I am looking to have a page with a redirect based on what is in the database.
I have a table called "nametable" and 2 columns "id" and "switch"
The id never changes, only the switch entry does. Sometimes it will have "on" as the entry, and sometimes it will have "off" as the entry (depending on what I enter in there at the time)
So I want a page where the website visitor will go to, and if the database says "on" then they will be redirected to, lets say "pageon.php" and if it says off, the visitor will be redirected to "pageoff.php"
I managed to do a simple echo to show on or off in text on the page. But I don't have the foggiest on how to have them redirected based on that.
Any thoughts on what I should search for to make this happen? And advice is appreciated.
PS. I tend to get a -1 because the site thinks I'm not specific on what I am wanting to do. If I am unclear, please tell me so I can revise before closing or -1
Thank you
EDIT: Based on the advice I was given in the comments, I have made this so far. I'm only getting a blank page though. Any thoughts?
<?php
$servername = " ";
$username = " ";
$password = " ";
$dbname = " ";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT id, switch FROM nametable";
$result = $conn->query($sql);
if ($row['switch'] == "on") header("Location: off.php"); else header("Location: on.php");
$conn->close();
?>
Try this:
<?php
$servername = " ";
$username = " ";
$password = " ";
$dbname = " ";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT id, switch FROM nametable";
$result = $conn->query($sql);
$row = $result->fetch_assoc();
if ($row['switch'] == "on"){
header("Location: off.php");
} else {
header("Location: on.php");
}
$conn->close();
?>
I got it. Thanks to the help in the comments, and the answer by #Edgaras except I made a tiny switch to have the == off, and that made it work. thank you all so much. Here is the solution.
<?php
$servername = " ";
$username = " ";
$password = " ";
$dbname = " ";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT id, switch FROM nametable";
$result = $conn->query($sql);
$row = $result->fetch_assoc();
if ($row['switch'] == "off"){
header("Location: off.php");
} else {
header("Location: on.php");
}
$conn->close();
?>
Related
I am making a profile page in which I want the user's email to be displayed. I thought this would be quite a simple code that could be achieved using the select function from the database. However, this only works for one string and I cannot seem to figure out why.
This is my original code
session_start();
$_SESSION["user"] = $username;
$_SESSION["pass"] = $password;
$_SESSION["email"] = $email;
$connection = mysqli_connect ("localhost", "root", "", "picshare");
if ($connection ->connect_error) {
die("Connection failed: " . $connection->connect_error);
}else{
$query = mysqli_query($connection, "SELECT email FROM login WHERE username='".$_SESSION["user"]."'");
$field = mysqli_fetch_assoc($query);
if (!$query)
{
die('Error: ' . mysqli_error($con));
}if(mysqli_num_rows($query) > 0){
$field = mysqli_fetch_assoc($query);
}else{
echo "error";
$conn->close();
}}
When I try and echo $field, nothing was echoed
<p class ="right uc"><?php echo($field['email']);?></p>
I retried the code, but instead of using a session, I made a variable
$host = "localhost";
$dbusername = "root";
$dbpassword = "";
$dbname = "picshare";
$user = 'Eniola Olaogun';
$conn = new mysqli ($host, $dbusername, $dbpassword, $dbname);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}else{
$query = mysqli_query($conn, "SELECT email FROM login WHERE username='".$user."'");
$field = mysqli_fetch_assoc($query);
if (!$query)
{
die('Error: ' . mysqli_error($con));
}if(mysqli_num_rows($query) > 0){
$field = mysqli_fetch_assoc($query);
echo($field['email']);
}else{
echo "error";
$conn->close();
This code displayed the email, and so I proceeded to change the $user variable to another name and the original problem occurred where nothing was echoed.
I went back to the original code and I logged in as Eniola Olaogun and the email was echoed, but as soon as I changed the person I logged in as, no email was echoed.
I am not sure why I am experiencing this problem and some help would be greatly appreciated
$host = "localhost";
$dbusername = "root";
$dbpassword = "";
$dbname = "picshare";
$user = 'Eniola Olaogun';
$conn = new mysqli ($host, $dbusername, $dbpassword, $dbname);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
else {
$sql = "SELECT email FROM login WHERE username= {$user}";
$result = $conn->query($sql);
if($result->num_rows > 0) {
$row = mysqli_fetch_array($result,MYSQLI_ASSOC);
echo($row['email']);
}
else {
echo "error";
$conn->close();
error connecting to mysql database through crazy domains
It sounds like it is a permission issue based on the user you're logging in as.
