i want to find data through id, i have an array like that
$result=
Array
(
[3] => 536371014
[38] => 1435902884
[53] => 100000224980743
)
user _id is
[3], [38], [53]
in my user tabe
user_id name
3 usii
38 test
53 test 2
i want to find all data through user id, how can i do that with the result set user id which is index, i tried alot but didn't get success, please help me to do that, thanks a ton in advance.
Use foreach like this
foreach($result as $val) {
echo $val[$user_id];
}
Something like this should work (brutal pseudo code)
in_list = implode(", ", array_keys($result));
$all_users = mysql.query("select * from user_table where user_id in (" . in_list . ");";
array_keys should give you an array of just the indexes used (3, 38 and 53)
implode with ", " as glue should give you a string like this "3, 38, 53" suitable for a mysql IN condition.
$user_ids = implode(",",array_keys($result));
$query = "SELECT * FROM usertable WHERE user_id IN (".$user_ids.")";
Related
Good mornin'.
I've been tryin to make "something" that will compare matchup percentage but i'm stuck'd at searching for matches with 2 same players.
I've found something about AND OR parenthesis so here is my sql query
$ccc = "SELECT * FROM zapasy WHERE (playerName01 = '".$player1."' OR playerName01 ='".$player2."') AND (playerName02 = '".$player2."' OR playerName02='".$player1."')";
$result3 = $db->query($ccc);
$ids = array();
while ($row55 = $result3->fetch_assoc())
{
$ids[] = $row55['winner'];
}
But , the problem is whenever i try to get data , it gives me more indexes than actualy expected.
This is the result of printing array values after fetching.
Array ( [0] => 2 [1] => 3 [2] => 4 [3] => 5 [4] => 6 )
As expected is only 2 3 4 as u can see in the DB sample here.
db sample
Anyone suggestions on what i'm doing wrong?
A simple way to write this in MySQL uses tuples:
where (?, ?) in ( (playername01, playername02), (playername02, playername01) )
The ? are for parameters. That should be the way that you pass values into queries.
You are doing wrong while using AND OR in where clause
$ccc = "SELECT * FROM zapasy WHERE (playerName01 = '".$player1."' AND playerName02 ='".$player2."') OR (playerName01 = '".$player2."' AND playerName02='".$player1."')";
Try this #Patrik Dano
I have an array lets say: Array ( [0] => 9 [1] => 7 [2] => 8 )
I want to SELECT from a table (users) all phone numbers where userID matches one from the array (if there is a phone number listed).
I want to do this without selecting all of the users from the database and only those that match that of the array and with actual phone numbers, should I do this in a loop?
Typically when I am doing an UPDATE, I do them within a foreach loop. Like so:
foreach($userArr as $user) {
$pid = $user;
if(!$statement->execute()) {
throw new Exception($statement->error, $statement->errno);
}
}
$statement->close();
Can we do SELECT like that as well?
Thanks in advance for any advice.
If you want to select all these users, just do the follow:
$idList = implode(',', $yourArray);
$sql = "SELECT * FROM users WHERE id IN($idList)";
// execute this $sql query
Try this:
<?php
$array = array(9, 7, 8);
$query = "SELECT * FROM mytable WHERE id = ";
$condition = implode(' OR id = ', $array);
$query .= $condition;
echo $query;
?>
Output:
SELECT * FROM mytable WHERE id = 9 OR id = 7 OR id = 8
You should do the following:
Build a string to express the userid seperated by comma. - Loop will be needed. i.e id1, id2, id3
Build the query string to search for them.
Example:
SELECT * FROM `Users` WHERE id IN (id1, id2, id3)
I have 2 MySql queries which are interdependent.
My 'table1'
----------
id
----------
1
2
3
4
5
6
7
My First query
$sql1 = "SELECT * FROM table1 WHERE";// some condition which gives me id's 1,2,3
$res1=$obj->_executeQuery($sql1);
$res1=$obj->getAll($res1);
The result of this is giving me array
Array
(
[0] => Array
(
[id] => 1
..
..
)
[1] => Array
(
[id] => 2
..
..
)
[2] => Array
(
[id] => 3
..
..
)
)
I want to run another query on same 'table1', where not equal to list of ID's which i am getting from the first query.
My Second Query
$sql2 = "SELECT * FROM table1 WHERE id NOT IN (" . implode(',', $res1) . ")";
This is not showing me only one id i,e first. In above case i should get id's 4,5,6,7
Since implode will not give the desired value on multidimensional array so first you need to get the array of all id's to form one-dimensional array then use implode on the array of id's:
$id=array();
foreach ($res1 as $key=>$inner_array){
$id[]= $inner_array['id'];
}
you can use array_walk also here like this:
array_walk($res1,function($c) use (&$id) {$id[] = $c['id'];});
but i think the best one is array_map :
$id = array_map(function($i) {
return $i['id'];
}, $res1);
$sql2 = "SELECT * FROM table1 WHERE id NOT IN (" . implode(',', $id) . ")";
Note: when ever you are doing select please specify your column if you need few to select,unnecessarily selecting all will slow your sql processing.
suppose here:SELECT * FROM table1 WHERE, if you need only id then please select id only.
