I am creating a online application in PHP and as part of this I need to have a function where I give it a directory and it will count all the files in that folder, all the folders in that folder, and all the folders in the sub-directories etc until all files and sub-files in that folder are counted.
I have tried multiple methods and from doing my own research most people do it the way I have tried to attempt it but I am getting no success with my method.
Here is the code i currently use: (The $uniqueKey parameter is not the issue already debugged that out.)
//Get file count of user
function getFolderFileCount($uniqueKey){
$totalCount = 0;
$directory = "data/storage/uploads/" . $uniqueKey;
$dirContents = scandir($directory);
foreach($dirContents as $row){
if(is_dir($row)){
$totalCount += getFolderFileCount($directory . "/" . $row);
$totalCount++;
}else{
$totalCount++;
}
}
return $totalCount - 2;
}
The tree of my directory is as follows:
-www
--access
--code.php ( <- this is where the code is being ran from)
---data
----storage
-----uploads
------user500493 ( <- this is the $uniqueKey variable and therefore the folder than i need the file count of)
The errors i am getting in my error log is:
https://pastebin.com/g3jGD7u8
You are sending the $directory variable to the function again instead of the $uniqueKey '/' $row.
On the second loop it tries to access 'data/storage/uploads/data/storage/uploads/{$uniqueKey}/{$row}'.
//Get file count of user
function getFolderFileCount($uniqueKey){
$totalCount = 0;
$directory = "data/storage/uploads/" . $uniqueKey;
$dirContents = scandir($directory);
foreach($dirContents as $row){
if($row == '.' || $row == '..')
continue;
if(is_dir($directory. $row)){
$totalCount += getFolderFileCount($uniqueKey . "/" . $row);
$totalCount++;
}else{
$totalCount++;
}
}
return $totalCount;
}
Edit: The code considers subfolders inside the user500493 folder as well.
I did some tests on PHP 7.1.9-1 and it's fully working.
The is_dir() parameters must be the path to the folder, not only $rowbecause it is only the file or directory name.
Related
I'm using bootstrap tables and rows to count how much files are in a folder, but the destination is pointing to a different server the code below does not work.
As i'm using localhost (xampp) trying to do this don't know if its possible.
<?php
// integer starts at 0 before counting
$i = 0;
$dir = 'uploads/'; <!--\\189.207.00.122\folder1\folder2\folder3\test-->
if ($handle = opendir($dir)) {
while (($file = readdir($handle)) !== false){
if (!in_array($file, array('.', '..')) && !is_dir($dir.$file))
$i++;
}
}
// prints out how many were in the directory
echo "There were $i files";
?>
Here is a handy little function you might want to try out. Just pass the path to the Directory as the first argument to it and you'd get your result.
NOTE: This Function is RECURSIVE, which means: it will traverse all sub-directories... to disable this behaviour, simply comment out or delete the following lines towards the end of the Funciton:
<?php
}else if(is_dir($temp_file_or_dir) && !preg_match('/^\..*/', $val) ){
getFilesInFolder($temp_file_or_dir);
}
THE CODE:
<?php
$folder = dirname(__FILE__).'/uploads'; // ASSUMES YOUR uploads DIRECTORY
// IS IN THE SAME DIRECTORY AS index.php
// (/htdocs/php/pages)
// OR
$folder = dirname(__FILE__).'/../uploads'; // ASSUMES YOUR uploads DIRECTORY
// IS ONE DIRECTORY ABOVE
// THE CURRENT DIRECTORY (/htdocs/php)
// THIS IS MOST LIKELY RIGHT
// OR
$folder = dirname(__FILE__).'/../../uploads';// ASSUMES YOUR uploads DIRECTORY
// IS TWO DIRECTORIES ABOVE
// THE CURRENT DIRECTORY (/htdocs)
// MAKE SURE THE FOLDER IN QUESTION HAS THE RIGHT PERMISSIONS
// OR RATHER CHANGE PERMISSIONS ON THE FOLDER TO BE ABLE TO WORK WITH IT
chmod($folder, 0777);
var_dump(getFilesInFolder($folder));
// IF YOU PASS false AS THE THE 2ND ARGUMENT TO THIS FUNCTION
// YOU'D GET AN ARRAY OF ALL FILES IN THE $path2Folder DIRECTORY
// AS WELL AS IN SUB-DIRECTORIES WITHIN IT...