Test it with a 'root' user password that has global access and then troubleshoot and isolate it from there. I'm betting you will find it then.
Pretty much impossible for me to test this remotely since I don't have your DB schema and user accounts to validate with.
I've been trying to figure out how to insert data into mySQL database for a long time. When I try to insert data, it returns "no database selected". I'm not too sure what's wrong with the code, could someone check it out?
<?php
$servername = "localhost";
$database= "learnsc2_ts";
$username = "learnsc2_admin";
$password = "Ts#123";
$conn = new mysqli($servername, $username, $password, $database);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
else {
echo "Connection successful";
}
$query = "INSERT INTO users(fname, lname) VALUES ('Owen',
'Feng')";
mysqli_query($conn, $query);
if (mysqli_query($conn, $query)) {
echo "New record created successfully";
} else {
echo "Error: " . $query . "<br>" . mysqli_error($conn);?>
Make sure your database name is correct.
i tested it in my local, It's work Just fine.
$servername = "localhost";
$database= "test";
$username = "root";
$password = "";
$conn = new mysqli($servername, $username, $password, $database);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$query = "INSERT INTO users(fname, lname) VALUES ('Owen',
'Feng')";
$query = mysqli_query($conn, $query);
if ($query) {
echo "New record created successfully";
} else {
echo "Error: " . $query . "<br>" . mysqli_error($conn);
}
You forgot to add database name
$conn = new mysqli($servername, $username, $password, $database);
I figured it out. Something was wrong with the old username I was using. After changing to a new username and database, it worked out!
Im still new in PHP, I'd like help in a php example where I click a link, a value gets updated in mysql and redirect the user to a page.
Your will be greatly appreciated.
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "UPDATE MyGuests SET lastname='Doe' WHERE id=2";
if ($conn->query($sql) === TRUE) {
// if all ok, redirecting
header("Location: http://example.com/myOtherPage.php");
die();
} else {
echo "Error updating record: " . $conn->error;
}
$conn->close();
?>
Ok, so it seems like my SELECT count query doesn't work here:
<?php
$servername = " ";
$username = " ";
$password = " ";
$dbname = " ";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
if (isset($_POST['submitted1'])) {
$result= mysqli_query("SELECT COUNT (Motspillerid)
FROM SESSION
WHERE Motspillerid= 3 ");
echo $result ;
} else {
echo "Wrong" ;
}
?>
And when I press submitt nothing happens, I don't get any error message and I don't get the result. So it's something wrong with the SELECT query I guess.
I'm noob I know, I'm new to this.
:)
You're not calling mysqli_query() correctly, the first argument has to be the database connection object returned by mysqli_connect.
And after performing the query, you have to fetch the results using one of the mysqli_fetch_X() functions.
if (isset($_POST['submitted1'])) {
$result= mysqli_query($conn, "SELECT COUNT(*) AS count
FROM SESSION
WHERE Motspillerid= 3 ");
$row = mysqli_fetch_assoc($result);
echo $row['count'];
} else {
echo "Wrong" ;
}
i am testing my database by executing some MySQLi statements
in this case : i want to display all the records of 2 specefic rows (name,score)
i checked how to do such thing in PHP , and i did it
problem is , the page is not showing anything at all , (blank empty page)
My code :
<?php
$servername = "sql3.freesqldatabase.com";
$username = "MY USERNAME";
$password = "MY PASSWORD";
$dbname = "MY DBNAME";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT name,score FROM Scores");
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "Name: " . $row["name"]. " " . $row["score"]. "<br>";
}
} else {
echo "0 results";
}
$conn->close();
?>
and , i executed the same query in phpMyAdmin Control Panel , and it worked
What have i done wrong ?
This line
$sql = "SELECT name,score FROM Scores");
Should be
$sql = "SELECT name,score FROM Scores";
This syntax error will cause an error and your environment is likely suppressing errors/warnings.