I get the time:
$today = time();
$date = date('h:i:s A', strtotime($today));
if the current time is "1:00:00 am", how do i add 10 more hours to become 11:00:00 am??
strtotime() gives you a number back that represents a time in seconds. To increment it, add the corresponding number of seconds you want to add. 10 hours = 60*60*10 = 36000, so...
$date = date('h:i:s A', strtotime($today)+36000); // $today is today date
Edit: I had assumed you had a string time in $today - if you're just using the current time, even simpler:
$date = date('h:i:s A', time()+36000); // time() returns a time in seconds already
$tz = new DateTimeZone('Europe/London');
$date = new DateTime($today, $tz);
$date->modify('+10 hours');
// use $date->format() to outputs the result.
see DateTime Class
(PHP 5 >= 5.2.0)
You can simply make use of the DateTime class , OOP Style.
<?php
$date = new DateTime('1:00:00');
$date->add(new DateInterval('PT10H'));
echo $date->format('H:i:s a'); //"prints" 11:00:00 a.m
$date = date('h:i:s A', strtotime($today . ' + 10 hours'));
(untested)
$date = date('h:i:s A', strtotime($today . " +10 hours"));
Full code that shows now and 10 minutes added.....
$nowtime = date("Y-m-d H:i:s");
echo $nowtime;
$date = date('Y-m-d H:i:s', strtotime($nowtime . ' + 10 minute'));
echo "<br>".$date;
In order to increase or decrease time using strtotime you could use a Relative format in the first argument.
In your case to increase the current time by 10 hours:
$date = date('h:i:s A', strtotime('+10 hours'));
In case you need to apply the change to another timestamp, the second argument can be specified.
Note:
Using this function for mathematical operations is not advisable. It is better to use DateTime::add() and DateTime::sub() in PHP 5.3 and later, or DateTime::modify() in PHP 5.2.
So, the recommended way since PHP 5.3:
$dt = new DateTime(); // assuming we need to add to the current time
$dt->add(new DateInterval('PT10H'));
$date = $dt->format('h:i:s A');
or using aliases:
$dt = date_create(); // assuming we need to add to the current time
date_add($dt, date_interval_create_from_date_string('10 hours'));
$date = date_format($dt, 'h:i:s A');
In all cases the default time zone will be used unless a time zone is specified.
Related
I currently have php returning the current date/time like so:
$now = date("Y-m-d H:m:s");
What I'd like to do is have a new variable $new_time equal $now + $hours, where $hours is a number of hours ranging from 24 to 800.
Any suggestions?
You may use something like the strtotime() function to add something to the current timestamp. $new_time = date("Y-m-d H:i:s", strtotime('+5 hours')).
If you need variables in the function, you must use double quotes then like strtotime("+{$hours} hours"), however better you use strtotime(sprintf("+%d hours", $hours)) then.
An other solution (object-oriented) is to use DateTime::add
Example:
<?php
$now = new DateTime(); //now
echo $now->format('Y-m-d H:i:s'); // 2021-09-11 01:01:55
$hours = 36; // hours amount (integer) you want to add
$modified = (clone $now)->add(new DateInterval("PT{$hours}H")); // use clone to avoid modification of $now object
echo "\n". $modified->format('Y-m-d H:i:s'); // 2021-09-12 13:01:55
Run script
DateTime::add PHP doc
DateInterval::construct PHP doc
You can use strtotime() to achieve this:
$new_time = date("Y-m-d H:i:s", strtotime('+3 hours', $now)); // $now + 3 hours
Correct
You can use strtotime() to achieve this:
$new_time = date("Y-m-d H:i:s", strtotime('+3 hours', strtotime($now))); // $now + 3 hours
You can also use the unix style time to calculate:
$newtime = time() + ($hours * 60 * 60); // hours; 60 mins; 60secs
echo 'Now: '. date('Y-m-d') ."\n";
echo 'Next Week: '. date('Y-m-d', $newtime) ."\n";
Um... your minutes should be corrected... 'i' is for minutes. Not months. :) (I had the same problem for something too.
$now = date("Y-m-d H:i:s");
$new_time = date("Y-m-d H:i:s", strtotime('+3 hours', $now)); // $now + 3 hours
I use this , its working cool.
//set timezone
date_default_timezone_set('GMT');
//set an date and time to work with
$start = '2014-06-01 14:00:00';
//display the converted time
echo date('Y-m-d H:i',strtotime('+1 hour +20 minutes',strtotime($start)));
for add 2 hours to "now"
$date = new DateTime('now +2 hours');
or
$date = date("Y-m-d H:i:s", strtotime('+2 hours', $now)); // as above in example
or
$now = new DateTime();
$now->add(new DateInterval('PT2H')); // as above in example
You can try lib Ouzo goodies, and do this in fluent way:
echo Clock::now()->plusHours($hours)->format("Y-m-d H:m:s");
API's allow multiple operations.
