I am not familiar with PHP at all and had a quick question.
I have 2 variables pricePerUnit and InvoicedUnits. Here's the code that is setting these to values:
$InvoicedUnits = ((string) $InvoiceLineItem->InvoicedUnits);
$pricePerUnit = ((string) $InvoiceLineItem->PricePerUnit);
If I output this, I get the correct values. Lets say 5000 invoiced units and 1.00 for price.
Now, I need to show the total amount spent. When I multiply these two together it doesn't work (as expected, these are strings).
But I have no clue how to parse/cast/convert variables in PHP.
What should I do?
$rootbeer = (float) $InvoicedUnits;
Should do it for you. Check out Type-Juggling. You should also read String conversion to Numbers.
You want the non-locale-aware floatval function:
float floatval ( mixed $var ) - Gets the float value of a string.
Example:
$string = '122.34343The';
$float = floatval($string);
echo $float; // 122.34343
Well, if user write 1,00,000 then floatvar will show error. So -
floatval(preg_replace("/[^-0-9\.]/","",$input));
This is much more reliable.
Usage :
$input = '1,03,24,23,434,500.6798633 this';
echo floatval(preg_replace("/[^-0-9\.]/","",$input));
Dealing with markup in floats is a non trivial task. In the English/American notation you format one thousand plus 46*10-2:
1,000.46
But in Germany you would change comma and point:
1.000,46
This makes it really hard guessing the right number in multi-language applications.
I strongly suggest using Zend_Measure of the Zend Framework for this task. This component will parse the string to a float by the users language.
you can follow this link to know more about How to convert a string/number into number/float/decimal in PHP.
HERE IS WHAT THIS LINK SAYS...
Method 1: Using number_format() Function. The number_format() function is used to convert a string into a number. It returns the formatted number on success otherwise it gives E_WARNING on failure.
$num = "1000.314";
//Convert string in number using
//number_format(), function
echo number_format($num), "\n";
//Convert string in number using
//number_format(), function
echo number_format($num, 2);
Method 2: Using type casting: Typecasting can directly convert a string into a float, double, or integer primitive type. This is the best way to convert a string into a number without any function.
// Number in string format
$num = "1000.314";
// Type cast using int
echo (int)$num, "\n";
// Type cast using float
echo (float)$num, "\n";
// Type cast using double
echo (double)$num;
Method 3: Using intval() and floatval() Function. The intval() and floatval() functions can also be used to convert the string into its corresponding integer and float values respectively.
// Number in string format
$num = "1000.314";
// intval() function to convert
// string into integer
echo intval($num), "\n";
// floatval() function to convert
// string to float
echo floatval($num);
Method 4: By adding 0 or by performing mathematical operations. The string number can also be converted into an integer or float by adding 0 with the string. In PHP, performing mathematical operations, the string is converted to an integer or float implicitly.
// Number into string format
$num = "1000.314";
// Performing mathematical operation
// to implicitly type conversion
echo $num + 0, "\n";
// Performing mathematical operation
// to implicitly type conversion
echo $num + 0.0, "\n";
// Performing mathematical operation
// to implicitly type conversion
echo $num + 0.1;
Use this function to cast a float value from any kind of text style:
function parseFloat($value) {
return floatval(preg_replace('#^([-]*[0-9\.,\' ]+?)((\.|,){1}([0-9-]{1,3}))*$#e', "str_replace(array('.', ',', \"'\", ' '), '', '\\1') . '.\\4'", $value));
}
This solution is not dependant on any locale settings. Thus for user input users can type float values in any way they like. This is really helpful e.g. when you have a project wich is in english only but people all over the world are using it and might not have in mind that the project wants a dot instead of a comma for float values.
You could throw javascript in the mix and fetch the browsers default settings but still many people set these values to english but still typing 1,25 instead of 1.25 (especially but not limited to the translation industry, research and IT)
I was running in to a problem with the standard way to do this:
$string = "one";
$float = (float)$string;
echo $float; : ( Prints 0 )
If there isn't a valid number, the parser shouldn't return a number, it should throw an error. (This is a condition I'm trying to catch in my code, YMMV)
To fix this I have done the following:
$string = "one";
$float = is_numeric($string) ? (float)$string : null;
echo $float; : ( Prints nothing )
Then before further processing the conversion, I can check and return an error if there wasn't a valid parse of the string.
