My table structure is
I want to get the recent video uploaded of the user
What I want to do is:
"select video_id of a record who is having minimum of timestamp where userid='something'"
What I currently have is:
$recent_video = "$db->query("
SELECT video_id
FROM video_primary
ORDER BY timestamp DESC LIMIT 1
WHERE userid = '$userid'"
) or die($db->error);"`
while($row=mysqli_fetch_assoc($recent_video))
{
$video_id=$row['video_id'];
}
echo $video_id;
My table data is
How do I get the most recent view uploaded by the user?
Write WHERE clause after FROM part
Try this:
SELECT vp.video_id
FROM video_primary vp
WHERE userid='$userid'
ORDER BY vp.timestamp DESC
LIMIT 1;
try this
$recent_video=$db->query("select video_id from video_primary where userid='$userid'
ORDER BY timestamp DESC LIMIT 1 ") or die($db->error);
instead of
$recent_video="$db->query("select video_id from video_primary ORDER BY timestamp DESC
LIMIT 1 where userid='$userid'") or die($db->error);"
you are using where clause after order by and limit 1 which is a syntax error. see tutorial
Tutorial
There is a specific sequence of every clause in Query statement. Below is the sequence:
Select
Where
Order by
Limit
So, as per the above sequence, you should correct your query like below. Also, you should place double quote(") correctly.
$recent_video = $db->query("
SELECT video_id
FROM video_primary
WHERE userid = '$userid'
ORDER BY timestamp DESC LIMIT 1"
) or die($db->error);
Related
I want to select last 5 records from first 50 records in the table, currently i have following query, somebody tell me best way to select these records without calculating the limit and offset?
SELECT id FROM table WHERE enabled=1 ORDER BY date LIMIT 5, 45
Try this
SELECT id FROM (SELECT id FROM (SELECT id FROM table ORDER BY id ASC LIMIT 50) AS tbl ORDER BY id DESC LIMIT 5) as tbldata ORDER BY id ASC
this works:
SELECT id FROM (SELECT id,date FROM table ORDER BY date LIMIT 50) AS
temptable ORDER BY date DESC LIMIT 5
I have this line:
$query = mysql_query("SELECT * FROM livechat WHERE type='public' ORDER BY id ASC LIMIT 15") ;
And this is for chat, however ASC takes only first ID comments, so it shows only 15 old comments (id1, id2 and so on). If I use DESC instead of ASC, it shows new comments, but in a bad way - newest at the top, since this is a chat, newest comments must be at the bottom.
Try creating a temporary table that contains the last 15 results, and then ordering from that table.
select * from (
select * from livechat where type='public' order by id desc limit 15
) tmp order by tmp.id asc
try like this:
$query = mysql_query("SELECT *
FROM (
SELECT *
FROM livechat
WHERE type='public'
ORDER BY id DESC LIMIT 15
) t
order by t.id") ;
i have a table in mysql with columns: id , view , agree.
i have upload my table's image below:
i want to select 8 rows that greater than others in view column. my condition is agree = 1.
can you tell me how can i do it by mysql query or php.
Select * from table_name WHERE agree = 1 ORDER BY view desc LIMIT 8
Try this:
SELECT * from table
WHERE agree = 1
ORDER BY view DESC
LIMIT 8
use limit and order by
Select * from mytable
where aggree=1
ORDER BY view DESC
LIMIT 8
You can do this:
SELECT *
FROM yourTableName
WHERE agree = 1
ORDER BY view DESC
LIMIT 8
You have to use ORDER BY clause.
SELECT * FROM <TABLE_NAME> WHERE AGREE = 1 ORDER BY VIEW DESC LIMIT 8
Use ORDER BY for DESC or ASC sorting.
and For selection of 8 rows use Limit Data Selections From a MySQL Database
Select * from table_name WHERE agree = 1 ORDER BY view desc LIMIT 8
If you want to take the top 8 'view' values from the table the MySql query for that is:
SELECT * FROM tablename WHERE agree=1 ORDER BY view DESC LIMIT 8;
Note: Replace tablename with the actual name of your table
I am working on mysql querying a table which keeps on increasing every minute. The query is also being used for pagination also having the limit clause. The table consist of user session being visited on store website. I have already added indexes for store_id, session_id
Following is the query.
SELECT *,
GROUP_CONCAT(email) as email_id
FROM
(
SELECT *
FROM clickstream
WHERE clickstream.store_id = ''
ORDER BY id DESC
) as clck
GROUP BY session_id
ORDER BY server_now DESC
LIMIT ".$offset.",".PER_PAGE_PRODUCT_COUNT
Any ideas?
Your index on store_id will help you in this query, you can't Speed the query up further by other indices. You just can remove the subquery:
SELECT
*,
GROUP_CONCAT(email ORDER BY id) as email_id
FROM
clickstream
WHERE
clickstream.store_id = ''
GROUP BY
session_id
ORDER BY
server_now DESC
LIMIT
$offset,PER_PAGE_PRODUCT_COUNT
How can I get the latest entry by the latest DATE field from a MySQL database using PHP?
The rows will not be in order of date, so I can't just take the first or last row.
You want the ORDER BY clause, and perhaps the LIMIT clause.
$query = 'SELECT * FROM `table` ORDER BY `date` DESC LIMIT 1';
SELECT * FROM [Table] ORDER BY [dateColumn] DESC
If you want only the first row:
In T-SQL:
SELECT TOP(1) * FROM [Table] ORDER BY [dateColumn] DESC
In MySQL:
SELECT * FROM `Table` ORDER BY `dateColumn` DESC LIMIT 1
You don't have a unique recordid or date revised field you could key in on? I always have at least an auto incrementing numeric field in addition to data created and date revised fields. Are you sure there is nothing you can key in on?
SELECT * FROM table ORDER BY recno DESC LIMIT 1;
or
SELECT * FROM table ORDER BY date_revised DESC LIMIT 1;
So the PHP call would be:
$result = mysql_query("SELECT * FROM table ORDER BY date_revised DESC LIMIT 1");
-- Nicholas
You can use a combination of the LIMIT and ORDER BY clauses.
For example:
SELECT * FROM entries ORDER BY timestamp DESC LIMIT 1