For a given DateTime, you can add days, hours, minutes, etc. Here's some examples:
$now = new \DateTime();
$now->add(new DateInterval('PT24H')); // adds 24 hours
$now->add(new DateInterval('P2D')); // adds 2 days
PHP: DateTime::add - Manual https://www.php.net/manual/fr/datetime.add.php
$to = date('Y-m-d H:i:s'); //"2022-01-09 12:55:46"
$from = date("Y-m-d H:i:s", strtotime("$to -3 hours")); // 2022-01-09 09:55:46
$date_to_be-added="2018-04-11 10:04:46";
$added_date=date("Y-m-d H:i:s",strtotime('+24 hours', strtotime($date_to_be)));
A combination of date() and strtotime() functions will do the trick.
$now = date("Y-m-d H:i:s");
date("Y-m-d H:i:s", strtotime("+1 hours $now"));
I have the current date format $date = 'yyyy-mm-dd hh:mm' and notice that $date is already set and not using the Date class. I understand I have to use strtotime which I have done to my $date $datestr = strtotime($date). I wish to subtract 5 minutes to the set time.
I've tried this simple thing $A = strtotime($date) - strtotime('-5 min'); But it does not aid me.
its simple to subtract the seconds of 5 minutes which is (5*60)=300 from your time
like this
$time = strtotime($date);
$time_new = $time-(5*60); // will time of the -5 min from the current $time
example
$date = date('d-M-Y g:i:s A'); // current date
echo $date."<br/>"; // output : 17-Feb-2014 8:35:58 AM
$time = strtotime($date); // convert current date to timestamp
$time_new = $time - (5*60); // subtract 5 minutes from current time.
$date_new = date('d-M-Y g:i:s A', $time_new); // convert time to the date again
echo $date_new; // output : 17-Feb-2014 8:30:58 AM
I'm really stuck with adding X minutes to a datetime, after doing lots of google'ing and PHP manual reading, I don't seem to be getting anywhere.
The date time format I have is:
2011-11-17 05:05: year-month-day hour:minute
Minutes to add will just be a number between 0 and 59
I would like the output to be the same as the input format with the minutes added.
Could someone give me a working code example, as my attempts don't seem to be getting me anywhere?
$minutes_to_add = 5;
$time = new DateTime('2011-11-17 05:05');
$time->add(new DateInterval('PT' . $minutes_to_add . 'M'));
$stamp = $time->format('Y-m-d H:i');
The ISO 8601 standard for duration is a string in the form of P{y}Y{m1}M{d}DT{h}H{m2}M{s}S where the {*} parts are replaced by a number value indicating how long the duration is.
For example, P1Y2DT5S means 1 year, 2 days, and 5 seconds.
In the example above, we are providing PT5M (or 5 minutes) to the DateInterval constructor.
PHP's DateTime class has a useful modify method which takes in easy-to-understand text.
$dateTime = new DateTime('2011-11-17 05:05');
$dateTime->modify('+5 minutes');
You could also use string interpolation or concatenation to parameterize it:
$dateTime = new DateTime('2011-11-17 05:05');
$minutesToAdd = 5;
$dateTime->modify("+{$minutesToAdd} minutes");
$newtimestamp = strtotime('2011-11-17 05:05 + 16 minute');
echo date('Y-m-d H:i:s', $newtimestamp);
result is
2011-11-17 05:21:00
Live demo is here
If you are no familiar with strtotime yet, you better head to php.net to discover it's great power :-)
You can do this with native functions easily:
strtotime('+59 minutes', strtotime('2011-11-17 05:05'));
I'd recommend the DateTime class method though, just posted by Tim.
I don't know why the approach set as solution didn't work for me.
So I'm posting here what worked for me in hope it can help anybody:
$startTime = date("Y-m-d H:i:s");
//display the starting time
echo '> '.$startTime . "<br>";
//adding 2 minutes
$convertedTime = date('Y-m-d H:i:s', strtotime('+2 minutes', strtotime($startTime)));
//display the converted time
echo '> '.$convertedTime;
I thought this would help some when dealing with time zones too. My modified solution is based off of #Tim Cooper's solution, the correct answer above.
$minutes_to_add = 10;
$time = new DateTime();
**$time->setTimezone(new DateTimeZone('America/Toronto'));**
$time->add(new DateInterval('PT' . $minutes_to_add . 'M'));
$timestamp = $time->format("Y/m/d G:i:s");
The bold line, line 3, is the addition. I hope this helps some folks as well.