You have to change $res1, which is a two-dimensional array, into a one-dimensional array of IDs to be able to use implode:
$ids_from_first_query = array();
foreach($res1 as $result_row) {
$ids_from_first_query[] = $result_row['id'];
}
$ids_as_string = implode(',', $ids_from_first_query);
$sql2 = 'SELECT * FROM table1 WHERE id NOT IN(' . $ids_as_string . ')';
In the above code, $ids_as_string will look like this:
1,2,3
Thus it can be used in your MySQL query
Here you are getting two dimensional array so that's reason it is not working
while($each=mysql_fetch_array($res1))
{
$array[]=$each[id];
}
$imp=implode(",",$array);
$sql2 = "SELECT * FROM table1 WHERE id NOT IN (".$imp.")";
Try this it will works
I have this PHP syntax and works as I expected :
$sqldata = mysql_query("
SELECT FirstName, LastName, NumberOfChildren, SchoolTuition FROM User WHERE User.Username = '$Username' LIMIT 1;
");
$rows = array();
while($r = mysql_fetch_assoc($sqldata)) {
$rows[] = $r;
}
echo json_encode($rows);
now, the problem is I want to calculate total school tuition (NumberOfChildren * SchoolTuition) and it must be done before json_encode() function. and my client doesn't want to add one extra column on their database.
so I must calculate this TOTAL School Tuition using PHP and put it back on $rows array as latest value of array before json_encode.
I tried calculate using mysql_fetch_array first to get $rows[2] and $rows[3], but since I already use mysql_fetch_assoc before, this mysql_fetch_array won't work.
last thing, I mysql_fetch_assoc generates 2 dimensional array. because when I use print_r($rows), I see this :
Array ( [0] => Array ( [FirstName] => Mary [LastName] => Smith [NumberOfChildren] => 3 [SchoolTuition] => 2000 ) )
while array_push function only used to push 1 dimensional array, right?
please kindly give me solution of this problem. thank you very much.
You can just do the calculation in SQL, without having to add the column.
SELECT FirstName, LastName, NumberOfChildren, SchoolTuition,
(NumberOfChildren * SchoolTuiton) AS TotalSchoolTuiton
FROM User WHERE User.Username = '$Username' LIMIT 1
SELECT FirstName, LastName, NumberOfChildren, SchoolTuition, NumberOfChildren*SchoolTuition AS TotalTuition FROM User WHERE User.Username = '$Username' LIMIT 1;
I am creating a php app and am now creating the DB interface code. In my APP their are three tables, user, network, user_network. They have the following columsn:
user<-------------------->user_network<-------------------->network
user_ID un_ID network_ID
user_Name un_Member network_Name
un_Network network_Description
I have created the following query which querys the user_network table and returns the ID's of all networks which the user is a member of:
$STH = $DBH->query("SELECT * FROM user_network WHERE nm_Member ='$userID'");
I then pull the network_ID's from this array using the following code:
$DB_NetworkID = array();
foreach($STH as $row)
{
$DB_NetworkID[$counter] = $row['nm_networkID'];
$counter++;
}
print_r($DB_NetworkID);
The array now holds of all the network IDs that the user is a member of, like so
Array ( [0] => 1 [1] => 3 [2] => 5 [3] => 7 ) //network IDs = 1, 3, 5, 7
I would now like to pull rows from the networks tables, how do i go about about SELECTing rows from the networks database WHERE the ID is contained in the array?
Thanks for any help.
You should use a JOIN instead and make it a single query:
SELECT
*
FROM
user
INNER JOIN
user_network
ON
user.user_ID = user_network.un_ID
INNER JOIN
network
ON
user_network.un_Network = network.network_ID
WHERE
user_ID = '$userID'
That query will give you all networks that a user is member of.
If your problem is the comparison against an array, then an easy workaround is using FIND_IN_SET() like this:
$list = implode(",", $DB_NetworkID); // turns it into "1,3,5,7"
... "SELECT * FROM foo WHERE FIND_IN_SET(network_ID, '$list')";
For better performance you should construct an .. IN (?,?,..) clause however.
Of course using JOIN as "halfdan" said, is the best way.
But I gonna answer your question:
If your array is like this:
$un = Array ( [0] => 1 [1] => 3 [2] => 5 [3] => 7 ) //network IDs = 1, 3, 5, 7
You can use a Foreach like this:
Foreach($un as $key => $value) {
and your query will be like this:
SELECT * FROM network WHERE network_ID ='$value'