PHP Check if array element exists in any part of the string - php

I know how to find if your string equals an array value:
$colors = array("blue","red","white");
$string = "white";
if (!in_array($string, $colors)) {
echo 'not found';
}
...but how do I find if the string CONTAINS any part of the array values?
$colors = array("blue","red","white");
$string = "whitewash"; // I want this to be found in the array
if (!in_array($string, $colors)) {
echo 'not found';
}

Or in one shot:
if( preg_match("(".implode("|",array_map("preg_quote",$colors)).")",$string,$m)) {
echo "Found ".$m[0]."!";
}
This can also be expanded to only allow words that start with an item from your array:
if( preg_match("(\b(?:".implode("|",array_map("preg_quote",$colors))."))",$string,$m)) {
Or case-insensitive:
if( preg_match("(".implode("|",array_map("preg_quote",$colors)).")i",$string,$m)) {
CI with starting only:
if( preg_match("(\b(?:".implode("|",array_map("preg_quote",$colors))."))i",$string,$m)) {
Or anything really ;)

Just loop the array containing the values, and check if they are found in the input string, using strpos
$colors = array("blue","red","white");
$string = "whitewash"; // I want this to be found in the array
foreach ( $colors as $c ) {
if ( strpos ( $string , $c ) !== FALSE ) {
echo "found";
}
}
You can wrap it in a function:
function findString($array, $string) {
foreach ( $array as $a ) {
if ( strpos ( $string , $a ) !== FALSE )
return true;
}
return false;
}
var_dump( findString ( $colors , "whitewash" ) ); // TRUE

Try this working solution
$colors = array("blue", "red", "white");
$string = "whitewash";
foreach ($colors as $color) {
$pos = strpos($string, $color);
if ($pos === false) {
echo "The string '$string' not having substring '$color'.<br>";
} else {
echo "The string '$string' having substring '$color'.<br>";
}
}

There is no built-in function for that, but you could do something like:
$colors = array("blue","red","white");
$string = "whitewash"; // I want this to be found in the array
if (!preg_match('/\Q'.implode('\E|\Q',$colors).'\E/',$string)) {
echo 'not found';
}
This basically makes a regex from your array and matches the string against it. Good method, unless your array is really large.

You would have to iterate over each array element and individually check if it contains it (or a substr of it).
This is similar to what you want to do:
php check if string contains a value in array

$colors = array("blue","red","white");
$string = "whitewash"; // I want this to be found in the array
$hits = array();
foreach($colors as $color) {
if(strpos($string, $color) !== false) {
$hits[] = $color;
}
}
$hits will contain all $colors that have a match in $string.
if(empty($hits)) {
echo 'not found';
}

Related

How to make if condition word found in array [duplicate]

This question already has answers here:
Search for partial string in PHP array? Search value contains hashtag
(4 answers)
Closed last year.
In PHP
echo $avatar["name"];
$array = ["hello", "world", "!"];
$string = "wor";
if (in_array($string, [$array])){
echo "match";
}else
echo "not match";
I want a script like that to print match if the word found in array , not string equal to array
You can try like this :
function partial_array_search( $array, $keyword ) {
$found = [];
// Loop through each item and check for a match.
foreach ( $array as $string ) {
// If found somewhere inside the string, add.
if ( strpos( $string, $keyword ) !== false ) {
$found[] = $string;
}
}
return $found;
}
$array = ["hello", "world", "!"];
$string = "wor";
$data = partial_array_search( $array, $string );
if($data){
print_r($data) ;
}else{
echo 'NOT MATCH';
}

Search for matching partial values in an array [duplicate]

