How can I get the latest entry by the latest DATE field from a MySQL database using PHP?
The rows will not be in order of date, so I can't just take the first or last row.
You want the ORDER BY clause, and perhaps the LIMIT clause.
$query = 'SELECT * FROM `table` ORDER BY `date` DESC LIMIT 1';
SELECT * FROM [Table] ORDER BY [dateColumn] DESC
If you want only the first row:
In T-SQL:
SELECT TOP(1) * FROM [Table] ORDER BY [dateColumn] DESC
In MySQL:
SELECT * FROM `Table` ORDER BY `dateColumn` DESC LIMIT 1
You don't have a unique recordid or date revised field you could key in on? I always have at least an auto incrementing numeric field in addition to data created and date revised fields. Are you sure there is nothing you can key in on?
SELECT * FROM table ORDER BY recno DESC LIMIT 1;
or
SELECT * FROM table ORDER BY date_revised DESC LIMIT 1;
So the PHP call would be:
$result = mysql_query("SELECT * FROM table ORDER BY date_revised DESC LIMIT 1");
-- Nicholas
You can use a combination of the LIMIT and ORDER BY clauses.
For example:
SELECT * FROM entries ORDER BY timestamp DESC LIMIT 1
Related
Is possible, and how to ask MySQL for
SELECT * FROM my_table ORDER by row_id DESC LIMIT 8
get the last 8, newest record from my table, with randomized order for PHP showing method
$results = $mysqli->query($query);
while($row = $results->fetch_assoc()) {
echo $row['my_col_name'];
}
Colud I, and where put the rand() in my SQL query?
Without randomize I get last 8 rows ORDERED 10,9,8,7,6,5,4,3
I want to get in the following order:
9,7,5,4,6,10,3,8;
8,7,3,6,10,9,5,4
...
You can place it inside another select:
SELECT * FROM (SELECT * FROM my_table ORDER by row_id DESC LIMIT 8) t ORDER BY RAND()
Use a subquery:
SELECT t.*
FROM (SELECT t.*
FROM my_table t
ORDER by row_id DESC
LIMIT 8
) t
ORDER BY rand();
I have this line:
$query = mysql_query("SELECT * FROM livechat WHERE type='public' ORDER BY id ASC LIMIT 15") ;
And this is for chat, however ASC takes only first ID comments, so it shows only 15 old comments (id1, id2 and so on). If I use DESC instead of ASC, it shows new comments, but in a bad way - newest at the top, since this is a chat, newest comments must be at the bottom.
Try creating a temporary table that contains the last 15 results, and then ordering from that table.
select * from (
select * from livechat where type='public' order by id desc limit 15
) tmp order by tmp.id asc
try like this:
$query = mysql_query("SELECT *
FROM (
SELECT *
FROM livechat
WHERE type='public'
ORDER BY id DESC LIMIT 15
) t
order by t.id") ;
i have a table in mysql with columns: id , view , agree.
i have upload my table's image below:
i want to select 8 rows that greater than others in view column. my condition is agree = 1.
can you tell me how can i do it by mysql query or php.
Select * from table_name WHERE agree = 1 ORDER BY view desc LIMIT 8
Try this:
SELECT * from table
WHERE agree = 1
ORDER BY view DESC
LIMIT 8
use limit and order by
Select * from mytable
where aggree=1
ORDER BY view DESC
LIMIT 8
You can do this:
SELECT *
FROM yourTableName
WHERE agree = 1
ORDER BY view DESC
LIMIT 8
You have to use ORDER BY clause.
SELECT * FROM <TABLE_NAME> WHERE AGREE = 1 ORDER BY VIEW DESC LIMIT 8
Use ORDER BY for DESC or ASC sorting.
and For selection of 8 rows use Limit Data Selections From a MySQL Database
Select * from table_name WHERE agree = 1 ORDER BY view desc LIMIT 8
If you want to take the top 8 'view' values from the table the MySql query for that is:
SELECT * FROM tablename WHERE agree=1 ORDER BY view DESC LIMIT 8;
Note: Replace tablename with the actual name of your table
i want to get the last 6 rows but skip the last one in result:
SELECT * FROM stats_follow ORDER BY id DESC LIMIT 6
How can i make this?
Try this:
SELECT *
FROM (SELECT *
FROM TableName
ORDER BY FieldName DESC
LIMIT 5) sub
ORDER BY FieldName ASC
Try this:
SELECT * FROM stats_follow ORDER BY id DESC LIMIT 1,6
My table structure is
I want to get the recent video uploaded of the user
What I want to do is:
"select video_id of a record who is having minimum of timestamp where userid='something'"
What I currently have is:
$recent_video = "$db->query("
SELECT video_id
FROM video_primary
ORDER BY timestamp DESC LIMIT 1
WHERE userid = '$userid'"
) or die($db->error);"`
while($row=mysqli_fetch_assoc($recent_video))
{
$video_id=$row['video_id'];
}
echo $video_id;
My table data is
How do I get the most recent view uploaded by the user?
Write WHERE clause after FROM part
Try this:
SELECT vp.video_id
FROM video_primary vp
WHERE userid='$userid'
ORDER BY vp.timestamp DESC
LIMIT 1;
try this
$recent_video=$db->query("select video_id from video_primary where userid='$userid'
ORDER BY timestamp DESC LIMIT 1 ") or die($db->error);
instead of
$recent_video="$db->query("select video_id from video_primary ORDER BY timestamp DESC
LIMIT 1 where userid='$userid'") or die($db->error);"
you are using where clause after order by and limit 1 which is a syntax error. see tutorial
Tutorial
There is a specific sequence of every clause in Query statement. Below is the sequence:
Select
Where
Order by
Limit
So, as per the above sequence, you should correct your query like below. Also, you should place double quote(") correctly.
$recent_video = $db->query("
SELECT video_id
FROM video_primary
WHERE userid = '$userid'
ORDER BY timestamp DESC LIMIT 1"
) or die($db->error);