I've been trying to figure out how to insert data into mySQL database for a long time. When I try to insert data, it returns "no database selected". I'm not too sure what's wrong with the code, could someone check it out?
<?php
$servername = "localhost";
$database= "learnsc2_ts";
$username = "learnsc2_admin";
$password = "Ts#123";
$conn = new mysqli($servername, $username, $password, $database);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
else {
echo "Connection successful";
}
$query = "INSERT INTO users(fname, lname) VALUES ('Owen',
'Feng')";
mysqli_query($conn, $query);
if (mysqli_query($conn, $query)) {
echo "New record created successfully";
} else {
echo "Error: " . $query . "<br>" . mysqli_error($conn);?>
Make sure your database name is correct.
i tested it in my local, It's work Just fine.
$servername = "localhost";
$database= "test";
$username = "root";
$password = "";
$conn = new mysqli($servername, $username, $password, $database);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$query = "INSERT INTO users(fname, lname) VALUES ('Owen',
'Feng')";
$query = mysqli_query($conn, $query);
if ($query) {
echo "New record created successfully";
} else {
echo "Error: " . $query . "<br>" . mysqli_error($conn);
}
You forgot to add database name
$conn = new mysqli($servername, $username, $password, $database);
I figured it out. Something was wrong with the old username I was using. After changing to a new username and database, it worked out!
Related
I want to set up a website with a form in it. The form will transfer the data to the DB, but I think it is not safe to let the personal data in the DB which is external reachable.
So I thought I should transfer the data via PHP from the DB1(server1 - external reachable) to DB2(server2 - only internal reachable).
The following picture should help to know what I am searching for.
Is there any names/methods to google for?
From php you just have to create a new connection for DB2.
<?php
$servername = "localhost";
$username = "database1";
$password = "xxxxxxxx";
$dbname = "database1";
$servername2 = "localhost";
$username2 = "database2";
$password2 = "xxxxxxxx";
$dbname2 = "database2";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
$conn2 = new mysqli($servername2, $username2, $password2, $dbname2);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
if ($conn2->connect_error) {
die("Connection failed: " . $conn2->connect_error);
}
//escape variables for security
$fname = mysqli_real_escape_string($conn, $_POST['fname']);
$lname = mysqli_real_escape_string($conn, $_POST['lname']);
$sql = "INSERT INTO mytable (fname,lname)
VALUES ('$fname','$lname')";
if ($conn->query($sql) === TRUE) {
echo "Successfully Saved";
} else {
echo "Error: Go back and Try Again ! " . $sql . "<br>" . $conn->error;
}
if ($conn2->query($sql) === TRUE) {
echo "Successfully Saved";
} else {
echo "Error: Go back and Try Again ! " . $sql . "<br>" . $conn2->error;
}
$conn->close();
$conn2->close();
?>
I have very strange problem. I want to run mysql query as it is shown down below, but it's not working. Connection to database is successful, INSERT query is ok too, because when I run it directly in phpmyadmin Console it works, but it's not working here in PHP code.
Could you tell me what I'm missing?
$servername = "localhost";
$username = "admin";
$password = "admin123";
$dbname = "database1";
$conn = mysqli_connect($servername, $username, $password, $dbname);
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
$sql = "INSERT INTO last_visit (ip, lastvisit) VALUES ('123', '123')";
You need to run your $sql, because now your $sql is only a string, it does nothing.
Add this :
if ($conn->query($sql) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
function inseartinto()
{
$DEL_LOG_REP = $connection->prepare("DELETE FROM test WHERE itemname='111'")$DEL_LOG_REP->execute()$DEL_LOG_REP->close()return $DEL_LOG_REP
}
This is short tutorails on connection in insert query into php...
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "INSERT INTO MyGuests (firstname, lastname, email)
VALUES ('John', 'Doe', 'john#example.com')";
if ($conn->query($sql) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$conn->close();
?>
For more better understand..go to http://www.w3schools.com/php/default.asp
What code are you trying to writing man..
This is not a valid code for just not insert but also for connetion..
ya go onto W3School.com as mention by #Sasa.D... it provide you with knowledge from basic to expertise..
I'm not exactly sure what happened but this database and the php effecting it were working just fine until it hit the fourth row and now it won't insert new records at all.
if($_POST)
{
$servername = ******;
$username = ******;
$password = ******;
$db = ******;
$conn = mysqli_connect($servername, $username, $password, $db);
mysqli_select_db($conn,$db);
$uuid = $_POST['uuid'];
$sql = "INSERT INTO uuid VALUES ('$uuid');";
mysqli_query($conn,$sql);
mysqli_close($conn);
}
I'm not sure what happened but this is the relevant code for the mysqli query.
try this
<?php
if(isset($_POST['uuid']))
{
$servername = yourServerName;
$username = username;
$password = password;
$dbname = databaseName;
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
$uuid = $_POST['uuid'];
$sql = "INSERT INTO tableName (columnName) VALUES ('$uuid')";
if (mysqli_query($conn, $sql)) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . mysqli_error($conn);
}
mysqli_close($conn);
}
?>
Also, I recommend using prepared statements.
I have problem with MySQL database, I can't insert the information into the table. My php code seems to work, but when I run it nothing happens.
<?php
$servername = "localhost";
$fname = "fname";
$lname = "lname";
$klas = "klas";
$nomer = "nomer";
$file = "dom";
$dbname = "homeworks";
$conn = new mysqli($servername, $fname, $lname,$klas,$file,$dbname);
$sql = "INSERT INTO student (fname, lname,klas,file)
VALUES ($servername, $fname, $lname,$klas,$file,)";
?>
You have three main problems in your code:
You're still not connected to the database
Only constructing and not executing
Having not matched parameters in the insert values
Solution :
1. Make a connection first
$conn = new mysqli($servername, $username, $password, $dbname);
The Parameter $servername, $username, $password, $dbname is obviously your hostname, Database Username, Password and the Database name
You should not have your table name or column names in the connection parameters
2. Construct the parameters which matches the coloumn name and variables correctly
$sql = "INSERT INTO student (fname, lname,klas,file)
VALUES ($fname, $lname,$klas,$file)";
3. Execute Your Query :
if ($conn->query($sql) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
Note :
Also it's good practice to close your connection once you are done
$conn->close();
So, you should be having something like this
<?php
$servername = "localhost";
$username = "YourDBUsername";
$password = "YourDBPassword";
$fname = "fname";
$lname = "lname";
$klas = "klas";
$nomer = "nomer";
$file = "dom";
$dbname = "homeworks"; //Hope you will have your db name here
$conn = new mysqli($servername, $username, $password, $dbname);
$sql = "
INSERT INTO student (fname, lname,klas,file) VALUES
('$fname'
,'$lname'
,'$klas'
,'$file');
";
if ($conn->query($sql) === TRUE) {
echo "New record inserted successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
$conn->close();
Advice :
Always use prepared statements else clean your inputs before you insert.
Your connection should look something like this. link
<?php
//change the data into your connection data
$conn = mysqli_connect("localhost","my_user","my_password","my_db");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
?>
You made your query but didn't execute it.
if (mysqli_query($conn, $sql)) {
echo 'records created successfully<br>';
} else {
echo $sql . '"<br>"' . mysqli_error($conn);
}