For the sake of completeness, although this question is ancient, it's worth mentioning the filter_var() set of functions, which should not only handle the formatting bits itself, but also validate or sanitise the output, thus being safer to use in the context of a form being filled in by users (or, eventually, a database that might have some corrupted/inconsistent fields):
$InvoicedUnits = (float) filter_var($InvoiceLineItem->InvoicedUnits,
FILTER_SANITIZE_NUMBER_FLOAT, FILTER_FLAG_ALLOW_FRACTION));
$pricePerUnit = (float) filter_var($InvoiceLineItem->PricePerUnit,
FILTER_SANITIZE_NUMBER_FLOAT, FILTER_FLAG_ALLOW_FRACTION));
printf("The total is: %.2f\n", $InvoicedUnits * $pricePerUnit); // both are now floats and the result is a float, formatted to two digits after the decimal sign.
This sanitises the output (which will still remain a string) and will accept the current locale's setting of the decimal separator (e.g. dot vs. comma); also, there are more options on the PHP manual for validation (which will automatically convert the result to a float if valid). The results will be slightly different for different scenarios — e.g. if you know in advance that the $InvoiceLineItem will only have valid digits and symbols for floating-point numbers, or if you need to 'clean up' the field first, getting rid of whitespace, stray characters (such as currency symbols!), and so forth.
Finally, if you wish to have nicely-formatted output — since the total is expressed in a currency — you should also take a look at the built-in NumberFormatter class, and do something like:
$InvoicedUnits = (float) filter_var($InvoiceLineItem->InvoicedUnits,
FILTER_SANITIZE_NUMBER_FLOAT, FILTER_FLAG_ALLOW_FRACTION));
$pricePerUnit = (float) filter_var($InvoiceLineItem->PricePerUnit,
FILTER_SANITIZE_NUMBER_FLOAT, FILTER_FLAG_ALLOW_FRACTION));
$fmt = new NumberFormatter('de_DE', NumberFormatter::CURRENCY);
echo 'Total is: ' . $fmt->formatCurrency($InvoicedUnits * $pricePerUnit, 'EUR') . PHP_EOL;
This will also handle thousand separators (spaces, dots, commas...) according to the configured locale, and other similar fancy things.
Also, if you wish, you can use '' (the empty string) for the default locale string (set either by the server or optionally by the browser) and $fmt->getSymbol(NumberFormatter::INTL_CURRENCY_SYMBOL) to get the default 3-letter currency code (which might not be what you want, since usually prices are given in a specific currency — these functions do not take currency exchange rates into account!).
If you need to handle values that cannot be converted separately, you can use this method:
try {
// use + 0 if you are accounting in cents
$doubleValue = trim($stringThatMightBeNumeric) + 0.0;
} catch (\Throwable $th) {
// bail here if you need to
}
Related
I need execute json_encode() and convert my original number from:
50610101800060384093800100001010000000056199999999
to
"50610101800060384093800100001010000000056199999999"
But it return
5.061010180006E+49
I tried this:
ini_set('precision', 30); //With 1, 30, 50, 100, 1000
ini_set('serialize_precision', -1);
'content' => json_encode($params, JSON_NUMERIC_CHECK)
but doesn't work. Can you help me?
50610101800060384093800100001010000000056199999999 exceeds the value of the maximum integer in PHP and so it is promoted to a float and expressed in scientific notation. The float result may be problematic for various reasons as the Manual explains in warning about floating point precision.
If you wish to express the value as if it were an integer you must encapsulate it in a string. That string you may add zero to it but when you do so the result in scientific notation will refer to a float, as follows:
<?php
$s = "50610101800060384093800100001010000000056199999999";
echo $s,"\n";
$x = $s + 0;
echo $x, "\n",is_float($x);
See here.
For more info in re PHP and floats, see here.
On the other hand, if there were an array of numbers whose digits corresponded to the numerical display in the OP's post, you could write code as follows:
<?php
$a = [5,0,6,1,0,1,0,1,8,0,0,0,6,0,3,8,4,0,9,3,8,0,0,1,0,0,0,0,1,0,1,0,0,0,0,0,0,0,0,5,6,1,9,9,9,9,9,9,9,9];
foreach($a as $e) {
$e = (string) $e;
}
$foo = join($a);
var_dump($foo);
$foo = bcadd($foo, 1);
var_dump($foo);
See live code.
