I want to push key and value in array , but I can't
$con = mysqli_connect('localhost','root','','wp') or die (mysqli_error('Error:'));
$query = mysqli_query($con,'set names utf8')or die (mysql_error());
$qy = mysqli_query($con,"SELECT ID,post_title FROM wp_posts WHERE post_type='page' AND post_status='publish'")or die (mysql_error());
$arr = array();
while ($row = mysqli_fetch_array($qy)){
$id = "?page_id=".$row['ID'];
$title = $row['post_title'];
$arr[] = $id . "=>" . $title;
array_push($arr, "$id" => "$title");
}
plz help me ..
thanks ^_^
Here's what I would do instead:
$arr = array();
while ($row = mysqli_fetch_assoc($qy)){
$id = $row['ID'];
$arr[$id] = $row['post_title'];
}
And then when you need to print them:
foreach ($arr as $id => $title) {
echo "?page_id={$id}'>{$title}</a>";
// or whatever, depends on how you want to print it
}
Don't store unnecessary information (ie: ?page_id=) in arrays.
Do you want to do $arr[$id] = $title? Or do you want this:
if (!isSet($arr[$id])) {
$arr[$id] = array();
}
$arr[$id][] = $title;
The former will make it so that $arr contains $id=>$title. The latter will make it so that $arr contains $id=>array($title1,$title2,$title3) etc if there are multiples.
Related
This shows all the elements from an array in a string but without a separator. I used ',' as a separator in this code. And it does not work. How can i separate them with separator.
$con = mysql_connect("localhost","root","");
if(!$con)
{
die("Database Connection failed.".mysql_error());
}
$db = mysql_select_db("test1",$con);
if(!$db)
{
die("Database selection failed.".mysql_error());
}
$query = "select * from menu limit 10";
$result = mysql_query($query,$con);
while($row = mysql_fetch_array($result))
{
$id = $row['id'];
//$menu_name = $row['m_name'];
//$menu_image = $row['m_image'];
$menu_name = array($row['m_name']);
$menu_image = array($row['m_image']);
echo implode(',',$menu_name);
//echo "<img src='images/$menu_image' style='height:200px;width:200px;'>";
}
if(!$result)
{
echo mysql_error;
}
?>
you are storing array into variable . so if you will use imploade on an variable it will not show the result so best way is to store your result into an array and then use implode .
Don't use depricated mysql_* function use mysqli_* or pdo
instead
$menu_image=array(); // start array to store
$menu_name=array();
while($row = mysql_fetch_array($result))
{
$id = $row['id'];
$menu_name[] = $row['m_name']; // store menu name
$menu_image[] = $row['m_image']; // store menu image
}
echo implode(',',$menu_name); // finaly use implode
You can try this:
$menu_name[];
$menu_image[];
while($row = mysql_fetch_array($result)) {
$id = $row['id'];
$menu_name[] = $row['m_name']; // I change your $menu_name into an array so that when you fetch $row['m_name'] it returns an array
$menu_image[] = $row['m_image']; //same thing
}
echo implode(',',$menu_name);
//echo "<img src='images/$menu_image' style='height:200px;width:200px;'>";
try this in place of your while loop
$menu_name = array();
$menu_image = array();
while($row = mysql_fetch_array($result))
{
$id = $row['id'];
$menu_name[] = $row['m_name'];
$menu_image[] = $row['m_image'];
}
echo implode(',',$menu_name);
At the moment I have this code looping through the whole results of a query:
$result = mysqli_query($con, $sql);
$data = array();
while($row = mysqli_fetch_array($result)) {
$name = $row ['name'];
$desc = $row ['description'];
$cat = $row ['category'];
$price = $row ['price'];
$quantity = $row ['quantity'];
$id = $row ['productID'];
$image = $row ['image'];
$arr = array();
$arr ["id"] = $id;
$arr ["name"] = $name;
$arr ["desc"] = $desc;
$arr ["cat"] = $cat;
$arr ["price"] = $price;
$arr ["quantity"] = $quantity;
$arr ["image"] = $image;
array_push($data, $arr);
}
echo json_encode($data);
I want to change this to only loop through a set amount of results. I have a variable further up the code called $amount which is the amount of results I would like.
I hear I should use mysql_result() and a for loop to count to $amount, but I'm not sure how my existing code will work with that set up! Suggestions please.
EDIT:
#Styphon Pointed out that I don't actually need to change my iteration code for this to be solved. Just needed to add a LIMIT to my SQL query.
$sql = "rest of query...
LIMIT $amount"; //This will limit it to whatever is $amount. Just make sure to have it on the end of your query.
$result = mysqli_query($con, $sql);
$data = array();
while($row = mysqli_fetch_array($result)) {
$arr = array();
$arr["id"] = $row['productID'];
$arr["name"] = $row['name'];
$arr["desc"] = $row['description'];
$arr["cat"] = $row['category'];
$arr["price"] = $row['price'];
$arr["quantity"] = $row['quantity'];
$arr["image"] = $row['image'];
array_push($data, $arr);
}
echo json_encode($data);
Solution is the same whether you use mysql_ or mysqli_ (but you should use mysqli or even pdo). It goes something along this lines:
$num = 0;
$amount = 10;
while ($f = mysql_fetch_array($q)) {
// your code;
$num++;
if ($num==$amount) break;
}
As you mentioned for loops, with for loop you might do something like this
for ($i=0;$i<$amount;$i++) {
$f = mysql_fetch_array($q);
//your code
}
Obviously you should adjust it to suit your needs.
