Php Listing Data with datatables - php

I have a datatable and i am listing 3 columns from database.(Actually got 25)
I have added a submit button for each row and want to see the all data when user click that button on the bottom of the page.
Here is my code:
<?php
require_once 'config.php';
// Attempt select query execution
$sql = "SELECT * FROM jobs";
if($result = mysqli_query($db, $sql)){
if(mysqli_num_rows($result) > 0){
while($row =
mysqli_fetch_array($result)){
echo "<td><button type='submit' value=".$row['id']".">Show Details</a></td>";
echo "<td>'" . $row['type'] . "</td>";
echo "<td>" . $row['status'] . "</td>";
echo "<td>" . $row['location'] . "</td>";
echo "<td>" . $row["result"] . "</td>";
}
// Free result set
mysqli_free_result($result);
} else{
echo "<p class='lead'><em>No data.</em></p>";
}
} else{
echo "ERROR: Could not able to execute
$sql. " . mysqli_error($link);
}
// Close connection
mysqli_close($db);
?>
I tried to use Post method but didn't worked.

you can use jquery to do it like this.
<?php
require_once 'config.php';
// Attempt select query execution
if(!mysqli_select_db($conn,$db))
die("Cant select to database");
$sql = "SELECT * FROM jobs";
if($result = mysqli_query($db, $sql)){
echo "<table id='example'>";
if(mysqli_num_rows($result) > 0){
while($row = mysqli_fetch_array($result)){
echo "<tr>";
echo "<td><button type='submit' value=". $row['id'] . ">Show Details</a></td>";
echo "<td>" . $row['type'] . "</td>";
echo "<td>" . $row['status'] . "</td>";
echo "<td>" . $row['location'] . "</td>";
echo "<td>" . $row["result"] . "</td>";
echo "</tr>";
}
// Free result set
mysqli_free_result($result);
} else{
echo "<p class='lead'><em>No data.</em></p>";
}
echo "</table>";
} else{
echo "ERROR: Could not able to execute
$sql. " . mysqli_error($link);
}
// Close connection
mysqli_close($db);
?>
<script>
$('#example').on('click', 'tbody .edit_btn', function () {
var $row = $(this).closest("tr"), // Finds the closest row <tr>
$tds = $row.find("td"); // Finds all children <td> elements
$.each($tds, function() { // Visits every single <td> element
console.log($(this).text()); // Prints out the text within the <td>
});
});
</script>

