I have a controller with Index function, Now i am trying to make a more fundtion for on scroll pagintion in codeignitor Controller.
This is my function
public function load_more($cat2,$cat1)
{
$group_no = $this->input->post('group_no');
$content_per_page = 12;
$start = ceil($group_no * $content_per_page);
$all_content = $this->product__model->get_all_content($start,$content_per_page,$cat2,$cat1);
if(isset($all_content) && is_array($all_content) && count($all_content)) :
foreach ($all_content as $key => $content) :
echo '<li>'.$content->id.'</li>';
echo '<p>'.$content->ITEM_CODE.'</p>';
endforeach;
endif;
}
Controller name is Product
When i check this fucntion at my url its hows page not found...
this is URL
http://www.dezaro.com/Product/load_more/160/2
How can i resolve it ???
Siddharth vyas The issue is with your URL you are hitting. Use product instead Product.
So Use http://www.dezaro.com/product/load_more/160/2 instead of
http://www.dezaro.com/Product/load_more/160/2
It will work for sure. Because it take the filename instead of Classname.
Try this
$route['method/(:any)/(:any)'] = 'controller/method/$1/$2';
your route should be
$route['method/(:cat1)/(:cat2)'] = 'product/load_more/$1/$2';
It seemd you are facing issue of index.php
Please try using url:
http://www.dezaro.com/index.php/Product/load_more/160/2
Related
I have this code in my header.php to change the website's logo based on the page's slug:
$logo_img = 'default';
if (is_page('brookside')) {
$logo_img = 'brookside';
} elseif (is_page('hilltop')) {
$logo_img = 'hilltop';
} elseif (is_page('reserve')) {
$logo_img = 'reserve';
}
Which works great. However, the pages a need to change the logo are query string URL, so they don't have slugs. I was able to add a unique class to each page. My question is:
How do I translate that code to "if a page has "x" class? So, what function should I use instead of is_page?
Any help would be very appreciated!
Thanks!
You can use:
if($_GET['ct_additional_features'] == 'brookside') {
$logo_img = 'brookside';
}
You could use get_class that outputs the Class Name and there solve your if with what are you saying
please help me, this is simple thing but I don't know why this still keep error for an hour,
on my view I've got :
<a href="admin/editProduct?idd=$id">
on my controller that directed from above :
public function editProduct(){
$data["id"] = $_GET['idd'];
$data["produk"] = $this->model_get->get_data_list(2);
//this below doesn't work either, i just want to past the parameter to my model
//$data["produk"] = $this->model_get->get_data_list($_GET['idd']);
$this->adminHeader();
$this->load->view("adminPages/editProduct", $data);
$this->adminFooter();
}
I can not use the array id. It keeps telling me undefined variable idd.
I don't know what to do anymore, please anyone help!
I am using Codeigniter framework
Change your view as:
<a href="admin/editProduct/<?php echo $id;?>">
And in the controller, either get the id as parameter,
public function editProduct($id) {
}
or as uri segment
public function editProduct() {
$id = $this->uri->segment(3);
}
Change your link (in view) with this
<a href="admin/editProduct/$id">
And change your controller as
public function editProduct($id) {
}
Then user $id inside your controller
Make the href link as follows:
...
And edit the controller like this:
public function editProduct($id){
...
$this->model_get->get_data_list($id);
}
Where $id will be the passed $id.
make
try this this works fine
public function editProduct()
{
$id=$this->uri->segment(3);
$data["produk"] = $this->model_get->get_data_list($id);
$this->adminHeader();
$this->load->view("adminPages/editProduct", $data);
$this->adminFooter();
}
I have a blog page of posts that I am trying to paginate using CodeIgniter. The numbering and limiting seem to be working fine, except I keep getting a 404 when I try to travel to another page.
The strange thing is the normal culprits that cause this issue are correct. The baseUrl and the uri_segment.
My controller looks like this:
$config = array();
$config["base_url"] = $this->config->site_url("/blog");
$config["total_rows"] = $this->blog_model->count();
$config["per_page"] = 2;
$config["uri_segment"] = 2;
$config["num_links"] = round($config["total_rows"] / $config["per_page"]);
$config['use_page_numbers'] = TRUE;
$this->pagination->initialize($config);
$page = ($this->uri->segment(2)) ? $this->uri->segment(2) : 0;
$this->load->view('blog', array(
'user' => $this->user,
'blog' => $this->blog_model->loadPosts($config['per_page'], $page),
'links' => $this->pagination->create_links(),
'footer' => $this->blog_model->loadFooter()
));
And then in my model I am grabbing the posts
public function loadPosts($limit, $start)
{
$this->db->limit($limit, $start);
$this->db->order_by("date", "desc");
//this loads the contact info
$query = $this->db->get('entries');
return $query->result();
}
My full URL is www.mysite.com/blog and then with the pagination it appears as www.mysite.com/blog/2.
For the base_Url I have also tried base_url() . "/blog";.
And I have tried setting the uri_segment to 1 and 3, but nothing seems to work.
As well I have tried playing around with the routing and have added just to see if it would do anything:
$route['blog/(:num)'] = 'blog/$1';
You can use this line of code if your code is inside the index method:
$route['blog/:any'] = "blog/index/$1";
Because you have used the segment(2), and you should change the blog/index/$1 to blog/:any.
Assuming the function name that contain your pagination code is index(), you should change the route to:
$route['blog/(:num)'] = 'blog/index/$1';
And in your index() function, add the $page parameter:
public function index($page = 1){
...
With your routes, try if you can to add as many :anys or :nums after as you like:
$route['blog'] = 'blog/index'; // For the first level
$route['blog/(:any)/(:any)'] = 'blog/index/$1/$2'; // For extra "uri" segments.
