Get value from $_GET and use it as a ID - php

Question

I have problem with reciving $_GET value, I need it as a ID to update my table.
Im using <a href='includes/edit_section.php?id=$id'>Change</a>. Variable $id is properly fetched and it is working, when I click on this link (because it is in table) it shows right value.
But problem is in next part, when I recive it with $_GET. I tryed to make variable ($id = $_GET['id']) but there is no any change.
When I execute this, nothing updates, when I replace $_GET with number it works perfectly.
My table looks like this Table(ID,Title,Paragraph,Image)
This is my code:
<?php
if(isset($_POST['submit'])) {
$title = $_POST['title'];
$paragraph = $_POST['paragraph'];
$query = "UPDATE table SET title = '{$title}', paragraph = '{$paragraph}' WHERE id = '{$_GET['id']}' ";
$c= mysqli_query($connection, $query);
}
This is my form
<form action="edit_section.php" method="post" enctype="multipart/form-data">
<div class="form-group">
<label for="title">Title</label>
<input type="text" class="form-control" name="title">
<label for="paragraph">Paragraph</label>
<input type="text" class="form-control" name="paragraph">
</div>
<div class="form-group">
<input class="btn btn-primary" type="submit" name="submit" value="cHANGE">
</div>
</form>

Answer 1

The problem is that you need to send the id when you submit the form, a traditional way of doing it is using a hidden type input, for example <input type="hidden" name="id" value="<?= $id ?>"> And of course it is necessary to pass the id to the view where the form is rendered
So you could try this
<form action="edit_section.php" method="post" enctype="multipart/form-data">
<input type="hidden" name="id" value="<?= $id ?>">
<div class="form-group">
<label for="title">Title</label>
<input type="text" class="form-control" name="title">
</div>
<div class="form-group">
<label for="paragraph">Paragraph</label>
<input type="text" class="form-control" name="paragraph">
</div>
<div class="form-group">
<input class="btn btn-primary" type="submit" name="submit" value="cHANGE">
</div>
</form>
And when processing the form
<?php
if(isset($_POST['submit'])) {
$id = $_POST['id'];
$title = $_POST['title'];
$paragraph = $_POST['paragraph'];
$query = "UPDATE table SET title = '{$title}', paragraph = '{$paragraph}' WHERE id = '{$id}' ";
$c= mysqli_query($connection, $query);
}
I separated in its respective form-group the inputs of title and paragraph

Answer 2

At top add
$id = $_GET['id'];
then
basically problem is in
<form action="edit_section.php"
it should be
<form action="edit_section.php?id=<?php echo $id;?>"
plus in your update query id should be ID (capital).. also check for other column names for case-sensitivity

Answer 3

change the action for form at HMTL like tihs
<form action="edit_section.php?<?=$_GET['id']?>" method="post" enctype="multipart/form-data">

Answer 4

Add "id" as a hidden variable in your form.
Edited - Missed out an enclosing double quote for the hidden 'id' value in the form.
<form action="edit_section.php" method="post" enctype="multipart/form-data">
<input type="hidden" name="id" value="<?php echo $_GET['id']; ?>">
<div class="form-group">
<label for="title">Title</label>
<input type="text" class="form-control" name="title">
<label for="paragraph">Paragraph</label>
<input type="text" class="form-control" name="paragraph">
</div>
<div class="form-group">
<input class="btn btn-primary" type="submit" name="submit" value="cHANGE">
</div>
</form>
Make the following changes to your PHP script
<?php
if(isset($_POST['submit'])) {
$title = $_POST['title'];
$id = $_POST['id'];
$paragraph = $_POST['paragraph'];
$query = "UPDATE table SET title = '{$title}', paragraph = '{$paragraph}' WHERE id = '{$id}' ";
$c= mysqli_query($connection, $query);
}
?>