I am having trouble trying to figure out how to populate a multi-dimensional array. Let's say I have a table of transactions with various billing dates. First I have an array that retrieves the following 'billed' dates:
Array
(
[0] => Array
(
[BILLED] => 2011-11-18 00:00:00
)
[1] => Array
(
[BILLED] => 2011-11-22 00:00:00
)
)
I also have the following query which is currently hard-coded to one of the two 'billed' dates shown above:
$qryOrders = $this->db->query("
SELECT tblOrders.*
FROM tblOrders
WHERE tbltc.BILLED = '2011-11-22'");
$data['Orders'] = $qryOrders->result_array();
I know that I can very easily determine the count of array items by using count($Orders); but how can I instead pass through each of the 'billed' dates of 2011-11-18 and 2011-11-22 to that I can determine the overall count, for both of the specified dates?
I hope I've explained it clearly enough. I am thinking that I probably need some kind of foreach loop and each time through the loop I could pass in the billed date, and keep track of a running total each time through the loop.
Any ideas would be greatly appreciated. Thanks,
// this is getting all results for a record
$sql =
<<<sql
SELECT tblOrders.*
FROM tblOrders
WHERE tbltc.BILLED between '{$arr[0]}' and '{$arr[1]}'
sql;
// this is to get total count of matched record
// $sql = 'select count(*) from ..';
if you are using CI, you can easily using bind
example:-
$sql = 'SELECT tblOrders.* FROM tblOrders WHERE tbltc.BILLED between ? AND ?';
$this->db->query($sql, array($arr[0], $arr[1]));
Related
Let me preface this with I know this question has been asked plenty of times on here (ie here among other pages) and I've trawled through each of the answers and tried the solutions but keep getting an empty json array.
I've got a mysql query as per below:
$myQuery = $wpdb->get_results('SELECT player_name, player_team,
SUM(ruckContests) AS contests FROM afl_master
WHERE player_team = "COLL" AND year = 2019 AND ruckContests > 0
GROUP BY player_id ORDER BY contests DESC LIMIT 2');
The output to this query is as follows:
Array ( [0] => stdClass Object ( [player_name] => Brodie Grundy [player_team] => COLL [contests] => 661 ) [1] => stdClass Object ( [player_name] => Mason Cox [player_team] => COLL [contests] => 51 ) )
What I want to do is convert this to the following json object in php:
{
player_name: "Brodie Grundy",
player_team: "COLL",
contests: 661
},
{
player_name: "Mason Cox",
player_team: "COLL",
contests: 51
}
I've tried mysql_fetch_array() as well as fetch_assoc() using the method here but to no avail. I'd appreciate any help available.
This simple solution recommended in the comments worked:
json_encode($myQuery)
$JsonData=array();
foreach($myQuery as $val){
$JsonData[]='
{
"player_name": "'.$val->player_name.'",
"player_team": "'.$val->player_team.'",
"contests": $val->contests
}
';
}
$expectedJson=implode(',',$JsonData);
Just cast your result to array with fetch_array() or (array) $myQuery then:
json_encode($myQuery);
json_last_error(); // to see the error
You can do it in single SQL Statement (I have just formatted it in multiple lines for better understanding). The inner Select statement uses your query as a sub-query, while using JSON_OBJECT to generate JSON object of each row, finally using GROUP_CONCAT to combine each row with a comma, and then add the "[" and "]" to the final result for creating a perfect JSON array. (Just another way, apart from the json_encode($myQuery), the simpler version :) ).
SELECT CONCAT('[',
GROUP_CONCAT(
JSON_OBJECT(
'player_name', player_name,
'player_team' , player_team,
'contests', contests)
) , ']') as json
FROM (
SELECT player_name, player_team, SUM(ruckContests) as contests
FROM afl_master
WHERE player_team = "COLL" AND year = 1995 AND ruckContests > 0
GROUP BY player_name, player_team
ORDER BY SUM(ruckContests) DESC
LIMIT 2
) AS TT
Good mornin'.
I've been tryin to make "something" that will compare matchup percentage but i'm stuck'd at searching for matches with 2 same players.
I've found something about AND OR parenthesis so here is my sql query
$ccc = "SELECT * FROM zapasy WHERE (playerName01 = '".$player1."' OR playerName01 ='".$player2."') AND (playerName02 = '".$player2."' OR playerName02='".$player1."')";
$result3 = $db->query($ccc);
$ids = array();
while ($row55 = $result3->fetch_assoc())
{
$ids[] = $row55['winner'];
}
But , the problem is whenever i try to get data , it gives me more indexes than actualy expected.
This is the result of printing array values after fetching.
Array ( [0] => 2 [1] => 3 [2] => 4 [3] => 5 [4] => 6 )
As expected is only 2 3 4 as u can see in the DB sample here.
db sample
Anyone suggestions on what i'm doing wrong?
A simple way to write this in MySQL uses tuples:
where (?, ?) in ( (playername01, playername02), (playername02, playername01) )
The ? are for parameters. That should be the way that you pass values into queries.
You are doing wrong while using AND OR in where clause
$ccc = "SELECT * FROM zapasy WHERE (playerName01 = '".$player1."' AND playerName02 ='".$player2."') OR (playerName01 = '".$player2."' AND playerName02='".$player1."')";
Try this #Patrik Dano
I have 2 MySql queries which are interdependent.
My 'table1'
----------
id
----------
1
2
3
4
5
6
7
My First query
$sql1 = "SELECT * FROM table1 WHERE";// some condition which gives me id's 1,2,3
$res1=$obj->_executeQuery($sql1);
$res1=$obj->getAll($res1);
The result of this is giving me array
Array
(
[0] => Array
(
[id] => 1
..