function getFilesInFolder($path2Folder, $countOnly=true){
$files_in_dir = scandir($path2Folder);
$returnable = array();
foreach($files_in_dir as $key=>$val){
$temp_file_or_dir = $path2Folder . DIRECTORY_SEPARATOR . $val;
if(is_file($temp_file_or_dir) && !preg_match("#^\..*#", $temp_file_or_dir)){
$arrRX = array('#\.{2,4}$#', '#\.#');
$arrReplace = array("", "_");
$returnVal = preg_replace($arrRX, $arrReplace, $val);
$returnable[$returnVal] = $temp_file_or_dir;
}else if(is_dir($temp_file_or_dir) && !preg_match('/^\..*/', $val) ){
getFilesInFolder($temp_file_or_dir);
}
}
return ($countOnly) ? count($returnable) : $returnable;
}
Use $_SERVER['DOCUMENT_ROOT'] to get your root directory.
$dir = $_SERVER['DOCUMENT_ROOT'].'/uploads/';
I am trying to figure out a way of searching through all of the *.php files inside the parent directory, parent directory example:
/content/themes/default/
I am not wanting to search through all of the files in the sub-directories. I am wanting to search for a string embedded in the PHP comment syntax, such as:
/* Name: default */
If the variable is found, then get the file name and/or path. I have tried googling this, and thinking of custom ways to do it, this is what I have attempted so far:
public function build_active_theme() {
$dir = CONTENT_DIR . 'themes/' . $this->get_active_theme() . '/';
$theme_files = array();
foreach(glob($dir . '*.php') as $file) {
$theme_files[] = $file;
}
$count = null;
foreach($theme_files as $file) {
$file_contents = file_get_contents($file);
$count++;
if(strpos($file_contents, 'Main')) {
$array_pos = $count;
$main_file = $theme_files[$array_pos];
echo $main_file;
}
}
}
So as you can see I added all the found files into an array, then got the content of each file, and search through it looking for the variable 'Main', if the variable was found, get the current auto-incremented number, and get the path from the array, however it was always telling me the wrong file, which had nothing close to 'Main'.
I believe CMS's such as Wordpress use a similar feature for plugin development, where it searches through all the files for the correct plugin details (which is what I want to make, but for themes).
Thanks,
Kieron
Like David said in his comment arrays are zero indexed in php. $count is being incremented ($count++) before being used as the index for $theme_files. Move $count++ to the end of the loop, And it will be incremented after the index look up.
public function build_active_theme() {
$dir = CONTENT_DIR . 'themes/' . $this->get_active_theme() . '/';
$theme_files = array();
foreach(glob($dir . '*.php') as $file) {
$theme_files[] = $file;
}
$count = null;
foreach($theme_files as $file) {
$file_contents = file_get_contents($file);
if(strpos($file_contents, 'Main')) {
$array_pos = $count;
$main_file = $theme_files[$array_pos];
echo $main_file;
}
$count++;
}
}
So I'm trying to make a simple script, it will have a list of predefined files, search for anything that's not on the list and delete it.
I have this for now
<?php
$directory = "/home/user/public_html";
$files = glob($directory . "*.*");
foreach($files as $file)
{
$sql = mysql_query("SELECT id FROM files WHERE FileName='$file'");
if(mysql_num_rows($sql) == 0)
unlink($directory . $file);
}
?>
However, I'd like to avoid the query so I can run the script more often (there's about 60-70 files, and I want to run this every 20 seconds or so?) so how would I embedd a file list into the php file and check against that instead of database?
Thanks!
You are missing a trailing / twice.. In glob() you are giving /home/user/public_html*.* as the argument, I think you mean /home/user/public_html/*.*.
This is why I bet nothing matches the files in your table..
This won't give an error either because the syntax is fine.
Then where you unlink() you do this again.. your argument home/user/public_htmltestfile.html should be home/user/public_html/testfile.html.
I like this syntax style: "{$directory}/{$file}" because it's short and more readable. If the / is missing, you see it immediately. You can also change it to $directory . "/" . $file, it you prefer it. The same goes for one line conditional statements.. So here it comes..