A bit of a late answer, but the method I would use is:
// Create a new \DateTime instance
$date = DateTime::createFromFormat('Y-m-d H:i:s', '2015-10-26 10:00:00');
// Modify the date
$date->modify('+5 minutes');
// Output
echo $date->format('Y-m-d H:i:s');
Or in PHP >= 5.4
echo (DateTime::createFromFormat('Y-m-d H:i:s', '2015-10-26 10:00:00'))->modify('+5 minutes')->format('Y-m-d H:i:s')
If you want to give a variable that contains the minutes.
Then I think this is a great way to achieve this.
$minutes = 10;
$maxAge = new DateTime('2011-11-17 05:05');
$maxAge->modify("+{$minutes} minutes");
Use strtotime("+5 minute", $date);
Example:
$date = "2017-06-16 08:40:00";
$date = strtotime($date);
$date = strtotime("+5 minute", $date);
echo date('Y-m-d H:i:s', $date);
As noted by Brad and Nemoden in their answers above, strtotime() is a great function. Personally, I found the standard DateTime Object to be overly complicated for many use cases. I just wanted to add 5 minutes to the current time, for example.
I wrote a function that returns a date as a string with some optional parameters:
1.) time:String | ex: "+5 minutes" (default = current time)
2.) format:String | ex: "Y-m-d H:i:s" (default = "Y-m-d H:i:s O")
Obviously, this is not a fully featured method. Just a quick and simple function for modifying/formatting the current date.
function get_date($time=null, $format='Y-m-d H:i:s O')
{
if(empty($time))return date($format);
return date($format, strtotime($time));
}
// Example #1: Return current date in default format
$date = get_date();
// Example #2: Add 5 minutes to the current date
$date = get_date("+5 minutes");
// Example #3: Subtract 30 days from the current date & format as 'Y-m-d H:i:s'
$date = get_date("-30 days", "Y-m-d H:i:s");
one line mysql datetime format
$mysql_date_time = (new DateTime())->modify('+15 minutes')->format("Y-m-d H:i:s");
One more example of a function to do this: (changing the time and interval formats however you like them according to this for function.date, and this for DateInterval):
(I've also written an alternate form of the below function.)
// Return adjusted time.
function addMinutesToTime( $dateTime, $plusMinutes ) {
$dateTime = DateTime::createFromFormat( 'Y-m-d H:i', $dateTime );
$dateTime->add( new DateInterval( 'PT' . ( (integer) $plusMinutes ) . 'M' ) );
$newTime = $dateTime->format( 'Y-m-d H:i' );
return $newTime;
}
$adjustedTime = addMinutesToTime( '2011-11-17 05:05', 59 );
echo '<h1>Adjusted Time: ' . $adjustedTime . '</h1>' . PHP_EOL . PHP_EOL;
Without using a variable:
$yourDate->modify("15 minutes");
echo $yourDate->format( "Y-m-d H:i");
With using a variable:
$interval= 15;
$yourDate->modify("+{$interval } minutes");
echo $yourDate->format( "Y-m-d H:i");
I have $adate; which contains:
Tue Jan 4 07:59:59 2011
I want to add to this date the following:
$duration=674165; // in seconds
Once the seconds are added I need the result back into date format.
I don't know what I'm doing, but I am getting odd results.
Note: both variables are dynamic. Now they are equal to the values given, but next query they will have different values.
If you are using php 5.3+ you can use a new way to do it.