Related

How to make sql query to display 1 result based on id in the database table

I need help, I cannot figure out, I cannot find why I am having errors and I am not able to achieve something freaking simple.
Long story short, I have a website to manage projects, so when I run the search function it throws a table with some records from the database, there is a button called "see details" which is assigned to a project id with database i.e. 21, 1, 48 etc, the problem is that when I click "see details" it throws everything from the table proposals instead of 1 project, no matter which button I click on, if its id 1, 21, 48, it prints everything.
details page
details.php:
<?php
include '../includes/config.php';
// Check connection
if($link === false){
die("ERROR: Could not connect. " . mysqli_connect_error());
}
// Attempt select query execution
$sql = "SELECT * FROM proposals_table WHERE id LIKE '_%'";
if($result = mysqli_query($link, $sql)){
if(mysqli_num_rows($result) > 0){
echo "<table class='table table-bordered'>";
echo "<tr>";
echo "<th>Organisation</th>";
echo "<th>Project</th>";
echo "<th>Proposal Date</th>";
echo "<th>Date Received</th>";
echo "<th>Notes</th>";
echo "</tr>";
while($row = mysqli_fetch_array($result)){
echo "<tr>";
echo "<td>" . $row['company'] . "</td>";
echo "<td>" . $row['project'] . "</td>";
echo "<td>" . $row['proposal_date'] . "</td>";
echo "<td>" . $row['date_received'] . "</td>";
echo "<td>" . $row['notes'] . "</td>";
echo "</tr>";
}
echo "</table>";
// Free result set
mysqli_free_result($result);
} else{
echo "No records matching your query were found.";
}
} else{
echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);
}
?>
search/result page
proposals.php
<?php
include '../includes/config.php';
// Check connection
if($link === false){
die("ERROR: Could not connect. " . mysqli_connect_error());
}
// Attempt select query execution
$sql = "SELECT * FROM proposals_table";
if($result = mysqli_query($link, $sql)){
if(mysqli_num_rows($result) > 0){
echo "<table class='table table-bordered'>";
echo "<tr>";
echo "<th>Organisation</th>";
echo "<th>Project</th>";
echo "<th>Proposal Date</th>";
echo "<th>Date Received</th>";
echo "<th>Options</th>";
echo "</tr>";
while($row = mysqli_fetch_array($result)){
echo "<tr>";
echo "<td>" . $row['company'] . "</td>";
echo "<td>" . $row['project'] . "</td>";
echo "<td>" . $row['proposal_date'] . "</td>";
echo "<td>" . $row['date_received'] . "</td>";
echo "<td> <a class='btn btn-primary' href='details.php?id={$row['id']}'>See details</a></td>";
echo "</tr>";
}
echo "</table>";
// Free result set
mysqli_free_result($result);
} else{
echo "No records matching your query were found.";
}
} else{
echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);
}
?>
If you want to show only the selected element on your details page then you need to fetch only that selected item from the database.
First of all you should separate HTML from PHP. The best would be to have them in separate files. In PHP you prepare the data to be displayed and then in HTML you fill in the blanks with PHP values.
To select a value from MySQL using a given ID you must use prepared statements with parameter binding. So if you create your link in this way:
echo "<td> <a class='btn btn-primary' href='details.php?id=".urlencode($row['id'])."'>See details</a></td>";
You can receive this ID in your details page using $_GET['id']. You can bind that value to your WHERE clause in SQL.
<?php
include '../includes/config.php';
// Attempt select query execution
$stmt = $link->prepare("SELECT * FROM proposals_table WHERE id=?");
$stmt->bind_param('s', $_GET['id']);
$stmt->execute();
$proposals = $stmt->get_result()->fetch_all(MYSQLI_ASSOC);
if($proposals) {
?>
<table class='table table-bordered'>
<tr>
<th>Organisation</th>
<th>Project</th>
<th>Proposal Date</th>
<th>Date Received</th>
<th>Notes</th>
</tr>
<?php foreach($proposals as $row): ?>
<tr>
<td><?=$row['company'] ?></td>
<td><?=$row['project'] ?></td>
<td><?=$row['proposal_date'] ?></td>
<td><?=$row['date_received'] ?></td>
<td><?=$row['notes'] ?></td>
</tr>
<?php endforeach; ?>
</table>
<?php
} else {
echo 'No records matching your query were found.';
}
And of course your config.php page should look like this:
<?php
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$link = new mysqli('localhost', 'user', 'pass', 'db');
$link->set_charset('utf8mb4'); // always set the charset

call php function to put data in a table

i have a function called displayMenu() that brings data from a table .. this function is inside a php file named functions.php
if (isset($_POST['Starters'])) {
$sql = "SELECT * FROM product WHERE category_id=1";
$sql1= "SELECT cat_name,cat_description FROM category WHERE cat_id=1";
displayMenu();
}
function displayMenu(){
global $db, $sql,$sql1,$nb;
if($result = mysqli_query($db, $sql1)){
if(mysqli_num_rows($result) > 0){
while($row = mysqli_fetch_array($result)){
echo '<h1 class="header">' . $row['cat_name'] . '</h2>';
echo '<h3 class="content">' . $row['cat_description'] . '</h3>';
}
}
}
if($result = mysqli_query($db, $sql)){
if(mysqli_num_rows($result) > 0){
echo "<table>";
while($row = mysqli_fetch_array($result)){
echo "<tr>";
echo "<td>" . $row['p_code'] . "</td>";
echo "<td>" . $row['p_name'] . "</td>";
echo "<td>" . $row['p_description'] . "</td>";
echo "<td>" . $row['p_price'] . "</td>";
echo "<td>" ;
echo '<form class="nbItem" action="order.php" method="post">Nb of items:';
echo '<input type="number" name="item"> <button type="submit" class="btn" name="addtocart">Add To Cart</button>';
echo '</form>';
echo "</td>";
echo "</tr>";
}
echo "</table>";
// Free result set
mysqli_free_result($result);
} else{
echo "No records matching your query were found.";
}
} else{
echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);
}
this actually works .. but i want to create the table inside another file called order.php and call this function from this file
how should i do it ?
If I understand correctly, you just need to include your functions.php file in your order.php file and then call the displayMenu from includes your order file?
order.php
include 'functions.php';
echo displayMenu();

