SQL PHP : How to SELECT and fetch like this? - php

Question

Hello I'm know how to use basic SQL about select, join, fetch
but don't have idea how fetch like this to my website (see screenshot)
From screenshot It has column room_number too.
<table>
<tr>
<td>room no.</td>
<td>room name</td>
</tr>
<?php
$sql = SELECT * FROM si_room;
$query = $db->query($sql);
while($row = $query->fetch(PDO::FETCH_ASSOC))
{ ?>
<tr>
<td><?php echo ????? ; ?></td>
<td><?php echo ?????; ?></td>
</tr>
<?php } ?>
</table>
UPDATE :
I try with this code
<?php
$sql = "SELECT * FROM si_room";
$querymain = $db->query($sql)->fetchAll(PDO::FETCH_GROUP);
?>
<table>
<tr>
<td>room no.</td>
<td>room_name</td>
</tr>
<?php
foreach ($querymain as $list_id => $list_data)
{
echo "<tr>";
echo "<td> floor ".$list_data[0]['room_floor']."<br>";
foreach ($list_data as $row)
{
echo $row['room_no']."</td>";
echo "<td>".$row['room_name']."</td>";
}
} ?>
</tr>
</table>
but the result is
floor 2
201 | ROOM A
floor 2
202 | ROOM B
floor 3
301 | ROOM E
floor 3
302 | ROOM F
That's not I want.

Answer 1

Luckily you are using PDO which already has this functionality for you, that can do exactly what you want - group the data based on some column.
PDO can group results into the nested arrays, based on the first field selected. So you need to list your list id as the first field in the field list , and then get your rows using fetchAll() with aforementioned fetch mode:
$sql = "select room_floor, room_name, room_no from si_room";
$building = $dbh->query($sql)->fetchAll(PDO::FETCH_GROUP);
and now you get a neat nested array where your rows are grouped by list id!
To make it output neatly you have to use two nested foreach operators
foreach ($building as $floor_no => $rooms)
{
echo $floor_no."\n";
foreach ($rooms as $row)
{
echo $row['room_name']."\n";
}
}