The reason this example works is because each array value is converted to a numerical string and then the individual elements are joined to form one very long numerical string. BC Math is an extension in PHP which supports arbitrary precision. In this case, the bcadd() function adds one to the numerical string which results in the display of an incremented numerical string value.
Try This [https://3v4l.org/biNJG][1]
If you want this output "50610101800060384093800100001010000000056199999999"
you may want to pass this Value as string after encoding the value to JSON using json_encode
An integer data type is a non-decimal number between -2,147,483,648 and 2,147,483,647.
Rules for integers:
An integer must have at least one digit
An integer must not have a decimal point
An integer can be either positive or negative
Integers can be specified in three formats: decimal (10-based), hexadecimal (16-based - prefixed with 0x) or octal (8-based - prefixed with 0)
I am trying to create an ecommerce store and our prices need to fluctuate with the exchange rate for different countries so I'm dealing with a lot of decimal places.
What I want to do is round the original price to the nearest full number (as in they can keep the change). But then I want to format that as a currency with two decimal places.
<?php
$number = 12345.6789;
echo $number; // outputs '12345.6789'
$number = number_format($number,0);
echo $number; // outputs '12,346'
$number = number_format($number,2);
echo $number; // outputs '12.00'
?>
After formatting to no decimal places it starts reading the ',' as the decimal separator instead of the thousands separator and formats that for two decimal places.
It also gives the following error:
A non well formed numeric value encountered in C:\wamp64\www\Lifting365\test.php on line 6
How can I achieve what I am looking for?
As specified in the documentation, number_format returns a string value, you can't reuse it as a number.
Use the function round() to round your number, if you want to round it to the direct upper integer use ceil() instead.
number_format(round(12345.6789), 2);
// apply intval to get the low integer value (for change purposes)
$number = 12345.6789;
echo $number; // outputs '12345.6789'
echo intval($number)."<br/>"; // outputs '12345'
echo number_format(intval($number),0,'.','.'); // outputs '12.345'
echo number_format(intval($number),0,'.',','); // outputs '12,345'
Use round function and then number_format.
// returns 12,346.00
number_format(round(12345.6789), 2);
The function number_format accepts 4 parameters. Per default a point will be used as decimal seperator and comma as thousands seperator (12345.6789 become 12,346 after your first call; as excepted). It's not explicitly documented but number_format also rounds.
http://php.net/manual/de/function.number-format.php
string number_format ( float $number , int $decimals = 0 , string $dec_point = "." , string $thousands_sep = "," )
You are getting an error because you reuse the same variable $number. After your first call to number_format you dont have a float value anymore.
<?php
$number = 12345.6789;
echo $number."<br>"; // outputs 12345.6789
echo number_format($number,0)."<br>"; // outputs 12,346
echo number_format($number,2)."<br>"; // outputs 12,345.68
?>
If you are not sure what is in your variable you can apply floatval to it.
echo number_format(floatval($number),2);
The PHP function that you're looking for is money_format() http://php.net/manual/en/function.money-format.php have a good read through the manual page (including the comments)
I need to multiply this POST variable by 12. As an example, if the amount was 10, the result should say:
Amount: 120
Here's my code so far:
Amount :'.$_POST['my_amount'].'<br/>
I tried to run the calculation in another variable, but this doesn't seem to work:
$result = ($_POST['my_amount'])*12;
or maybe it works and my output code is not working:
$vl_text='';
Amount :'.$_POST['my_amount'].'<br/>'.;
If you want your output to resemble your first example.,.. Amount:120 your missing chunks in each of the following 3 examples. first ensure that your $_POST variable is a valid one and set it to a new variable so you can print out the variable if you need to ...
// if you only expect $_POST['my_amount'] to contain integers...
if(is_int(intval($_POST['my_amount']))){
$my_amount = intval($_POST['my_amount']) * 12;
// or if you expect $_POST['my_amount'] to possibly contain a decimal
if(is_float(floatval($_POST['my_amount']))){
$my_amount = floatval($_POST['my_amount']) * 12;
intval ensures that a variable is cast as an integer if it can be, while not entirely necessary as multiplying in php will do this...its good practice to check any variables that you are using for and math functionality.
floatval does the same for for numbers with decimal. as an integer has to be a whole number if your variable could numbers that could contain decimals... use floatval
all of your examples then need to specify to print/echo the string....so
// your second line
echo 'Amount :'.$my_amount .'<br/>';
// your fourth line...
