I am getting some slashes inside my JSON array key using PHP. I am providing my code below.
$result[] = $fcm->send_fcm_notify($device_id, $message);
echo json_encode($result);
The output of the above code is below:
{\"multicast_id\":7339396188598826217,\"success\":1,\"failure\":0,\"canonical_ids\":0,\"results\":[{\"message_id\":\"0:1482327583160431%2d865361f9fd7ecd\"}]}"]
I need to remove the slashes, because I need to check success==1.
Use stripslashes() first on response then do json_decode()
Try
$json = json_decode(stripslashes('{\"multicast_id\":7339396188598826217,\"success\":1,\"failure\":0,\"canonical_ids\":0,\"results\":[{\"message_id\":\"0:1482327583160431%2d865361f9fd7ecd\"}]}'));
if( $json->success == '1' )
{
echo "I got it";
}
Output
You can use json_decode() to conrect received json string into multidimensional array then you can use json_encode() to print that array in json format without any slashes.
But make sure your received json string is valid as i can see the json code is not valid this will throw error when you use json_decode.
Your json string is wrong so json_encode will not work i have removed extra ] at the end of string so that json can parse without any error.
<?php
$json_code = "{\"multicast_id\":7339396188598826217,\"success\":1,\"failure\":0,\"canonical_ids\":0,\"results\":[{\"message_id\":\"0:1482327583160431%2d865361f9fd7ecd\"}]}";
$result = json_decode($json_code,true);
//for json output use json_encode()
echo json_encode($code);
?>
Related
I run the following PHP after I submit a form and get the output shown below:
$data = json_encode($_POST);
// output
{"First_Name":"Fred"}
How do I use PHP to just display the value 'Fred'?
I tried echo $data['First_Name']; but this is blank.
You no need to encode your incoming $_POST data.
Just say:
echo $_POST['First_Name'];
If you get a json data, decode it into an array:
$data = '{"First_Name":"Fred"}';
$decoded = json_decode($data, true);
echo $decoded['First_name'];
First of all, don't know why you use json_encode on PHP Array, and try to access it like it's an array - because after json_encode it's a string.
You have to use json_decode($data, true) and then you can access it like $data['First_Name'] or try to access it directly without json_encode() by $_POST['First_Name']
The json_decode() function is used to decode or convert a JSON object to a PHP object.And try to put the object to decode in another variable to avoid errors
<?php
$obj = '{"First_Name":"Fred"}';
$data = json_decode($obj);
echo ($data->First_Name);
?>
anyone can help to decode this?
var_dump
sring(56441) "{"success":{"message":"PDF \u0444\u0430\u0439\u043b\u0430 \u0435 \u0433\u0435\u043d\u0435\u0440\u0438\u0440\u0430\u043d \u0443\u0441\u043f\u0435\u0448\u043d\u043e!","name":"invoice-0000000001.pdf","data":"JVBERi0xLjQKMSAwIG9iago8PAovVGl0bGUgKP7\/BCQEMAQ6BEIEQwRABDAAICEWADAAMAAwADAAMAAwADAAMA","type":"application\/pdf"}}"
I need to get "data" from this code.
<?php
$data='{"success":{"message":"PDF \u0444\u0430\u0439\u043b\u0430 \u0435 \u0433\u0435\u043d\u0435\u0440\u0438\u0440\u0430\u043d \u0443\u0441\u043f\u0435\u0448\u043d\u043e!","name":"invoice-0000000001.pdf","data":"JVBERi0xLjQKMSAwIG9iago8PAovVGl0bGUgKP7\/BCQEMAQ6BEIEQwRABDAAICEWADAAMAAwADAAMAAwADAAMA","type":"application\/pdf"}}';
$data=json_decode($data,true);
echo '<pre>';
print_r($data['success']['data']);
It's a simple json that you need to make it an array and access it as a normal array. The output is the data field you asked:
JVBERi0xLjQKMSAwIG9iago8PAovVGl0bGUgKP7/BCQEMAQ6BEIEQwRABDAAICEWADAAMAAwADAAMAAwADAAMA
Well, you only need to json_decode() that string and you have your result:
<?php
$input = '{"success":{"message":"PDF \u0444\u0430\u0439\u043b\u0430 \u0435 \u0433\u0435\u043d\u0435\u0440\u0438\u0440\u0430\u043d \u0443\u0441\u043f\u0435\u0448\u043d\u043e!","name":"invoice-0000000001.pdf","data":"JVBERi0xLjQKMSAwIG9iago8PAovVGl0bGUgKP7\/BCQEMAQ6BEIEQwRABDAAICEWADAAMAAwADAAMAAwADAAMA","type":"application\/pdf"}}';
$output = json_decode($input);
print_r($output->success->data);
JVBERi0xLjQKMSAwIG9iago8PAovVGl0bGUgKP7/BCQEMAQ6BEIEQwRABDAAICEWADAAMAAwADAAMAAwADAAMA
I am trying to convert cdnjs api JSON result to php array from this link. Here is my code:
<pre>
<?php
$cdnLinks = file_get_contents('http://api.cdnjs.com/libraries');
$cdnLinks = json_encode($cdnLinks);
$j = json_decode($cdnLinks);
print_r($j);
?>
</pre>
What am I missing? Thanks
This is what you are doing:
Download a string of JSON
Encode that string into JSON (you now have a JSON string containing a JSON object)
Decode that JSON back to a string of JSON
Print the string
You need to skip step 2.
