Adding time in PHP - php

I am pulling a datetime from a mysql db and i would like to add X hours to it then compare it to the current time. So far i got
$dateNow = strtotime(date('Y-m-d H:i:s'));
$dbTime = strtotime($row[0]);
then i tried $dbTime + strtotime("4 hours"); but 4 hours seem to add 4hrs to the current time instead of raw 4hours. How do i add X hours to dbTime?
NOTE: I am using php 5.1.2 so date_add doesnt work (5.3.0)

You have quite a few options here:
1.
$result = mysql_query("SELECT myDate FROM table");
$myDate = mysql_result($result, 0);
$fourHoursAhead = strtotime("+4 hours", strtotime($myDate));
2.
// same first two lines from above
$fourHoursAhead = strtotime($myDate) + 4 * 60 * 60;
3.
$result = mysql_query("SELECT UNIX_TIMESTAMP(myDate) FROM table");
$myDate = mysql_result($result, 0);
$fourHoursAhead = $myDate + 4 * 60 * 60;
4.
$fourHoursAhead = strtotime("+4 hours", $myDate);
5.
$result = mysql_query("SELECT UNIX_TIMESTAMP(DATE_ADD(myDate, INTERVAL 4 HOUR))");
$fourHoursAhead = mysql_result($result, 0);

then i tried $dbTime + strtotime("4 hours"); but 4 hours seem to add 4hrs to the current time instead of raw 4hours. How do i add X hours to dbTime?
strtotime has an optional second argument. Provide a Unix timestamp there and the output will be relative to that date instead of the current date.
$newTime = strtotime('+4 hours', $dbTime);
You can also use the fact that Unix timestamps are seconds-based - if you know what four hours are in seconds, you can just add that to the time integer value.

time() and strtotime() result in unix timestamps in seconds, so you can do something like the following, provided your db and do your comparison:
$fourHours = 60 * 60 * 4;
$futureTime = time() + $fourHours;

strtotime("+4 hours", $dbTime);
The second argument is the timestamp which is used as a base for the calculation of relative dates; it defaults to the current time. Check out the documentation.
Edit:
For short periods of time, max 1 week, adding seconds to a timestamp is perfectly acceptable. There is always (7 * 24 * 3600) seconds in a week; the same cannot be said for a month or year. Furthermore, a unix timestamp is just the number of seconds that have elapsed since the Unix Epoch (January 1 1970 00:00:00 GMT). That is not effected by timezones or daylight-savings. Timezones and daylight-savings are only important when converting a unix timestamp to an actual calendar day and time.

I tend to use the time() function, and this page from the manual shows them displaying the date a week in the future:
http://us3.php.net/manual/en/function.time.php

Here's how I'd do it:
Pull the time from the database using the UNIX_TIMESTAMP() function.
The UNIX timestamp is in seconds, so add 4*60*60 to it.
Convert the modified UNIX timestamp to a date using PHP's localtime() or strftime() function.
query("SELECT UNIX_TIMESTAMP(someDatetimeColumn) ...");
. . .
$dbTimeAdjusted = localtime($row[0] + 4*60*60);

Probably the safest way to do the compare is right in the SQL
SELECT * FROM my_table WHERE someDateTimeColumn < DATE_ADD(NOW(), INTERVAL 4 hour)
And since you're assembling it in PHP, you can dynamically replace the "4 hour" bit with whatever your code needs to compare.
(Note: putting the entire calculation on the other side of the comparison to the column allows MySQL to do the calculation once per query, rather than once per row, and also use the table's index, if that column has one.)

Assuming that the timestamp returned by the DB is in SQL format, the following should work fine:
$dbTime = strtotime($row[0]);
$nowTime = time();
$future_dbTime = strtotime("+4 hours", $dbTime);
$diff_time_seconds = $nowTime - $dbTime;
if ($diff_time_seconds > 0) {
echo "The current time is greater than the database time by:\n";
$not_equal = true;
}
if ($diff_time_seconds == 0) {
echo "The current time is equal to the database time!";
}
if ($diff_time_seconds < 0) {
echo "The current time is less than the database time by:\n";
$not_equal = true;
}
if ($not_equal) {
$diff_time_abs_seconds = abs($diff_time_seconds);
echo date('h:m:s', $diff_time_abs_seconds);
}