SELECT * FROM tbl
LIMIT 0, $amount
This will limit your result to $amount.
i noticed that there are a lot of topics like this in stackoverflow, but the ones that i read are with just 1 variable, and i have two and i'm a little confuse.
so this is my code,
$query = mysql_query("SELECT Provider.provider_id, provider.company_name FROM Provider");
while($row = mysql_fetch_array($query)){
echo "'".$row['provider_id']."':'".$row['company_name']."',";
}
I am using this to generate javascript code for Jeditable.
I need to take out the last comma, so I can wrap up with the rest of the code...
I like to use an array:
$query = ...;
$out = Array();
while($row = mysql_fetch_assoc($query)) {
$out[] = "'".$row['provider_id']."':'".$row['company_name']."'";
}
echo implode(",",$out);
It looks like you're trying to output some kind of JSON though, so perhaps you could use:
$query = ...;
$out = Array();
while($row = mysql_fetch_assoc($query)) {
$out[$row['provider_id']] = $row['company_name'];
}
echo json_encode($out);
So i usually just stack things like this into an array and then implode:
$parts = array();
while($row = mysql_fetch_array($query)){
$parts[] = "'".$row['provider_id']."':'".$row['company_name']."'";
}
echo implode(',', $parts);
That said it looks like youre outputting the body of a JSON string. If so you shouldnt manually build it you should use json_encode instead.
$data = array();
while($row = mysql_fetch_array($query)){
$data[$row['provider_id']] = $row['company_name'];
}
echo json_encode($data);
$query = mysql_query("SELECT Provider.provider_id, provider.company_name FROM Provider");
$result = "";
while($row = mysql_fetch_array($query)){
$result .= "'".$row['provider_id']."':'".$row['company_name']."',";
}
$result = rtrim($result, ',');
OR
$query = mysql_query("SELECT Provider.provider_id, provider.company_name FROM Provider");
$result = array;
while($row = mysql_fetch_array($query)){
$result[] = "'".$row['provider_id']."':'".$row['company_name']."',";
}
$result = implode(',' $result);
OR
get count of records (mysql_num_rows($query)) and when you hit last row just do what you want
I'm trying to store the title(summary) and date(created) of an event in an array. But I think im missing something in my loop.
<?php
$summary = array();
$date = array();
mysql_connect('mysql.server', 'myUsername', 'myPass') or die('Could not connect: ' . mysql_error());
mysql_select_db("mxgsite") or die(mysql_error());
$query_summary = mysql_query('SELECT summary FROM event_info') or die(mysql_error());
$query_date = mysql_query('SELECT created FROM event_details') or die(mysql_error());
$row_summary = mysql_fetch_array($query_summary);
$row_date = mysql_fetch_array($query_date);
$i = 0;
while(($row1 = mysql_fetch_array($query_summary))) {
$row2 = mysql_fetch_array($query_date);
$summary[] = $row['summary'];
$date[] = $row['created'];
echo $summary[$i] . " " . $date[$i] . "<br ?>";
$i++;
}
I know i'm getting values because I can echo out 1 value, but if I want to put all the values in an array and try to echo out that array I keep getting blank values?
It seems to me like you are trying to do too many things here. Since the 2 sets of values are not being stored in a way where they are related/linked to each other, you might as well deal with them in separate while loops. Try something like this:
while ($row = mysql_fetch_array($query_summary)){
$summary[] = $row[0];
}
while ($row = mysql_fetch_array($query_date)){
$date[] = $row[0];
}
If you want to relate the tables, per the comments above, you can try something more like:
$result = mysql_query('SELECT a.eventid, a.summary, b.created
FROM event_info a
join event_details b
on a.eventid = b.eventid');
$events = array();
while ($row = mysql_fetch_array($result)){
$event = array();
foreach ($row as $key=>$value){
$event[$key]=$value;
}
$events[] = $event;
}
This is the function that im calling.
function GetSubmissions($coach){
$result = mysql_query("SELECT * FROM `ptable` WHERE coach = '$_SESSION[username]'") or trigger_error(mysql_error());
while($row = mysql_fetch_array($result)){
foreach($row AS $key => $value) { $row[$key] = stripslashes($value); }
$id = $row['id'];
$teampre = $row['team'];
$eventpre = $row['event'];
$statuspre = $row['status'];
$eventarray = DecodeEvent($eventpre);
$event = $eventarray[0];
$cat = $eventarray[1];
$subcat = $eventarray[2];
$division = $eventarray[3];
$type = $eventarray[4];
$teamarray = explode(",", $teampre);
foreach ($teamarray AS $tkey => $tvalue){
$result = mysql_query("SELECT * FROM `students` WHERE id = '$tvalue'") or trigger_error(mysql_error());
while($row = mysql_fetch_array($result)){
foreach($row AS $skey => $svalue) { $row[$skey] = stripslashes($svalue); }
$firstname = $row['firstname'];
$lastname = $row['lastname'];
$teamgo .= "$firstname $lastname<br/>";
}
}
$push .= "<div id=submission><div id=event>$event</div><div id=status>$statuspre</div><div id=subinfo>$cat $subcat $division $type</div><div id=team>$teamgo</div></div>";
}
return $push;
}
It works, except its only returning a single result. Ive made little tweaks here and there, but im not seeing any positive changes in the output. Any ideas where im going wrong?
You have nested $result variables. You should try to avoid using the same variable name twice. Renaming the second one inside your second foreach loop would probably do the trick.
You use the same $result for inner loop.