Here is my sample code:
$issue_id = $_POST['issue_id'];
if(!empty($issue_id)){
echo 'true';
}
else{
echo 'false';
}
If I pass 0 to $_POST['issue_id'] by form submitting then it echo false. Which I want is: Condition will be true if the following conditions are fulfilled:
1. true when I pass any value having 0.
2. false when I don't pass any value. i.e: $_POST['issue_id'] is undefined.
I also tried this:
if(!isset($issue_id)){
echo 'true';
}
else{
echo 'false';
}
if(!empty($issue_id) || $issue==0){
echo 'true';
}
else{
echo 'false';
}
The last one is okay, meaning if I pass any value having ZERO then it will echo true. But it will also echo true if I don't pass any value. Any idea?
The last is okay, meaning if I pass any value having ZERO then it echo true. But it also echo true if I don't pass any value. Any idea?
if (isset($_POST["issue_id"]) && $_POST["issue_id"] !== "") {
}
please notice I used !== not !=. this is why:
0 == "" // true
0 === "" // false
See more at http://php.net/manual/en/language.operators.comparison.php
also if you are expecting number you can use
if (isset($_POST["issue_id"]) && is_numeric($_POST["issue_id"])) {
}
since is_numeric("") returns false
http://php.net/manual/en/function.is-numeric.php
Alternatively if you expect number good option is filter_var
if (isset($_POST["issue_id"]) {
$issue_id = filter_var($_POST["issue_id"], FILTER_VALIDATE_INT);
if ($issue_id !== false) {
}
}
since filter_var("", FILTER_VALIDATE_INT) will returns false and filter_var("0", FILTER_VALIDATE_INT) will return (int) 0
http://php.net/manual/en/function.filter-var.php
if(isset($_POST['issue_id'])) {
if($_POST['issue_id'] == 0) {
echo "true";
}
else {
echo "false";
}
}
When you get data from a form, remember:
All text boxes, whether input or textarea will come as strings. That includes empty text boxes, and text boxes which contain numbers.
All selected buttons will have a value, but buttons which are not selected will not be present at all. This includes radio buttons, check boxes and actual buttons.
This means that $_POST['issue_id'] will be the string '0', which is actually truthy.
If you need it to be an integer, use something like: $issue_id=intval($_POST['issue_id']);
#Abdus Sattar Bhuiyan you can also full fill your two condition like below one:
<?php
$_POST["issue_id"] = "0";
$issue_id = isset($_POST['issue_id']) ? (!empty($_POST['issue_id']) || $_POST['issue_id'] === 0 || $_POST['issue_id'] === "0") ? true : false : false;
if($issue_id){
echo 'true';
}
else{
echo 'false';
}
Related
I am checking if two values are null. If both are null I want to return false, if either or both are not null, I want to return true.
My current code returns true only when both are not null but I want it to return true when either or not null.
// check if both null
if (!isset($myarray['dataone'], $myarray['datatwo']))
{
echo 'false';
);
} else {
echo 'true';
);
}
return $emptytabs;
For that you can use relational operators. AND (&&) OR (||)
By using AND (&&) operators.
if ( (!isset($myarray['dataone']) || (!isset$myarray['datatwo'] ))
{
echo 'false';
}
else
{
echo 'true';
}
By using OR ( || ) operators.
if (isset($myarray['dataone'] && isset$myarray['datatwo'])
{
echo 'false';
}
else
{
echo 'true';
}
// check if both null
if ( !isset($myarray['dataone']) && !isset($myarray['datatwo'])) {
echo 'false';
} else {
echo 'true';
}
// check if one or both are null
if ( !isset($myarray['dataone']) || !isset($myarray['datatwo'])) {
echo 'false';
} else {
echo 'true';
}
// check if both null
if ( !isset($myarray['dataone'], $myarray['datatwo']) )
{
echo 'false';
} else {
echo 'true';
}
return $emptytabs;
this approach you provided is totally true , but it only return true if all the provided parameters are set according to php documentations .
so your code should works correctly . except you have unwanted parentheses that should deleted
The simplest way is to use the OR (||) operator. You want to show 'true' if one thing is set OR another thing is set. Just say that with code.
if ( isset($myarray['dataone']) || isset($myarray['datatwo']) ) {
echo 'true';
} else {
echo 'false';
}
Using the AND operator adds pointless complexity by checking that both of the two things are not set in order for it to show 'false'. That's not an intuitive way to think about it, so it doesn't make sense to write the code that way.
DISCLAIMER: This answer is opinionated.
I need to match two string using PHP. Here is my code:
<?php
$fistno="9937229853";
$secondno="+919937229853";
?>
Here I need the value in $fistno is present in $secondno or not. If the value in $fistno is present in $secondno it will return true. In this case 9937229853 is present in $secondno so it should return true.
Use strpos, see here.
if (strpos($mystring, $findme) === false) {
return false;
}
return true;
Be careful and use === false as the string position in the other string can be 0 which when using == will evaluate to false when it is actually true.
Use strpos
if (strpos($fistno, $secondno) !== false) {
echo 'true';
}
You need to use == not just =
$check = 'this is a string 111';
if (strpos($mystring, $findme) === false) {
echo 'perfect match';
}
else {
echo 'it did not match up';
}
= will assign the variable.
