call php function to put data in a table - php

i have a function called displayMenu() that brings data from a table .. this function is inside a php file named functions.php
if (isset($_POST['Starters'])) {
$sql = "SELECT * FROM product WHERE category_id=1";
$sql1= "SELECT cat_name,cat_description FROM category WHERE cat_id=1";
displayMenu();
}
function displayMenu(){
global $db, $sql,$sql1,$nb;
if($result = mysqli_query($db, $sql1)){
if(mysqli_num_rows($result) > 0){
while($row = mysqli_fetch_array($result)){
echo '<h1 class="header">' . $row['cat_name'] . '</h2>';
echo '<h3 class="content">' . $row['cat_description'] . '</h3>';
}
}
}
if($result = mysqli_query($db, $sql)){
if(mysqli_num_rows($result) > 0){
echo "<table>";
while($row = mysqli_fetch_array($result)){
echo "<tr>";
echo "<td>" . $row['p_code'] . "</td>";
echo "<td>" . $row['p_name'] . "</td>";
echo "<td>" . $row['p_description'] . "</td>";
echo "<td>" . $row['p_price'] . "</td>";
echo "<td>" ;
echo '<form class="nbItem" action="order.php" method="post">Nb of items:';
echo '<input type="number" name="item"> <button type="submit" class="btn" name="addtocart">Add To Cart</button>';
echo '</form>';
echo "</td>";
echo "</tr>";
}
echo "</table>";
// Free result set
mysqli_free_result($result);
} else{
echo "No records matching your query were found.";
}
} else{
echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);
}
this actually works .. but i want to create the table inside another file called order.php and call this function from this file
how should i do it ?

If I understand correctly, you just need to include your functions.php file in your order.php file and then call the displayMenu from includes your order file?
order.php
include 'functions.php';
echo displayMenu();

Related

Does not print everything from sql database

I am trying to build a forum for my school project. Now i want to get the data out of my database so i can print it and people can see and react to it. Now i have the problem that it only print the commenters post and not the creators post. I will ad some picture and the code so you guys can undestand. (PS. i have a form on the previous page where you can search)
Database
Website
<!DOCTYPE html>
<html>
<head>
<link rel="stylesheet" href="./style.css">
<title><?php echo $_GET["search"];?></title>
</head>
<body>
<?php
//navbar
include "./include/nav.php";
//database connection
include "./include/conn.php";
$search = $_GET["search"];
if($search == ""){
// if empty return to index
echo "
<script>alert('thread does not exist')</script>
<script>window.location = './index.php'</script>
";
} else {
//check if data exist
$sql = "SELECT thread, post, username, status FROM post WHERE thread = ? ";
$query = $conn->prepare($sql);
$query->execute(array($search));
$data = $query->fetch();
if($data){
// print data if exist
echo "<div class='padding'>";
foreach ($query as $test) {
echo "<tr>";
echo "<td>" . $test["thread"] . "</td>";
echo "<td>" . $test["post"] . "</td>";
echo "<td>" . $test["username"] . "</td>";
echo "<td>" . $test["status"] . "</td>";
echo "</tr>" . "</br>";
}
echo "<button onclick='comment()'>Comment</button>";
echo "</div>";
echo "<div id='test'>";
} else {
// if data does not exist return to index
echo "
<script>alert('thread does not exist')</script>
<script>window.location = './index.php'</script>
";
}
}
?>
<script>
// if comment btn is pressed save thread name and send to comment.php
function comment() {
document.getElementById("test").innerHTML =
"<?php
session_start();
$_SESSION['thread'] = $data['thread'];
?>";
window.location.assign("./comment.php")
}
</script>
</body>
</html>
I never used the data that i got out of the database. I should have printed it like this:
if($data){
// print data if exist
echo "<div class='padding'>";
foreach ($data as $test) {
echo "<tr>";
echo "<td>" . $test["thread"] . "</td>";
echo "<td>" . $test["post"] . "</td>";
echo "<td>" . $test["username"] . "</td>";
echo "<td>" . $test["status"] . "</td>";
echo "</tr>" . "</br>";
}
echo "<button onclick='comment()'>Comment</button>";
echo "</div>";
echo "<div id='test'>";
} else {
// if data does not exist return to index
echo "
<script>alert('thread does not exist')</script>
<script>window.location = './index.php'</script>
";
}
}