<?php
$directory = "/home/user/public_html";
$files = glob("{$directory}/*.*");
foreach($files as $file)
{
$sql = mysql_query("SELECT id FROM files WHERE FileName=\"{$file}\";");
if(mysql_num_rows($sql) == 0)
{
unlink("{$directory}/{$file}");
}
}
?>
EDIT: You requested recursion. Here it goes..
You need to make a function that you can run once with a path as it's argument. Then you can run that function from inside that function on subdirectories. Like this:
<?php
/*
ListDir list files under directories recursively
Arguments:
$dir = directory to be scanned
$recursive = in how many levels of recursion do you want to search? (0 for none), default: -1 (for "unlimited")
*/
function ListDir($dir, $recursive=-1)
{
// if recursive == -1 do "unlimited" but that's no good on a live server! so let's say 999 is enough..
$recursive = ($recursive == -1 ? 999 : $recursive);
// array to hold return value
$retval = array();
// remove trailing / if it is there and then add it, to make sure there is always just 1 /
$dir = rtrim($dir,"/") . "/*";
// read the directory contents and process each node
foreach(glob($dir) as $node)
{
// skip hidden files
if(substr($node,-1) == ".") continue;
// if $node is a dir and recursive is greater than 0 (meaning not at the last level or disabled)
if(is_dir($node) && $recursive > 0)
{
// substract 1 of recursive for ever recursion.
$recursive--;
// run this same function again on itself, merging the return values with the return array
$retval = array_merge($retval, ListDir($node, $recursive));
}
// if $node is a file, we add it to the array that will be returned from this function
elseif(is_file($node))
{
$retval[] = $node;
// NOTE: if you want you can do some action here in your case you can unlink($node) if it matches your requirements..
}
}
return $retval;
}
// Output the result
echo "<pre>";
print_r(ListDir("/path/to/dir/",1));
echo "</pre>";
?>
If the list is not dynamic, store it in an array:
$myFiles = array (
'some.ext',
'next.ext',
'more.ext'
);
$directory = "/home/user/public_html/";
$files = glob($directory . "*.*");
foreach($files as $file)
{
if (!in_array($file, $myFiles)) {
unlink($directory . $file);
}
}
So I have this app that processes CSV files. I have a line of code to load the file.
$myFile = "data/FrontlineSMS_Message_Export_20120721.csv"; //The name of the CSV file
$fh = fopen($myFile, 'r'); //Open the file
I would like to find a way in which I could look in the data directory and get the newest file (they all have date tags so they would be in order inside of data) and set the name equal to $myFile.
I really couldn't find and understand the documentation of php directories so any helpful resources would be appreciated as well. Thank you.
Here's an attempt using scandir, assuming the only files in the directory have timestamped filenames:
$files = scandir('data', SCANDIR_SORT_DESCENDING);
$newest_file = $files[0];
We first list all files in the directory in descending order, then, whichever one is first in that list has the "greatest" filename — and therefore the greatest timestamp value — and is therefore the newest.
Note that scandir was added in PHP 5, but its documentation page shows how to implement that behavior in PHP 4.
For a search with wildcard you can use:
<?php
$path = "/var/www/html/*";
$latest_ctime = 0;
$latest_filename = '';
$files = glob($path);
foreach($files as $file)
{
if (is_file($file) && filectime($file) > $latest_ctime)
{
$latest_ctime = filectime($file);
$latest_filename = $file;
}
}
return $latest_filename;
?>
My solution, improved solution from Max Hofmann:
$ret = [];
$dir = Yii::getAlias("#app") . "/web/uploads/problem-letters/{$this->id}"; // set directory in question
if(is_dir($dir)) {
$ret = array_diff(scandir($dir), array(".", "..")); // get all files in dir as array and remove . and .. from it
}
usort($ret, function ($a, $b) use ($dir) {
if(filectime($dir . "/" . $a) < filectime($dir . "/" . $b)) {
return -1;
} else if(filectime($dir . "/" . $a) == filectime($dir . "/" . $b)) {
return 0;
} else {
return 1;
}
}); // sort array by file creation time, older first
echo $ret[count($ret)-1]; // filename of last created file
Here's an example where I felt more confident in using my own validator rather than simply relying on a timestamp with scandir().
In this context, I want to check if my server has a more recent file version than the client's version. So I compare version numbers from the file names.
