I have the following array to show menu's based on the order the user specified.
The array is as follows:
$menuArray = [
'Main Street' => [
['/index.php', 'Home'],
['/city.php', $cityData[$user->city][0]],
['/travel.php', 'Travel'],
['/bank.php', 'Bank'],
['/inventory.php', 'Inventory'],
['/dailies.php', 'Dailies'],
],
'Activities' => [
(!$my->hospital) ? ['/hospital.php', 'Hospital'] : [],
(!$my->hospital && !$my->prison) ? ['/crime.php', 'Crime'] : [],
['/missions.php', 'Missions'],
['/achievements.php', 'Achievements'],
],
'Services' => [
['/hospital.php', 'Hospital'],
['/prison.php', 'Prison'],
['/search.php', 'Search'],
],
'Account' => [
['/edit_account.php', 'Edit Account'],
['/notepad.php', 'Notepad'],
['/logout.php', 'Logout'],
]
];
I have a column menu_order stored in the database, which has a default value of 0,1,2,3,4, but this can change per user as they will be able to change their menu to their likes.
What I'd like to achieve:
0 => Main Street
1 => Activities
2 => Services
3 => Account
4 => Communication
To get the menu order, I do
$menuOrder = explode(',', $user->menu_order);
But I'm not sure how to handle the foreach for displaying the menu.
Here's one way to do it -- use replacement rather than a sorting algorithm.
Code: (Demo)
$menuArray = [
'Main Street' => [],
'Activities' => [],
'Services' => [],
'Account' => []
];
$lookup = [
0 => 'Main Street',
1 => 'Activities',
2 => 'Services',
3 => 'Account',
4 => 'Communication'
];
$customsort = '4,2,1,3,0';
$keys = array_flip(explode(',', $customsort)); convert string to keyed array
//var_export($keys);
$ordered_keys = array_flip(array_replace($keys, $lookup)); // apply $lookup values to keys, then invert key-value relationship
//var_export($ordered_keys);
$filtered_keys = array_intersect_key($ordered_keys, $menuArray); // remove items not on the current menu ('Communication" in this case)
//var_export($filtered_keys);
$final = array_replace($filtered_keys, $menuArray); // apply menu data to ordered&filtered keys
var_export($final);
Output:
array (
'Services' =>
array (
),
'Activities' =>
array (
),
'Account' =>
array (
),
'Main Street' =>
array (
),
)
And here's another way using uksort() and a spaceship operator:
$ordered_keys = array_flip(array_values(array_replace(array_flip(explode(',', $customsort)), $lookup)));
uksort($menuArray, function($a, $b) use ($ordered_keys) {
return $ordered_keys[$a] <=> $ordered_keys[$b];
});
var_export($menuArray);
As a consequence of how your are storing your custom sort order, most of the code involved is merely to set up the "map"/"lookup" data.
You could try something like this to produce the menu:
function display_menu($menus, $m) {
if (!isset($menus[$m])) return;
echo "<ul>";
foreach ($menus[$m] as $item) {
if (!count($item)) continue;
echo "<li>{$item[1]}\n";
}
echo "</ul>";
}
$menuMap = array(0 => 'Main Street',
1 => 'Activities',
2 => 'Services',
3 => 'Account',
4 => 'Communication');
$menuOrder = explode(',', $user->menu_order);
foreach ($menuOrder as $menuIndex) {
$thisMenu = $menuMap[$menuIndex];
display_menu($menuArray, $thisMenu);
}
Small demo on 3v4l.org
Related
foreach ($courses as $user) {
$options[$user['uid']] = [
'coursecode' => $user['coursecode'],
'coursename' => $user['coursename'],
'credithours' => $user['credithours'],
'coursetype' => $user['coursetype'],
'building' => $user['building'],
'place' => $user['place'],
'day' => $user['day'],
'time' => $user['time'],
];
}
$form['table'] = [
'#type' => 'tableselect',
'#header' => $header,
'#options' => $options,
'#empty' => t('No Courses found'),
'#js_select' => false,
'#attributes' => ['checked' => 'checked'],
];
this code generates all courses I can register is there any way to check specific values as default, I had a problem with making a specific checkbox checked
so anyhelp ?
I'm using drupal 8
//Inside your foreach loop
foreach($courses as $user) {
$default_value[$user['uid']] = 1; // use 1 or 0 as appropriate
}
// now with your table select
$form['table']['#default_value'] = $default_value;
// default_value is not provided with each options, rather an array of default values is provided in the tableselect main array.
Hope this solves your problem.
** I have edited this to show how I got my code to work using array_search
I have an array, $arr1 with 5 columns as such:
key id name style age whim
0 14 bob big 33 no
1 72 jill big 22 yes
2 39 sue yes 111 yes
3 994 lucy small 23 no
4 15 sis med 24 no
5 16 maj med 87 yes
6 879 Ike larg 56 no
7 286 Jed big 23 yes
This array is in a cache, not a database.
I then have a second array with a list of id values -
$arr2 = array(0=>14, 1=>72, 2=>8790)
How do I filter $arr1 so it returns only the rows with the id values in $arr2?
