PHP SQL - Search for match with same players - php

Good mornin'.
I've been tryin to make "something" that will compare matchup percentage but i'm stuck'd at searching for matches with 2 same players.
I've found something about AND OR parenthesis so here is my sql query
$ccc = "SELECT * FROM zapasy WHERE (playerName01 = '".$player1."' OR playerName01 ='".$player2."') AND (playerName02 = '".$player2."' OR playerName02='".$player1."')";
$result3 = $db->query($ccc);
$ids = array();
while ($row55 = $result3->fetch_assoc())
{
$ids[] = $row55['winner'];
}
But , the problem is whenever i try to get data , it gives me more indexes than actualy expected.
This is the result of printing array values after fetching.
Array ( [0] => 2 [1] => 3 [2] => 4 [3] => 5 [4] => 6 )
As expected is only 2 3 4 as u can see in the DB sample here.
db sample
Anyone suggestions on what i'm doing wrong?

A simple way to write this in MySQL uses tuples:
where (?, ?) in ( (playername01, playername02), (playername02, playername01) )
The ? are for parameters. That should be the way that you pass values into queries.

You are doing wrong while using AND OR in where clause
$ccc = "SELECT * FROM zapasy WHERE (playerName01 = '".$player1."' AND playerName02 ='".$player2."') OR (playerName01 = '".$player2."' AND playerName02='".$player1."')";
Try this #Patrik Dano

Related

MySql NOT IN many values from the mysql fetched result

I have 2 MySql queries which are interdependent.
My 'table1'
----------
id
----------
1
2
3
4
5
6
7
My First query
$sql1 = "SELECT * FROM table1 WHERE";// some condition which gives me id's 1,2,3
$res1=$obj->_executeQuery($sql1);
$res1=$obj->getAll($res1);
The result of this is giving me array
Array
(
[0] => Array
(
[id] => 1
..
..
)
[1] => Array
(
[id] => 2
..
..
)
[2] => Array
(
[id] => 3
..
..
)
)
I want to run another query on same 'table1', where not equal to list of ID's which i am getting from the first query.
My Second Query
$sql2 = "SELECT * FROM table1 WHERE id NOT IN (" . implode(',', $res1) . ")";
This is not showing me only one id i,e first. In above case i should get id's 4,5,6,7
Since implode will not give the desired value on multidimensional array so first you need to get the array of all id's to form one-dimensional array then use implode on the array of id's:
$id=array();
foreach ($res1 as $key=>$inner_array){
$id[]= $inner_array['id'];
}
you can use array_walk also here like this:
array_walk($res1,function($c) use (&$id) {$id[] = $c['id'];});
but i think the best one is array_map :
$id = array_map(function($i) {
return $i['id'];
}, $res1);
$sql2 = "SELECT * FROM table1 WHERE id NOT IN (" . implode(',', $id) . ")";
Note: when ever you are doing select please specify your column if you need few to select,unnecessarily selecting all will slow your sql processing.
suppose here:SELECT * FROM table1 WHERE, if you need only id then please select id only.
You have to change $res1, which is a two-dimensional array, into a one-dimensional array of IDs to be able to use implode:
$ids_from_first_query = array();
foreach($res1 as $result_row) {
$ids_from_first_query[] = $result_row['id'];
}
$ids_as_string = implode(',', $ids_from_first_query);
$sql2 = 'SELECT * FROM table1 WHERE id NOT IN(' . $ids_as_string . ')';
In the above code, $ids_as_string will look like this:
1,2,3
Thus it can be used in your MySQL query
Here you are getting two dimensional array so that's reason it is not working
while($each=mysql_fetch_array($res1))
{
$array[]=$each[id];
}
$imp=implode(",",$array);
$sql2 = "SELECT * FROM table1 WHERE id NOT IN (".$imp.")";
Try this it will works

Is using PHP to loop a mySQL query efficient?