Delete button on PHP echo table not working

Below is my code for a PHP echo delete that contains a delete button. When pressed I want that entry to be deleted from the database
$result = mysql_query("SELECT * ,CONCAT (HomeScore,'-',AwayScore) AS Score, CONCAT(Against) AS Game FROM Fixture WHERE TeamID='9' ORDER BY Date DESC");
echo "<table id='customers' border='1'>;
<tr>
<th>FixtureID</th>
<th>Competition</th>
<th>Match</th>
<th>Date</th>
<th>Time</th>
<th>Score</th>
<th>test</th>
</tr>";
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['FixtureID'] . "</td>";
echo "<td>" . $row['Competition'] . "</td>";
echo "<td>" . $row["Against"] . "</td>";
echo "<td>" . $row['Date'] . "</td>";
echo "<td>" . $row['Time'] . "</td>";
echo "<td>" . $row['Score'] . "</td>";
echo "<td><form method=post>
<input name=id type=hidden value='".$row['FixtureID']."';>
<input type=submit name=submit value=Delete>
</form></td>";
echo "</tr>";
echo "</tr>";
}
}
echo "</table>";
// delete record
if($_SERVER['REQUEST_METHOD'] == "POST")
{
if(isset($_POST['FixtureID']))
{
$id = FixtureID;
$sql = mysql_query("DELETE FROM Fixture WHERE FixtureID =$id");
if(!$sql)
{
echo ("Could not delete rows" .mysql_error());
}
}
}
How do I get this to work? Also FixtureID is stored as an integer in the database.
Try with these changes :
// delete record
if(isset($_POST['submit']) && isset($_POST['id']) && !empty($_POST['id'])) {
$id = $_POST['id'];
$sql = mysql_query("DELETE FROM Fixture WHERE FixtureID =$id");
if(!$sql) {
echo ("Could not delete rows" .mysql_error());
}
}
Edit :
// Delete record if ID submitted
if(isset($_POST['submit']) && isset($_POST['id']) && !empty($_POST['id'])) {
$id = $_POST['id'];
$sql = mysql_query("DELETE FROM Fixture WHERE FixtureID =$id");
if(!$sql) {
echo ("Could not delete rows" .mysql_error());
}
}
// Get datas from BDD
$result = mysql_query("SELECT * ,CONCAT (HomeScore,'-',AwayScore) AS Score, CONCAT(Against) AS Game FROM Fixture WHERE TeamID='9' ORDER BY Date DESC");
// Display data
echo "
<table id='customers' border='1'>
<tr>
<th>FixtureID</th>
<th>Competition</th>
<th>Match</th>
<th>Date</th>
<th>Time</th>
<th>Score</th>
<th>test</th>
</tr>";
// For each result
while($row = mysql_fetch_array($result)) {
echo "<tr>";
echo "<td>" . $row['FixtureID'] . "</td>";
echo "<td>" . $row['Competition'] . "</td>";
echo "<td>" . $row["Against"] . "</td>";
echo "<td>" . $row['Date'] . "</td>";
echo "<td>" . $row['Time'] . "</td>";
echo "<td>" . $row['Score'] . "</td>";
echo "<td><form method=post>
<input name=id type=hidden value='".$row['FixtureID']."';>
<input type=submit name=submit value=Delete>
</form></td>";
echo "</tr>";
echo "</tr>";
}
echo "</table>";
just try this
if(isset($_POST['submit']))
{
$id = $_POST['id']; // here you should use form post value
$sql = mysql_query("DELETE FROM Fixture WHERE FixtureID =$id");
if(!$sql)
{
echo ("Could not delete rows" .mysql_error());
}
}
}
$id value is not properly set
$id = $_POST['FixtureID'];