This question already has answers here:
Filter multidimensional array based on partial match of search value
(3 answers)
startsWith() and endsWith() functions in PHP
(34 answers)
Closed 1 year ago.
$target = 285
$array = array("260-315", "285-317", "240-320")
I need to search the array for the value that begins with the $target value. Also, the $target value will not be limited to 3 digits so I'm searching for a match of the digits before the hyphen.
So I want to end up with
$newTarget = 285-317
$finalTarget = 317
Note: I'm only searching for a match of the digits before the hyphen so "200-285" would not be a match
What you asked me in comment(below my answer),for that you can do it like below (My changed answer):-
<?php
$target = 285;
$array = array('260-315', '285-317', '240-320',"200-285");
foreach($array as $key=>$value){
if($target ==explode('-',$value)[0]){
echo $newTarget = $array[$key];
echo PHP_EOL;
echo $finalTarget = explode('-',$array[$key])[1];
}
}
?>
https://eval.in/702862
I can help you filter your array down to members that start with your target.
You can then split the return values to get to your final target.
<?php
$target = '285';
$array = array('260-315', '285-317', '240-320');
$out = array_filter($array, function($val) use ($target) {
return strpos($val, $target) === 0;
});
var_export($out);
Output:
array (
1 => '285-317',
)
<?php
$target = 285;
$arrStack = array(
"260-315",
"285-317",
"240-320",
);
$result = preg_grep('/'.$target.'/',$arrStack);
echo "<pre>"; print_r($result); echo "</pre>";
Something like this could work for you ? array_filter
$target = 285;
$array = array("260-315", "285-317", "240-320");
$newTarget = null;
$finalTarget = null;
$filteredArray = array_filter($array, function($val) use ($target) {
return strpos($val, $target."-") === 0;
});
if(isset($filteredArray[0])){
$newTarget = $filteredArray[0];
$finalTarget = explode($filteredArray[0], "-")[1];
}
Instead of finding what matches, you could exclude what doesn't match with array_filter.
For example:
$target = 285;
$original = array('260-315', '285-317', '240-320');
$final = array_filter($original, function ($value) use ($target) {
// Check if match starts at first character. Have to use absolute check
// because no match returns false
if (stripos($value, $target) === 0) {
return true;
}
return false;
});
The $final array will be a copy of the $original array without the non-matching values.
To output the first digits, you can then loop through your array of matches and get the value before the hyphen:
foreach ($final as $match) {
$parts = explode('-', $match);
if (is_array($parts) && ! empty($parts[0])) {
// Show or do something with value
echo $parts[0];
}
}
Use array_filter:
Example:
$target = '260';
$array = ['260-315', '285-317', '240-320'];
$matches = array_filter($array, function($var) use ($target) { return $target === explode('-', $var)[0]; });
print_r($matches);
Output:
Array
(
[0] => 260-315
)

How to check if a string inside of an array,contains a part of a string in php?

I have this code:
$arr = array("Hello_backup","World!","Beautiful_backup","Day!");
if(in_array("backup", $arr)){
echo "Da";
} else { echo "Nu";
}
But is not working because,in_array instruction check the array for the complete string "backup" , which doesnt exist.I need to check for a part of the string,for example,to return true because backup is a part of the "Hello_backup" and "Beautiful_backup" strings
EDIT: I take the advice and i have used stripos like this:
$arr = array("Hello_backup-2014","World!","Beautiful_backup-2014","Day!");
$word='backup';
if(stripos($arr,$word) !== false){
echo "Da";
} else { echo "Nu";}
but now i get an error: "stripos() expects parameter 1 to be string, array given in if(stripos($arr,$word) !== false){"
Use implode to basically concatenate the array values as a string, then use strpos to check for a string within a string.
The first argument you pass to implode is used to separate each value in the array.
$array = array("Hello_backup","World!","Beautiful_backup","Day!");
$r = implode(" ", $array);
if (strpos($r, "backup") !== false) {
echo "found";
}
In this case you need to use stripos(). Example:
$arr = array("Hello_backup","World!","Beautiful_backup","Day!");
$needle = 'backup';
function check($haystack, $needle) {
foreach($haystack as $word) {
if(stripos($word, $needle) !== false) {
return 'Da!'; // if found
}
}
return 'Nu'; // if not found
}
var_dump(check($arr, $needle));
Without a function:
$arr = array("Hello_backup","World!","Beautiful_backup","Day!");
$found = false;
foreach($arr as $word) {
if(stripos($word, 'backup') !== false) {
$found = true;
break;
}
}
if($found) {
echo 'Da!';
} else {
echo 'Nu';
}
Try with strpos()
$arr = array("Hello_backup","World!","Beautiful_backup","Day!");
foreach($arr as $v){
echo (strpos($v,"backup")!== false ? "Da" : "Nu");
}
output :- DaNuDaNu
Here is the one line solution for you.
$arr = array("Hello_backup-2014","World!","Beautiful_backup-2014","Day!");
$returned_a = array_map(function($u){ if(stripos($u,'backup') !== false) return "Da"; else return "Nu";}, $arr);
You can use $returned_a with array as your answer..
Array ( [0] => Da [1] => Nu [2] => Da [3] => Nu )
Use this method. It is little bit simple to use.
$matches = preg_grep('/backup/', $arr);
$keys = array_keys($matches);
print_r($matches);
Look this working example
According to your question
$matches = preg_grep('/backup/', $arr);
$keys = array_keys($matches);
$matches = trim($matches);
if($matches != '')
{echo "Da";
}else { echo "Nu";}
<?php
$arr = array("Hello_backup","World!","Beautiful_backup","Day!");
foreach($arr as $arr1) {
if (strpos ($arr1,"backup")) {
echo "Da";
} else {
echo "Nu";
}
}
?>

