SELECT COUNT if statement - php

Ok, so it seems like my SELECT count query doesn't work here:
<?php
$servername = " ";
$username = " ";
$password = " ";
$dbname = " ";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
if (isset($_POST['submitted1'])) {
$result= mysqli_query("SELECT COUNT (Motspillerid)
FROM SESSION
WHERE Motspillerid= 3 ");
echo $result ;
} else {
echo "Wrong" ;
}
?>
And when I press submitt nothing happens, I don't get any error message and I don't get the result. So it's something wrong with the SELECT query I guess.
I'm noob I know, I'm new to this.
:)

You're not calling mysqli_query() correctly, the first argument has to be the database connection object returned by mysqli_connect.
And after performing the query, you have to fetch the results using one of the mysqli_fetch_X() functions.
if (isset($_POST['submitted1'])) {
$result= mysqli_query($conn, "SELECT COUNT(*) AS count
FROM SESSION
WHERE Motspillerid= 3 ");
$row = mysqli_fetch_assoc($result);
echo $row['count'];
} else {
echo "Wrong" ;
}

Related

how to use database data to determine what action to take

I am looking to have a page with a redirect based on what is in the database.
I have a table called "nametable" and 2 columns "id" and "switch"
The id never changes, only the switch entry does. Sometimes it will have "on" as the entry, and sometimes it will have "off" as the entry (depending on what I enter in there at the time)
So I want a page where the website visitor will go to, and if the database says "on" then they will be redirected to, lets say "pageon.php" and if it says off, the visitor will be redirected to "pageoff.php"
I managed to do a simple echo to show on or off in text on the page. But I don't have the foggiest on how to have them redirected based on that.
Any thoughts on what I should search for to make this happen? And advice is appreciated.
PS. I tend to get a -1 because the site thinks I'm not specific on what I am wanting to do. If I am unclear, please tell me so I can revise before closing or -1
Thank you
EDIT: Based on the advice I was given in the comments, I have made this so far. I'm only getting a blank page though. Any thoughts?
<?php
$servername = " ";
$username = " ";
$password = " ";
$dbname = " ";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT id, switch FROM nametable";
$result = $conn->query($sql);
if ($row['switch'] == "on") header("Location: off.php"); else header("Location: on.php");
$conn->close();
?>
Try this:
<?php
$servername = " ";
$username = " ";
$password = " ";
$dbname = " ";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT id, switch FROM nametable";
$result = $conn->query($sql);
$row = $result->fetch_assoc();
if ($row['switch'] == "on"){
header("Location: off.php");
} else {
header("Location: on.php");
}
$conn->close();
?>
I got it. Thanks to the help in the comments, and the answer by #Edgaras except I made a tiny switch to have the == off, and that made it work. thank you all so much. Here is the solution.
<?php
$servername = " ";
$username = " ";
$password = " ";
$dbname = " ";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT id, switch FROM nametable";
$result = $conn->query($sql);
$row = $result->fetch_assoc();
if ($row['switch'] == "off"){
header("Location: off.php");
} else {
header("Location: on.php");
}
$conn->close();
?>

Select and print out Data from MySQL with php, not working

I have a table ("module databas") in a database in MySQL and I need to print out that table (very simple, two rows "Fnamn" and "Enamn" with names in it) on the server by writing a php script and using MySQL. Problem is : it doesn't work. The html part of the document (.php) works perfectly fine (the h1 appears on the screen) but I get nothing else. What could be the problem ?
Tried a few different ways to do it, even by copy/pasting from w3 schools (https://www.w3schools.com/php/php_mysql_select.asp) and changing a few variables, but nothing (had a "0 results" with this W3 one, and now nothing with the new one).
<h1>Script modul</h1>
<?php
$servername = "localhost";
$username = "antony";
$password = "thepassword";
$dbname = "antony";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$query = "SELECT * FROM moduledatabas";
$result = mysqli_query($query);
if (!$result) {
$message = 'Invalid query: ' . mysqli_error() . "\n";
$message .= 'Whole query: ' . $query;
die($message);
}
while ($row = mysqli_fetch_assoc($result)) {
echo $row['Fnamn'];
echo $row['Enamn'];
}
mysqli_free_result($result);
You have not pass $conn in your mysqli_query(),just change your code like below :
$query = "SELECT * FROM moduledatabas";
$result = mysqli_query($conn,$query);
For more info refer mysqli_query

Get rows from database

I have a connection where i want to get some data from my database.
I have inserted some data but now i want to retreive it but i get NULL.
I have no idea why.
<?php
require "connect.php";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT * FROM tbltemperature ORDER BY time DESC LIMIT 1";
$result = $conn->query($sql);
var_dump($results);
$t = 0;
while($row = $result->fetch_assoc()) {
$weather[] = array(
$row["time"],
$row["inside_temperature"]
);
echo $row["time"];
echo $row["inside_temperature"];
}
$conn->close();
?>
check var_dump($results); , it looks like it should be var_dump($result);
otherwise you should check $result->num_rows() first to know if there is any row available.
Firstly you have to check your query in phpmyadmin query is working or not. If working you should try to var_dump($result); and after
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "<br> time: ". $row["time"]. " - inside_temperature: ". $row["inside_temperature"]."<br>";
}
} else {
echo "0 results";
}

PHP SELECT * FROM not working

I am trying to query data from a table using the following script:
//connect file
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
//connect file included above - ECHO tested and it is connected as $conn
$sql = "SELECT * FROM userInfo";
$results = $conn->query($sql);
if (!$results) {
printf("Errormessage: %s\n", $conn->error);
exit;
} else {
echo $row['username'];
}
UPDATE --
It now no longer tries to throw an error and seems to go to the else section; however, no echo - and the spelling is correct this time and the column is filled.
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo $row["username"];
}
} else {
echo "0 results";
}
This now returns results. Thank you #Fred -ii- especially for your help on this.
Also thanks #jjczopek for the error checking advice!

not able to show all records in my database

i am testing my database by executing some MySQLi statements
in this case : i want to display all the records of 2 specefic rows (name,score)
i checked how to do such thing in PHP , and i did it
problem is , the page is not showing anything at all , (blank empty page)
My code :
<?php
$servername = "sql3.freesqldatabase.com";
$username = "MY USERNAME";
$password = "MY PASSWORD";
$dbname = "MY DBNAME";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT name,score FROM Scores");
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "Name: " . $row["name"]. " " . $row["score"]. "<br>";
}
} else {
echo "0 results";
}
$conn->close();
?>
and , i executed the same query in phpMyAdmin Control Panel , and it worked
What have i done wrong ?
This line
$sql = "SELECT name,score FROM Scores");
Should be
$sql = "SELECT name,score FROM Scores";
This syntax error will cause an error and your environment is likely suppressing errors/warnings.

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