Update values in sql when the data is being printed using while - php

Question

The form is used so that the method post could be used whenever the button is clicked, for more info go through the code.
<form action="<?php echo htmlspecialchars($_SERVER['PHP_SELF']); ?>" method="post">
<?php
//selecting rowa where the approve status is false or simple "0"
$result = mysqli_query($db,"SELECT id, rid, time, amount, transid, wallet FROM donations WHERE approve = 0");
//this button will be used later update the rows and set approve to true or "1"
$button = "<button type='submit' name='approve' class='btn btn-success' role='button'>" . "APPROVE" . "</button>";
echo "<table class='table'>
<tr>
<th>ID</th>
<th>RID</th>
<th>TIME</th>
<th>AMOUNT</th>
<th>TRANS HASH</th>
<th>WALLET</th>
<th>APPROVE</th>
</tr>";
//printing all the values where approve = '0'
while($row = mysqli_fetch_array($result, MYSQLI_ASSOC)){
echo "<tr>";
echo "<td class='col-sm-1'>" . $row['id'] . "</td>";
echo "<td class='col-sm-1'>" . $row['rid'] . "</td>";
echo "<td class='col-sm-2'>" . $row['time'] . "</td>";
echo "<td class='col-sm-1'>" . $row['amount'] . "</td>";
echo "<td class='col-sm-3'>" . $row['transid'] . "</td>";
echo "<td class='col-sm-3'>" . $row['wallet'] . "</td>";
echo "<td class='col-sm-1'>" . $button . "</td>";
echo "</tr>";
}echo "</table>";
//when the button is clicked, the method 'post' is invoked and the value is updated
if($_SERVER["REQUEST_METHOD"] == "POST"){
$id = $row['id'];
$approve = mysqli_query($db,"UPDATE `donations` SET approve = 1 WHERE approve = 0 and id = '$id'");
}
?>
The problem here is that I want a button for each row and each should be updated individually when that row's button is clicked.

Answer 1

1st : Change your code order . update part should be in page top.Because you need to update if it's submit .then only you need to fetch data from database . In your order your fetching the data and showing to user then updating at last . it should not be like this.
2nd : Just pass the row id as submit button value like this and it should be inside the while loop .
$button = "<button type='submit' name='approve' value='".$row["id"]."' class='btn btn-success' role='button'>" . "APPROVE" . "</button>";
3rd : On submit you will get the row id in $_POST['approve']
<?php
if($_SERVER["REQUEST_METHOD"] == "POST"){
$id = $_POST['approve'];
$approve = mysqli_query($db,"UPDATE `donations` SET approve = 1 WHERE approve = 0 and id =$id");
}
?>
Note : The above code should be on page top .
Update 1 : The code order should be like this
<?php
//when the button is clicked, the method 'post' is invoked and the value is updated
if($_SERVER["REQUEST_METHOD"] == "POST"){
$id = $_POST['approve'];
$approve = mysqli_query($db,"UPDATE `donations` SET approve = 1 WHERE approve = 0 and id =$id");
}
?>
<form action="<?php echo htmlspecialchars($_SERVER['PHP_SELF']); ?>" method="post">
<?php
//selecting rowa where the approve status is false or simple "0"
$result = mysqli_query($db,"SELECT id, rid, time, amount, transid, wallet FROM donations WHERE approve = 0");
//this button will be used later update the rows and set approve to true or "1"
echo "<table class='table'>
<tr>
<th>ID</th>
<th>RID</th>
<th>TIME</th>
<th>AMOUNT</th>
<th>TRANS HASH</th>
<th>WALLET</th>
<th>APPROVE</th>
</tr>";
//printing all the values where approve = '0'
while($row = mysqli_fetch_array($result, MYSQLI_ASSOC)){
$button = "<button type='submit' name='approve' value='".$row["id"]."' class='btn btn-success' role='button'>" . "APPROVE" . "</button>";
echo "<tr>";
echo "<td class='col-sm-1'>" . $row['id'] . "</td>";
echo "<td class='col-sm-1'>" . $row['rid'] . "</td>";
echo "<td class='col-sm-2'>" . $row['time'] . "</td>";
echo "<td class='col-sm-1'>" . $row['amount'] . "</td>";
echo "<td class='col-sm-3'>" . $row['transid'] . "</td>";
echo "<td class='col-sm-3'>" . $row['wallet'] . "</td>";
echo "<td class='col-sm-1'>" . $button . "</td>";
echo "</tr>";
}echo "</table>";
?>
Update 2 : Try to use prepared statement to avoid sql injection