// base_url pagination
$config["base_url"] = base_url("blog"); // Is preferred
You can keep your other code as it is. Just add this at your routes.php file:
$route['blog/:num'] = "blog/index";
//Assumes your code is inside the index method.
//If not, use this way:
//$route['blog/:num'] = "blog/YOUR_METHOD_NAME";
You can't pass a parameter to the index() function of a controller like it is a random function.
If you try to do controller/var instead of controller/function/var, CodeIgniter will search for a function var() inside the controller which does not exists. That's what happen when you try to access blog/2: 2() isn't a function in your controller.
You can create a new function in your controller, let's say page(), and move your code inside. That way, you will call blog/page/2. Function page() will exists and will not get a 404. Also don't fordet to redefine your base_url for pagination.
$config["base_url"] = site_url("blog/page");
Another solution if you absolutely need the URL like /blog/2, routes:
$route['blog/(:any)'] = 'blog/index/$1';
Remap may also be a solution: http://www.codeigniter.com/user_guide/general/controllers.html#remapping
I am having difficulty getting the correct URL when I call a method to load a view.
Heres my controller:
public function post() {
$title = $this->input->post('title');
$data = $this->p_Model->post($title);
$this->qs($data);
}
public function qs($id){
$title = $this->s_Model->getTitle($id);
$result = $title->result();
$this->load->view('q_View', array('results' => $result));
}
Heres my view:(note this view is not the view which gets loaded from the qs function, but one which calls the qs function)
<html>
<body>
<table>
<?php
if (isset($qs)) {
foreach ($qs as $row) {
$id = $row->qID;
echo '<a href="'.site_url('myController/qs/'.$id).'">';
echo $row->title;
echo "<br>";
}
}
?>
</table>
</body>
</html>
So in my controller I have two functions, the qs function works separately by itself so can be called in the view and give the following url myController/qs/1 however when I use the post function I get a url like this myController/post so my question is how can I get my url to be like the first example?
Instead of using the line:
$this->qs($data);
You can use a redirect:
redirect('/mainController/qs/'.$data);
That should work in the same way that you have used in your view
Try base_url and also you can use current_url() returns the full URL (including segments) of the page being currently viewed.
echo '<a href="'.base_url('myController/qs/'.$id).'">';
I have a page with URL http://arslan/admin/category/index/0/name/asc/10 in Codeigniter.
In this URL, the uri_segment start from 0. This (0) is the default search value, name and asc are the default sort field and order, and 10 is the pagination index.
Now if I move to an add page with URL (http://arslan/admin/category/add/)
similarly like above "add" is the current function.
Now if i want to go back through a link to back page... How can I divert the user back? I can't make the URL go back.
Can somebody help me please?
I am not sure if i understand the question correctly, if not please ignore my answer, but I think you want a link to "go back to previous page", similar to the back-button in a web browser.
If so you could use javascript to solve this by simply using this line:
Go back
I extend the session class by creating /application/libaries/MY_Session.php
class MY_Session extends CI_Session {
function __construct() {
parent::__construct();
$this->tracker();
}
function tracker() {
$this->CI->load->helper('url');
$tracker =& $this->userdata('_tracker');
if( !IS_AJAX ) {
$tracker[] = array(
'uri' => $this->CI->uri->uri_string(),
'ruri' => $this->CI->uri->ruri_string(),
'timestamp' => time()
);
}
$this->set_userdata( '_tracker', $tracker );
}
function last_page( $offset = 0, $key = 'uri' ) {
if( !( $history = $this->userdata('_tracker') ) ) {
return $this->config->item('base_url');
}
$history = array_reverse($history);
if( isset( $history[$offset][$key] ) ) {
return $history[$offset][$key];
} else {
return $this->config->item('base_url');
}
}
}
And then to retrieve the URL of the last page visited you call
$this->session->last_page();
And you can increase the offset and type of information returned etc too
$this->session->last_page(1); // page before last
$this->session->last_page(2); // 3 pages ago
The function doesn't add pages called using Ajax to the tracker but you can easily remove the if( !IS_AJAX ) bit to make it do so.
Edit:
If you run to the error Undefined constant IS_AJAX, assumed IS_AJAX
add the line below to /application/config/constants.php
define('IS_AJAX', isset($_SERVER['HTTP_X_REQUESTED_WITH']) && strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) == 'xmlhttprequest');
There are two ways to solve your problem: First you could place a link that is using the javascript back-function onclick, like this ...
go back
... or you always save the current full page url into a cookie and use that for generating the back link - a helper could look like this (not tested) ...
/**
* save url to cookie
*/
if(!function_exists('urlhistory_save'))
{
function urlhistory_save()
{
$CI =& get_instance();
$CI->load->library('session');
$array = array(
'oldUrl' = $CI->session->userdata('newurl'),
'newurl' = $CI->uri->uri_string()
);
$CI->session->set_userdata($array);
}
}
/**
* get old url from cookie
*/
if(!function_exists('urlhistory_get'))
{
function urlhistory_get()
{
$CI =& get_instance();
$CI->load->library('session');
return $CI->session->userdata('oldurl');
}
}
In your controller you would use urlhistory_save() to save the current URL and in the view youd could use urlhistory_get() to retreive the old address like this:
<a href="<?php echo base_url().urlhistory_get(); ?>go back</a>
The most simplest way to redirect to your previous page , try this it work for me
redirect($this->agent->referrer());
you need to import user_agent library too $this->load->library('user_agent');
You can create a Session to go to back page as:
$this->session->set_userdata('ses_back_jobs','controller
name'.array_pop(explode('controller name',$this->input->server('REQUEST_URI'),2))); //Back page
Then if u want to redirect to some page use it:
redirect($this->session->userdata('ses_back_jobs'));
or use it to the anchor.