Get last two items of json_decode results with PHP - php

Question

The following code works and pulls all the images in from the json file.
$content = file_get_contents('URL');
$json = json_decode($content, true);
foreach($json['format'] as $item) {
echo '<img src="' . $item['picture'] . '">';
}
Is there a way that I can have it only grab the last two pictures.

Answer 1

Yes, there is a way.
$result = array_slice($json['format'], -2);
Have a try.

Answer 2

Use this:
$numItems = count(foreach($json['format']);
$i = 0;
foreach($json['format'] as $item) {
if(++$i === $numItems-1) {
result1 = $json['format'][$i]
echo "first picture!";
} if(++$i === $numItems) {
result2 = $json['format'][$i]
echo "second picture!";
}
}
And result1 and result2 is your pictures

Answer 3

You can reverse the order of the array, run it backwards in your foreach loop, grab the first two then break.
$reversed = array_reverse($json);
$counter = 0;
foreach ($reversed['format'] as $item) {
if ($counter == 2) {
break;
}
//your echo image code
++$counter;
}

Answer 4

My version using array_pop:
$content = file_get_contents('URL');
$json = json_decode($content, true);
// take last element of array, array reduces by 1 element
$last = array_pop($json['format']);
print_r($last);
// take last element of array again, array reduces by 1 element
$last = array_pop($json['format']);
print_r($last);
// Beware - using `$json['format']` later means that
// you use array without two last elements