how to Edit a particular id in php - php

Question

I have a page which is showing around 3000 entries. what i am trying to do is when i click on filter button the data of only that entry will change. but currently, when i click on filter button the data of all the entries are changing.
here is my code:-
<?php
include("config.php");
$sql="SELECT * FROM inventory_details where status ='0' limit 0,100";
$query=mysqli_query($conn, $sql);
while($row=mysqli_fetch_assoc($query)){
$id = $row['id'];
$inventorybackground = $row['inventorybackground'];
$inventorycolor = $row['inventorycolor'];
$firm_name = $row['firm_name'];
$position = $row['position'];
$city = $row['city'];
$catagory_name = $row['catagory_name'];
$supplier = $row['supplier'];
if (isset($_POST['update'])){
$position=$_POST['position'];
$update_query="UPDATE inventory_details SET position ='$position' WHERE id='$id'";
$run_update=mysqli_query($conn, $update_query);
}
?>
<div class="container">
<div class="row" style="background-color: <?php echo $inventorybackground; ?> !important; color: <?php echo $inventorycolor; ?>; padding-top: 10px;">
<form class="form-horizontal" method="post" enctype="multipart/form-data">
<div class="col-md-1 inventory-data">
<input type="text" class="form-control" id="id" name="id" value="<?php echo $id;?>" disabled>
</div>
<div class="col-md-3 inventory-data">
<input type="text" class="form-control" id="firm_name" name="firm_name" value="<?php echo $firm_name;?>" disabled>
</div>
<div class="col-md-1 inventory-data">
<input type="text" class="form-control" id="position" name="position" value="<?php echo $position;?>">
</div>
<div class="col-md-1 inventory-data">
<input type="text" class="form-control" id="city" name="city" value="<?php echo $city;?>" disabled>
</div>
<div class="col-md-2 inventory-data">
<input type="text" class="form-control" id="catagory_name" name="catagory_name" value="<?php echo $catagory_name;?>" disabled>
</div>
<div class="col-md-2 inventory-data">
<input type="text" class="form-control" id="supplier" name="supplier" value="<?php echo $supplier;?>" disabled>
</div>
<div class="col-md-2 inventory-data">
<button type="submit" name="update" value="update" class="btn btn-primary">Filter</button>
</div>
</form>
</div>
</div>
<?php } ?>
Currently, i am only trying to change the position and I think, this problem is because of loop.
Please help me out, Thanks in advance.

Answer 1

When you click the button, the entire list is updated on your loop to list the rows.
Add this code at your page to detect the form POST to do the update:
if ($_SERVER["REQUEST_METHOD"] === "POST") {
// perform update here
$id = $_POST['id'];
$position = $_POST['position'];
$update_query="UPDATE inventory_details SET position ='$position' WHERE id='$id'";
$run_update=mysqli_query($conn, $update_query);
}
Edit:
Your input can't be disabled, try to use input hidden to pass id to POST:
<input type="hidden" id="id" name="id" value="<?php echo $id;?>">
If you need to show the id on input text, change the name to different name istead of id, because it will be used from input hidden

Answer 2

while($row=mysqli_fetch_assoc($query)){
This has ending bracket on the end. So you are basically looping through all the data and updating it all. Do the update query outside of loop.
$update_query="UPDATE inventory_details SET position ='$position' WHERE id='$id'";
You have SQL injection vulnerability here, please use prepared statements.
https://www.w3schools.com/php/php_mysql_prepared_statements.asp
If id is integer, you dont have to put quotation marks around it