I'm trying to write an excel from a laravel controller where i have all the data in an array, and i managed to write it, but i have to format it now, this is the array that i have:
[2020-12-30 13:22:05] local.DEBUG: array (
0 =>
array (
0 => '1',
1 => '2',
),
1 =>
array (
0 => 'Test Name 1',
1 => 'Test Name 2',
),
2 =>
array (
0 => 'user',
1 => 'user2',
),
3 =>
array (
0 => '1',
1 => '2',
),
)
This is the way i'm creating the Excel:
Excel::create('Filename', function($excel) use ($budgets) {
$excel->sheet('Sheetname', function($sheet) use ($budgets) { //$budgets is the array i'm printing on Log
$sheet->fromArray($budgets);
});
})->export('xls');
And this is the way that my excel is printing it:
1
2
Test Name 1
Test Name 2
user1
user2
1
2
And the way i want to print it is:
Code
Name
User
Number
1
Test Name 1
user1
1
2
Test Name 2
user2
2
But i don't know how to achieve this. Can anyone help me with this?
//edits//
I added some code to re estructure the array, now i have this:
$users = ['Code', 'Name', 'User', 'Number'];
for ($i=0; $i<count($code); $i++){
array_push($users, array($code[$i], $name[$i], $user[$i], $number[$i]));
}
Log::debug($users);
And this is the Log:
[2020-12-30 15:17:40] local.DEBUG: array (
0 => 'Code',
1 => 'Name',
2 => 'User',
3 => 'Number',
4 =>
array (
0 => '1',
1 => 'Test Name 1',
2 => 'user1',
3 => '1',
),
5 =>
array (
0 => '2',
1 => 'Test Name 2',
2 => 'user2',
3 => '2',
),
)
But i'm getting this error:
[message] => Row `Code` must be array.
[class] => PHPExcel_Exception
You will could re-structure your array.
To get the print you want array should look like:
$budget = [
['Code', 'Name', 'User', 'Number'],
[1, 'Test Name 1', 'user1', 1],
...
];
Ok, so, i managed to re-structure the array and getting the Excel the way i wanted doing this:
public function generateExcel(Request $request)
{
$code = $request->input('code');
$name = $request->input('name');
$user = $request->input('user');
$number = $request->input('number');
$users = array();
array_push($users, array('Code', 'Name', 'User', 'Number'));
for ($i=0; $i<count($code); $i++){
array_push($users, array($code[$i], $name[$i], $user[$i], $number[$i]));
}
Excel::create('Filename', function($excel) use ($users) {
$excel->sheet('Sheetname', function($sheet) use ($users) {
$sheet->fromArray($users);
});
})->export('xls');
return true;
Related
i have a query like that:
$pd= DB::table("projects")
->orderBy("project_number", "asc")
->select('name' , "type")
->get()->keyBy('date_scheduled');;
and i get a array keyed By the date_scheduled which is fine, but the problem is date_scheduled is not unique so it overwrites the entries. So i need to get a two dimensional array with keyby date_scheduled like:
[
'date_1_of_date_scheduled' => [0 => '1', 1 => '4', 2 => '17']
'date_2_of_date_scheduled' => [0 => '15', 1 => '64', 2 => '1142']
'date_3_of_date_scheduled' => [0 => '25', 1 => '125', 2 => '66']
]
You can use groupBy() instead of keyBy(): https://laravel.com/docs/8.x/collections#method-groupby
$pd = DB::table("projects")
->orderBy("project_number", "asc")
->select('name' , "type")
->get()
->groupBy('date_scheduled');
You can use the laravel map function for the purpose
Try that:
$pd= DB::table("projects")
->orderBy("project_number", "asc")
->select('name' , "type")
->get()
->map(function ($item) {
return ['date_'.$item->date_scheduled.'_of_date_scheduled' => $item->YOUR_DESIRED_DATA] ;
}
I have the following array to show menu's based on the order the user specified.
