I'm looking to create a PHP Range loop
In a first and second number in the range, but have noticed the first number which is
00006
Is being rounded down / flattened to show "6".
So when I echo the first number value I get "6" back. I need it to be "00006"
Then the next number will need to be 00007 and so on, via the range loop.
My PHP code at present is :
$first_number = 00006;
$last_number = 11807;
foreach(range($first_number, $last_number) as $id)
{
echo $id;
}
How do I go about making sure that the number has the previous 0's in it?
You can do it by using printf() function.
See the documentation : printf
First of all in PHP, a number starting with zero is treated as octal number, But I guess range() function converts it as decimal. So if you want to start it with 20. Like $first_number = 00020; then the output will be start with 16 not 20.
So, if you want the output starting with 0's, then you can do like this:
$first_number = 6;
$last_number = 11807;
foreach(range($first_number, $last_number) as $id)
{
printf("%05d",$id);
}
Hi i need to save a 010 number in $number and if i do like this php will remove the starting 0
$number = 010
And echo of this will return 10 how can i make it not to remove the initial 0
BR
Martin
Use it as a String:
$number = '010';
Use str_pad() function.
echo str_pad('10',3,'0',STR_PAD_LEFT)
http://php.net/manual/en/function.str-pad.php
Do remember that numbers starting with 0 can also be treated as octal number notation by the PHP compiler, hence if you want to work with decimal numbers, simply use:
$num = '010';
This way the number is saved, can be stored in the database and manipulated like any other number. (Thx to the fact that PHP is very loosely typed language.)
Another method to use would be:
Save number as $num = 10;
Later while printing the value you can use sprintf, like:
sprintf("%03d", $i);
This will print your number in 3 digit format, hence 0 will be added automatically.
Another method:
<?php
$num = 10;
$zerofill = 3;
echo str_pad($num, $zerofill, "0", STR_PAD_LEFT);
/* Returns the wanted result of '010' */
?>
You can have a look at the various options available to you and make a decision. Each of the method given above will give you a correct output.
How do I output a value as a number in php? I suspect I have a php value but it is outputting as text and not as a number.
Thanks
Here is the code - Updated for David from question below
<?php
if (preg_match('/\-(\d+)\.asp$/', $pagename1, $a))
{
$pageNumber = $a[1];}
else
{ // failed to match number from URL}
}
?>
If I call it in: This code it does not seem to work.
$maxRows_rs_datareviews = 10;
$pageNum_rs_datareviews = $pagename1; <<<<<------ This is where I want to use it.
if (isset($_GET['pageNum_rs_datareviews'])) {
$pageNum_rs_datareviews = $_GET['pageNum_rs_datareviews'];
}
If I make page name a static number like 3 the code works, if I use $pagename1 it does not, this gives me the idea $pagename1 is not seen as a number?
My stupidity!!!! - I used $pagename1 instead of pageNumber
What kind of number? An integer, decimal, float, something else?
Probably the easiest method is to use printf(), eg
printf('The number %d is an integer', $number);
printf('The number %0.2f has two decimal places', $number);
This might be blindingly obvious but it looks like you want to use
$pageNum_rs_datareviews = $pageNumber;
and not
$pageNum_rs_datareviews = $pagename1;
echo (int)$number; // integer 123
echo (float)$number; // float 123.45
would be the easiest
I prefer to use number_format:
echo number_format(56.30124355436,2).'%'; // 56.30%
echo number_format(56.30124355436,0).'%'; // 56%
$num = 5;
echo $num;
Any output is text, since it's output. It doesn't matter what the type of what you're outputting is, since the human eye will see it as text. It's how you actually treat is in the code is what matters.
Converting (casting) a string to a number is different. You can do stuff like:
$num = (int) $string;
$num = intval($string);
Googling php string to number should give you a beautiful array of choices.
Edit: To scrape a number from something, you can use preg_match('/\d+/', $string, $number). $number will now contain all numbers in $string.
I have a variable that is definited by a POST call from a form where it is inputed into a text field. Is there any way to convert this variable to an interger?
From the form:
Lenght: <input name="length" value="10" type="text" id="lenght" size="2" />
From the php code:
$length = $_POST['lenght'];
$url = substr($url, 0, $length);
This doesn't seem to work and the only reason why I think it isn't working is because $lenght is defined as text and not an interger.
Two things:
It doesn't work because you misspelled length <-> lenght
The correct way to convert a string to an integer is using the function intval.
