I am developing a quiz site and there is time for x min to answer the quiz. So when user clicks on start quiz link the starttime (current time at this instant) is recored in session. Also the endtime (start_time+ 30 min) is recorded in session and every time he submits a answer the current time is compared with the quiz end time. Only if the current time is less than end_time the answer should be accepted.
How can I get the currentdatetime?
How can I add x minutes to current this datetime?
How can I compare (<=) datetime ?
I think we should use date time. Is it right?
PHP measures time as seconds since Unix epoch (1st January 1970). This makes it really easy to work with, since everything just a single number.
To get the current time, use: time()
For basic maths like adding 30 minutes, just convert your interval into seconds and add:
time() + 30 * 60 // (30 * 60 ==> 30 minutes)
And since they're just numbers, just do regular old integer comparison:
$oldTime = $_SESSION['startTime'];
$now = time();
if ($now < $oldTime + 30 * 60) {
//expired
}
If you need to do more complicated things like finding the date of "next tuesday" or something, look at strtotime(), but you shouldn't need it in this case.
use php builtin functions to get time:
<?php
$currentTimeStamp = time(); // number of seconds since 1970, returns Integer value
$dateStringForASpecificSecond = date('Y-m-d H:i:s', $currentTimeStamp);
?>
for your application that needs to compare those times, using the timestamp is more appropriate.
<?php
$start = time();
$end = $start + (30 * 60); // 30 minutes
$_SESSION['end_time'] = $end;
?>
in the page where the quiz is submitted:
<?php
$now = time();
if ( $now <= $_SESSION['end_time'] ) {
// ok!
}
?>
Use the time() function to get a UNIX timestamp, which is really just a large integer.
The number returned by time() is the number of seconds since some date (like January 1, 1970), so to add $x minutes to it you do something like (time() + ($x*60)).
Since UNIX timestamps are just numbers, you can compare them with the usual comparison operators for numbers (< <= > >= ==)
time() will give you the current time in seconds since 1/1/1970 (an integer), which looks like it should be good.
To add x minutes, you'd just need to add x*60 to that, and you can compare it like any other two integers.
Source: http://us3.php.net/time
This is an old question but I wanted to provide an answer based on the PHP 5.2 DateTime class which I feel is much easier to use and much more versatile than any previous functions.
So how can i get the currentdatetime?
You can create a new DateTime object like this:
$currentTime = new DateTime();
But at this point, $currentTime is a datetime object and must be converted to a string in order to store it in a database or output it.
$currentTime = $currentTime->format('Y-m-d H:i:s');
echo $currentTime;
Outputs 2014-05-10 21:14:06
How can i add x minutes tocurrent this datetime?
You can add x minutes with the modify method:
$currentTime = new DateTime();
$addedMinutes = $currentTime->modify('+10 minutes');
echo $addedMinutes;
Outputs 2014-05-10 21:24:06
How can i comapare (<=) datetime ?
With the DateTime class, you can not only easily compare datetime objects, you can get the difference between them.
$currentTime = new DateTime('2014-05-10 21:14:06');
$addDays = $currentTime->modify('+10 days');
To compare
if ($currentTime >= $addDays) {
//do something//
}
$diffTime = new DateTime('2014-05-10 21:14:06');
$diff = $addDays->diff($diffTime);
$diff = $diff->format('There are %d days difference.');
echo $diff;
Outputs There are 10 days difference.
Related
How exactly is this done? There's so many questions on stack-overflow about what I'm trying to do; However all of the solutions are to edit the MYSQL Query, and I need to do this from within PHP.
I read about the strtotime('-30 days') method on another question and tried it, but I can't get any results. Here's what I'm trying:
$current_date = date_create();
$current_date->format('U');
... mysql code ...
$transaction_date = date_create($affiliate['Date']);
$transaction_date->format('U');
if($transaction_date > ($current_date - strtotime('-30 days'))) {
} else if(($transaction_date < (($current_date) - (strtotime('-30 days'))))
&& ($transaction_date > (($current_date) - (strtotime('-60 days'))))) {
}
Effectively, I'm trying to sort all of the data in the database based on a date, and if the database entry was posted within the last 30 days, I want to perform a function, then I want to see if the database entry is older than 30 days, but not older than 60 days, and perform more actions.
This epoch math is really weird, you'd think that getting the epoch of the current time, the epoch of the data entry, and the epoch of 30 and 60 days ago would be good enough to do what I wanted, but for some reason it's not working, everything is returning as being less than 30 days old, even if I set the date in the database to last year.
