How to do match exactly the content using PHP? - php

I need to match two string using PHP. Here is my code:
<?php
$fistno="9937229853";
$secondno="+919937229853";
?>
Here I need the value in $fistno is present in $secondno or not. If the value in $fistno is present in $secondno it will return true. In this case 9937229853 is present in $secondno so it should return true.

Use strpos, see here.
if (strpos($mystring, $findme) === false) {
return false;
}
return true;
Be careful and use === false as the string position in the other string can be 0 which when using == will evaluate to false when it is actually true.

Use strpos
if (strpos($fistno, $secondno) !== false) {
echo 'true';
}

You need to use == not just =
$check = 'this is a string 111';
if (strpos($mystring, $findme) === false) {
echo 'perfect match';
}
else {
echo 'it did not match up';
}
= will assign the variable.
== will do a loose comparison.
=== will do a strict comparison.

Related

How to generate dynamic IF statement

I have array look like this.
$setLogic = array(array("Conj"=>null,"Topic"=>True),array("Conj"=>"Or","Topic"=>True),array("Conj"=>"Or","Topic"=>false),
I try to build a IF statement with the dynamicly with this way.
foreach($setLogic as $value){
echo $value['Conj'].(int)$value['Topic'];
if($value['Conj'].(int)$value['Topic'] == true){
$getBoolean[] = true;
}
else{
$getBoolean[] = false;
}
I just need something like this.
(true or true or false) and return true or false
I found my answer with my self.
It's look like this.
$abc= '';
foreach($setLogic2 as $key => $value){
$abc.= $value['Conj'].' '.(int)$value['Topic'].' ';
}
//$abc = "0 And 1 And 1";
if(eval("return $abc;") == true) {
echo 'true boolean';
}
else if(eval("return $abc;") == false){
echo 'false boolean';
}
else{
echo 'none';
}
Ok i will re formulate my answer....
You want to dynamically evaluate an array which contains for each subarray
* a verb : "and" or "or"
* a value "true or "false"
Quicker and most dirty way is to use eval().
* build your conditions as a string (replace "and" by "&&" and "or" by "||"
'true || true && false'
then put the result in a variable and evaluate
eval('$result = (true || true && false);');
var_dump($result);
This works for sure...

I am not understanding why this is happening with empty php variables

I try to do this:
if ($var !== ""){
$message = "whatever";
}
But end up having to do this:
if ($var == ""){
//do nothing
} else {
$message = "whatever";
}
Why does that happen? Shouldn't both of those mean the same thing?
!= and == are opposites (non-strict comparison operators).
!== and === are opposites (strict comparison operators, where the value must match what you are comparing exactly).
If you use != instead of !==, your code should work. But:
You should understand what the actual value of your variable is - it's not an empty string. You can use print_r( $var ); to see it.
It's better to use the strict comparison operators === and !==, because they have well-defined behavior that is easier to remember and debug.
As $var is really string just use:
if ($var){//any non-empty string will work fine as it will be casted to boolean automatically
$message = "whatever";
}
$var could be != '' but not= '' eg .. null
if ($var == ""){
//do nothing
} else {
if (is_null($var) {
$message ='NULL';
} else {
$message = "whatever";
}
}

How to treat zero values as true using php?