== will do a loose comparison.
=== will do a strict comparison.
I have a variable that can be int or bool, this is because the db from where im querying it change the variable type at some point from bool to int, where now 1 is true and 0 is false.
Since php is "delicate" with the '===' i like to ask if this is the correct why to know if that var is true:
if($wallet->locked === 1 || $wallet->locked === true)
I think in this way im asking for: is the type is int and one? or is the var type bool and true?
How will you approach this problem?
Your code is the correct way.
It indeed checks if the type is integer and the value is 1, or the type is boolean and the value is true.
The expression ($x === 1 || $x === true) will be false in every other case.
If you know your variable is an integer or boolean already, and you're okay with all integers other than 0 evaluating to true, then you can just use:
if($wallet->locked) {
Which will be true whenever the above expression is, but also for values like -1, 2, 1000 or any other non-zero integer.
$wallet->locked = 1;
if($wallet->locked === true){
echo 'true';
}else{
echo 'false';
}
will produce:
false
and
$wallet->locked = 1;
if($wallet->locked == true){
echo 'true';
}else{
echo 'false';
}
will produce:
true
Let me know if that helps!
Your solution seems to be perfect, but You can also use gettype. After that You can check the return value with "integer" or "boolean". Depending on the result You can process the data the way You need it.
solution #1. If $wallet has the value of either false or 0, then PHP will not bother to check its type (because && operator is short-circuit in PHP):
$wallet = true;
//$wallet = 1;
if( $wallet && (gettype($wallet) == "integer" || gettype($wallet) == "boolean") )
{ echo "This value is either 'true and 1' OR it is '1 and an integer'"; }
else { echo "This value is not true"; }
solution #2 (depending on what You want to achieve):
$wallet = 0;
//$wallet = 1; // $wallet = 25;
//$wallet = true;
//$wallet = false;
if($wallet)
{ echo "This value is true"; }
else { echo "This value is not true"; }
I'm using a variable in Javascript which will be set via Php e.g. var usesInterview = <?php echo 1;?>
If not, then var usesInterview = <?php echo 0;?>
How best should I handle this in my code? There will be a If statement to check for the variable and determine the route to take.
I've tried using typeof() == 1 and when I set it to 0, it still carries out the routine as if it where 1.
Why not set it with javascript:
usesInterview = 1;
Even if you set it with PHP, you can check like this:
if (usesInterview === 1){
// variable is equal to 1
}
else if (usesInterview === 0){
// variable is equal to 0
}
Notice the === to check for both type as well as value. If you don't want to check for type, you need to use == like this:
if (usesInterview == 1){
// variable is equal to 1 or "1" or true
}
else if (usesInterview == 0){
// variable is equal to 0 or "0" or "" or false
}
You should avoid the later approach when you are sure about both type as well as value.
More Information:
http://w3schools.com/JS/js_comparisons.asp
There are so many ways you can do it... Ie
var usesInterview = <?php echo [0|1];?>
usesInterview ? goingTrueWay() : goingFalsegWay();
or
<?php echo [0|1];?> ? goingTrueWay() : goingFalseWay();
or something like this:
var waysCollection = {
0: function () {...} //routine for usesInterview == 0
1: function () {...} //routine for usesInterview == 1
}
waysCollection[<?php echo [0|1];?>]();
also you can use one of the early suggestion:
if (<?php echo [0|1];?>) {
// truthy branch
} else {
// falsy branch
}
BTW, if you want usesInterview to be a boolean, yes/no trigger, - use true/false not 0/1. Its easier to read and understand later. For ex
var usesInterview = <?php echo [false|true];?>
if (usesInterview) {
//do this if `true`
} else {
//do this if `false`
}
typeof will return the type of the value - "number" in this case. You're using a non-strict equality check (==) so "number" == 1 is true.
Just check the value, using type-strict equality operator (===):
if (usesInterview === 1) {
// do something
}
else if (usesInterview === 0) {
// do something else
}
Read more about JavaScript comparison operators at https://developer.mozilla.org/en/JavaScript/Reference/Operators/Comparison_Operators.
When usesInterview is 1 it's truthy. So it's as simple as:
if (usesInterview) {
// truthy branch
} else {
// falsy branch
}
if(0 == ('Pictures'))
{
echo 'true';
}
why it's giving me 'true' ?
Your string will be evaluated as an Integer, so becomes 0, use this : 0 === 'Pictures' that verifies identity (same value and same type)
Check PHP type comparison tables to understand how comparison operators behave in PHP.
In your case, 'Pictures' becomes "0" and therefore 0 = 0.
Let's check following example:
echo (int)'Pictures'; // 0 => 'Picture' as int
echo 0 == 'Pictures'; // 1 => true, 0 = 0
Use:
if (0 === 'Pictures')
{
echo 'true';
}
The === is strict type operator, it not only checks the value but the type as well.
Quick Test:
if(0 == 'Pictures')
{
echo 'true';
}
else
{
echo 'false';
}
outputs true but:
if(0 === 'Pictures')
{
echo 'true';
}
else
{
echo 'false';
}
outputs false