..
)
[1] => Array
(
[id] => 2
..
..
)
[2] => Array
(
[id] => 3
..
..
)
)
I want to run another query on same 'table1', where not equal to list of ID's which i am getting from the first query.
My Second Query
$sql2 = "SELECT * FROM table1 WHERE id NOT IN (" . implode(',', $res1) . ")";
This is not showing me only one id i,e first. In above case i should get id's 4,5,6,7
Since implode will not give the desired value on multidimensional array so first you need to get the array of all id's to form one-dimensional array then use implode on the array of id's:
$id=array();
foreach ($res1 as $key=>$inner_array){
$id[]= $inner_array['id'];
}
you can use array_walk also here like this:
array_walk($res1,function($c) use (&$id) {$id[] = $c['id'];});
but i think the best one is array_map :
$id = array_map(function($i) {
return $i['id'];
}, $res1);
$sql2 = "SELECT * FROM table1 WHERE id NOT IN (" . implode(',', $id) . ")";
Note: when ever you are doing select please specify your column if you need few to select,unnecessarily selecting all will slow your sql processing.
suppose here:SELECT * FROM table1 WHERE, if you need only id then please select id only.
You have to change $res1, which is a two-dimensional array, into a one-dimensional array of IDs to be able to use implode:
$ids_from_first_query = array();
foreach($res1 as $result_row) {
$ids_from_first_query[] = $result_row['id'];
}
$ids_as_string = implode(',', $ids_from_first_query);
$sql2 = 'SELECT * FROM table1 WHERE id NOT IN(' . $ids_as_string . ')';
In the above code, $ids_as_string will look like this:
1,2,3
Thus it can be used in your MySQL query
Here you are getting two dimensional array so that's reason it is not working
while($each=mysql_fetch_array($res1))
{
$array[]=$each[id];
}
$imp=implode(",",$array);
$sql2 = "SELECT * FROM table1 WHERE id NOT IN (".$imp.")";
Try this it will works
I have this PHP syntax and works as I expected :
$sqldata = mysql_query("
SELECT FirstName, LastName, NumberOfChildren, SchoolTuition FROM User WHERE User.Username = '$Username' LIMIT 1;
");
$rows = array();
while($r = mysql_fetch_assoc($sqldata)) {
$rows[] = $r;
}
echo json_encode($rows);
now, the problem is I want to calculate total school tuition (NumberOfChildren * SchoolTuition) and it must be done before json_encode() function. and my client doesn't want to add one extra column on their database.
so I must calculate this TOTAL School Tuition using PHP and put it back on $rows array as latest value of array before json_encode.
I tried calculate using mysql_fetch_array first to get $rows[2] and $rows[3], but since I already use mysql_fetch_assoc before, this mysql_fetch_array won't work.
last thing, I mysql_fetch_assoc generates 2 dimensional array. because when I use print_r($rows), I see this :
Array ( [0] => Array ( [FirstName] => Mary [LastName] => Smith [NumberOfChildren] => 3 [SchoolTuition] => 2000 ) )
while array_push function only used to push 1 dimensional array, right?
please kindly give me solution of this problem. thank you very much.
You can just do the calculation in SQL, without having to add the column.
SELECT FirstName, LastName, NumberOfChildren, SchoolTuition,
(NumberOfChildren * SchoolTuiton) AS TotalSchoolTuiton
FROM User WHERE User.Username = '$Username' LIMIT 1
SELECT FirstName, LastName, NumberOfChildren, SchoolTuition, NumberOfChildren*SchoolTuition AS TotalTuition FROM User WHERE User.Username = '$Username' LIMIT 1;
I am creating a php app and am now creating the DB interface code. In my APP their are three tables, user, network, user_network. They have the following columsn:
user<-------------------->user_network<-------------------->network
user_ID un_ID network_ID
user_Name un_Member network_Name
un_Network network_Description
I have created the following query which querys the user_network table and returns the ID's of all networks which the user is a member of:
$STH = $DBH->query("SELECT * FROM user_network WHERE nm_Member ='$userID'");
I then pull the network_ID's from this array using the following code:
$DB_NetworkID = array();
foreach($STH as $row)
{
$DB_NetworkID[$counter] = $row['nm_networkID'];
$counter++;
}
print_r($DB_NetworkID);
The array now holds of all the network IDs that the user is a member of, like so
Array ( [0] => 1 [1] => 3 [2] => 5 [3] => 7 ) //network IDs = 1, 3, 5, 7
I would now like to pull rows from the networks tables, how do i go about about SELECTing rows from the networks database WHERE the ID is contained in the array?
Thanks for any help.
You should use a JOIN instead and make it a single query:
SELECT
*
FROM
user
INNER JOIN
user_network
ON
user.user_ID = user_network.un_ID
INNER JOIN
network
ON
user_network.un_Network = network.network_ID
WHERE
user_ID = '$userID'
That query will give you all networks that a user is member of.
If your problem is the comparison against an array, then an easy workaround is using FIND_IN_SET() like this:
$list = implode(",", $DB_NetworkID); // turns it into "1,3,5,7"
... "SELECT * FROM foo WHERE FIND_IN_SET(network_ID, '$list')";
For better performance you should construct an .. IN (?,?,..) clause however.
Of course using JOIN as "halfdan" said, is the best way.
But I gonna answer your question:
If your array is like this:
$un = Array ( [0] => 1 [1] => 3 [2] => 5 [3] => 7 ) //network IDs = 1, 3, 5, 7
You can use a Foreach like this:
Foreach($un as $key => $value) {
and your query will be like this:
SELECT * FROM network WHERE network_ID ='$value'