I got my code to work as follows:
$arr1 = new CachedStuff(); // get cache
$resultingArray = []; // create an empty array to hold rows
$filter_function = function ($row) use ($arr2) {
return (array_search($row['id'], $arr2));
};
$resultingArrayIDs = $arr1->GetIds($filter_function, $resultingArray);
This gives me two outputs: $resultingArray & $resultingArrayIDs both of which represent the intersection of the $arr1 and $arr2.
This whole task can be accomplished with just one slick, native function call -- array_uintersect().
Because the two compared parameters in the custom callback may come either input array, try to access from the id column and if there isn't one declered, then fallback to the parameter's value.
Under the hood, this function performs sorting while evaluating as a means to improve execution time / processing speed. I expect this approach to outperform iterated calls of in_array() purely from a point of minimized function calls.
Code: (Demo)
var_export(
array_uintersect(
$arr1,
$arr2,
fn($a, $b) =>
($a['id'] ?? $a)
<=>
($b['id'] ?? $b)
)
);
Something like this should do it, provided I've understood your question and data structure correctly:
$dataArray = [
[ 'key' => 0, 'id' => 14 , 'name' => 'bob' , 'style' => 'big' , 'age' => 33 , 'whim' => 'no' ],
[ 'key' => 1, 'id' => 72 , 'name' => 'jill' , 'style' => 'big' , 'age' => 22 , 'whim' => 'yes' ],
[ 'key' => 2, 'id' => 39 , 'name' => 'sue' , 'style' => 'yes' , 'age' => 111 , 'whim' => 'yes' ],
[ 'key' => 3, 'id' => 994 , 'name' => 'lucy' , 'style' => 'small' , 'age' => 23 , 'whim' => 'no' ],
[ 'key' => 4, 'id' => 15 , 'name' => 'sis' , 'style' => 'med' , 'age' => 24 , 'whim' => 'no' ],
[ 'key' => 5, 'id' => 16 , 'name' => 'maj' , 'style' => 'med' , 'age' => 87 , 'whim' => 'yes' ],
[ 'key' => 6, 'id' => 879 , 'name' => 'Ike' , 'style' => 'larg' , 'age' => 56 , 'whim' => 'no' ],
[ 'key' => 7, 'id' => 286 , 'name' => 'Jed' , 'style' => 'big' , 'age' => 23 , 'whim' => 'yes' ]
];
$filterArray = [14, 72, 879];
$resultArray = array_filter( $dataArray, function( $row ) use ( $filterArray ) {
return in_array( $row[ 'id' ], $filterArray );
} );
View this example on eval.in
However, your question appears to suggest this data might be coming from a database; is that correct? If so, perhaps it's more efficient to pre-filter the results at the database-level. Either by adding a field in the SELECT query, that represents a boolean value whether a row matched your filter ids, or by simply not returning the other rows at all.
One way is with foreach loop with array_search()
$result = [];
foreach ($arr1 as $value) { // Loop thru $arr1
if (array_search($value['id'], $arr2) !== false) { // Check if id is in $arr2
$result[] = $value; // Push to result if true
}
}
// print result
print_r($result);
As #DecentDabbler mentioned - if the data is coming out of a database, using an IN on your WHERE will allow you to retrieve only the relevant data.
Another way to filter is to use array functions
array_column extracts the value of the id column into an array
array_intersect returns the elements which are in both $arr1['id'] and $arr2
array_flip flips the resulting array such that the indices into $arr1 indicate the elements in both $arr1 and $arr2
$arr1 = [ [ 'id' => 14, 'name' => 'bob'],
['id' => 72, 'name' => 'jill'],
['id' => 39, 'name' => 'sue'],
['id' => 994, 'name' => 'lucy'],
['id' => 879, 'name'=> 'large']];
$arr2 = [ 14,72,879 ];
$intersection = array_flip(array_intersect(array_column($arr1,'id'),$arr2));
foreach ($intersection as $i) {
var_dump($arr1[$i]);;
}
I have a probleme with a array.
In my array that has 15,000 rows, I have columns with associated names and values (sku).
I need to show all the names and make a separate on it if the sku is equal or not to the sku that is present on my product page
Exemple : array = [ 'code' => 'name1' ,
'sku' => '123456',
'code' => 'name1',
'sku' => '456789',
'code' => 'name2',
'sku' => '4565999']
etc ..........
if sku equals sku or not in my page product, i want to show the code with distinct on this .
First you need an array of arrays structure like this:
$arr = [
[ 'code' => 'name1', 'sku' => '123456' ],
[ 'code' => 'name2', 'sku' => '456789' ],
[ 'code' => 'name3', 'sku' => '4565999' ],
.
.
.
Then you can filter your array like this:
$existing_items_on_array = array_filter($arr,
function($item) use ($existing_items_on_page){
return array_search($item["sku"], $existing_items_on_page) !== false;
});
Or better (you still need to structure an array like on first solution):
I assume your SKU's are unique. Why not make them array keys?