I have a HTML table full of check-boxes on page 1 with the name attribute set like this:
input type="checkbox" name="A_1"
input type="checkbox" name="B_2"
On the following page, I loop through my $_POST array in PHP with explode to make an array like this:
Array ( [A_1] => on [A_2] => on [B_2] => on [B_5] => on [C_5] => on [submit] => Submit )
Into two arrays:
row_Array = Array ( [0] => 1 [1] => 2 [2] => 2 [3] => 5 [4] => 5 )
column_Array = Array ( [0] => A [1] => A [2] => B [3] => B [4] => C )
This is my SQL query:
for($i=0; $i < count($column_array); $i++) {
$sql = "SELECT {$column_array[$i]} FROM table WHERE num IN ({$row_array[$i]})";
$result = mysqli_query($connection, $sql);
while ($data = mysqli_fetch_assoc($result)) {
$result_array[] = $data[$column_array[$i]];
}
}
Here is an example of my SQL table:
A B C
1 cat cot cet
2 rat rot ret
3 hat hot het
4 lat lot let
5 bat bot bet
The individual SQL queries from my loop look like this and return the correct values:
SELECT A FROM table WHERE num IN (1) returns cat
SELECT A FROM table WHERE num IN (2) returns rat
SELECT B FROM table WHERE num IN (2) returns rot
SELECT B FROM table WHERE num IN (5) returns bot
SELECT C FROM table WHERE num IN (5) returns bet
I am quite new to sql and php. This works but it seems like a terrible way to do this. Any advice or help would be greatly appreciated.
I believe it's a better practice to run a single query and loop through the data returned rather than looping and then running multiple queries.
However, depending on your data structure and application layout, UI, etc, that may not be possible.
I would aim for something like SELECT A,B,C,num FROM table WHERE num IN (1,2,5)
then maybe
foreach($result as $r){
$data[$r['num']] = $r;
}
Let's try just running one query and loop trough it. It's pretty much #Andy Gee 's answer expressed in code.
$cols = implode(',', array_unique($column_array));
$rows = implode(',', array_unique($row_array));
$sql = "SELECT {$cols} FROM table WHERE num IN ({$rows})";
$result = mysqli_query($connection, $sql);
while ($data = mysqli_fetch_assoc($result)) {
//Do your stuff here
}
Something like, it's realy bad idea but..:
$columns = implode(', ', $column_array);
$num_values = implode(', ', $row_array);
$sql = "SELECT {$columns}, num FROM table WHERE num IN ({$num_values})";
$result = mysqli_query($connection, $sql);
while ($data = mysqli_fetch_assoc($result)) {
$result_array[] = $data[$column_array[$i]];
}
Other way is to build one long Query with UNION
SELECT A as value, num FROM table WHERE num = 1
UNION
SELECT A as value, num FROM table WHERE num = 2
UNION
SELECT B as value, num FROM table WHERE num = 2
UNION
SELECT B as value, num FROM table WHERE num = 5
UNION
SELECT C as value, num FROM table WHERE num = 5
returns:
array(
array("num" => 1, "value" => 'cat'),
array("num" => 1, "value" => 'rat'),
...
);

How to find data when results set is in array?

i want to find data through id, i have an array like that
$result=
Array
(
[3] => 536371014
[38] => 1435902884
[53] => 100000224980743
)
user _id is
[3], [38], [53]
in my user tabe
user_id name
3 usii
38 test
53 test 2
i want to find all data through user id, how can i do that with the result set user id which is index, i tried alot but didn't get success, please help me to do that, thanks a ton in advance.
Use foreach like this
foreach($result as $val) {
echo $val[$user_id];
}
Something like this should work (brutal pseudo code)
in_list = implode(", ", array_keys($result));
$all_users = mysql.query("select * from user_table where user_id in (" . in_list . ");";
array_keys should give you an array of just the indexes used (3, 38 and 53)
implode with ", " as glue should give you a string like this "3, 38, 53" suitable for a mysql IN condition.
$user_ids = implode(",",array_keys($result));
$query = "SELECT * FROM usertable WHERE user_id IN (".$user_ids.")";

