Delete button on PHP echo table not working - php

Question

Below is my code for a PHP echo delete that contains a delete button. When pressed I want that entry to be deleted from the database
$result = mysql_query("SELECT * ,CONCAT (HomeScore,'-',AwayScore) AS Score, CONCAT(Against) AS Game FROM Fixture WHERE TeamID='9' ORDER BY Date DESC");
echo "<table id='customers' border='1'>;
<tr>
<th>FixtureID</th>
<th>Competition</th>
<th>Match</th>
<th>Date</th>
<th>Time</th>
<th>Score</th>
<th>test</th>
</tr>";
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['FixtureID'] . "</td>";
echo "<td>" . $row['Competition'] . "</td>";
echo "<td>" . $row["Against"] . "</td>";
echo "<td>" . $row['Date'] . "</td>";
echo "<td>" . $row['Time'] . "</td>";
echo "<td>" . $row['Score'] . "</td>";
echo "<td><form method=post>
<input name=id type=hidden value='".$row['FixtureID']."';>
<input type=submit name=submit value=Delete>
</form></td>";
echo "</tr>";
echo "</tr>";
}
}
echo "</table>";
// delete record
if($_SERVER['REQUEST_METHOD'] == "POST")
{
if(isset($_POST['FixtureID']))
{
$id = FixtureID;
$sql = mysql_query("DELETE FROM Fixture WHERE FixtureID =$id");
if(!$sql)
{
echo ("Could not delete rows" .mysql_error());
}
}
}
How do I get this to work? Also FixtureID is stored as an integer in the database.

Answer 1

Try with these changes :
// delete record
if(isset($_POST['submit']) && isset($_POST['id']) && !empty($_POST['id'])) {
$id = $_POST['id'];
$sql = mysql_query("DELETE FROM Fixture WHERE FixtureID =$id");
if(!$sql) {
echo ("Could not delete rows" .mysql_error());
}
}
Edit :
// Delete record if ID submitted
if(isset($_POST['submit']) && isset($_POST['id']) && !empty($_POST['id'])) {
$id = $_POST['id'];
$sql = mysql_query("DELETE FROM Fixture WHERE FixtureID =$id");
if(!$sql) {
echo ("Could not delete rows" .mysql_error());
}
}
// Get datas from BDD
$result = mysql_query("SELECT * ,CONCAT (HomeScore,'-',AwayScore) AS Score, CONCAT(Against) AS Game FROM Fixture WHERE TeamID='9' ORDER BY Date DESC");
// Display data
echo "
<table id='customers' border='1'>
<tr>
<th>FixtureID</th>
<th>Competition</th>
<th>Match</th>
<th>Date</th>
<th>Time</th>
<th>Score</th>
<th>test</th>
</tr>";
// For each result
while($row = mysql_fetch_array($result)) {
echo "<tr>";
echo "<td>" . $row['FixtureID'] . "</td>";
echo "<td>" . $row['Competition'] . "</td>";
echo "<td>" . $row["Against"] . "</td>";
echo "<td>" . $row['Date'] . "</td>";
echo "<td>" . $row['Time'] . "</td>";
echo "<td>" . $row['Score'] . "</td>";
echo "<td><form method=post>
<input name=id type=hidden value='".$row['FixtureID']."';>
<input type=submit name=submit value=Delete>
</form></td>";
echo "</tr>";
echo "</tr>";
}
echo "</table>";

Answer 2

just try this
if(isset($_POST['submit']))
{
$id = $_POST['id']; // here you should use form post value
$sql = mysql_query("DELETE FROM Fixture WHERE FixtureID =$id");
if(!$sql)
{
echo ("Could not delete rows" .mysql_error());
}
}
}

Answer 3

$id value is not properly set
$id = $_POST['FixtureID'];