Compare elements of two arrays php - php

Question

So I have two arrays:
$badwords = array('bad-word', 'some-racist-term', 'nasty', 'bad-language');
$inputphrases = array('this-is-sentence-with-bad-word', 'nothing-bad-here', 'more-clean-stuff', 'this-is-nasty', 'this-contains-some-racist-term', 'one-more-clean', 'clean-clean', 'contains-bad-language');
I need to compare elements of input phrases array with bad words array and output new array with phrases WITHOUT bad words like this:
$outputarray = array('nothing-bad-here', 'more-clean-stuff','one-more-clean', 'clean-clean');
I tried doing this with two foreach loops but it gives me opposite result, aka it outputs phrases WITH bad words.
Here is code I tried that outputs opposite result:
function letsCompare($inputphrases, $badwords)
{
foreach ($inputphrases as $inputphrase) {
foreach ($badwords as $badword) {
if (strpos(strtolower(str_replace('-', '', $inputphrase)), strtolower(str_replace('-', '', $badword))) !== false) {
$result[] = ($inputphrase);
}
}
}
return $result;
}
$result = letsCompare($inputphrases, $badwords);
print_r($result);

Answer 1

this is not a clean solution, but hope, you'll got what is going on. do not hesitate to ask for clearence. repl.it link
$inputphrases = array('this-is-sentence-with-bad-word', 'nothing-bad-here', 'more-clean-stuff', 'this-is-nasty', 'this-contains-some-racist-term', 'one-more-clean', 'clean-clean', 'contains-bad-language');
$new_arr = array_filter($inputphrases, function($phrase) {
$badwords = array('bad-word', 'some-racist-term', 'nasty', 'bad-language');
$c = count($badwords);
for($i=0; $i<$c; $i++) {
if(strpos($phrase, $badwords[$i]) !== false){
return false;
}
}
return true;
});
print_r($new_arr);