Php Listing Data with datatables

I have a datatable and i am listing 3 columns from database.(Actually got 25)
I have added a submit button for each row and want to see the all data when user click that button on the bottom of the page.
Here is my code:
<?php
require_once 'config.php';
// Attempt select query execution
$sql = "SELECT * FROM jobs";
if($result = mysqli_query($db, $sql)){
if(mysqli_num_rows($result) > 0){
while($row =
mysqli_fetch_array($result)){
echo "<td><button type='submit' value=".$row['id']".">Show Details</a></td>";
echo "<td>'" . $row['type'] . "</td>";
echo "<td>" . $row['status'] . "</td>";
echo "<td>" . $row['location'] . "</td>";
echo "<td>" . $row["result"] . "</td>";
}
// Free result set
mysqli_free_result($result);
} else{
echo "<p class='lead'><em>No data.</em></p>";
}
} else{
echo "ERROR: Could not able to execute
$sql. " . mysqli_error($link);
}
// Close connection
mysqli_close($db);
?>
I tried to use Post method but didn't worked.
you can use jquery to do it like this.
<?php
require_once 'config.php';
// Attempt select query execution
if(!mysqli_select_db($conn,$db))
die("Cant select to database");
$sql = "SELECT * FROM jobs";
if($result = mysqli_query($db, $sql)){
echo "<table id='example'>";
if(mysqli_num_rows($result) > 0){
while($row = mysqli_fetch_array($result)){
echo "<tr>";
echo "<td><button type='submit' value=". $row['id'] . ">Show Details</a></td>";
echo "<td>" . $row['type'] . "</td>";
echo "<td>" . $row['status'] . "</td>";
echo "<td>" . $row['location'] . "</td>";
echo "<td>" . $row["result"] . "</td>";
echo "</tr>";
}
// Free result set
mysqli_free_result($result);
} else{
echo "<p class='lead'><em>No data.</em></p>";
}
echo "</table>";
} else{
echo "ERROR: Could not able to execute
$sql. " . mysqli_error($link);
}
// Close connection
mysqli_close($db);
?>
<script>
$('#example').on('click', 'tbody .edit_btn', function () {
var $row = $(this).closest("tr"), // Finds the closest row <tr>
$tds = $row.find("td"); // Finds all children <td> elements
$.each($tds, function() { // Visits every single <td> element
console.log($(this).text()); // Prints out the text within the <td>
});
});
</script>

My dropdown list would not drop down

I tried to use php to create a dropdown list populated by a SELECT query but it would not dropdown. Here is my php script
<?php
require_once ('mysqli_connect.php');
#mysqli_select_db($dbc,"test");
$query = "SELECT category_id, category_name FROM forum_category ORDER BY category_name";
$result = #mysqli_query($dbc, $query);
if(!$result)
{
echo "query error: " . mysqli_error($dbc);
}
// while($row = #mysqli_fetch_array($result))
// {
// echo "<p>$row[0] $row[1]</p>\n"; //this works
// }
echo "<td bgcolor=\"#E6E6E6\"";
echo "<strong>Category:</strong>";
echo "<select name=\"category\">";
while($row = #mysqli_fetch_array($result))
{
// echo "<p><option value='".$row[0]."'>".$row[1]."</option></p>\n";
echo "<option value='".$row[0]."'>".$row[1]."</option>";
}
mysqli_close($dbc);
echo "</select>";
echo "</td>";
?>
The query worked (the commented while loop outside the dropdown list displayed 15 records). But the dropdown list only showed one category_name and would not dropdown. Can someone help me figure out the problem? Thanks.
There are a few problems with your code.
You can either remove both echo "<td bgcolor=\"#E6E6E6\""; and echo "</td>";
which is the reason why your data is not showing.
Or, add the appropriate <table></table> tags.
Plus this echo "<td bgcolor=\"#E6E6E6\""; should be echo "<td bgcolor=\"#E6E6E6\">"; there was a missing > so that alone is breaking your <td>.
So in order to have the proper table syntax do:
Sidenote: I added . "\n" in order to get clean and well-aligned HTML source.
<?php
require_once ('mysqli_connect.php');
#mysqli_select_db($dbc,"test");
$query = "SELECT category_id, category_name FROM forum_category ORDER BY category_name";
$result = #mysqli_query($dbc, $query);
if(!$result)
{
echo "query error: " . mysqli_error($dbc);
}
echo "<table>" . "\n";
echo "<tr>" . "\n";
echo "<td bgcolor=\"#E6E6E6\">" . "\n";
echo "<strong>Category:</strong>" . "\n";
echo "<select name=\"category\">" . "\n";
while($row= mysqli_fetch_array($result)){
echo "<option value='".$row[0]."'>".$row[1]."</option>" . "\n";
}
echo "</select>" . "\n";
echo "</td>" . "\n";
echo "</tr>" . "\n";
echo "</table>" . "\n";
mysqli_close($dbc);
?>
Edit: (Try this) since I don't know what your full code looks like.
<form id="form1" name="form1" method="post" action="form1_handler.php">
<?php
require_once ('mysqli_connect.php');
#mysqli_select_db($dbc,"test");
if(isset($_POST['submit'])){
$query = "SELECT category_id, category_name FROM forum_category ORDER BY category_name";
$result = #mysqli_query($dbc, $query);
if(!$result)
{
echo "query error: " . mysqli_error($dbc);
}
echo "<table>" . "\n";
echo "<tr>" . "\n";
echo "<td bgcolor=\"#E6E6E6\">" . "\n";
echo "<strong>Category:</strong>" . "\n";
echo "<select name=\"category\">" . "\n";
while($row= mysqli_fetch_array($result)){
echo "<option value='".$row[0]."'>".$row[1]."</option>" . "\n";
}
echo "</select>" . "\n";
echo "</td>" . "\n";
echo "</tr>" . "\n";
echo "</table>" . "\n";
mysqli_close($dbc);
} // brace for if(isset($_POST['submit']))
?>
<input type="submit" name="submit" value="Submit">
</form>