No need to convert to unix timestamp, you can already compare DateTime objects:
$current_date = data_create();
$before_30_day_date = date_create('-30 day');
$before_60_day_date = date_create('-60 day');
$transaction_date = date_create($affiliate['Date']);
if ($transaction_date > $before_30_day_date) {
# transation date is between -30 day and future
} elseif ($transaction_date < $before_30_day_date && $transaction_date > $before_60_day_date) {
# transation date is between -60 day and -30 day
}
This creates (inefficiently, see my comment above) an object:
$current_date = date_create(date("Y-m-d H:i:s"));
From which you try to subtract an integer:
if($transaction_date > ($current_date - strtotime('-30 days'))) {
which is basically
if (object > (object - integer))
which makes no sense.
you're mixing the oldschool time() system, which deals purely with unix timestamps, and the newer DateTime object system, which deals with objects.
What you should have is
$current_date = date_create(); // "now"
$d30 = new DateInterval('P30D'); // 30 days interval
$transaction_date = date_create($affiliate['Date']);
if ($transaction_date > ($current_date->sub($d30)) { ... }
You might consider DatePeriod class, which in essence gives you the ability to deal with a seires of DateTime objects at specified intervals.
$current_date = new DateTime();
$negative_thirty_days = new DateInterval::createFromDateString('-30 day');
$date_periods = new DatePeriod($current_date, $negative_thrity_days, 3);
$thirty_days_ago = $date_periods[1];
$sixty_day_ago = $date_periods[2];
Here you would use $thirty_days_ago, $sixty_days_ago, etc. for your comparisons.
Just showing this as alternative to other options (which will work) as this is more scalable if you need to work with a larger number of interval periods.
I have stored date field at DB.
In PHP, i am getting that field and converted into date.
I want to compare that time with current time. If that difference is above 60 minutes. It will return some value.
I dont know how to write logic for that
$lastUpdatedField = $rows_fetch['lastUpdatedTime'];
$lastUpdatedDate = new DateTime($lastUpdatedField);
$nowDate = new DateTime(date('y-m-d h:m:s'));
I have old date&time is in $lastUpdatedDate variable, and current time is in $nowDate.
How to compare these two
$interval = $nowDate->diff($lastUpdatedDate);
echo $interval->h;
DateDiff: http://www.php.net/manual/en/datetime.diff.php
DateInterval: http://www.php.net/manual/en/class.dateinterval.php
Had The same problem earlier its actually quit simple
heres the piece where you declare your variables
$lastUpdateddate = new DateTime($lastUpdatedField);
$nowDate = new DateTime(date('y-m-d h:m:s'));
Then you have to convert them to second - format so that you can do math with them
To do that use strtotime
$Diff = strtotime($lastUpdatedDate) - strtotime($nowDate);
Then just check to see if the difference in time is more then 60 minutes,
So devide by 60 seconds to get minutes and by 60 to get hours
if ($diff/60/60 <= 1){
//do your thing here
{
First convert the current time and old time to one unit like Unix timestamp passing it through strtotime(). Then differentiate both the timestamp to get the difference between two times.
$difftime = strtotime(date('Y-m-d H:i:s')) - strtotime($rows_fetch['lastUpdatedTime']);
Then convert the difference to days as follows :
$days=$difftime/24*60*60;
Once you get the days you can get the minutes from it as below to compare to meet your need.
$timediff = $days * 24 * 60;
How can I compute time difference in PHP?
example: 2:00 and 3:30.
I want to convert the time to seconds then subtract them then convert it back to hours and minutes to know the difference. Is there an easier way to get the difference?
Look at the PHP DateTime object.
$dateA = new DateTime('2:00');
$dateB = new DateTime('3:00');
$difference = $dateA->diff($dateB);
(assuming you have >= PHP 5.3)
You can also do it the procedural way...
$dateA = strtotime('2:00');
$dateB = strtotime('3:00');
$difference = $dateB - $dateA;
See it on CodePad.org.
You can get the hour offset like so...
$hours = $difference / 3600;
If you are dealing with times that fall between a 24 hour period (0:00 - 23:59), you could also do...
$hours = (int) date('g', $difference);
Though that is probably too inflexible to be worth implementing.
Check this link ...
http://www.onlineconversion.com/days_between_advanced.htm
I used this to calculate the difference between server time and the users local time. Grab the hour difference and drop that in a form when the user is registering. I then use it to update the time on the site for the user when they do stuff online.
Once I got it working, I switched this line ...
if (form.date1.value == "")
form.date1.value = s;
to ...
form.date1.value = "<?PHP echo date("m/d/Y H:i:s", time()) ?>";
Now I can compare the user time and the server time! You can grab the seconds and mins as well.
I have a field in database that has type of datetime in which I add time when user visit a page. When user again comes I want to check the interval between his first visit and current. If it is less or equal to 1 hour then I want to show him some message.
I store time like this
2011-03-04 00:25:01
The thing that I want to ask that how to check the interval in PHP
You could try
SELECT COUNT(#UserID) FROM table WHERE LastVisit > (DateADD(now(),interval -1 Hour))
you can then check the count
Edit: added FROM clause
If you have PHP >= 5.3 you can use DateTime objects and functions:
$visit = DateTime::createFromFormat('Y-m-d H:i:s', '2011-03-04 00:25:01');
$now = new DateTime("now");
$diff = $now->diff($visit);
What you can so is, retrieve the the datetime, store it in a variable.