Check if string contains word in array [duplicate]

This question already has answers here:
String contains any items in an array (case insensitive)
(15 answers)
Closed 2 years ago.
This is for a chat page. I have a $string = "This dude is a mothertrucker". I have an array of badwords: $bads = array('truck', 'shot', etc). How could I check to see if $string contains any of the words in $bad?
So far I have:
foreach ($bads as $bad) {
if (strpos($string,$bad) !== false) {
//say NO!
}
else {
// YES! }
}
Except when I do this, when a user types in a word in the $bads list, the output is NO! followed by YES! so for some reason the code is running it twice through.
function contains($str, array $arr)
{
foreach($arr as $a) {
if (stripos($str,$a) !== false) return true;
}
return false;
}
1) The simplest way:
if ( in_array( 'three', ['one', 'three', 'seven'] ))
...
2) Another way (while checking arrays towards another arrays):
$keywords=array('one','two','three');
$targets=array('eleven','six','two');
foreach ( $targets as $string )
{
foreach ( $keywords as $keyword )
{
if ( strpos( $string, $keyword ) !== FALSE )
{ echo "The word appeared !!" }
}
}
can you please try this instead of your code
$string = "This dude is a mothertrucker";
$bads = array('truck', 'shot');
foreach($bads as $bad) {
$place = strpos($string, $bad);
if (!empty($place)) {
echo 'Bad word';
exit;
} else {
echo "Good";
}
}
There is a very short php script that you can use to identify bad words in a string which uses str_ireplace as follows:
$string = "This dude is a mean mothertrucker";
$badwords = array('truck', 'shot', 'ass');
$banstring = ($string != str_ireplace($badwords,"XX",$string))? true: false;
if ($banstring) {
echo 'Bad words found';
} else {
echo 'No bad words in the string';
}
The single line:
$banstring = ($string != str_ireplace($badwords,"XX",$string))? true: false;
does all the work.
You can flip your bad word array and do the same checking much faster. Define each bad word as a key of the array. For example,
//define global variable that is available to too part of php script
//you don't want to redefine the array each time you call the function
//as a work around you may write a class if you don't want global variable
$GLOBALS['bad_words']= array('truck' => true, 'shot' => true);
function containsBadWord($str){
//get rid of extra white spaces at the end and beginning of the string
$str= trim($str);
//replace multiple white spaces next to each other with single space.
//So we don't have problem when we use explode on the string(we dont want empty elements in the array)
$str= preg_replace('/\s+/', ' ', $str);
$word_list= explode(" ", $str);
foreach($word_list as $word){
if( isset($GLOBALS['bad_words'][$word]) ){
return true;
}
}
return false;
}
$string = "This dude is a mothertrucker";
if ( !containsBadWord($string) ){
//doesn't contain bad word
}
else{
//contains bad word
}
In this code we are just checking if an index exist rather than comparing bad word with all the words in the bad word list.
isset is much faster than in_array and marginally faster than array_key_exists.
Make sure none of the values in bad word array are set to null.
isset will return false if the array index is set to null.
Put and exit or die once it find any bad words, like this
foreach ($bads as $bad) {
if (strpos($string,$bad) !== false) {
//say NO!
}
else {
echo YES;
die(); or exit;
}
}
You can do the filter this way also
$string = "This dude is a mothertrucker";
if (preg_match_all('#\b(truck|shot|etc)\b#', $string )) //add all bad words here.
{
echo "There is a bad word in the string";
}
else {
echo "There is no bad word in the string";
}
Wanted this?
$string = "This dude is a mothertrucker";
$bads = array('truck', 'shot', 'mothertrucker');
foreach ($bads as $bad) {
if (strstr($string,$bad) !== false) {
echo 'NO<br>';
}
else {
echo 'YES<br>';
}
}
If you want to do with array_intersect(), then use below code :
function checkString(array $arr, $str) {
$str = preg_replace( array('/[^ \w]+/', '/\s+/'), ' ', strtolower($str) ); // Remove Special Characters and extra spaces -or- convert to LowerCase
$matchedString = array_intersect( explode(' ', $str), $arr);
if ( count($matchedString) > 0 ) {
return true;
}
return false;
}
I would go that way if chat string is not that long.
$badwords = array('mothertrucker', 'ash', 'whole');
$chatstr = 'This dude is a mothertrucker';
$chatstrArr = explode(' ',$chatstr);
$badwordfound = false;
foreach ($chatstrArr as $k => $v) {
if (in_array($v,$badwords)) {$badwordfound = true; break;}
foreach($badwords as $kb => $vb) {
if (strstr($v, $kb)) $badwordfound = true;
break;
}
}
if ($badwordfound) { echo 'You\'re nasty!';}
else echo 'GoodGuy!';
$string = "This dude is a good man";
$bad = array('truck','shot','etc');
$flag='0';
foreach($bad as $word){
if(in_array($word,$string))
{
$flag=1;
}
}
if($flag==1)
echo "Exist";
else
echo "Not Exist";

