I have this JSON encoded code in my mysql database:
{"Suggestion":{"Title":"Casinos","Text":"maybe it will be good if its there casinos "},"ID":6,"VoteNo":[],"Status":"Voting","Player":{"SteamID":"STEAM_0:1:36988062","Name":"Pepi"},"Approved":{"Name":"Nido Johnson","Is":true,"SteamID":"STEAM_0:0:47457253"},"VoteYes":{"1":"STEAM_0:0:56939043","2":"STEAM_0:0:55948188","3":"STEAM_0:1:25856984","4":"STEAM_0:1:40894071"}}
And i want to query and decode it to echo it at my website.
You have to use a php "json_decode()" function to decode a json encoded data.
Basically json_decode() function converts JSON data to a PHP array.
Syntax: json_decode( data, dataTypeBoolean, depth, options )
data : - The json data that you want to decode in PHP.
dataTypeBoolean(Optional) :- boolean that makes the function return a PHP Associative Array if set to "true", or return a PHP stdClass object if you omit this parameter or set it to "false". Both data types can be accessed like an array and use array based PHP loops for parsing.
depth :- Optional recursion limit. Use an integer as the value for this parameter.
options :- Optional JSON_BIGINT_AS_STRING parameter.
Now Comes to your Code
$json_string = '{"Suggestion":{"Title":"Casinos","Text":"maybe it will be good if its there casinos "},"ID":6,"VoteNo":[],"Status":"Voting","Player":{"SteamID":"STEAM_0:1:36988062","Name":"Pepi"},"Approved":{"Name":"Nido Johnson","Is":true,"SteamID":"STEAM_0:0:47457253"},"VoteYes":{"1":"STEAM_0:0:56939043","2":"STEAM_0:0:55948188","3":"STEAM_0:1:25856984","4":"STEAM_0:1:40894071"}}';
Assign a valid json data to a variable $json_string within single quot's ('') as
json string already have double quots.
// here i am decoding a json string by using a php 'json_decode' function, as mentioned above & passing a true parameter to get a PHP associative array otherwise it will bydefault return a PHP std class objecy array.
/ just can check here your encoded array data.
// echo '<pre>';
// print_r($json_decoded_data);
// loop to extract data from an array
foreach ($json_decoded_data as $key => $value) {
echo "$key <br/>";
foreach($value as $k=>$data)
{
echo "$k | $data <br/>";
}
}
Related
I using codeigniter. I want to retrive data from database and convert it into JSON object not JSON array.I'm using following code
public function json()
{
$content = $this->db->get('todolist'); //todolist table name
$data = $content->result_array();
echo json_encode($data);
}
Above code is converting database into JSON array.
Output
[{"todo_id":"1","todo_content":"Homework","date":"2016-05-05","iscomplete":null,"imagelink":"Lighthouse.jpg"},{"todo_id":"2","todo_content":"exam","date":"2015-04-21","iscomplete":null,"imagelink":"Desert.jpg"},{"todo_id":"3","todo_content":"Lab report","date":"2014-08-29","iscomplete":null,"imagelink":"FB_IMG_14700753538617403.jpg"}]
What will be best way to convert it into JSON object
Sangam try to understand the concept, check the following line:
$data = $content->result_array(); // $data is an array
echo json_encode($data); // here you are converting it into an json object
Your $data array contains more than one index in it that's why the json object is having multiple {} inside [];
You want to json_encode($data, JSON_FORCE_OBJECT).
The JSON_FORCE_OBJECT flag, as the name implies, forces the json output to be an object, even when it otherwise would normally be represented as an array.
Refer: PHP Array to Json Object
You can use JSON_FORCE_OBJECT see the example below.
echo json_encode($data, JSON_FORCE_OBJECT);
Assuming you're only getting one row back from your query.
change
echo json_encode($data);
to
echo json_encode($data[0]);
My php file receives a post from ajax call. The string received by the php file is as follows :
array(1) { ["userid"]=> string(21) "assssssss,camo,castor" }
I am trying unsuccessfully to decode this string then loop through the values in the array. I have tried the following :
$myarray =json_decode($_POST["userid"],true);
foreach ($myarray as $value) {
//do something with value
}
I am not sure whether the decode is the issue or my syntax to loop through the PHP array.
The POST data you'd want to manipulate is stored in $_POST['userid]
In case you're trying to access this comma separated user ids, you need to convert this to an array first using explode(). And then loop through these id's.
if (isset($_POST)) {
$user_ids = $_POST['userid']; // assssssss,camo,castor
$user_id_arr = explode(',', $user_ids); // Converts string to array Array (0 => assssssss, 1 => camo, 2 => castor)
foreach ($user_id_arr as $user_id) {
//Statements
}
}
$_POST is an associative array of variables passed to the current script via the HTTP POST method when using application/x-www-form-urlencoded or multipart/form-data as the HTTP Content-Type in the request. So when you decode with json_decode that will decode JSON string to Object/Array.
But in your scenario you have not passed JSON String to $_POST so it not looks decoding.
The string you have passed into your $_POST is not JSON, so json_decode will not work on some random comma seperated values.
You can either pass in real JSON, or just use the explode method of splitting these values:
// explode example
$users = "assssssss,camo,castor";
$usersarray = explode(",", $users);
How to get the corresponding value for key associated
[{"name":"challenge","properties":[{"name":"mobileNo","value":"aa"},{"name":"challengeT","value":"1Day"},{"name":"emailId","value":"ff#gmail.com"},{"name":"deviceId","value":"9500e297-081b-4f97-93b7-dafddc55db31"}]},{"name":"challenge","properties":[{"name":"emailId","value":"a#b.com"},{"name":"mobileNo","value":"345345"},{"name":"deviceId","value":"435435dfgdfg"}]}]
Your Json is valid. You can validate at following
website: http://jsonlint.com/
You have to use a php "json_decode()" function to decode a json encoded data.