$item_codes = [];
foreach($arr as $item){
$item_codes[$item["sku"]] = $item["code"];
}
then you would be accessing any element's code like this:
echo $item_codes[$product["sku"]]
I have a question. So I have this array :
$a_list_id = array(
0 => 1234
1 => 739
3 => 538
);
And this array :
$a_users = array(
0 => array(
id => 15627,
name => test
),
1 => array(
id => 1234,
name => test1
),
2 => array(
id => 739,
name => test2
)
)
The result should be :
$a_response = array(
0 => array(
id => 1234,
name => test1
)
)
Because the id 1234 is in both arrays.
I try with array_intersect but not work. Can you help me please ?
Just use loops :
$a_response = array();
foreach ($a_users as $array) {
if (in_array($array['id'], $a_list_id)) {
$a_response []= $a_users;
}
}
array_intersect will only produce useful results if the values of both arrays can be cast to the same type. You've got an array of integers and another array of arrays, they can never* match so intersect will always be empty
If you want an intersection between the arrays then you have two options:
Index the arrays so their keys are the values you want to intersect and use array_intersect_key
Implement your own array comparison logic with array_uintersect and a callback function that knows the structure of the arrays being compared
example of the former:
$a_list_id = array(
1234 => 1234
739 => 739
538 => 538
);
$a_users = array(
15627 => array(
id => 15627,
name => test
),
1234 => array(
id => 1234,
name => test1
),
739 => array(
id => 739,
name => test2
)
)
var_dump (array_intersect_key ($a_users, $a_list_id));
Example of the latter:
var_dump (array_uintersect ($a_users, $a_list_id, function ($user, $id) {
return $user ["id"] - $id; // Result should be 0 if they match, as per documentation
}))
*They can be considered the same in the case where one value is integer 0 and the other is an empty array, but that's not very useful
Try the below code using array_search() function:
$a_list_id = array(1234, 538,739);
$a_users = array(
array(
'id'=> 15627,
'name' => 'test'
),
array(
'id' => 1234,
'name' => 'test1'
),
array(
'id' => 739,
'name' => 'test2'
)
);
foreach($a_users as $a_user){
if (in_array($a_user['id'], $a_list_id)) {
$a_response[array_search($a_user['id'], $a_list_id)] = $a_user;
}
}
print_r($a_response);
Have you tried using array_intersect_uassoc? http://php.net/manual/en/function.array-intersect-uassoc.php
function compare_ids($a, $b)
{
return $a - $b['id'];
}
print_r(array_intersect_uassoc($a_list_id, $a_users, "compare_ids"));
I have two sets of array ,first array contains all categories called "all", and second array contains selected categories called "selected", I want to populate this concept to multiple combo box,
$all = [
0 => [
'id'=>1,
'name' => 'news'
],
1 => [
'id'=>2,
'name' => 'tips'
],
2 => [
'id'=>3,
'name' => 'trick'
],
3 => [
'id'=>4,
'name' => 'review'
]
];
$selected = [
0 => [
'id'=>2,
'name' => 'trick'
],
1 => [
'id'=>4,
'name' => 'review'
],
];
I've try to do foreach in foreach , but i have duplicated data when show in combo box, i want to have all data from "all" shown with selected data from "selected".
i just solved my problem in deferent way , first i add default pair of key and value "sel"=>0 in "all" array set, then i loop trough array "all" and array "sel" to get similar value and when it match change sel key to 1 ,this code for further explanation
public static function compare($sel,$all){
// add sel key with default value = 0
foreach($all as $k=>$v){
$all[$k]['sel'] = 0;
}
foreach($all as $k=>$v){
foreach($sel as $k2=>$v2){
// when match change sel to 1
if($v['id'] == $v2['id']){
$all[$k]['sel'] = 1;
}
}
}
return $all;
}
final result :
$all = [
0 => [
'id'=>1,
'name' => 'news',
'sel' => 0
],
1 => [
'id'=>2,
'name' => 'tips',
'sel' => 0
],
2 => [
'id'=>3,
'name' => 'trick',
'sel' => 1
],
3 => [
'id'=>4,
'name' => 'review',
'sel' => 1
]
];
just add if condition when $all['sel'] = 1 they should be selected, thanks all :D
You can get the intersection of both arrays with array_uintersect and a custom callback function (compare).
function compare($a, $b){
if($a['id'] == $b['id']){
return 0;
}
return 1;
}
$res = array_uintersect($selected, $all,"compare");
print_r($res);
>Array ( [0] => Array ( [id] => 2 [name] => trick ) [1] => Array ( [id] => 4 [name] => review ) )
After that you only need to loop through the final array and set the corresponding check boxes.
If you want to compare by name just create another callback function.
function compare2($a, $b){
if($a['name'] == $b['name']){
return 0;
}
return 1;
}
The duplicates are caused by the inner for loop continuing to create select elements even after it has found a selected element. You can avoid having an inner loop and using php's in_array() function to check if $all is in $selected like this:
$x = '';
foreach($all as $a){
if(in_array($a, $selected)){
$x .= '<option selected>'.$a['id'].'Selected </option>';
}else{
$x .= '<option>'.$a['id'].'Not selected </option>';
}
}
echo $x;
Note that in_array will check all values of the elements, so for example element with id 2 but different name will appear as not selected. You may want to change both names to tips. I hope that helps.