I have the current date format $date = 'yyyy-mm-dd hh:mm' and notice that $date is already set and not using the Date class. I understand I have to use strtotime which I have done to my $date $datestr = strtotime($date). I wish to subtract 5 minutes to the set time.
I've tried this simple thing $A = strtotime($date) - strtotime('-5 min'); But it does not aid me.
its simple to subtract the seconds of 5 minutes which is (5*60)=300 from your time
like this
$time = strtotime($date);
$time_new = $time-(5*60); // will time of the -5 min from the current $time
example
$date = date('d-M-Y g:i:s A'); // current date
echo $date."<br/>"; // output : 17-Feb-2014 8:35:58 AM
$time = strtotime($date); // convert current date to timestamp
$time_new = $time - (5*60); // subtract 5 minutes from current time.
$date_new = date('d-M-Y g:i:s A', $time_new); // convert time to the date again
echo $date_new; // output : 17-Feb-2014 8:30:58 AM
Related
So, I'm creating a booking system. When I retrieve this booking from the database, I need to check if the current date and time is closer to the actual booked date and time.
On the admin dashboard, the admins specify how much time earlier the client can make a checkin, let's say for example, 30minutes. But this time can be different. Can be 1hour, 2hours, 10minutes.
When I get the result from the database I get them like this:
$date_schedule = '2021-03-25 15:40:00'; // Can be any date in the future as well;
$time_to_check = '00:30:00'; // Can be '01:05:00', whatever the admins set as time_to_check;
// Expected result
'2021-03-25 15:10:00';
I tried subtracting this but I didn't made it work.. This is what I did.
$current_date = date("Y-m-d H:i:s");
$booking_date = '2021-03-25 15:00:00'; // From database
$time_to_check = '00:30:00'; // From database
$hours = explode(':', $time_to_check);
$data_check = date($booking_date, strtotime('-' . $hours[0] . ' hour -' . $hours[1] . ' minutes'));
But with this, $data_check returns the same value as $booking_date, it's not subtracting the time.
Convert your date to DateTime to make some operations on it :
function changeDate($date, $interval) {
$datetime = new DateTime($date);
$values = explode(':', $interval);
$datetime->modify("-$values[0] hours -$values[1] minutes -$values[2] seconds");
return $datetime->format('Y-m-d H:i:s');
}
$date = changeDate('2021-03-25 15:00:00', '00:30:00');
echo $date; // 2021-03-25 14:30:00
$date = changeDate('2021-03-25 15:00:00', '01:30:00');
echo $date; // 2021-03-25 13:30:00
$date = changeDate('2021-03-25 15:00:00', '02:30:15');
echo $date; // 2021-03-25 12:29:45
You can find documentation here https://www.php.net/manual/en/book.datetime.php
Just convert the timestamp to Unix time, and then subtract 30 minutes in seconds (30 * 60) from the Unix time.
Like this:
$date = '2021-03-25 15:10:00';
$timestamp = strtotime($date);
$timestamp = ($timestamp - (30 * 60));
echo gmdate("Y-m-d H:i:s", $timestamp);
EDIT: If you are in an odd timezone, like me (GMT+0100) add or subtract difference;
$timestamp = (($timestamp - (30 * 60)) + (1 * 60 * 60))
I am trying to format a date as 2015-07-12 15:00 from the values declared in my variables
// unix
$date = 1436713200
// string
$time = '15:00';
to get a date format 2015-07-12 15:00 but failing, using this
$newdate = date('Y-m-d H:i:s', $date.' '.$time);
I get 'A non well formed numeric value encountered'. Can anyone help? I understand it is possibly due to the mix of string and unix but unsure how to get round this.
I would suggest you to use DateTime instance to avoid timezone issues:
$d = date_create('#1436713200'); // creates DateTime instance
$d->setTime(15, 00); // sets current time to desired hours, minutes
echo $d->format('Y-m-d H:i:s'); // prints it out with format specified
//⇒ 2015-07-12 15:00:00
You do not have to provie the $time variable. Unix time is a full date with time.
Use:
$newdate = date('Y-m-d H:i:s', $date);
Use this
$date = date('Y-m-d','1436713200');
// string
$time = '15:00';
echo $newdate = date('Y-m-d H:i', strtotime($date.' '.$time));
I have the data 2013-02-04 03:20:00
How do I arrive into this 07:20 using php.
Same is through with this 2013-02-04 08:00:00 to this 12:00
I have this data labeled timestamp_diff which is 14400
Any idea? Thank You
I think the answer was base on the timestamp_diff not just adding 4 or any values to it.
Is there any datetime() function(s) to get the equivalent of 14400 to 4
<?php
$add4hour = time() + (4*60*60);
$newTime = date("d m Y H:i:s",$add4hour);
echo $newTime;
?>
Edit because of your requirements
<?php
$add4hour = time() + (4*60*60); // 4 hour adding
$d1 = date("d-m-Y H:i:s"); // date 1 assume that hour 03:20:00
$d2 = date("d-m-Y H:i:s",$add4hour); // date 2, Assume that hour 07:20:00 by adding 4hour
$d1_timestamp = strtotime($d1); // first date's timestamp
$d2_timestamp = strtotime($d2); // second date's timestamp
$time_diff = $d2_timestamp - $d1_timestamp; //difference
echo $time_diff; // this will give you 14400
?>
$date = date("Y-m-d H:i:s");
$addhr= 4;//Replace you value to be added here
$format="H:i";
echo $date."<br>";
echo date($format, strtotime("$date + $addhr hours"));
You can use \DateTime class and add any interval with DateTime::add. Also you can use procedure style.