$length = intval($_POST['length']);
$url = substr($url, 0, $length);
It likely doesn't work because you misspelled length twice, instead of zero or three times.
Seems to be a spelling error in your code: length vs. lenght - that could be your problem right there.
To do an explicit conversion, use the intval() function
$length = intval($_POST['length']);
Ignoring the misspellings of 'length' above, there are a few ways to explicitly convert a string into an integer in PHP. Usually this conversion will happen automatically. Take the following code:
$numeric_string = '42';
echo ($numeric_string * 2);
This will print out "84", as expected. See the reference on Type-Juggling.
If you KNOW that the string you have is a number (perhaps by checking is_numeric()) then you can either cast the variable to an Integer
$numeric_string = '42';
$converted_integer = (int) $numeric_string;
// or
$converted_integer = (integer) $numeric_string;
or use intval()
$numeric_string = '42';
$converted_integer = intval($numeric_string);
An important point to remember about intval() is that it will return a 0 if it can't resolve the string into an Integer. This could (potentially) give you a second way to check for errors (after is_numeric()), or it could cause unexpected results if you aren't properly insuring that the variable is numeric to begin with.
If you are sure that the value you are looking at has a correct representation for the type you want to convert to, you can also use a vanilla type cast operation:
$int = (int) "1"; // var_dump($int) => int(1)
$float = (float) "1.2345"; // var_dump($float) => float(1.2345)
Beware of incorrect representations of the variable that you are converting though, i.e casting "a random string" to a number might not yield the results you expect. If you are handling user input, you're better of using the above suggested solutions with function calls such as intval and floatval
That is because the PHP Web Server uses the name tag instead of the id tag. Even though the id is lenght, the name tag also has to be lenght, or it will malfunction.
I am not familiar with PHP at all and had a quick question.
I have 2 variables pricePerUnit and InvoicedUnits. Here's the code that is setting these to values:
$InvoicedUnits = ((string) $InvoiceLineItem->InvoicedUnits);
$pricePerUnit = ((string) $InvoiceLineItem->PricePerUnit);
If I output this, I get the correct values. Lets say 5000 invoiced units and 1.00 for price.
Now, I need to show the total amount spent. When I multiply these two together it doesn't work (as expected, these are strings).
But I have no clue how to parse/cast/convert variables in PHP.
What should I do?
$rootbeer = (float) $InvoicedUnits;
Should do it for you. Check out Type-Juggling. You should also read String conversion to Numbers.
You want the non-locale-aware floatval function:
float floatval ( mixed $var ) - Gets the float value of a string.
Example:
$string = '122.34343The';
$float = floatval($string);
echo $float; // 122.34343
Well, if user write 1,00,000 then floatvar will show error. So -
floatval(preg_replace("/[^-0-9\.]/","",$input));
This is much more reliable.
Usage :
$input = '1,03,24,23,434,500.6798633 this';
echo floatval(preg_replace("/[^-0-9\.]/","",$input));
Dealing with markup in floats is a non trivial task. In the English/American notation you format one thousand plus 46*10-2:
1,000.46
But in Germany you would change comma and point:
1.000,46
This makes it really hard guessing the right number in multi-language applications.
I strongly suggest using Zend_Measure of the Zend Framework for this task. This component will parse the string to a float by the users language.
you can follow this link to know more about How to convert a string/number into number/float/decimal in PHP.
HERE IS WHAT THIS LINK SAYS...
Method 1: Using number_format() Function. The number_format() function is used to convert a string into a number. It returns the formatted number on success otherwise it gives E_WARNING on failure.
$num = "1000.314";
//Convert string in number using
//number_format(), function
echo number_format($num), "\n";
//Convert string in number using
//number_format(), function
echo number_format($num, 2);
Method 2: Using type casting: Typecasting can directly convert a string into a float, double, or integer primitive type. This is the best way to convert a string into a number without any function.
// Number in string format
$num = "1000.314";
// Type cast using int
echo (int)$num, "\n";
// Type cast using float
echo (float)$num, "\n";
// Type cast using double
echo (double)$num;
Method 3: Using intval() and floatval() Function. The intval() and floatval() functions can also be used to convert the string into its corresponding integer and float values respectively.
// Number in string format
$num = "1000.314";
// intval() function to convert
// string into integer
echo intval($num), "\n";
// floatval() function to convert
// string to float
echo floatval($num);
Method 4: By adding 0 or by performing mathematical operations. The string number can also be converted into an integer or float by adding 0 with the string. In PHP, performing mathematical operations, the string is converted to an integer or float implicitly.
