In PHP, I have an array which I created and usueally the value of that array are like ['a','b','c'], but I dont know why, my array is in this form : [['a'],['b'],['c']]
Here is my code :
<?php
$res1 = array();
$result1 = mysqli_query($con,$dfcv) ;
while($row2 = mysqli_fetch_array($result1)){
array_push($res1, array(
$row2['username2'])
);
}
echo json_encode($res1);
?>
Because you add the result into additional an array (...array(
$row2['username2'])...).
<?php
$res1 = array();
$result1 = mysqli_query($con,$dfcv) ;
while($row2 = mysqli_fetch_array($result1))
array_push($res1, $row2['username2']);
echo json_encode($res1);
?>
Your code should look like this:
<?php
$res1 = array();
$result1 = mysqli_query($con,$dfcv) ;
while($row2 = mysqli_fetch_array($result1)) {
array_push($res1, $row2['username2']);
}
echo json_encode($res1);
?>
You've put an extra array on $row2 when you were doing the array_push()
array_push($res1, array($row2['username2']));
Related
I have the following code:
<?php
if(isset($_POST['indexSearchSubmit']))
{
foreach($_POST['industryList'] as $selected)
{
$_POST['industryList'] = $selected;
$locationListResults = $_POST['locationList'];
$results = mysqli_query($con,"SELECT * FROM currentListings WHERE location = '$locationListResults' AND industry = '$selected'");
while($row = mysqli_fetch_array($results))
{
echo $row['industry'];
echo $row['location'];
echo $row['title'];
echo $row['description'];
}
}
mysqli_close($con);
}
?>
Could anyone tell me how I would go about storing the echo part into a variable so I can then display it as and where I want in other parts of the site?
If I remove the echo and instead store $row as a variable when I echo that variable it only outputs once and doesn't run the loop.
You should use mysqli_fetch_all for this. The result will be an array where each element is a row and each row is an associative array with the same keys as row in your example
$data = mysqli_fetch_all($result);
$data[0]["industry"]; //Data in the first row
You can then loop over $data to output it any place on your page.
put in array,
$list = array();
while($row = mysqli_fetch_array($results))
{
$list[] = $row;
}
you may try this
$arrayList = array();
while($row = mysqli_featch_array($results)){
$arrayList[] = $row;
}
print_r($arrayList);
Put all the values in an array
$rows = array();
$x = 0;
while($row = mysqli_fetch_array($results))
{
$rows[$x]['industry'] = $row['industry'];
$rows[$x]['location'] = $row['location'];
$rows[$x]['title'] = $row['title'];
$rows[$x]['description'] = $row['description'];
$x++;
}
return $rows;
Then you can use $rows as an array.
foreach($rows as $v){
echo $v['industry']." ".$v['location']."<br />";
echo $v['title']." ".$v['description']."<br />";
}
Sorry for the relatively newbie question.
Ive been stuck the past hour trying to figure out why the array named $propname does not want to print when i loop over it. Here follows my code
$result = mysql_query("SELECT * FROM `player_info` WHERE `position` = 'THP'") or die(mysql_error()) ;
while($row = mysql_fetch_array($result)) //create arrays
{
$id[] = $row['player_id'];
$propName[] = $row['name'];
$propLastName[]= $row['surname'];
}//end while
//create variables for looping
$x = sizeof($propName);
$index = 0;
while($index < $x) //print variables
{
echo $propName[$index];
$index ++;
}
Just simplify your code
$result = mysql_query("SELECT * FROM `player_info` WHERE `position` = 'THP'") or die(mysql_error()) ;
while($row = mysql_fetch_array($result)) //create arrays
{
echo $row['name'];
}
$result = mysql_query("SELECT * FROM `player_info` WHERE `position` = 'THP'") or die(mysql_error()) ;
while($row = mysql_fetch_assoc($result)) //create arrays
{
$id = $row['player_id'];
echo $propName = $row['name'];
$propLastName = $row['surname'];
}
i noticed that there are a lot of topics like this in stackoverflow, but the ones that i read are with just 1 variable, and i have two and i'm a little confuse.
so this is my code,
$query = mysql_query("SELECT Provider.provider_id, provider.company_name FROM Provider");
while($row = mysql_fetch_array($query)){
echo "'".$row['provider_id']."':'".$row['company_name']."',";
}
I am using this to generate javascript code for Jeditable.
I need to take out the last comma, so I can wrap up with the rest of the code...