$vl_text='Amount: '.$my_amount;
echo $vl_text;
}
The most logical explanation is that you get string from POST. A good way to achieve what you want is to convert the POST value to int but keep in mind that it could not be numerical.
$int = (is_numeric($_POST['my_amount']) ? (int)$_POST['my_amount'] : 0); //If POST value is numeric then convert to int. If it's not numeric then convert it to 0
$_POST['my_amount'] = 150;
$data = $_POST['my_amount'] * 12;
echo $data;
Result will be 1800
When I do this typecasting:
(float) '0.00';
I get 0. How do I get 0.00 and still have the data type as a float?
A float doesn't have 0 or 0.00 : those are different string representations of the internal (IEEE754) binary format but the float is the same.
If you want to express your float as "0.00", you need to format it in a string, using number_format :
$numberAsString = number_format($numberAsFloat, 2);
As far as i know there is no solution for PHP to fix this. All other (above and below) answers given in this thread are nonsense.
The number_format function returns a string as result as written in PHP.net's own specification.
Functions like floatval/doubleval do return integers if you give as value 3.00 .
If you do typejuggling then you will get an integer as result.
If you use round() then you will get an integer as result.
The only possible solution that i can think of is using your database for type conversion to float. MySQL for example:
SELECT CAST('3.00' AS DECIMAL) AS realFloatValue;
Execute this using an abstraction layer which returns floats instead of strings and there you go.
JSON output modification
If you are looking for a solution to fix your JSON output to hold 2 decimals then you can probably use post-formatting like in the code below:
// PHP AJAX Controller
// some code here
// transform to json and then convert string to float with 2 decimals
$output = array('x' => 'y', 'price' => '0.00');
$json = json_encode($output);
$json = str_replace('"price":"'.$output['price'].'"', '"price":'.$output['price'].'', $json);
// output to browser / client
print $json;
exit();
Returns to client/browser:
{"x":"y","price":0.00}
0.00 is actually 0. If you need to have the 0.00 when you echo, simply use number_format this way:
number_format($number, 2);
You can show float numbers
with a certain number of decimals
with a certain format (localised)
i.e.
$myNonFormatedFloat = 5678.9
$myGermanNumber = number_format($myNonFormatedFloat, 2, ',', '.'); // -> 5.678,90
$myAngloSaxonianNumber = number_format($myNonFormatedFloat, 2, '.', ','); // -> 5,678.90
Note that, the
1st argument is the float number you would like to format
2nd argument is the number of decimals
3rd argument is the character used to visually separate the decimals
4th argument is the character used to visually separate thousands
Use the number_format() function to change how a number is displayed. It will return a string, the type of the original variable is unaffected.
try this
$nom="5695.5";
number_format((float)($nom), 2, '.', ','); // -> 5,695.50
$nom="5695.5215";
number_format((float)($nom), 2, '.', ','); // -> 5,695.52
$nom="5695.12";
number_format((float)($nom), 0, '.', ','); // -> 5,695
//use round()
$nom="5695.12";
number_format((float)round($nom), 2, '.', ','); // -> 5,695.00
$nom="5695.52";
number_format((float)round($nom), 2, '.', ','); // -> 5,696.00
you can try this,it will work for you
number_format(0.00, 2)
A number of comments on this page have missed the fundamental point that the question is ill-formed. Floating point is a binary representation, designed for efficient calculations; it fundamentally has no notion of decimal digits of any sort.
So asking this:
How do I get "0.00" instead of "0" and still have the data type as a float?
Is like asking this:
How do I get "deux" instead of "zwei" and still have the language as English?
Whether you specify the input as "2", or "2.0", or "2.000000000", if you ask for a floating point value, what will be stored in memory is this (in IEEE 754 double-precision):
0100000000000000000000000000000000000000000000000000000000000000
If you convert to an integer, the value stored in memory is this (assuming a 64-bit system):
0000000000000000000000000000000000000000000000000000000000000010
(Note that "integer" in this context is not just a synonym for "whole number", it is a specific data type, with its own rules for how values should be represented in memory.)
