How to contain a while loop in a variable - php

Question

I have the following code:
<?php
if(isset($_POST['indexSearchSubmit']))
{
foreach($_POST['industryList'] as $selected)
{
$_POST['industryList'] = $selected;
$locationListResults = $_POST['locationList'];
$results = mysqli_query($con,"SELECT * FROM currentListings WHERE location = '$locationListResults' AND industry = '$selected'");
while($row = mysqli_fetch_array($results))
{
echo $row['industry'];
echo $row['location'];
echo $row['title'];
echo $row['description'];
}
}
mysqli_close($con);
}
?>
Could anyone tell me how I would go about storing the echo part into a variable so I can then display it as and where I want in other parts of the site?
If I remove the echo and instead store $row as a variable when I echo that variable it only outputs once and doesn't run the loop.

Answer 1

You should use mysqli_fetch_all for this. The result will be an array where each element is a row and each row is an associative array with the same keys as row in your example
$data = mysqli_fetch_all($result);
$data[0]["industry"]; //Data in the first row
You can then loop over $data to output it any place on your page.

Answer 2

put in array,
$list = array();
while($row = mysqli_fetch_array($results))
{
$list[] = $row;
}

Answer 3

you may try this
$arrayList = array();
while($row = mysqli_featch_array($results)){
$arrayList[] = $row;
}
print_r($arrayList);

Answer 4

Put all the values in an array
$rows = array();
$x = 0;
while($row = mysqli_fetch_array($results))
{
$rows[$x]['industry'] = $row['industry'];
$rows[$x]['location'] = $row['location'];
$rows[$x]['title'] = $row['title'];
$rows[$x]['description'] = $row['description'];
$x++;
}
return $rows;
Then you can use $rows as an array.
foreach($rows as $v){
echo $v['industry']." ".$v['location']."<br />";
echo $v['title']." ".$v['description']."<br />";
}