<?php
$date = new DateTime();
echo $date->getTimestamp(). "<br>";
$date->add(new DateInterval('PT674165S')); // adds 674165 secs
echo $date->getTimestamp();
?>
Just use some nice PHP date/time functions:
$adate="Tue Jan 4 07:59:59 2011";
$duration=674165;
$dateinsec=strtotime($adate);
$newdate=$dateinsec+$duration;
echo date('D M H:i:s Y',$newdate);
Given the fact that $adate is a timestamp (if that's the case), you could do something like this:
$duration = 674165;
$result_date = strtotime(sprintf('+%d seconds', $duration), $adate);
echo date('Y-m-d H:i:s', $result_date);
// add 20 sec to now
$duration = 20;
echo date("Y-m-d H:i:s", strtotime("+$duration sec"));
Do this:
$seconds = 1;
$date_now = "2016-06-02 00:00:00";
echo date("Y-m-d H:i:s", (strtotime(date($date_now)) + $seconds));
$current_time_zone = 150;
date("Y-m-d H:i:s",strtotime(date("Y-m-d H:i:s"))+$current_time_zone);
I made this example for a timezone, but if you change some parts it may help you out:
$seconds_to_add = 30;
$time = new DateTime();
$time->setTimezone(new DateTimeZone('Europe/London'));
$time2 = $time->format("Y/m/d G:i:s");
$time->add(new DateInterval('PT' . $seconds_to_add . 'S'));
$timestamp = $time->format("Y/m/d G:i:s");
echo $timestamp;
echo '========';
echo $time2;
Result:
2018/06/17 3:16:23========2018/06/17 3:15:53
It would be easier with DateTime::modify
(new DateTime($str))->modify("+$duration seconds"); //$str is the date in string
I have trouble with strtotime() to resolve my problem of add dynamic data/time value in the current time
This was my solution:
$expires = 3600; //my dynamic time variable (static representation here)
$date = date_create(date('Y-m-d H:i:s')); //create a date/time variable (with the specified format - create your format, see (1))
echo date_format($date, 'Y-m-d H:i:s')."<br/>"; //shows the date/time variable without add seconds/time
date_add($date, date_interval_create_from_date_string($expires.' seconds')); //add dynamic quantity of seconds to data/time variable
echo date_format($date, 'Y-m-d H:i:s'); //shows the new data/time value
font: https://secure.php.net/manual/en/datetime.add.php (consult Object Oriented style too, the Elzo Valugi solution)
(1) https://secure.php.net/manual/en/function.date.php
In certain situations I want to add 1 day to the value of my DATETIME formatted variable:
$start_date = date('Y-m-d H:i:s', strtotime("{$_GET['start_hours']}:{$_GET['start_minutes']} {$_GET['start_ampm']}"));
What is the best way to do this?
There's more then one way to do this with DateTime which was introduced in PHP 5.2. Unlike using strtotime() this will account for daylight savings time and leap year.
$datetime = new DateTime('2013-01-29');
$datetime->modify('+1 day');
echo $datetime->format('Y-m-d H:i:s');
// Available in PHP 5.3
$datetime = new DateTime('2013-01-29');
$datetime->add(new DateInterval('P1D'));
echo $datetime->format('Y-m-d H:i:s');
// Available in PHP 5.4
echo (new DateTime('2013-01-29'))->add(new DateInterval('P1D'))->format('Y-m-d H:i:s');
// Available in PHP 5.5
$start = new DateTimeImmutable('2013-01-29');
$datetime = $start->modify('+1 day');
echo $datetime->format('Y-m-d H:i:s');
If you want to do this in PHP:
// replace time() with the time stamp you want to add one day to
$startDate = time();
date('Y-m-d H:i:s', strtotime('+1 day', $startDate));
If you want to add the date in MySQL:
-- replace CURRENT_DATE with the date you want to add one day to
SELECT DATE_ADD(CURRENT_DATE, INTERVAL 1 DAY);
The DateTime constructor takes a parameter string time. $time can be different things, it has to respect the datetime format.
There are some valid values as examples :
'now' (the default value)
2017-10-19
2017-10-19 11:59:59
2017-10-19 +1day
So, in your case you can use the following.
$dt = new \DateTime('now +1 day'); //Tomorrow
$dt = new \DateTime('2016-01-01 +1 day'); //2016-01-02
Use strtotime to convert the string to a time stamp
Add a day to it (eg: by adding 86400 seconds (24 * 60 * 60))
eg:
$time = strtotime($myInput);
$newTime = $time + 86400;
If it's only adding 1 day, then using strtotime again is probably overkill.
You can use
$now = new DateTime();
$date = $now->modify('+1 day')->format('Y-m-d H:i:s');
You can use as following.
$start_date = date('Y-m-d H:i:s');
$end_date = date("Y-m-d 23:59:59", strtotime('+3 days', strtotime($start_date)));
You can also set days as constant and use like below.
if (!defined('ADD_DAYS')) define('ADD_DAYS','+3 days');
$end_date = date("Y-m-d 23:59:59", strtotime(ADD_DAYS, strtotime($start_date)));
I suggest start using Zend_Date classes from Zend Framework. I know, its a bit offtopic, but I'll like this way :-)
$date = new Zend_Date();
$date->add('24:00:00', Zend_Date::TIMES);
print $date->get();
Using server request time to Add days. Working as expected.
25/08/19 => 27/09/19
$timestamp = $_SERVER['REQUEST_TIME'];
$dateNow = date('d/m/y', $timestamp);
$newDate = date('d/m/y', strtotime('+2 day', $timestamp));
Here '+2 days' to add any number of days.
One liner !
echo (new \DateTime('2016-01-01 +1 day'))->format('Y-m-d H:i:s');