The array is as follows:
$menuArray = [
'Main Street' => [
['/index.php', 'Home'],
['/city.php', $cityData[$user->city][0]],
['/travel.php', 'Travel'],
['/bank.php', 'Bank'],
['/inventory.php', 'Inventory'],
['/dailies.php', 'Dailies'],
],
'Activities' => [
(!$my->hospital) ? ['/hospital.php', 'Hospital'] : [],
(!$my->hospital && !$my->prison) ? ['/crime.php', 'Crime'] : [],
['/missions.php', 'Missions'],
['/achievements.php', 'Achievements'],
],
'Services' => [
['/hospital.php', 'Hospital'],
['/prison.php', 'Prison'],
['/search.php', 'Search'],
],
'Account' => [
['/edit_account.php', 'Edit Account'],
['/notepad.php', 'Notepad'],
['/logout.php', 'Logout'],
]
];
I have a column menu_order stored in the database, which has a default value of 0,1,2,3,4, but this can change per user as they will be able to change their menu to their likes.
What I'd like to achieve:
0 => Main Street
1 => Activities
2 => Services
3 => Account
4 => Communication
To get the menu order, I do
$menuOrder = explode(',', $user->menu_order);
But I'm not sure how to handle the foreach for displaying the menu.
Here's one way to do it -- use replacement rather than a sorting algorithm.
Code: (Demo)
$menuArray = [
'Main Street' => [],
'Activities' => [],
'Services' => [],
'Account' => []
];
$lookup = [
0 => 'Main Street',
1 => 'Activities',
2 => 'Services',
3 => 'Account',
4 => 'Communication'
];
$customsort = '4,2,1,3,0';
$keys = array_flip(explode(',', $customsort)); convert string to keyed array
//var_export($keys);
$ordered_keys = array_flip(array_replace($keys, $lookup)); // apply $lookup values to keys, then invert key-value relationship
//var_export($ordered_keys);
$filtered_keys = array_intersect_key($ordered_keys, $menuArray); // remove items not on the current menu ('Communication" in this case)
//var_export($filtered_keys);
$final = array_replace($filtered_keys, $menuArray); // apply menu data to ordered&filtered keys
var_export($final);
Output:
array (
'Services' =>
array (
),
'Activities' =>
array (
),
'Account' =>
array (
),
'Main Street' =>
array (
),
)
And here's another way using uksort() and a spaceship operator:
$ordered_keys = array_flip(array_values(array_replace(array_flip(explode(',', $customsort)), $lookup)));
uksort($menuArray, function($a, $b) use ($ordered_keys) {
return $ordered_keys[$a] <=> $ordered_keys[$b];
});
var_export($menuArray);
As a consequence of how your are storing your custom sort order, most of the code involved is merely to set up the "map"/"lookup" data.
You could try something like this to produce the menu:
function display_menu($menus, $m) {
if (!isset($menus[$m])) return;
echo "<ul>";
foreach ($menus[$m] as $item) {
if (!count($item)) continue;
echo "<li>{$item[1]}\n";
}
echo "</ul>";
}
$menuMap = array(0 => 'Main Street',
1 => 'Activities',
2 => 'Services',
3 => 'Account',
4 => 'Communication');
$menuOrder = explode(',', $user->menu_order);
foreach ($menuOrder as $menuIndex) {
$thisMenu = $menuMap[$menuIndex];
display_menu($menuArray, $thisMenu);
}
Small demo on 3v4l.org
** I have edited this to show how I got my code to work using array_search
I have an array, $arr1 with 5 columns as such:
key id name style age whim
0 14 bob big 33 no
1 72 jill big 22 yes
2 39 sue yes 111 yes
3 994 lucy small 23 no
4 15 sis med 24 no
5 16 maj med 87 yes
6 879 Ike larg 56 no
7 286 Jed big 23 yes
This array is in a cache, not a database.
I then have a second array with a list of id values -
$arr2 = array(0=>14, 1=>72, 2=>8790)
How do I filter $arr1 so it returns only the rows with the id values in $arr2?
I got my code to work as follows:
$arr1 = new CachedStuff(); // get cache
$resultingArray = []; // create an empty array to hold rows
$filter_function = function ($row) use ($arr2) {
return (array_search($row['id'], $arr2));
};
$resultingArrayIDs = $arr1->GetIds($filter_function, $resultingArray);
This gives me two outputs: $resultingArray & $resultingArrayIDs both of which represent the intersection of the $arr1 and $arr2.
This whole task can be accomplished with just one slick, native function call -- array_uintersect().
Because the two compared parameters in the custom callback may come either input array, try to access from the id column and if there isn't one declered, then fallback to the parameter's value.
