PHP - Displaying Specific data on a text boxes - php

Question

I need to display only the id row of the database on a textbox, my problem was the data is displaying all id's rows and columns.
I was fetching all data in the database, but what I need is only the id on the database.
Here is my code in forms, input text fields and submit.
<form action="" method="POST">
<div class="row col-md-4">
<label>Amount</label>
<input type="text" name="id" class="form-control validate">
<br>
<input type="submit" class="form-control btn-warning" name="search" value="Search Data"></input><br>
<?php
$connection = mysqli_connect("localhost","root","");
$db = mysqli_select_db($connection, 'qrproject');
if(isset($_POST['search']))
{
$id = $_POST['id'];
$query = "SELECT * FROM scratch_cards WHERE amount='$id' ";
$query_run = mysqli_query($connection, $query);
while($row = mysqli_fetch_array($query_run))
{
?>
<form action="" method="POST">
<input type="text" name="code" value="<?php echo $row['code'] ?>" class="form-control validate" id="mapo">
<input type="text" name="pin" value="<?php echo $row['pin'] ?>" class="form-control validate" id="mact">
<input type="text" name="status" value="<?php echo $row['status'] ?>" class="validate form-control" id="soluong">
<input type="date" name="card_expiration" value="<?php echo $row['card_expiration'] ?>" class="validate form-control" id="cardex">
<input type="number" name="card_validity" value="<?php echo $row['card_validity'] ?>" class="validate form-control" id="cardval">
</form>
<?php
}
}
?>
</form>

Answer 1

From your comments, it seems what you want to do is output a single, random row which matches the $_POST['id'] value against the amount column in your table. You can do this by changing your query to this:
SELECT * FROM scratch_cards WHERE amount='$id' ORDER BY RAND() LIMIT 1
You can also change
while($row = mysqli_fetch_array($query_run))
to
if($row = mysqli_fetch_array($query_run))
although with the change to the query to limit the output to one row this is no longer absolutely necessary.
As has been pointed out, you are vulnerable to SQL injection, you should read this question to see how to resolve that.