Beginner: Delete row from Table and Database PHP/HTML/MySQL

Complete newbie to PHP/MySQL and HTML so please bear with me if I dont explain myself properly. At present I have an order form which stores the order in my database and shows it on a table in my admin area. I would like to be able to delete the row from the table and my database when I have completed the order.
At present my code looks like this:
<?php
//87229feely.php
include('connection.php');
$result = mysql_query("SELECT * FROM orderform");
echo "<table border='1' >
<tr>
<th><u>ID</th>
<th><u>Date</th>
<th><u>Product</th>
<th><u>Product Comments</th>
<th><u>Name</th>
<th><u>Address</th>
<th><u>Age</th>
<th><u>Delivery</th>
<th><u>Delete</th>
</tr>";
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['id']. "</td>";
echo "<td>" . $row['date'] . "</td>";
echo "<td>" . $row['product'] . "</td>";
echo "<td>" . $row['productcomments'] . "</td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['address'] . "</td>";
echo "<td>" . $row['age'] . "</td>";
echo "<td>" . $row['delivery'] . "</td>";
echo "<td>delete</td>";
echo "</tr>";
}
echo "</table>";
?>
<?php
//deleterow.php
include('connection.php');
$id = $_GET['id']; //this needs to be sanitized
if(!empty($id)){
$result = mysql_query("DELETE FROM orderform WHERE id=".$id.";");
}
header("Location: 87229feely.php");
?>
Any help? All greatly appreciated. Thanks
This answer does not meet security standards but should do the job:
<?php
//index.php
include('connection.php');
$result = mysql_query("SELECT * FROM orderform");
echo "<table border='1' >
<tr>
<th><u>ID</th>
<th><u>Date</th>
<th><u>Product</th>
<th><u>Product Comments</th>
<th><u>Name</th>
<th><u>Address</th>
<th><u>Age</th>
<th><u>Delivery</th>
<th><u>Delete</th>
</tr>";
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['id']. "</td>";
echo "<td>" . $row['date'] . "</td>";
echo "<td>" . $row['product'] . "</td>";
echo "<td>" . $row['productcomments'] . "</td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['address'] . "</td>";
echo "<td>" . $row['age'] . "</td>";
echo "<td>" . $row['delivery'] . "</td>";
echo "<td>delete</td>";
echo "</tr>";
}
echo "</table>";
?>
<?php
//delete.php
include('connection.php');
$id = $_GET['id']; //this needs to be sanitized
if(!empty($id)){
$result = mysql_query("DELETE FROM orderform WHERE id=".$id.";");
}
header("Location: index.php");
?>
Many ways to do this. Since you're a beginner, this would probably be the most straight-forward (albeit not how I would do it)
Create a form around the table
Add a button on the delete column for each row and assign an id to it (the ID should be the ID from your database) <input type="submit" name="submit" value"/*YOUR ID*/">
Add some processing script before the table is being parsed
if (isset($_POST['submit'])) {
$sql = "DELETE FROM table WHERE id='/*YOUR ID*/'";
mysql_query($sql);
}
First of all ,you need to send ID of completed order to next form. You cam do this by adding:
echo("<input type='hidden' name='orderID' value='".$row['id']."'/>");
That will create a hidden field with value of ID.
If your form uses POST:
then:
if(isset($_POST['submit'])){
$orderID = $_POST['orderID'];
mysql_query("DELETE FROM table WHERE id=$oderID");
}
If you are using GET method:
<form method="GET">
You could either use hidden field as mentioned above or you could parse ID of order in GET url:
<form action='action.php?id=".$row['id']."'>
and after submitting:
if(isset($_GET['submit']) && isset($_GET['id')){
$orderID = $_GET['id'];
mysql_query("DELETE FROM table WHERE id=$orderID");
}
Maybe something like this with PDO
<?php
include('connection.php');
?>
<form name="" action="delete.php" method="post">
<table border='1' >
<tr>
<th> </th>
<th><u>ID</th>
<th><u>Date</th>
<th><u>Product</th>
<th><u>Product Comments</th>
<th><u>Name</th>
<th><u>Address</th>
<th><u>Age</th>
<th><u>Delivery</th>
<th><u>Delete</th>
</tr>
<?php
try {
$conn = new PDO('mysql:host=localhost;dbname=myDatabase', $username, $password);
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$row = $conn->query('SELECT * FROM orderform');
while($row = $stmt->fetch(PDO::FETCH_ASSOC)) {
echo "<tr>";
echo "<td><input type=\"checkbox\" name=\"id[]\" id=\"checkAll\" value=\"".$row['id']."\" /></td>"
echo "<td>" . $row['id']. "</td>";
echo "<td>" . $row['date'] . "</td>";
echo "<td>" . $row['product'] . "</td>";
echo "<td>" . $row['productcomments'] . "</td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['address'] . "</td>";
echo "<td>" . $row['age'] . "</td>";
echo "<td>" . $row['delivery'] . "</td>";
echo "</tr>";
}
} catch(PDOException $e) {
echo 'ERROR: ' . $e->getMessage();
}
?>
</table>
<input type="submit" name="submit" value="submit" />
</form>
delete.php
<?php
$id
if(isset($_POST['submit']) {
include('connection.php');
try {
$conn = new PDO('mysql:host=localhost;dbname=myDatabase', $username, $password);
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$sql="DELETE FROM orderform WHERE id IN (".implode(',',$conn->quote($id)).")";
$stmt->exec($sql);
} catch(PDOException $e) {
echo 'ERROR: ' . $e->getMessage();
}
}

