If GET query contains keywords from array - php

Question

I want to make a PHP script that takes a PHP GET variable $_GET[q] made up of many different words or terms and checks to see if it contains any "keywords" that are stored in an array. An example of this would be It could look like "What time is it in San Francisco". I would want the script to pick up on "time" and "san francisco" as an example. I have played about with using
if(stripos($_GET[q],'keyword1','keyword2'))
but haven't had much luck.
Does anyone know how I could do this?
I hope everyone can understand what I am trying to describe.

Answer 1

You can make an array of keywords, then loop though until you find a match.
$array = array('keyword1', 'keyword2');
$found = false;
foreach($array as $x){
if(stripos($_GET['q'], $x) !== false){
$found = true;
break;
}
}
if($found){
}
UPDATE: If you want to match ALL keywords, you can do this instead:
$array = array('keyword1', 'keyword2');
$found = true;
foreach($array as $x){
$found &= stripos($_GET['q'], $x) !== false;
}
if($found){
}
DEMO: http://codepad.org/LaEX6m67
UPDATE 2: Because I'm crazy and like one-liners, you can do this in PHP 5.3+:
$array = array('keyword1', 'keyword2');
$val = $_GET['q'];
$found = array_reduce($array, function($x, $v) use($val){
return $x && stripos($val, $v) !== false;
}, true);
if($found){
}
DEMO: http://codepad.viper-7.com/Y48sHR

Answer 2

foreach($arr as $value){
if(stripos($_GET[q],$value){
do stuff
}
}

Answer 3

Use in_array function:
// assuming $arr is your array of keywords
if (in_array($_GET['q'], $arr))
echo "found a match\n";
EDIT: Based on your comments here is the code you can use, that works without any loop:
$arr = array('keyword1', 'keyword2', 'keyword3');
$brr = array_map(create_function('$m', 'return "/\b" . $m . "\b/";'), $arr);
if ($_GET['q'] !== preg_replace($brr, '', $_GET['q']))
echo "found a match\n";
else
echo "didn't find a match\n";