Basically am trying to set a time and a date in PHP then set a time gap which will range between minutes, loop through between a start time and end time echoing something out for each one. Have tried loads of different ways and cant seem to figure a way to set a date and add to it.
This seems the best script I have modified so far:
$minutes = 5;
$endtime = new DateTime('2012-01-01 09:00');
$newendtime = $endtime->format('Y-m-d H:i');
$timedate = new DateTime('2012-01-01 09:00');
while($stamp < $newendtime)
{
$time = new DateTime($timedate);
$time->add(new DateInterval('PT' . $minutes . 'M'));
$timedate = $time->format('Y-m-d H:i');
echo $timedate;
}
$minutes = 5;
$endtime = new DateTime('2012-01-01 09:00');
//modified the start value to get something _before_ the endtime:
$time = new DateTime('2012-01-01 8:00');
$interval = new DateInterval('PT' . $minutes . 'M');
while($time < $endtime){
$time->add($interval);
echo $time->format('Y-m-d H:i');
}
Do everything in seconds, and use php's time(), date(), and mktime functions.
In UNIX Time, dates are stored as the number of seconds since Jan 1, 1970.
You can render UNIX Timestamps with date().
$time = time(); // gets current time
$endtime = mktime(0,0,0, 1, 31, 2012); // set jan 31 # midnight as end time
$interval = 60 * 5; // 300 seconds = 5 minutes
while($time < $endtime){
$time += $interval;
echo date("M jS Y h:i:s a",$time) . "<br>"; // echos time as Jan 17th, 2012 1:04:56 pm
}
date reference:
http://us3.php.net/manual/en/function.date.php (includes superb date format reference too)
mktime reference: http://us2.php.net/mktime
time() only gets the current time, but just for kicks n' giggles: http://us2.php.net/time
And, it's super easy to store in a database!
This function will let you add date to your existing datetime. This will also preserves HH:MM:SS
<?php
function add_date($givendate,$day=0,$mth=0,$yr=0) {
$cd = strtotime($givendate);
$newdate = date('Y-m-d h:i:s', mktime(date('h',$cd),
date('i',$cd), date('s',$cd), date('m',$cd)+$mth,
date('d',$cd)+$day, date('Y',$cd)+$yr));
return $newdate;
}
?>
Usage:
add_date($date,12,0,0);
where $date is your date.
I get the time:
$today = time();
$date = date('h:i:s A', strtotime($today));
if the current time is "1:00:00 am", how do i add 10 more hours to become 11:00:00 am??
strtotime() gives you a number back that represents a time in seconds. To increment it, add the corresponding number of seconds you want to add. 10 hours = 60*60*10 = 36000, so...
$date = date('h:i:s A', strtotime($today)+36000); // $today is today date
Edit: I had assumed you had a string time in $today - if you're just using the current time, even simpler:
$date = date('h:i:s A', time()+36000); // time() returns a time in seconds already
$tz = new DateTimeZone('Europe/London');
$date = new DateTime($today, $tz);
$date->modify('+10 hours');
// use $date->format() to outputs the result.
see DateTime Class
(PHP 5 >= 5.2.0)
You can simply make use of the DateTime class , OOP Style.
<?php
$date = new DateTime('1:00:00');
$date->add(new DateInterval('PT10H'));
echo $date->format('H:i:s a'); //"prints" 11:00:00 a.m
$date = date('h:i:s A', strtotime($today . ' + 10 hours'));
(untested)
$date = date('h:i:s A', strtotime($today . " +10 hours"));
Full code that shows now and 10 minutes added.....
$nowtime = date("Y-m-d H:i:s");
echo $nowtime;
$date = date('Y-m-d H:i:s', strtotime($nowtime . ' + 10 minute'));
echo "<br>".$date;
In order to increase or decrease time using strtotime you could use a Relative format in the first argument.
In your case to increase the current time by 10 hours:
$date = date('h:i:s A', strtotime('+10 hours'));
In case you need to apply the change to another timestamp, the second argument can be specified.
Note:
Using this function for mathematical operations is not advisable. It is better to use DateTime::add() and DateTime::sub() in PHP 5.3 and later, or DateTime::modify() in PHP 5.2.
So, the recommended way since PHP 5.3:
$dt = new DateTime(); // assuming we need to add to the current time
$dt->add(new DateInterval('PT10H'));
$date = $dt->format('h:i:s A');
or using aliases:
$dt = date_create(); // assuming we need to add to the current time
date_add($dt, date_interval_create_from_date_string('10 hours'));
$date = date_format($dt, 'h:i:s A');
In all cases the default time zone will be used unless a time zone is specified.