// Number into string format
$num = "1000.314";
// Performing mathematical operation
// to implicitly type conversion
echo $num + 0, "\n";
// Performing mathematical operation
// to implicitly type conversion
echo $num + 0.0, "\n";
// Performing mathematical operation
// to implicitly type conversion
echo $num + 0.1;
Use this function to cast a float value from any kind of text style:
function parseFloat($value) {
return floatval(preg_replace('#^([-]*[0-9\.,\' ]+?)((\.|,){1}([0-9-]{1,3}))*$#e', "str_replace(array('.', ',', \"'\", ' '), '', '\\1') . '.\\4'", $value));
}
This solution is not dependant on any locale settings. Thus for user input users can type float values in any way they like. This is really helpful e.g. when you have a project wich is in english only but people all over the world are using it and might not have in mind that the project wants a dot instead of a comma for float values.
You could throw javascript in the mix and fetch the browsers default settings but still many people set these values to english but still typing 1,25 instead of 1.25 (especially but not limited to the translation industry, research and IT)
I was running in to a problem with the standard way to do this:
$string = "one";
$float = (float)$string;
echo $float; : ( Prints 0 )
If there isn't a valid number, the parser shouldn't return a number, it should throw an error. (This is a condition I'm trying to catch in my code, YMMV)
To fix this I have done the following:
$string = "one";
$float = is_numeric($string) ? (float)$string : null;
echo $float; : ( Prints nothing )
Then before further processing the conversion, I can check and return an error if there wasn't a valid parse of the string.
For the sake of completeness, although this question is ancient, it's worth mentioning the filter_var() set of functions, which should not only handle the formatting bits itself, but also validate or sanitise the output, thus being safer to use in the context of a form being filled in by users (or, eventually, a database that might have some corrupted/inconsistent fields):
$InvoicedUnits = (float) filter_var($InvoiceLineItem->InvoicedUnits,
FILTER_SANITIZE_NUMBER_FLOAT, FILTER_FLAG_ALLOW_FRACTION));
$pricePerUnit = (float) filter_var($InvoiceLineItem->PricePerUnit,
FILTER_SANITIZE_NUMBER_FLOAT, FILTER_FLAG_ALLOW_FRACTION));
printf("The total is: %.2f\n", $InvoicedUnits * $pricePerUnit); // both are now floats and the result is a float, formatted to two digits after the decimal sign.
This sanitises the output (which will still remain a string) and will accept the current locale's setting of the decimal separator (e.g. dot vs. comma); also, there are more options on the PHP manual for validation (which will automatically convert the result to a float if valid). The results will be slightly different for different scenarios — e.g. if you know in advance that the $InvoiceLineItem will only have valid digits and symbols for floating-point numbers, or if you need to 'clean up' the field first, getting rid of whitespace, stray characters (such as currency symbols!), and so forth.
Finally, if you wish to have nicely-formatted output — since the total is expressed in a currency — you should also take a look at the built-in NumberFormatter class, and do something like:
$InvoicedUnits = (float) filter_var($InvoiceLineItem->InvoicedUnits,
FILTER_SANITIZE_NUMBER_FLOAT, FILTER_FLAG_ALLOW_FRACTION));
$pricePerUnit = (float) filter_var($InvoiceLineItem->PricePerUnit,
FILTER_SANITIZE_NUMBER_FLOAT, FILTER_FLAG_ALLOW_FRACTION));
$fmt = new NumberFormatter('de_DE', NumberFormatter::CURRENCY);
echo 'Total is: ' . $fmt->formatCurrency($InvoicedUnits * $pricePerUnit, 'EUR') . PHP_EOL;
This will also handle thousand separators (spaces, dots, commas...) according to the configured locale, and other similar fancy things.
Also, if you wish, you can use '' (the empty string) for the default locale string (set either by the server or optionally by the browser) and $fmt->getSymbol(NumberFormatter::INTL_CURRENCY_SYMBOL) to get the default 3-letter currency code (which might not be what you want, since usually prices are given in a specific currency — these functions do not take currency exchange rates into account!).
If you need to handle values that cannot be converted separately, you can use this method:
try {
// use + 0 if you are accounting in cents
$doubleValue = trim($stringThatMightBeNumeric) + 0.0;
} catch (\Throwable $th) {
// bail here if you need to
}