Related

How to compare current time with old time in PHP

I have stored date field at DB.
In PHP, i am getting that field and converted into date.
I want to compare that time with current time. If that difference is above 60 minutes. It will return some value.
I dont know how to write logic for that
$lastUpdatedField = $rows_fetch['lastUpdatedTime'];
$lastUpdatedDate = new DateTime($lastUpdatedField);
$nowDate = new DateTime(date('y-m-d h:m:s'));
I have old date&time is in $lastUpdatedDate variable, and current time is in $nowDate.
How to compare these two
$interval = $nowDate->diff($lastUpdatedDate);
echo $interval->h;
DateDiff: http://www.php.net/manual/en/datetime.diff.php
DateInterval: http://www.php.net/manual/en/class.dateinterval.php
Had The same problem earlier its actually quit simple
heres the piece where you declare your variables
$lastUpdateddate = new DateTime($lastUpdatedField);
$nowDate = new DateTime(date('y-m-d h:m:s'));
Then you have to convert them to second - format so that you can do math with them
To do that use strtotime
$Diff = strtotime($lastUpdatedDate) - strtotime($nowDate);
Then just check to see if the difference in time is more then 60 minutes,
So devide by 60 seconds to get minutes and by 60 to get hours
if ($diff/60/60 <= 1){
//do your thing here
{
First convert the current time and old time to one unit like Unix timestamp passing it through strtotime(). Then differentiate both the timestamp to get the difference between two times.
$difftime = strtotime(date('Y-m-d H:i:s')) - strtotime($rows_fetch['lastUpdatedTime']);
Then convert the difference to days as follows :
$days=$difftime/24*60*60;
Once you get the days you can get the minutes from it as below to compare to meet your need.
$timediff = $days * 24 * 60;

Check if datetime value is from last 30 days in php (not in the mysql query)?

I need to check with php if values got from a database are from last 30 days.
The values are formatted as follows:
2012-03-19 05:00:32
How can this be done?
You can use strtotime to turn it to a unix timestamp.
$db_date = "2012-03-19 05:00:32";
if (time() - strtotime($db_date) <= 30 * 86400) {
//...
}
$date = '2012-03-19 05:00:32';
if (strtotime($date) >= strtotime('-30 days')) {
// do something
}
See strtotime() reference.
You could do it in PHP, but that'd mean a roundtrip through the date/time system to process that string back into a date value:
$within_30 = ((strtotime('2012-03-19 05:00:32') + 30*86400) > time());
Assumign you're using MySQL, you could do it in the query directly, and save some time conversions:
SELECT ((yourtimefield + INTERVAL 30 DAY) > now()) AS within_30 ...

today and not last 24 hours?

i my php codes i do time()-86400 to fetch everything from the last 24 hours, but how i can get everything today or everything from yesterday. thus it is no longer 86400 seconds, it should be after 12 midnight till current time.
hope this makes sense.. but how i can do this?
If you are "fetching" from a database, why not do it in the query?
SELECT * FROM `table` WHERE DATE(`created_at`) = '2011-03-28';
If you are storing the date as a unix timestamp:
SELECT * FROM `table` WHERE DATE(FROM_UNIXTIME(`created_at`)) = '2011-03-28';
time()-strtotime('today') - difference between now and midnight; time()-strtotime('yesterday') - difference between now and yesterday midnight; time()-strtotime('-2 days')...
for yesterday only (range $min to $max)
$start = strtotime('yesterday')
$end = strtotime('today') - 1;
etc.
Following will give you the seconds passed since January 1, 1970. Every object with a timestamp higher than this value is from the current day (given that you have set your timezones and local time correctly).
$time = strtotime(date('Y-m-d 00:00:00'));
You can use the PHP date and strtotime function in order to pick a day from now and retrieve the seconds that specific date. For more info, see: http://php.net/manual/en/function.date.php and http://php.net/manual/en/function.strtotime.php
I agree with Gordon here - there are so many date/time examples. But hey, let's go over it again - assuming today begins at midnight, you use:
$start = strtotime('today');
Assuming "today" ends at 23:59, simple arithmetics imply that if you increment the $start by 24 hours and take away 1 second - you'll reach the end of today.
So:
$start = strtotime('today');
$end = $start + (3600 * 24) - 1;