Basically json_decode() function converts JSON data to a PHP array.
Syntax: json_decode( data, dataTypeBoolean, depth, options )
data : - The json data that you want to decode in PHP.
dataTypeBoolean(Optional) :- boolean that makes the function return a PHP Associative Array if set to "true", or return a PHP stdClass object if you omit this parameter or set it to "false". Both data types can be accessed like an array and use array based PHP loops for parsing.
depth :- Optional recursion limit. Use an integer as the value for this parameter.
options :- Optional JSON_BIGINT_AS_STRING parameter.
Now Comes to your Code
$json_string = '[{"name":"challenge","properties":[{"name":"mobileNo","value":"aa"},{"name":"challengeT","value":"1Day"},{"name":"emailId","value":"ff#gmail.com"},{"name":"deviceId","value":"9500e297-081b-4f97-93b7-dafddc55db31"}]},{"name":"challenge","properties":[{"name":"emailId","value":"a#b.com"},{"name":"mobileNo","value":"345345"},{"name":"deviceId","value":"435435dfgdfg"}]}]' ;
Assign a valid json data to a variable $json_string within single quot's ('') as
json string already have double quots.
// here i am decoding a json string by using a php 'json_decode' function, as mentioned above & passing a true parameter to get a PHP associative array otherwise it will bydefault return a PHP std class objecy array.
$json_decoded_data = json_decode($json_string, true);
// just can check here your encoded array data.
// echo '<pre>';
// print_r($json_decoded_data);
// loop to extract data from an array
foreach ($json_decoded_data as $key => $value) {
echo "$key <br/>";
foreach ($value as $key2 => $value2) {
echo "$key2 = $value2 <br />";
}
}
Output :
0
name = challenge
properties = Array
1
name = challenge
properties = Array
I just test this sample from php doc (http://au2.php.net/manual/en/function.json-decode.php)
here is my code:
<?php $json = '{"a":1,"b":2,"c":3,"d":4,"e":5}'; echo json_decode($json, true), '<br />';?>
But it just returns an EMPTY array.
Have no idea why...Been searching around but no solution found.
PLEASE help!
You can validate at following
website: http://jsonlint.com/
You have to use a php "json_decode()" function to decode a json encoded data.
Basically json_decode() function converts JSON data to a PHP array.
Syntax: json_decode( data, dataTypeBoolean, depth, options )
data : - The json data that you want to decode in PHP.
dataTypeBoolean(Optional) :- boolean that makes the function return a PHP Associative Array if set to "true", or return a PHP stdClass object if you omit this parameter or set it to "false". Both data types can be accessed like an array and use array based PHP loops for parsing.
depth :- Optional recursion limit. Use an integer as the value for this parameter.
options :- Optional JSON_BIGINT_AS_STRING parameter.
Now Comes to your Code
$json_string = '{"a":1,"b":2,"c":3,"d":4,"e":5}' ;
Assign a valid json data to a variable $json_string within single quot's ('') as
json string already have double quots.
// here i am decoding a json string by using a php 'json_decode' function, as mentioned above & passing a true parameter to get a PHP associative array otherwise it will bydefault return a PHP std class objecy array.
$json_decoded_data = json_decode($json_string, true);
// just can check here your encoded array data.
// echo '<pre>';
// print_r($json_decoded_data);
// loop to extract data from an array
foreach ($json_decoded_data as $key => $value) {
echo "$key | $value <br/>";
}
you should not use echo because it is an array. use print_r or var_dump .it works fine
$json = '{"a":1,"b":2,"c":3,"d":4,"e":5}';
print_r(json_decode($json, true));
Output:
Array
(
[a] => 1
[b] => 2
[c] => 3
[d] => 4
[e] => 5
)
No, it doesn't return an empty array.
Printing an array with echo just prints a string "Array()".
Use print_r or var_dump to get the structure of the variable.
In newer PHP it will also emit a notice when using echo on an array ("Array to string conversion"), so you shouldn't do it anyway. The manual you've mentioned changed to print_r.
It works fine, but you use wrong method to display array.
To display array you cannot use echo but you need to use var_dump
It works fine as others mention, but when you print the array it is converted to string, which means only the string "Array" will be printed instead of the real array data. You should use print_r(), var_dump(), var_export() or something similar to debug arrays like this.
If you turn on notices you will see:
PHP Notice: Array to string conversion in ...
The example you linked uses also var_dump for the same reason.
var_dump have pretty print in php5.4
$json = '{"a":1,"b":2,"c":3,"d":4,"e":5}';
var_dump( json_decode($json));
My JSON looks like this. How do I get a specific field, e.g. "title" or "url"?
{
"status":1,
"list":
{
"204216523":
{"item_id":"204216523",
"title":"title1",
"url":"url1",
},
"203886655":
{"item_id":"203886655",
"title":"titl2",
"url":"url2",
}
},"since":1344188496,
"complete":1
}
I know $result = json_decode($input, true); should be used to get parsable data in $result, but how do I get individual fields out of $result? I need to run through all the members (2 in this case) and get a field out of it.
json_decode() converts JSON data into an associative array. So to get title & url out of your data,
foreach ($result['list'] as $key => $value) {
echo $value['title'].','.$value['url'];
}
echo $result['list']['204216523']['item_id']; // prints 204216523
json_decode() translates your JSON data into an array. Treat it as an associative array because that's what it is.