$clientAppVersion = "1.0.5";
$latestVersionFileName = "";
$directory = "../../download/updates/darwin/"
$arrayOfFiles = scandir($directory);
foreach ($arrayOfFiles as $file) {
if (is_file($directory . $file)) {
// Your custom code here... For example:
$serverFileVersion = getVersionNumberFromFileName($file);
if (isVersionNumberGreater($serverFileVersion, $clientAppVersion)) {
$latestVersionFileName = $file;
}
}
}
// function declarations in my php file (used in the forEach loop)
function getVersionNumberFromFileName($fileName) {
// extract the version number with regEx replacement
return preg_replace("/Finance D - Tenue de livres-darwin-(x64|arm64)-|\.zip/", "", $fileName);
}
function removeAllNonDigits($semanticVersionString) {
// use regex replacement to keep only numeric values in the semantic version string
return preg_replace("/\D+/", "", $semanticVersionString);
}
function isVersionNumberGreater($serverFileVersion, $clientFileVersion): bool {
// receives two semantic versions (1.0.4) and compares their numeric value (104)
// true when server version is greater than client version (105 > 104)
return removeAllNonDigits($serverFileVersion) > removeAllNonDigits($clientFileVersion);
}
Using this manual comparison instead of a timestamp I can achieve a more surgical result. I hope this can give you some useful ideas if you have a similar requirement.
(PS: I took time to post because I was not satisfied with the answers I found relating to the specific requirement I had. Please be kind I'm also not very used to StackOverflow - Thanks!)
$value can = a folder structure to the language file. Example: languages/english.php
$value can also = the files name. Example: english.php
So I need to get the current folder that $value is in and delete the folder ONLY if there are no other files/folders within that directory (after deleting the actual file as I am doing already, ofcourse).
foreach($module['languages'] as $lang => $langFile)
{
foreach ($langFile as $type => $value)
{
#unlink($module_path . '/' . $value);
// Now I need to delete the folder ONLY if there are no other directories inside the folder where it is currently at.
// And ONLY if there are NO OTHER files within that folder also.
}
}
How can I do this?? And wondering if this can be done without using a while loop, since a while loop within a foreach loop could take some time, and need this to be as quick as possible.
And just FYI, the $module_path should never be deleted. So if $value = english.php, it should never delete the $module_path. Ofcourse, there will always be another file in there, so checking for this is not necessary, but won't hurt either way.
Thanks guys :)
EDIT
Ok, now I'm using this code here and it is NOT working, it is not removing the folders or the files, and I don't get any errors either... so not sure what the problem is here:
foreach($module['languages'] as $lang => $langFile)
{
foreach ($langFile as $type => $value)
{
if (#unlink($module_path . '/' . $value))
#rmdir(dirname($module_path . '/' . $value));
}
}
NEVERMIND, this works a CHARM!!! Cheers Everyone!!
The easyest way is try to use rmdir. This don't delete folder if it is not empty
rmdir($module_path);
also you can check is folder empty by
if(count(glob($module_path.'*'))<3)//delete
2 for . and ..
UPD: as I reviewed maybe you should replace $module_path by dirname($module_path.'.'.$value);
Since the directory you care about might be part of the $value, you need to use dirname to figure out what the parent directory is, you can't just assume that it's $module_path.
$file_path = $module_path . '/' . $value;
if (#unlink($file_path)) {
#rmdir(dirname($file_path));
}
if (is_file($value)) {
unlink($value);
} else if (is_dir($value)) {
if (count(scandir($value)) == 2) }
unlink($value)
}
}
http://php.net/manual/en/function.is-dir.php
http://www.php.net/manual/en/function.scandir.php
The code below will take a path, check if it is a file (i.e. not a directory). If it is a file, it will extract the directory name, then delete the file, then iterate over the dir and count the files in it, if the files are zero it'll delete the dir.
Code is as an example and should work, however privileges and environment setup may result in it not working.
<?php
if(!is_dir ( string $filename )){ //if it is a file
$fileDir = dirname ( $filename );
if ($handle = opendir($fileDir)) {
echo "Directory handle: $handle\n";
echo "Files:\n";
$numFiles=0;
//delete the file
unlink($myFile);
//Loop the dir and count the file in it
while (false !== ($file = readdir($handle))) {
$numFiles = $numFiles + 1;
}
if($numFiles == 0) {
//delete the dir
rmdir($fileDir);
}
closedir($handle);
}
}
?>