php -> delete items from array which contain words from a blacklist

I have got an array with several twitter tweets and want to delete all tweets in this array which contain one of the following words blacklist|blackwords|somemore
who could help me with this case?
Here's a suggestion:
<?php
$banned_words = 'blacklist|blackwords|somemore';
$tweets = array( 'A normal tweet', 'This tweet uses blackwords' );
$blacklist = explode( '|', $banned_words );
// Check each tweet
foreach ( $tweets as $key => $text )
{
// Search the tweet for each banned word
foreach ( $blacklist as $badword )
{
if ( stristr( $text, $badword ) )
{
// Remove the offending tweet from the array
unset( $tweets[$key] );
}
}
}
?>
You can use array_filter() function:
$badwords = ... // initialize badwords array here
function filter($text)
{
global $badwords;
foreach ($badwords as $word) {
return strpos($text, $word) === false;
}
}
$result = array_filter($tweetsArray, "filter");
use array_filter
Check this sample
$tweets = array();
function safe($tweet) {
$badwords = array('foo', 'bar');
foreach ($badwords as $word) {
if (strpos($tweet, $word) !== false) {
// Baaaad
return false;
}
}
// OK
return true;
}
$safe_tweets = array_filter($tweets, 'safe'));
You can do it in a lot of ways, so without more information, I can give this really starting code:
$a = Array(" fafsblacklist hello hello", "white goodbye", "howdy?!!");
$clean = Array();
$blacklist = '/(blacklist|blackwords|somemore)/';
foreach($a as $i) {
if(!preg_match($blacklist, $i)) {
$clean[] = $i;
}
}
var_dump($clean);
Using regular expressions:
preg_grep($array,"/blacklist|blackwords|somemore/",PREG_GREP_INVERT)
But i warn you that this may be inneficient and you must take care of punctuation characters in the blacklist.

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