Here is my sample code:
$issue_id = $_POST['issue_id'];
if(!empty($issue_id)){
echo 'true';
}
else{
echo 'false';
}
If I pass 0 to $_POST['issue_id'] by form submitting then it echo false. Which I want is: Condition will be true if the following conditions are fulfilled:
1. true when I pass any value having 0.
2. false when I don't pass any value. i.e: $_POST['issue_id'] is undefined.
I also tried this:
if(!isset($issue_id)){
echo 'true';
}
else{
echo 'false';
}
if(!empty($issue_id) || $issue==0){
echo 'true';
}
else{
echo 'false';
}
The last one is okay, meaning if I pass any value having ZERO then it will echo true. But it will also echo true if I don't pass any value. Any idea?
The last is okay, meaning if I pass any value having ZERO then it echo true. But it also echo true if I don't pass any value. Any idea?
if (isset($_POST["issue_id"]) && $_POST["issue_id"] !== "") {
}
please notice I used !== not !=. this is why:
0 == "" // true
0 === "" // false
See more at http://php.net/manual/en/language.operators.comparison.php
also if you are expecting number you can use
if (isset($_POST["issue_id"]) && is_numeric($_POST["issue_id"])) {
}
since is_numeric("") returns false
http://php.net/manual/en/function.is-numeric.php
Alternatively if you expect number good option is filter_var
if (isset($_POST["issue_id"]) {
$issue_id = filter_var($_POST["issue_id"], FILTER_VALIDATE_INT);
if ($issue_id !== false) {
}
}
since filter_var("", FILTER_VALIDATE_INT) will returns false and filter_var("0", FILTER_VALIDATE_INT) will return (int) 0
http://php.net/manual/en/function.filter-var.php
if(isset($_POST['issue_id'])) {
if($_POST['issue_id'] == 0) {
echo "true";
}
else {
echo "false";
}
}
When you get data from a form, remember:
All text boxes, whether input or textarea will come as strings. That includes empty text boxes, and text boxes which contain numbers.
All selected buttons will have a value, but buttons which are not selected will not be present at all. This includes radio buttons, check boxes and actual buttons.
This means that $_POST['issue_id'] will be the string '0', which is actually truthy.
If you need it to be an integer, use something like: $issue_id=intval($_POST['issue_id']);
#Abdus Sattar Bhuiyan you can also full fill your two condition like below one:
<?php
$_POST["issue_id"] = "0";
$issue_id = isset($_POST['issue_id']) ? (!empty($_POST['issue_id']) || $_POST['issue_id'] === 0 || $_POST['issue_id'] === "0") ? true : false : false;
if($issue_id){
echo 'true';
}
else{
echo 'false';
}

How to check the value and type of a unknown var

I have a variable that can be int or bool, this is because the db from where im querying it change the variable type at some point from bool to int, where now 1 is true and 0 is false.
Since php is "delicate" with the '===' i like to ask if this is the correct why to know if that var is true:
if($wallet->locked === 1 || $wallet->locked === true)
I think in this way im asking for: is the type is int and one? or is the var type bool and true?
How will you approach this problem?
Your code is the correct way.
It indeed checks if the type is integer and the value is 1, or the type is boolean and the value is true.
The expression ($x === 1 || $x === true) will be false in every other case.
If you know your variable is an integer or boolean already, and you're okay with all integers other than 0 evaluating to true, then you can just use:
if($wallet->locked) {
Which will be true whenever the above expression is, but also for values like -1, 2, 1000 or any other non-zero integer.
$wallet->locked = 1;
if($wallet->locked === true){
echo 'true';
}else{
echo 'false';
}
will produce:
false
and
$wallet->locked = 1;
if($wallet->locked == true){
echo 'true';
}else{
echo 'false';
}
will produce:
true
Let me know if that helps!
Your solution seems to be perfect, but You can also use gettype. After that You can check the return value with "integer" or "boolean". Depending on the result You can process the data the way You need it.
solution #1. If $wallet has the value of either false or 0, then PHP will not bother to check its type (because && operator is short-circuit in PHP):
$wallet = true;
//$wallet = 1;
if( $wallet && (gettype($wallet) == "integer" || gettype($wallet) == "boolean") )
{ echo "This value is either 'true and 1' OR it is '1 and an integer'"; }
else { echo "This value is not true"; }
solution #2 (depending on what You want to achieve):
$wallet = 0;
//$wallet = 1; // $wallet = 25;
//$wallet = true;
//$wallet = false;
if($wallet)
{ echo "This value is true"; }
else { echo "This value is not true"; }

PHP compare doubt

if(0 == ('Pictures'))
{
echo 'true';
}
why it's giving me 'true' ?
Your string will be evaluated as an Integer, so becomes 0, use this : 0 === 'Pictures' that verifies identity (same value and same type)
Check PHP type comparison tables to understand how comparison operators behave in PHP.
In your case, 'Pictures' becomes "0" and therefore 0 = 0.
Let's check following example:
echo (int)'Pictures'; // 0 => 'Picture' as int
echo 0 == 'Pictures'; // 1 => true, 0 = 0
Use:
if (0 === 'Pictures')
{
echo 'true';
}
The === is strict type operator, it not only checks the value but the type as well.
Quick Test:
if(0 == 'Pictures')
{
echo 'true';
}
else
{
echo 'false';
}
outputs true but:
if(0 === 'Pictures')
{
echo 'true';
}
else
{
echo 'false';
}
outputs false

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