Under the hood, this function performs sorting while evaluating as a means to improve execution time / processing speed. I expect this approach to outperform iterated calls of in_array() purely from a point of minimized function calls.
Code: (Demo)
var_export(
array_uintersect(
$arr1,
$arr2,
fn($a, $b) =>
($a['id'] ?? $a)
<=>
($b['id'] ?? $b)
)
);
Something like this should do it, provided I've understood your question and data structure correctly:
$dataArray = [
[ 'key' => 0, 'id' => 14 , 'name' => 'bob' , 'style' => 'big' , 'age' => 33 , 'whim' => 'no' ],
[ 'key' => 1, 'id' => 72 , 'name' => 'jill' , 'style' => 'big' , 'age' => 22 , 'whim' => 'yes' ],
[ 'key' => 2, 'id' => 39 , 'name' => 'sue' , 'style' => 'yes' , 'age' => 111 , 'whim' => 'yes' ],
[ 'key' => 3, 'id' => 994 , 'name' => 'lucy' , 'style' => 'small' , 'age' => 23 , 'whim' => 'no' ],
[ 'key' => 4, 'id' => 15 , 'name' => 'sis' , 'style' => 'med' , 'age' => 24 , 'whim' => 'no' ],
[ 'key' => 5, 'id' => 16 , 'name' => 'maj' , 'style' => 'med' , 'age' => 87 , 'whim' => 'yes' ],
[ 'key' => 6, 'id' => 879 , 'name' => 'Ike' , 'style' => 'larg' , 'age' => 56 , 'whim' => 'no' ],
[ 'key' => 7, 'id' => 286 , 'name' => 'Jed' , 'style' => 'big' , 'age' => 23 , 'whim' => 'yes' ]
];
$filterArray = [14, 72, 879];
$resultArray = array_filter( $dataArray, function( $row ) use ( $filterArray ) {
return in_array( $row[ 'id' ], $filterArray );
} );
View this example on eval.in
However, your question appears to suggest this data might be coming from a database; is that correct? If so, perhaps it's more efficient to pre-filter the results at the database-level. Either by adding a field in the SELECT query, that represents a boolean value whether a row matched your filter ids, or by simply not returning the other rows at all.
One way is with foreach loop with array_search()
$result = [];
foreach ($arr1 as $value) { // Loop thru $arr1
if (array_search($value['id'], $arr2) !== false) { // Check if id is in $arr2
$result[] = $value; // Push to result if true
}
}
// print result
print_r($result);
As #DecentDabbler mentioned - if the data is coming out of a database, using an IN on your WHERE will allow you to retrieve only the relevant data.
Another way to filter is to use array functions
array_column extracts the value of the id column into an array
array_intersect returns the elements which are in both $arr1['id'] and $arr2
array_flip flips the resulting array such that the indices into $arr1 indicate the elements in both $arr1 and $arr2
$arr1 = [ [ 'id' => 14, 'name' => 'bob'],
['id' => 72, 'name' => 'jill'],
['id' => 39, 'name' => 'sue'],
['id' => 994, 'name' => 'lucy'],
['id' => 879, 'name'=> 'large']];
$arr2 = [ 14,72,879 ];
$intersection = array_flip(array_intersect(array_column($arr1,'id'),$arr2));
foreach ($intersection as $i) {
var_dump($arr1[$i]);;
}
I have a simple joined table that looks like this.
NO CLASS NAME STATUS
1 1A JOHN 1
2 1A SARA 1
3 1A LYOD 1
4 1B JOHN 1
5 1B SHIN 1
I use textbox to display the CLASS and a TEXTAREA to display the NAME. The output of CLASS 1A should like this:
Class : 1A
Name : JOHN, SARA, LYOD
How to do it using the joined table only (not multiple query)?