Beginner: Delete row from Table and Database PHP/HTML/MySQL

Complete newbie to PHP/MySQL and HTML so please bear with me if I dont explain myself properly. At present I have an order form which stores the order in my database and shows it on a table in my admin area. I would like to be able to delete the row from the table and my database when I have completed the order.
At present my code looks like this:
<?php
//87229feely.php
include('connection.php');
$result = mysql_query("SELECT * FROM orderform");
echo "<table border='1' >
<tr>
<th><u>ID</th>
<th><u>Date</th>
<th><u>Product</th>
<th><u>Product Comments</th>
<th><u>Name</th>
<th><u>Address</th>
<th><u>Age</th>
<th><u>Delivery</th>
<th><u>Delete</th>
</tr>";
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['id']. "</td>";
echo "<td>" . $row['date'] . "</td>";
echo "<td>" . $row['product'] . "</td>";
echo "<td>" . $row['productcomments'] . "</td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['address'] . "</td>";
echo "<td>" . $row['age'] . "</td>";
echo "<td>" . $row['delivery'] . "</td>";
echo "<td>delete</td>";
echo "</tr>";
}
echo "</table>";
?>
<?php
//deleterow.php
include('connection.php');
$id = $_GET['id']; //this needs to be sanitized
if(!empty($id)){
$result = mysql_query("DELETE FROM orderform WHERE id=".$id.";");
}
header("Location: 87229feely.php");
?>
Any help? All greatly appreciated. Thanks
This answer does not meet security standards but should do the job:
<?php
//index.php
include('connection.php');
$result = mysql_query("SELECT * FROM orderform");
echo "<table border='1' >
<tr>
<th><u>ID</th>
<th><u>Date</th>
<th><u>Product</th>
<th><u>Product Comments</th>
<th><u>Name</th>
<th><u>Address</th>
<th><u>Age</th>
<th><u>Delivery</th>
<th><u>Delete</th>
</tr>";
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['id']. "</td>";
echo "<td>" . $row['date'] . "</td>";
echo "<td>" . $row['product'] . "</td>";
echo "<td>" . $row['productcomments'] . "</td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['address'] . "</td>";
echo "<td>" . $row['age'] . "</td>";
echo "<td>" . $row['delivery'] . "</td>";
echo "<td>delete</td>";
echo "</tr>";
}
echo "</table>";
?>
<?php
//delete.php
include('connection.php');
$id = $_GET['id']; //this needs to be sanitized
if(!empty($id)){
$result = mysql_query("DELETE FROM orderform WHERE id=".$id.";");
}
header("Location: index.php");
?>
Many ways to do this. Since you're a beginner, this would probably be the most straight-forward (albeit not how I would do it)
Create a form around the table
Add a button on the delete column for each row and assign an id to it (the ID should be the ID from your database) <input type="submit" name="submit" value"/*YOUR ID*/">
Add some processing script before the table is being parsed
if (isset($_POST['submit'])) {
$sql = "DELETE FROM table WHERE id='/*YOUR ID*/'";
mysql_query($sql);
}
First of all ,you need to send ID of completed order to next form. You cam do this by adding:
echo("<input type='hidden' name='orderID' value='".$row['id']."'/>");
That will create a hidden field with value of ID.
If your form uses POST:
then:
if(isset($_POST['submit'])){
$orderID = $_POST['orderID'];
mysql_query("DELETE FROM table WHERE id=$oderID");
}
If you are using GET method:
<form method="GET">
You could either use hidden field as mentioned above or you could parse ID of order in GET url:
<form action='action.php?id=".$row['id']."'>
and after submitting:
if(isset($_GET['submit']) && isset($_GET['id')){
$orderID = $_GET['id'];
mysql_query("DELETE FROM table WHERE id=$orderID");
}
Maybe something like this with PDO
<?php
include('connection.php');
?>
<form name="" action="delete.php" method="post">
<table border='1' >
<tr>
<th> </th>
<th><u>ID</th>
<th><u>Date</th>
<th><u>Product</th>
<th><u>Product Comments</th>
<th><u>Name</th>
<th><u>Address</th>
<th><u>Age</th>
<th><u>Delivery</th>
<th><u>Delete</th>
</tr>
<?php
try {
$conn = new PDO('mysql:host=localhost;dbname=myDatabase', $username, $password);
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$row = $conn->query('SELECT * FROM orderform');
while($row = $stmt->fetch(PDO::FETCH_ASSOC)) {
echo "<tr>";
echo "<td><input type=\"checkbox\" name=\"id[]\" id=\"checkAll\" value=\"".$row['id']."\" /></td>"
echo "<td>" . $row['id']. "</td>";
echo "<td>" . $row['date'] . "</td>";
echo "<td>" . $row['product'] . "</td>";
echo "<td>" . $row['productcomments'] . "</td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['address'] . "</td>";
echo "<td>" . $row['age'] . "</td>";
echo "<td>" . $row['delivery'] . "</td>";
echo "</tr>";
}
} catch(PDOException $e) {
echo 'ERROR: ' . $e->getMessage();
}
?>
</table>
<input type="submit" name="submit" value="submit" />
</form>
delete.php
<?php
$id
if(isset($_POST['submit']) {
include('connection.php');
try {
$conn = new PDO('mysql:host=localhost;dbname=myDatabase', $username, $password);
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$sql="DELETE FROM orderform WHERE id IN (".implode(',',$conn->quote($id)).")";
$stmt->exec($sql);
} catch(PDOException $e) {
echo 'ERROR: ' . $e->getMessage();
}
}