Skip step 2 because the output is already a json string.
To decode a json into an array you also need to use second parameter as true json_decode($jsonObj, true).
Thanks
I have this JSON encoded code in my mysql database:
{"Suggestion":{"Title":"Casinos","Text":"maybe it will be good if its there casinos "},"ID":6,"VoteNo":[],"Status":"Voting","Player":{"SteamID":"STEAM_0:1:36988062","Name":"Pepi"},"Approved":{"Name":"Nido Johnson","Is":true,"SteamID":"STEAM_0:0:47457253"},"VoteYes":{"1":"STEAM_0:0:56939043","2":"STEAM_0:0:55948188","3":"STEAM_0:1:25856984","4":"STEAM_0:1:40894071"}}
And i want to query and decode it to echo it at my website.
You have to use a php "json_decode()" function to decode a json encoded data.
Basically json_decode() function converts JSON data to a PHP array.
Syntax: json_decode( data, dataTypeBoolean, depth, options )
data : - The json data that you want to decode in PHP.
dataTypeBoolean(Optional) :- boolean that makes the function return a PHP Associative Array if set to "true", or return a PHP stdClass object if you omit this parameter or set it to "false". Both data types can be accessed like an array and use array based PHP loops for parsing.
depth :- Optional recursion limit. Use an integer as the value for this parameter.
options :- Optional JSON_BIGINT_AS_STRING parameter.
Now Comes to your Code
$json_string = '{"Suggestion":{"Title":"Casinos","Text":"maybe it will be good if its there casinos "},"ID":6,"VoteNo":[],"Status":"Voting","Player":{"SteamID":"STEAM_0:1:36988062","Name":"Pepi"},"Approved":{"Name":"Nido Johnson","Is":true,"SteamID":"STEAM_0:0:47457253"},"VoteYes":{"1":"STEAM_0:0:56939043","2":"STEAM_0:0:55948188","3":"STEAM_0:1:25856984","4":"STEAM_0:1:40894071"}}';
Assign a valid json data to a variable $json_string within single quot's ('') as
json string already have double quots.
// here i am decoding a json string by using a php 'json_decode' function, as mentioned above & passing a true parameter to get a PHP associative array otherwise it will bydefault return a PHP std class objecy array.
/ just can check here your encoded array data.
// echo '<pre>';
// print_r($json_decoded_data);
// loop to extract data from an array
foreach ($json_decoded_data as $key => $value) {
echo "$key <br/>";
foreach($value as $k=>$data)
{
echo "$k | $data <br/>";
}
}
I just test this sample from php doc (http://au2.php.net/manual/en/function.json-decode.php)
here is my code:
<?php $json = '{"a":1,"b":2,"c":3,"d":4,"e":5}'; echo json_decode($json, true), '<br />';?>
But it just returns an EMPTY array.
Have no idea why...Been searching around but no solution found.
PLEASE help!
You can validate at following
website: http://jsonlint.com/
You have to use a php "json_decode()" function to decode a json encoded data.
Basically json_decode() function converts JSON data to a PHP array.
Syntax: json_decode( data, dataTypeBoolean, depth, options )
data : - The json data that you want to decode in PHP.
dataTypeBoolean(Optional) :- boolean that makes the function return a PHP Associative Array if set to "true", or return a PHP stdClass object if you omit this parameter or set it to "false". Both data types can be accessed like an array and use array based PHP loops for parsing.
depth :- Optional recursion limit. Use an integer as the value for this parameter.
options :- Optional JSON_BIGINT_AS_STRING parameter.
Now Comes to your Code
$json_string = '{"a":1,"b":2,"c":3,"d":4,"e":5}' ;
Assign a valid json data to a variable $json_string within single quot's ('') as
json string already have double quots.
// here i am decoding a json string by using a php 'json_decode' function, as mentioned above & passing a true parameter to get a PHP associative array otherwise it will bydefault return a PHP std class objecy array.
$json_decoded_data = json_decode($json_string, true);
// just can check here your encoded array data.
// echo '<pre>';
// print_r($json_decoded_data);
// loop to extract data from an array
foreach ($json_decoded_data as $key => $value) {
echo "$key | $value <br/>";
}
you should not use echo because it is an array. use print_r or var_dump .it works fine
$json = '{"a":1,"b":2,"c":3,"d":4,"e":5}';
print_r(json_decode($json, true));
Output:
Array
(
[a] => 1
[b] => 2
[c] => 3
[d] => 4
[e] => 5
)
No, it doesn't return an empty array.
Printing an array with echo just prints a string "Array()".
Use print_r or var_dump to get the structure of the variable.
In newer PHP it will also emit a notice when using echo on an array ("Array to string conversion"), so you shouldn't do it anyway. The manual you've mentioned changed to print_r.
It works fine, but you use wrong method to display array.
To display array you cannot use echo but you need to use var_dump
It works fine as others mention, but when you print the array it is converted to string, which means only the string "Array" will be printed instead of the real array data. You should use print_r(), var_dump(), var_export() or something similar to debug arrays like this.
If you turn on notices you will see:
PHP Notice: Array to string conversion in ...
The example you linked uses also var_dump for the same reason.
var_dump have pretty print in php5.4
$json = '{"a":1,"b":2,"c":3,"d":4,"e":5}';
var_dump( json_decode($json));