don't have problem when we use explode on the string(we dont want empty elements in the array)
$str= preg_replace('/\s+/', ' ', $str);
$word_list= explode(" ", $str);
foreach($word_list as $word){
if( isset($GLOBALS['bad_words'][$word]) ){
return true;
}
}
return false;
}
$string = "This dude is a mothertrucker";
if ( !containsBadWord($string) ){
//doesn't contain bad word
}
else{
//contains bad word
}
In this code we are just checking if an index exist rather than comparing bad word with all the words in the bad word list.
isset is much faster than in_array and marginally faster than array_key_exists.
Make sure none of the values in bad word array are set to null.
isset will return false if the array index is set to null.
Put and exit or die once it find any bad words, like this
foreach ($bads as $bad) {
if (strpos($string,$bad) !== false) {
//say NO!
}
else {
echo YES;
die(); or exit;
}
}
You can do the filter this way also
$string = "This dude is a mothertrucker";
if (preg_match_all('#\b(truck|shot|etc)\b#', $string )) //add all bad words here.
{
echo "There is a bad word in the string";
}
else {
echo "There is no bad word in the string";
}
Wanted this?
$string = "This dude is a mothertrucker";
$bads = array('truck', 'shot', 'mothertrucker');
foreach ($bads as $bad) {
if (strstr($string,$bad) !== false) {
echo 'NO<br>';
}
else {
echo 'YES<br>';
}
}
If you want to do with array_intersect(), then use below code :
function checkString(array $arr, $str) {
$str = preg_replace( array('/[^ \w]+/', '/\s+/'), ' ', strtolower($str) ); // Remove Special Characters and extra spaces -or- convert to LowerCase
$matchedString = array_intersect( explode(' ', $str), $arr);
if ( count($matchedString) > 0 ) {
return true;
}
return false;
}
I would go that way if chat string is not that long.
$badwords = array('mothertrucker', 'ash', 'whole');
$chatstr = 'This dude is a mothertrucker';
$chatstrArr = explode(' ',$chatstr);
$badwordfound = false;
foreach ($chatstrArr as $k => $v) {
if (in_array($v,$badwords)) {$badwordfound = true; break;}
foreach($badwords as $kb => $vb) {
if (strstr($v, $kb)) $badwordfound = true;
break;
}
}
if ($badwordfound) { echo 'You\'re nasty!';}
else echo 'GoodGuy!';
$string = "This dude is a good man";
$bad = array('truck','shot','etc');
$flag='0';
foreach($bad as $word){
if(in_array($word,$string))
{
$flag=1;
}
}
if($flag==1)
echo "Exist";
else
echo "Not Exist";