Table ID in PHP

I'm trying to assign anID to the table I'm generating with PHP but it keeps returning an error. Here is the full code that works fine so far. All I want is to add an 'id' to the table so I can apply css styles to it in the relevant sheet
<?php
$con=mysqli_connect("localhost","<un>","<pw>","monitor");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT * FROM presnationalresults ORDER BY Percentage DESC");
echo "<table border='1'>
<tr>
<th>President</th>
<th>Party</th>
<th>Votes</th>
<th>Percentage</th>
</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['PresidentName'] . "</td>";
echo "<td>" . $row['PartyCode'] . "</td>";
echo "<td>" . $row['Votes'] . "</td>";
echo "<td>" . $row['Percentage'] . "</td>";
}
echo "</table>";
mysqli_close($con);
Any help? maybe I'm going about it the wrong way?
Please try below block of code . I have added table id and also close </tr> inside while loop
<?php
$con = mysqli_connect("localhost", "<un>", "<pw>", "monitor");
// Check connection
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con, "SELECT * FROM presnationalresults ORDER BY Percentage DESC");
echo "<table border='1' id='table-id'>
<tr>
<th>President</th>
<th>Party</th>
<th>Votes</th>
<th>Percentage</th>
</tr>";
while ($row = mysqli_fetch_array($result)) {
echo "<tr>";
echo "<td>" . $row['PresidentName'] . "</td>";
echo "<td>" . $row['PartyCode'] . "</td>";
echo "<td>" . $row['Votes'] . "</td>";
echo "<td>" . $row['Percentage'] . "</td>";
echo "</tr>"; // you forget close tr
}
echo "</table>";
mysqli_close($con);

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