Create a var with time().
You can then convert the db datetime to a timestring using strtotime()
Subtract the datetime timestring from the new time. That should give you a difference in seconds. You can then manipulate your values and do the relevant checks.
$db = datetime_from_database;
$now = time();
$last = strtotime($db);
$diff = $now - $last; //this is in seconds
You can do something like
$minutes = $diff / 60;
If ($minutes > 60) echo 'more than 1 hour; 60 minutes';
Just work in it.
You can then use the date functions to format the new datetime using the $now and update the database.
I am pulling a datetime from a mysql db and i would like to add X hours to it then compare it to the current time. So far i got
$dateNow = strtotime(date('Y-m-d H:i:s'));
$dbTime = strtotime($row[0]);
then i tried $dbTime + strtotime("4 hours"); but 4 hours seem to add 4hrs to the current time instead of raw 4hours. How do i add X hours to dbTime?
NOTE: I am using php 5.1.2 so date_add doesnt work (5.3.0)
You have quite a few options here:
1.
$result = mysql_query("SELECT myDate FROM table");
$myDate = mysql_result($result, 0);
$fourHoursAhead = strtotime("+4 hours", strtotime($myDate));
2.
// same first two lines from above
$fourHoursAhead = strtotime($myDate) + 4 * 60 * 60;
3.
$result = mysql_query("SELECT UNIX_TIMESTAMP(myDate) FROM table");
$myDate = mysql_result($result, 0);
$fourHoursAhead = $myDate + 4 * 60 * 60;
4.
$fourHoursAhead = strtotime("+4 hours", $myDate);
5.
$result = mysql_query("SELECT UNIX_TIMESTAMP(DATE_ADD(myDate, INTERVAL 4 HOUR))");
$fourHoursAhead = mysql_result($result, 0);
then i tried $dbTime + strtotime("4 hours"); but 4 hours seem to add 4hrs to the current time instead of raw 4hours. How do i add X hours to dbTime?
strtotime has an optional second argument. Provide a Unix timestamp there and the output will be relative to that date instead of the current date.
$newTime = strtotime('+4 hours', $dbTime);
You can also use the fact that Unix timestamps are seconds-based - if you know what four hours are in seconds, you can just add that to the time integer value.
time() and strtotime() result in unix timestamps in seconds, so you can do something like the following, provided your db and do your comparison:
$fourHours = 60 * 60 * 4;
$futureTime = time() + $fourHours;
strtotime("+4 hours", $dbTime);
The second argument is the timestamp which is used as a base for the calculation of relative dates; it defaults to the current time. Check out the documentation.
Edit:
For short periods of time, max 1 week, adding seconds to a timestamp is perfectly acceptable. There is always (7 * 24 * 3600) seconds in a week; the same cannot be said for a month or year. Furthermore, a unix timestamp is just the number of seconds that have elapsed since the Unix Epoch (January 1 1970 00:00:00 GMT). That is not effected by timezones or daylight-savings. Timezones and daylight-savings are only important when converting a unix timestamp to an actual calendar day and time.
I tend to use the time() function, and this page from the manual shows them displaying the date a week in the future:
http://us3.php.net/manual/en/function.time.php
Here's how I'd do it:
Pull the time from the database using the UNIX_TIMESTAMP() function.
The UNIX timestamp is in seconds, so add 4*60*60 to it.
Convert the modified UNIX timestamp to a date using PHP's localtime() or strftime() function.
query("SELECT UNIX_TIMESTAMP(someDatetimeColumn) ...");
. . .
$dbTimeAdjusted = localtime($row[0] + 4*60*60);
Probably the safest way to do the compare is right in the SQL
SELECT * FROM my_table WHERE someDateTimeColumn < DATE_ADD(NOW(), INTERVAL 4 hour)
And since you're assembling it in PHP, you can dynamically replace the "4 hour" bit with whatever your code needs to compare.
(Note: putting the entire calculation on the other side of the comparison to the column allows MySQL to do the calculation once per query, rather than once per row, and also use the table's index, if that column has one.)
Assuming that the timestamp returned by the DB is in SQL format, the following should work fine:
$dbTime = strtotime($row[0]);
$nowTime = time();
$future_dbTime = strtotime("+4 hours", $dbTime);
$diff_time_seconds = $nowTime - $dbTime;
if ($diff_time_seconds > 0) {
echo "The current time is greater than the database time by:\n";
$not_equal = true;
}
if ($diff_time_seconds == 0) {
echo "The current time is equal to the database time!";
}
if ($diff_time_seconds < 0) {
echo "The current time is less than the database time by:\n";
$not_equal = true;
}
if ($not_equal) {
$diff_time_abs_seconds = abs($diff_time_seconds);
echo date('h:m:s', $diff_time_abs_seconds);
}