create multi-dimensional array in php

I am having trouble trying to figure out how to populate a multi-dimensional array. Let's say I have a table of transactions with various billing dates. First I have an array that retrieves the following 'billed' dates:
Array
(
[0] => Array
(
[BILLED] => 2011-11-18 00:00:00
)
[1] => Array
(
[BILLED] => 2011-11-22 00:00:00
)
)
I also have the following query which is currently hard-coded to one of the two 'billed' dates shown above:
$qryOrders = $this->db->query("
SELECT tblOrders.*
FROM tblOrders
WHERE tbltc.BILLED = '2011-11-22'");
$data['Orders'] = $qryOrders->result_array();
I know that I can very easily determine the count of array items by using count($Orders); but how can I instead pass through each of the 'billed' dates of 2011-11-18 and 2011-11-22 to that I can determine the overall count, for both of the specified dates?
I hope I've explained it clearly enough. I am thinking that I probably need some kind of foreach loop and each time through the loop I could pass in the billed date, and keep track of a running total each time through the loop.
Any ideas would be greatly appreciated. Thanks,
// this is getting all results for a record
$sql =
<<<sql
SELECT tblOrders.*
FROM tblOrders
WHERE tbltc.BILLED between '{$arr[0]}' and '{$arr[1]}'
sql;
// this is to get total count of matched record
// $sql = 'select count(*) from ..';
if you are using CI, you can easily using bind
example:-
$sql = 'SELECT tblOrders.* FROM tblOrders WHERE tbltc.BILLED between ? AND ?';
$this->db->query($sql, array($arr[0], $arr[1]));

The best way to select rows from several tables?

I am creating a php app and am now creating the DB interface code. In my APP their are three tables, user, network, user_network. They have the following columsn:
user<-------------------->user_network<-------------------->network
user_ID un_ID network_ID
user_Name un_Member network_Name
un_Network network_Description
I have created the following query which querys the user_network table and returns the ID's of all networks which the user is a member of:
$STH = $DBH->query("SELECT * FROM user_network WHERE nm_Member ='$userID'");
I then pull the network_ID's from this array using the following code:
$DB_NetworkID = array();
foreach($STH as $row)
{
$DB_NetworkID[$counter] = $row['nm_networkID'];
$counter++;
}
print_r($DB_NetworkID);
The array now holds of all the network IDs that the user is a member of, like so
Array ( [0] => 1 [1] => 3 [2] => 5 [3] => 7 ) //network IDs = 1, 3, 5, 7
I would now like to pull rows from the networks tables, how do i go about about SELECTing rows from the networks database WHERE the ID is contained in the array?
Thanks for any help.
You should use a JOIN instead and make it a single query:
SELECT
*
FROM
user
INNER JOIN
user_network
ON
user.user_ID = user_network.un_ID
INNER JOIN
network
ON
user_network.un_Network = network.network_ID
WHERE
user_ID = '$userID'
That query will give you all networks that a user is member of.
If your problem is the comparison against an array, then an easy workaround is using FIND_IN_SET() like this:
$list = implode(",", $DB_NetworkID); // turns it into "1,3,5,7"
... "SELECT * FROM foo WHERE FIND_IN_SET(network_ID, '$list')";
For better performance you should construct an .. IN (?,?,..) clause however.
Of course using JOIN as "halfdan" said, is the best way.
But I gonna answer your question:
If your array is like this:
$un = Array ( [0] => 1 [1] => 3 [2] => 5 [3] => 7 ) //network IDs = 1, 3, 5, 7
You can use a Foreach like this:
Foreach($un as $key => $value) {
and your query will be like this:
SELECT * FROM network WHERE network_ID ='$value'

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