Check for multiple null isset values - php

Question

I am checking if two values are null. If both are null I want to return false, if either or both are not null, I want to return true.
My current code returns true only when both are not null but I want it to return true when either or not null.
// check if both null
if (!isset($myarray['dataone'], $myarray['datatwo']))
{
echo 'false';
);
} else {
echo 'true';
);
}
return $emptytabs;

Answer 1

For that you can use relational operators. AND (&&) OR (||)
By using AND (&&) operators.
if ( (!isset($myarray['dataone']) || (!isset$myarray['datatwo'] ))
{
echo 'false';
}
else
{
echo 'true';
}
By using OR ( || ) operators.
if (isset($myarray['dataone'] && isset$myarray['datatwo'])
{
echo 'false';
}
else
{
echo 'true';
}

Answer 2

// check if both null
if ( !isset($myarray['dataone']) && !isset($myarray['datatwo'])) {
echo 'false';
} else {
echo 'true';
}
// check if one or both are null
if ( !isset($myarray['dataone']) || !isset($myarray['datatwo'])) {
echo 'false';
} else {
echo 'true';
}

Answer 3

// check if both null
if ( !isset($myarray['dataone'], $myarray['datatwo']) )
{
echo 'false';
} else {
echo 'true';
}
return $emptytabs;
this approach you provided is totally true , but it only return true if all the provided parameters are set according to php documentations .
so your code should works correctly . except you have unwanted parentheses that should deleted

Answer 4

The simplest way is to use the OR (||) operator. You want to show 'true' if one thing is set OR another thing is set. Just say that with code.
if ( isset($myarray['dataone']) || isset($myarray['datatwo']) ) {
echo 'true';
} else {
echo 'false';
}
Using the AND operator adds pointless complexity by checking that both of the two things are not set in order for it to show 'false'. That's not an intuitive way to think about it, so it doesn't make sense to write the code that way.
DISCLAIMER: This answer is opinionated.