PHP - SUM number according to item name - php

Question

Am new in PHP, I need help in my scripts since I don't get preferred answer.
I have a "bills" table which store information's of sales items. as folows
id | gid | drinks | no_drinks | servicetime | date
1 2 Orange 4 1 2018-08-16
2 2 Orange 2 1 2018-08-16
3 2 Orange 3 1 2018-08-16
Below file (BillsController.php) query gid, servicetime and date, and the query is equal to true.
BillsController.php
$bi = Barz::whereRaw('gid=? and servicetime=? and date=?', array($gid, $t,date('Y-m-d')))->get();
return View::make('bills.show', compact('bi'));
Below is "show.php" file which display the information's from Database. I will just shows you few things in it.
<?php
$foods = array();
foreach($bi as $row){
$foods[] = $row->drinks;
$idadi[] = $row->no_drinks;
$unique = array_keys(array_count_values($foods));
$l = count($unique);
}
$newarr = array();
foreach ($unique as $key => $value) {
array_push($newarr, $value);
}
?>
<table class="table table-bordered" id="gt">
<tr style="background-color: #f5f5f5">
<th>Drink</th>
<th>Qty...sx</th>
<th>Time</th>
<th>#cost</th>
<th>Total#</th>
<th>
<select class="form-control active" id="tserv">
<option value="{{$row->servicetime}}">{{Bill::tm($row->servicetime)}}</option>
<select>
</th>
</tr>
<?php $total = 0; ?>
#for($i=0; $i < $l; $i++)
<tr>
<td>{{$newarr[$i]}}</td>
<td>{{$idadi[$i]}}</td> // Only problem is here
<td>{{Bill::appears($newarr[$i], $foods)}}</td>
<td>{{Bar::where('name', $newarr[$i])->first()->cost}} /=</td>
<td>{{($idadi[$i])*(Bar::where('name', $unique[$i])->first()->cost)}}/= </td>
</tr>
<?php $total = $total + (($idadi[$i])*(Bar::where('name', $newarr[$i])->first()->cost)); ?>
#endfor
<tr style="background-color: #f5f5f5">
<td ></td>
<td ></td>
<td></td>
<td><b>Total</b></td>
<td id="ttl">
{{$total}} /=
</td>
</tr>
When I run above query, I get 4 from ("{{$idadi[$i]}}"), which means it take only first row, and the rest is not selected. I want it to do like this (4+2+3) = 9.

Answer 1

To add columns together;
SELECT col1, col2, col3, (col1+col2+col3) AS Total FROM
To add rows together, use the SUM()
Aggregate below;
SELECT userid, SUM(col1) AS col1_total, SUM(col2) AS col2_total FROM table GROUP BY userid

Answer 2

Try this out :
select SUM(no_drinks) no_drinks from table_name GROUP BY drinks