By contrast, the string "2" would look like this:
00110010
And the string "2.00" would look like this:
00110010001011100011000000110000
(In a PHP program, there would actually be additional information in memory, such as an indicator of the type, but that's not really relevant here.)
So, the question can only be answered by rephrasing it as a conversion: given the input of a floating point number, how do I choose a string representation which has a fixed number of decimals.
As others have pointed out, the answer to that is to use number_format.
The question doesn't mention JSON, but several comments do, so I will also point out that PHP's json_encode function has an option JSON_PRESERVE_ZERO_FRACTION, which will format a floating point number that happens to be a whole number with a trailing ".0", for instance:
$example = ['int' => 2, 'float' => 2.0];
echo json_encode($example);
# => {"int":2,"float":2}
echo json_encode($example, JSON_PRESERVE_ZERO_FRACTION);
# => {"int":2,"float":2.0}
Again, note that this is a string representation of the value.
You can use round function
round("10.221",2);
Will return 10.22
You can use floatval()
floatval()
try this
$result = number_format($FloatNumber, 2);
You can use this simple function.
number_format ()
$num = 2214.56;
// default english notation
$english_format = number_format($num);
// 2,215
// French notation
$format_francais = number_format($num, 2, ',', ' ');
// 2 214,56
$num1 = 2234.5688;
// English notation with thousands separator
$english_format_number = number_format($num1,2);
// 2,234.57
// english notation without thousands separator
$english_format_number2 = number_format($num1, 2, '.', '');
// 2234.57
When we format any float value, that means we are changing its data type to string. So when we apply the formatting on any amount/float value then it will set with all possible notations like dot, comma, etc. For example
(float)0.00 => (string)'0.00',
(float)10000.56 => (string) '10,000.56'
(float)5000000.20=> (string) '5,000,000.20'
So, logically it's not possible to keep the float datatype after formatting.
I have a variable that is definited by a POST call from a form where it is inputed into a text field. Is there any way to convert this variable to an interger?
From the form:
Lenght: <input name="length" value="10" type="text" id="lenght" size="2" />
From the php code:
$length = $_POST['lenght'];
$url = substr($url, 0, $length);
This doesn't seem to work and the only reason why I think it isn't working is because $lenght is defined as text and not an interger.
Two things:
It doesn't work because you misspelled length <-> lenght
The correct way to convert a string to an integer is using the function intval.
$length = intval($_POST['length']);
$url = substr($url, 0, $length);
It likely doesn't work because you misspelled length twice, instead of zero or three times.
Seems to be a spelling error in your code: length vs. lenght - that could be your problem right there.
To do an explicit conversion, use the intval() function
$length = intval($_POST['length']);
Ignoring the misspellings of 'length' above, there are a few ways to explicitly convert a string into an integer in PHP. Usually this conversion will happen automatically. Take the following code:
$numeric_string = '42';
echo ($numeric_string * 2);
This will print out "84", as expected. See the reference on Type-Juggling.
If you KNOW that the string you have is a number (perhaps by checking is_numeric()) then you can either cast the variable to an Integer
$numeric_string = '42';
$converted_integer = (int) $numeric_string;
// or
$converted_integer = (integer) $numeric_string;
or use intval()
$numeric_string = '42';
$converted_integer = intval($numeric_string);
An important point to remember about intval() is that it will return a 0 if it can't resolve the string into an Integer. This could (potentially) give you a second way to check for errors (after is_numeric()), or it could cause unexpected results if you aren't properly insuring that the variable is numeric to begin with.
If you are sure that the value you are looking at has a correct representation for the type you want to convert to, you can also use a vanilla type cast operation:
$int = (int) "1"; // var_dump($int) => int(1)
$float = (float) "1.2345"; // var_dump($float) => float(1.2345)
Beware of incorrect representations of the variable that you are converting though, i.e casting "a random string" to a number might not yield the results you expect. If you are handling user input, you're better of using the above suggested solutions with function calls such as intval and floatval
That is because the PHP Web Server uses the name tag instead of the id tag. Even though the id is lenght, the name tag also has to be lenght, or it will malfunction.