I like to use an array:
$query = ...;
$out = Array();
while($row = mysql_fetch_assoc($query)) {
$out[] = "'".$row['provider_id']."':'".$row['company_name']."'";
}
echo implode(",",$out);
It looks like you're trying to output some kind of JSON though, so perhaps you could use:
$query = ...;
$out = Array();
while($row = mysql_fetch_assoc($query)) {
$out[$row['provider_id']] = $row['company_name'];
}
echo json_encode($out);
So i usually just stack things like this into an array and then implode:
$parts = array();
while($row = mysql_fetch_array($query)){
$parts[] = "'".$row['provider_id']."':'".$row['company_name']."'";
}
echo implode(',', $parts);
That said it looks like youre outputting the body of a JSON string. If so you shouldnt manually build it you should use json_encode instead.
$data = array();
while($row = mysql_fetch_array($query)){
$data[$row['provider_id']] = $row['company_name'];
}
echo json_encode($data);
$query = mysql_query("SELECT Provider.provider_id, provider.company_name FROM Provider");
$result = "";
while($row = mysql_fetch_array($query)){
$result .= "'".$row['provider_id']."':'".$row['company_name']."',";
}
$result = rtrim($result, ',');
OR
$query = mysql_query("SELECT Provider.provider_id, provider.company_name FROM Provider");
$result = array;
while($row = mysql_fetch_array($query)){
$result[] = "'".$row['provider_id']."':'".$row['company_name']."',";
}
$result = implode(',' $result);
OR
get count of records (mysql_num_rows($query)) and when you hit last row just do what you want
The query I have below will only show me one result even if there are multiple matching entries (completely or partially matching). How do I fix it so it will return all matching entries:
//$allowed is a variable from database.
$sql = "SELECT `users`.`full_name`, `taglines`.`name`, `users`.`user_id` FROM
`users` LEFT JOIN `taglines` ON `users`.`user_id` = `taglines`.`person_id`
WHERE ( `users`.`user_settings` = '$allowed' ) and ( `users`.`full_name`
LIKE '%$q%' ) LIMIT $startrow, 15";
$result = mysql_query($sql);
$query = mysql_query($sql) or die ("Error: ".mysql_error());
$num_rows1 = mysql_num_rows($result);
if ($result == "")
{
echo "";
}
echo "";
$rows = mysql_num_rows($result);
if($rows == 0)
{
}
elseif($rows > 0)
{
while($row = mysql_fetch_array($query))
{
$person = htmlspecialchars($row['full_name']);
}
}
}
print $person;
Because your overwriting $person on each iteration.
Hold it in a $person[] array if your expecting more then one. Then loop through it with a foreach loop when you intend to output.
Not related but your also querying twice, you only need 1 $result = mysql_query($sql);
Update (Simple Outputting Example):
<?php
$person=array();
while($row = mysql_fetch_array($query)){
$person[] = array('full_name'=>$row['full_name'],
'email'=>$row['email'],
'somthing_else1'=>$row['some_other_column']);
}
//Then when you want to output:
foreach($person as $value){
echo '<p>Name:'.htmlentities($value['full_name']).'</p>';
echo '<p>Eamil:'.htmlentities($value['email']).'</p>';
echo '<p>FooBar:'.htmlentities($value['somthing_else1']).'</p>';
}
?>
Or an alternative way to is to build your output within the loop using concatenation.
<?php
$person='';
while($row = mysql_fetch_array($query)){
$person .= '<p>Name:'.$row['full_name'].'</p>';
$person .= '<p>Email:'.$row['email'].'</p>';
}
echo $person;
?>
Or just echo it.
<?php
while($row = mysql_fetch_array($query)){
echo '<p>Name:'.$row['full_name'].'</p>';
echo '<p>Email:'.$row['email'].'</p>';
}
?>
I want to push key and value in array , but I can't
$con = mysqli_connect('localhost','root','','wp') or die (mysqli_error('Error:'));
$query = mysqli_query($con,'set names utf8')or die (mysql_error());
$qy = mysqli_query($con,"SELECT ID,post_title FROM wp_posts WHERE post_type='page' AND post_status='publish'")or die (mysql_error());
$arr = array();
while ($row = mysqli_fetch_array($qy)){
$id = "?page_id=".$row['ID'];
$title = $row['post_title'];
$arr[] = $id . "=>" . $title;
array_push($arr, "$id" => "$title");
}
plz help me ..
thanks ^_^
Here's what I would do instead:
$arr = array();
while ($row = mysqli_fetch_assoc($qy)){
$id = $row['ID'];
$arr[$id] = $row['post_title'];
}
And then when you need to print them:
foreach ($arr as $id => $title) {
echo "?page_id={$id}'>{$title}</a>";
// or whatever, depends on how you want to print it
}
Don't store unnecessary information (ie: ?page_id=) in arrays.
Do you want to do $arr[$id] = $title? Or do you want this:
if (!isSet($arr[$id])) {
$arr[$id] = array();
}
$arr[$id][] = $title;
The former will make it so that $arr contains $id=>$title. The latter will make it so that $arr contains $id=>array($title1,$title2,$title3) etc if there are multiples.