How do i delete the records from the table?

I am using a form to get the input of username and password to store the value into the database, once the form is submitted i have defined a table to show all the values from the users table, it have 3 fields (id, name, pass) i want to delete each record by it's id .
i am fetching the data from the users table by using the following code:
while($row = mysql_fetch_assoc($result_select)) {
echo "<tr>";
echo "<td>" . $row['id'] . "</td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['pass'] . "</td>";
echo "</tr>"; }
i want to add the delete hyperlink to delete the particular records by id.
i tried using the following code and i couldnt achieve it.
if(mysql_num_rows($result_select) > 0) {
if(isset($_POST['id'])) {
$query_delete = "DELETE FROM users WHERE id =" .$_POST['id'];
$result_delete = mysql_query($query_delete);
}
echo "<table cellpadding=10 border=1>";
while($row = mysql_fetch_assoc($result_select)) {
echo "<tr>";
echo "<td>" . $row['id'] . "</td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['pass'] . "</td>";
echo "<td>Delete</td>";
echo "</tr>";
}
echo "</table>";
}
I am a newbie to programming, i would appreciate if someone explain me in simple words.. thank you :)
First of all put your delete code in your page like this:
if(isset($_POST['submit'])) {
for($i = 0; $i < count($_POST['del']); $i++)
{
// check which records to delete
if (isset($_POST['del'][$i]))
{
$query_delete = "DELETE FROM users WHERE id = " . (int) $_POST['del'][$i];
$result_delete = mysql_query($query_delete) or die(mysql_error());
}
}
echo 'Record Deleted !!' . '<br /><br />';
}
Later put your select code and modify it like this:
echo '<form action="" method="POST">';
while($row = mysql_fetch_assoc($result_select)) {
echo "<tr>";
echo "<td>" . $row['id'] . "</td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['pass'] . "</td>";
echo "<td><input type=\"checkbox\" name=\"del[]\"></td>";
echo "</tr>";
}
echo '<input type="submit" name="submit">';
echo '</form>';
You need to change $_POST to $_GET, so this should work.
if(isset($_GET['id'])) {
$query_delete = "DELETE FROM users WHERE id =" .$_GET['id'];
$result_delete = mysql_query($query_delete);
and also put values of attributes inside double quotes, like this
echo '<td>Delete</td>';

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