THis is how I loop the result:
$query = $this->xxx->yyy($class_name); //JOINED RESULT
$data = array(
'titlepage' => APP_TITLEPAGE,
'record' => $query, //This is the result that is sent to the view
'complete' => 'true',
'loadmethod' => 'add',
'contentpage' => 'test_page/detail'
);
$this->load->view('shared/master_app', $data);
so your query array is something like this:
$query = [
['NO' => 1, 'CLASS' => '1A', 'NAME' => 'JOHN', 'STATUS' => '1'],
['NO' => 2, 'CLASS' => '1A', 'NAME' => 'SARA', 'STATUS' => '1'],
['NO' => 3, 'CLASS' => '1A', 'NAME' => 'LYOD', 'STATUS' => '1'],
['NO' => 4, 'CLASS' => '1B', 'NAME' => 'JOHN', 'STATUS' => '1'],
];
You may make a function that arrange it or group it
lets name it groupResults($query)
function groupResults($query) {
$result = [];
foreach($query as $queryItem) {
$result[$queryItem['CLASS']][] = $queryItem['NAME'];
}
return $result;
}
now result is looks like this:
$result = [
'1A' => ['JOHN', 'SARA', 'LYOD'],
'1B' => ['JOHN']
]
this is a snapshot of what I got:
so now you can use it like this
$query = $this->xxx->yyy($class_name); //JOINED RESULT
$data = array(
'titlepage' => APP_TITLEPAGE,
'record' => groupResults($query), //This is the result that is sent to the view
'complete' => 'true',
'loadmethod' => 'add',
'contentpage' => 'test_page/detail'
);
$this->load->view('shared/master_app', $data);
now in the view you may loop on this array as:
foreach($record as $class => $names) {
echo "<input type='text' value='" . $class . "'>";
echo "<textarea>" . implode(', ', $names) . "</textarea>";
}
If you want to add all name in same Class in one column then it can be possible by GROUP_CONCAT() mysql function.
adjust your query with GROUP_CONCAT. For an example see below
SELECT CLASS, GROUP_CONCAT(NAME)
FROM table_name
GROUP BY CLASS;
It will Output like this
1A JOHN,SARA,LYOD
2A JOHN,SHIN
You also can put custom separator between names using GROUP_COCAT separator
SELECT CLASS, GROUP_CONCAT(NAME SEPARATOR ' -- ')
FROM table_name
GROUP BY CLASS;
For reference MySql GROUP_CONCAT()
I have a question. So I have this array :
$a_list_id = array(
0 => 1234
1 => 739
3 => 538
);
And this array :
$a_users = array(
0 => array(
id => 15627,
name => test
),
1 => array(
id => 1234,
name => test1
),
2 => array(
id => 739,
name => test2
)
)
The result should be :
$a_response = array(
0 => array(
id => 1234,
name => test1
)
)
Because the id 1234 is in both arrays.
I try with array_intersect but not work. Can you help me please ?
Just use loops :
$a_response = array();
foreach ($a_users as $array) {
if (in_array($array['id'], $a_list_id)) {
$a_response []= $a_users;
}
}
array_intersect will only produce useful results if the values of both arrays can be cast to the same type. You've got an array of integers and another array of arrays, they can never* match so intersect will always be empty
If you want an intersection between the arrays then you have two options:
Index the arrays so their keys are the values you want to intersect and use array_intersect_key
Implement your own array comparison logic with array_uintersect and a callback function that knows the structure of the arrays being compared
example of the former:
$a_list_id = array(
1234 => 1234
739 => 739
538 => 538
);
$a_users = array(
15627 => array(
id => 15627,
name => test
),
1234 => array(
id => 1234,
name => test1
),
739 => array(
id => 739,
name => test2
)
)
var_dump (array_intersect_key ($a_users, $a_list_id));
Example of the latter:
var_dump (array_uintersect ($a_users, $a_list_id, function ($user, $id) {
return $user ["id"] - $id; // Result should be 0 if they match, as per documentation
}))
*They can be considered the same in the case where one value is integer 0 and the other is an empty array, but that's not very useful
Try the below code using array_search() function:
$a_list_id = array(1234, 538,739);
$a_users = array(
array(
'id'=> 15627,
'name' => 'test'
),
array(
'id' => 1234,
'name' => 'test1'
),
array(
'id' => 739,
'name' => 'test2'
)
);
foreach($a_users as $a_user){
if (in_array($a_user['id'], $a_list_id)) {
$a_response[array_search($a_user['id'], $a_list_id)] = $a_user;
}
}
print_r($a_response);
Have you tried using array_intersect_uassoc? http://php.net/manual/en/function.array-intersect-uassoc.php
function compare_ids($a, $b)
{
return $a - $b['id'];
}
print_r(array_intersect_uassoc($a_list_id, $a_users, "compare_ids"));