Echoing matched data from 2 arrays with php - php

Question

I am trying to compare the contents of 2 arrays
<?php
$badwords = array('badword1','badword2','badword3');
$domains = array('domainword1.com', 'word2domain.com', 'domain.com');
if (preg_match($badwords,$domains) { // searched and did not find if it works like this
- echo the $domains that matches the $badwords // this is what i don't know how to do
}
It should echo in this case:
Matched domains are:
domainword1.com
word2domain.com
in new rows.
How am i suppose to do this?

Answer 1

I really don't know why you need regex in this case. Secondly, as Jim mentioned What counts as a match in this case? Well that's the thing.
You need to rewrite your $badwords array from
$badwords = array('badword1','badword2','badword3');
to
$badwords = array('word1','word2','word3');
Using the below code you get the desired output.
<?php
$badwords = array('word1','word2','word3');
$domains = array('domainword1.com', 'word2domain.com', 'domain.com');
$newarr = array();
foreach($badwords as $k=>$v)
{
foreach($domains as $k1=>$v1)
{
if(strpos($v1,$v)!==false)
{
array_push($newarr,$v1);
}
}
}
print_r($newarr);
OUTPUT:
Array
(
[0] => domainword1.com
[1] => word2domain.com
)

Answer 2

You can't use preg_match like this if you need to match any of $badwords to any of $domains.
Instead you should do something like this:
<?php
$badwords = array('badword1', 'badword2', 'badword3', 'badword(\d+)');
$domains = array('domainword1.com', 'word2domain.com', 'domain.com', 'badword1.com', 'ohbadword123.com');
$badDomains = array_filter($domains, function($domain) use ($badwords) {
$found = false;
foreach ($badwords as $badword) {
// use this if you dont' need regular expressions:
// if (substr_count($domain, $badword)>0) {
// use this if you need them:
if (preg_match('/' . $badword . '/', $domain)) {
$found = true;
break;
}
}
return $found;
});
if (!empty($badDomains)) {
echo "Domains with bad words:\n - " . join("\n - ", $badDomains);
}