Check interval between datetimes in PHP

I have a field in database that has type of datetime in which I add time when user visit a page. When user again comes I want to check the interval between his first visit and current. If it is less or equal to 1 hour then I want to show him some message.
I store time like this
2011-03-04 00:25:01
The thing that I want to ask that how to check the interval in PHP
You could try
SELECT COUNT(#UserID) FROM table WHERE LastVisit > (DateADD(now(),interval -1 Hour))
you can then check the count
Edit: added FROM clause
If you have PHP >= 5.3 you can use DateTime objects and functions:
$visit = DateTime::createFromFormat('Y-m-d H:i:s', '2011-03-04 00:25:01');
$now = new DateTime("now");
$diff = $now->diff($visit);
What you can so is, retrieve the the datetime, store it in a variable.
Create a var with time().
You can then convert the db datetime to a timestring using strtotime()
Subtract the datetime timestring from the new time. That should give you a difference in seconds. You can then manipulate your values and do the relevant checks.
$db = datetime_from_database;
$now = time();
$last = strtotime($db);
$diff = $now - $last; //this is in seconds
You can do something like
$minutes = $diff / 60;
If ($minutes > 60) echo 'more than 1 hour; 60 minutes';
Just work in it.
You can then use the date functions to format the new datetime using the $now and update the database.

How to obtain, increment, and compare datetime in PHP?

I am developing a quiz site and there is time for x min to answer the quiz. So when user clicks on start quiz link the starttime (current time at this instant) is recored in session. Also the endtime (start_time+ 30 min) is recorded in session and every time he submits a answer the current time is compared with the quiz end time. Only if the current time is less than end_time the answer should be accepted.
How can I get the currentdatetime?
How can I add x minutes to current this datetime?
How can I compare (<=) datetime ?
I think we should use date time. Is it right?
PHP measures time as seconds since Unix epoch (1st January 1970). This makes it really easy to work with, since everything just a single number.
To get the current time, use: time()
For basic maths like adding 30 minutes, just convert your interval into seconds and add:
time() + 30 * 60 // (30 * 60 ==> 30 minutes)
And since they're just numbers, just do regular old integer comparison:
$oldTime = $_SESSION['startTime'];
$now = time();
if ($now < $oldTime + 30 * 60) {
//expired
}
If you need to do more complicated things like finding the date of "next tuesday" or something, look at strtotime(), but you shouldn't need it in this case.
use php builtin functions to get time:
<?php
$currentTimeStamp = time(); // number of seconds since 1970, returns Integer value
$dateStringForASpecificSecond = date('Y-m-d H:i:s', $currentTimeStamp);
?>
for your application that needs to compare those times, using the timestamp is more appropriate.
<?php
$start = time();
$end = $start + (30 * 60); // 30 minutes
$_SESSION['end_time'] = $end;
?>
in the page where the quiz is submitted:
<?php
$now = time();
if ( $now <= $_SESSION['end_time'] ) {
// ok!
}
?>
Use the time() function to get a UNIX timestamp, which is really just a large integer.
The number returned by time() is the number of seconds since some date (like January 1, 1970), so to add $x minutes to it you do something like (time() + ($x*60)).
Since UNIX timestamps are just numbers, you can compare them with the usual comparison operators for numbers (< <= > >= ==)
time() will give you the current time in seconds since 1/1/1970 (an integer), which looks like it should be good.
To add x minutes, you'd just need to add x*60 to that, and you can compare it like any other two integers.
Source: http://us3.php.net/time
This is an old question but I wanted to provide an answer based on the PHP 5.2 DateTime class which I feel is much easier to use and much more versatile than any previous functions.
So how can i get the currentdatetime?
You can create a new DateTime object like this:
$currentTime = new DateTime();
But at this point, $currentTime is a datetime object and must be converted to a string in order to store it in a database or output it.
$currentTime = $currentTime->format('Y-m-d H:i:s');
echo $currentTime;
Outputs 2014-05-10 21:14:06
How can i add x minutes tocurrent this datetime?
You can add x minutes with the modify method:
$currentTime = new DateTime();
$addedMinutes = $currentTime->modify('+10 minutes');
echo $addedMinutes;
Outputs 2014-05-10 21:24:06
How can i comapare (<=) datetime ?
With the DateTime class, you can not only easily compare datetime objects, you can get the difference between them.
$currentTime = new DateTime('2014-05-10 21:14:06');
$addDays = $currentTime->modify('+10 days');
To compare
if ($currentTime >= $addDays) {
//do something//
}
$diffTime = new DateTime('2014-05-10 21:14:06');
$diff = $addDays->diff($diffTime);
$diff = $diff->format('There are %d days difference.');
echo $diff;
Outputs There are 10 days difference.

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